+ All Categories
Home > Documents > บทที่ 7 การกรอง...

บทที่ 7 การกรอง...

Date post: 18-Mar-2020
Category:
Upload: others
View: 0 times
Download: 0 times
Share this document with a friend
48
FILTRATION Nur istianah,ST,MT,M.Eng – KP2 – THP UB
Transcript
Page 1: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

FILTRATION

Nur istianah,ST,MT,M.Eng – KP2 – THP UB

Page 2: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Introduction

Filtration may be defined as the separation of

solids from liquids by passing a suspension through a

permeable medium which retains the particles.

Figure 1. Schematic diagram of filtration system

Page 3: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

The fine apertures necessary for filtration are provided

by fabric filter cloths,

by meshes and screens of plastics or metals,

by beds of solid particles.

In some cases, a thin preliminary coat of cake, or of other fine particles, is put on the cloth prior to the main filtration process.

Page 4: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Types of filtration

1. Surface filters

2. Depth filters

Page 5: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

1.Surface filters

used for cake filtration in which the solids are

deposited in the form of a cake on the up-stream side

of a relatively thin filter medium.

Figure2. Mechanism of cake filtration

Page 6: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

2.Depth filters

used for deep bed filtration in which particle

deposition takes place inside the medium and cake

deposition on the surface is undesirable.

Figure 3. Mechanism of deep bed filtration

Page 7: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

The fluid passes through the filter medium, which

offers resistance to its passage, under the influence

of a force which is the pressure differential across

the filter.

rate of filtration = driving force/resistance

Page 8: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

The filter-cake resistance is obtained by multiplying the specific resistance of the filter cake, that is its resistance per unit thickness, by the thickness of the cake.

The resistances of the filter material and pre-coat are combined into a single resistance called the filter resistance.

It is convenient to express the filter resistance in terms of a fictitious thickness of filter cake.

This thickness is multiplied by the specific resistance of the filter cake to give the filter resistance.

Page 9: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Factor affected on filtration

Pressure drop ( ∆P )

Area of filtering surface ( A )

Viscosity of filtrate ( v )

Resistance of filter cake ( α )

Resistance of filter medium ( Rm )

Properties of slurry ( μ , ฯลฯ )

Page 10: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

rate of filtration = driving force/resistance

-(P) or

Pressure

drop

Filter cake ()

Filter medium (Rm)

Viscosity ()

Page 11: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filtration Equation

Flow of fluid through packed bed : Application of Carman-kozeny’s equation

โดย k1 = constant = 4.17 for particles with definite size and shape

= viscosity of filtrate (Pa.s)

v = linear velocity based on filter area (m/s)

= void fraction หรือ porosity of cake

L = thickness of cake (m)

S0 = specific surface area of particle area per volume of solid particle (m2/m3)

Pc = pressure drop in cake (N/m2)

3

2

0

2

1)1(

svk

L

Pc

Page 12: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Substitute v in term of volume (V)

A = filter area (m2)

V = volume of filtrate at t sec

L = thickness of filter cake

Cs = kg of solid/m3 of filtrate

P = density of solid particle in cake (kg/m3)

A

dtdVv

Page 13: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Substitute L in term of height of cake (L)

Obtain: p

s

A

VCL

)1(

ms R

A

VC

P

dt

dV

A

1

Page 14: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Specific cake resistance ()

โดย = Void fraction

S0 = specific surface area of particle (m2)

)Pressure,,(0

Sf

nP)(0

nP)(10

Page 15: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Specific cake resistance;

Their specific resistance change with pressure drop across the cake ∆pc. In such cases, an average specific cake resistance av should can be determine from

If the function = (∆pc) is known from pilot filtration tests, bomb filter test or from the use of a compressibility cell.

Page 16: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

An experimental empirical relationship can be used over a limit pressure range

Where 0 : the resistance at unit applied pressure drop

n : a compressibility index obtained from experiments

(n = 0 for incompressible substance)

n

cp )(0

nPc)(10

Page 17: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filter medium resistance; R

Normally be constant but may vary with time (as a

result of some penetration of solid into the medium)

and sometimes may also change with applied

pressure (because of the compression of fiber in the

medium).

Page 18: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

As the overall pressure drop across an installed

filter include losses not only in the medium but also in

the associated piping and in the inlet and outlet ports

It is convenient in practice to include all these extra

resistances in the value of the medium resistance R.

Page 19: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Constant pressure filtration

Equation is useful because it covers a situation that is

frequently found in a practical filtration plant.

We could predict the performance of filtration plant on

the basis of experimental results.

If a test is carried out using constant pressure, collecting

and measuring the filtrate at measured time intervals

Page 20: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filtration Equations for

Constant – Pressure Filtration

Page 21: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

At t = t sec At t = t sec

P

Rm

A

V

P

Cs

AV

t

2/

Page 22: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Determine and Rm

Page 23: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filtration equation for

Constant rate Filtration

Page 24: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

For incompresible cake: Kv and C are

constant

Page 25: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

dV/dt = constant = V/t

P

t

Slope Y-intercept

Page 26: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

From constant rate equation the pressure drop

required for any desired flow rate can be found.

Also, if a series of runs is carried out under different

pressures, the results can be used to determine the

resistance of the filter cake.

Page 27: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Ex1. Constant pressure

Filtration area = 0.01 m2 A

Solution density = 1,062 kg/m2

Solution viscosity = 1.610-3 Pa.s

Filtration pressure = 200 kPa P

Solid concentration = 3 kg/m3 Cs

Determine specific filter cake resistance and filter medium

resistance

Time (sec) Volume (cm3)

0 0

14 400

32 800

55 1200

80 1600

107 2000

Page 28: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Y = aX + C

Y axis = tA/V

X axis = V/A

Slope = Cs/2P

Y intercept = Rm/P

The solution

Page 29: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Time (sec) Volume (cm3) Volume (m3) tA/V V/A

0 0 0 0 0

14 400 0.0004 350 0.04

32 800 0.0008 400 0.08

55 1200 0.0012 458.33 0.12

80 1600 0.0016 500 0.16

107 2000 0.0020 535 0.20

y = 1175x + 307.67R2 = 0.9912

0

100

200

300

400

500

600

0 0.05 0.1 0.15 0.2 0.25V/A

tA/V

Page 30: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

kgm

P

CsSlope

/10792.9

1175)10200(2

)3()106.1(

11752

10

3

3

mR

R

P

Rercepty

m

m

m

/110845.3

67.30710200

)106.1(

67.307int

10

3

3

Page 31: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Ex2. Constant rate

A slurry containing 25.7 kg dry solids/m3 of filtrate across the

filter medium area 2.15 m2 at a constant rate of 0.00118

m3/s. If the pressure drop was observed 4,000 and 8,500 Pa

after 150 and 450 seconds of filtration, respectively. The

viscosity of filtrate was 0.001 Pa.s

Determine the specific cake resistance and filter medium

resistance.

Page 32: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

t

V

A

Rmt

t

V

A

CsP

At

RmV

tA

CsVP

t

RmA

VCs

PAV

dt

RmA

VCs

PAdV

tCons

RmA

VCs

PA

dt

dV

.

tan

2

2

2

2

The solution

P

(Pa)

t (sec)

t

V

A

Rercepty

t

V

A

CsSlope

m

int

2

2

(1)

(2)

(4)

(3)

Page 33: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

y = 15x + 1750R2 = 1

0100020003000400050006000700080009000

0 100 200 300 400 500t (sec)

P (

Pa)

P (Pa) t (sec)

4,000 150

8,500 450

Page 34: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

mR

R

t

V

A

Rercepty

kgm

t

V

A

CsSlope

m

m

m

/110189.3

175015.2

)00118.0()001.0(

1750int

/10938.1

1515.2

)00118.0)(7.25()001.0(

15

9

9

2

2

2

2

Page 35: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filtration Equipment

The basic requirements for filtration equipment are:

mechanical support for the filter medium

flow accesses to and from the filter medium

provision for removing excess filter cake.

Page 36: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

In some instances, washing of the filter cake to

remove traces of the solution may be necessary.

Pressure can be provided on the upstream side of

the filter, or a vacuum can be drawn downstream, or

both can be used to drive the wash fluid through.

Page 37: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Filtration equipment: (a) plate and frame press (b) rotary vacuum filter (c) centrifugal filter

Page 38: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

1.Plate and frame filter press

In the plate and frame filter press, a cloth or mesh is spread out over plates which support the cloth along ridges but at the same time leave a free area, as large as possible, below the cloth for flow of the filtrate.

The plates with their filter cloths may be horizontal, but they are more usually hung vertically with a number of plates operated in parallel to give sufficient area.

Page 39: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

In the early stages of the filtration cycle, the pressure

drop across the cloth is small and filtration proceeds

at more or less a constant rate.

As the cake increases, the process becomes more and

more a constant-pressure one and this is the case

throughout most of the cycle.

When the available space between successive frames

is filled with cake, the press has to be dismantled and

the cake scraped off and cleaned, after which a

further cycle can be initiated.

Page 40: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

The plate and frame filter press is cheap but it is difficult to mechanize to any great extent.

Filtration can be done under pressure or vacuum. The advantage of vacuum filtration is that the pressure drop

can be maintained whilst the cake is still under atmospheric pressure and so can be removed easily.

The disadvantages are the greater costs of maintaining a given pressure drop by applying a vacuum and the limitation on the vacuum to about 80 kPa maximum.

In pressure filtration, the pressure driving force is limited only by the economics of attaining the pressure and by the mechanical strength of the equipment

Page 41: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

BAS stainless steel plate and frame filter press

Page 42: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

2.Rotary filters

In rotary filters, the flow passes through a rotating cylindrical cloth from which the filter cake can be continuously scraped.

Either pressure or vacuum can provide the driving force, but a particularly useful form is the rotary vacuum filter.

Page 43: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

The rotary vacuum drum filter

Page 44: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

A suitable bearing applies the vacuum at the stage where the actual filtration commences and breaks the vacuum at the stage where the cake is being scraped off after filtration. Filtrate is removed through trunnion bearings.

Rotary vacuum filters are expensive, but they do provide a considerable degree of mechanization and convenience.

Page 45: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

3.Centrifugal filters

Centrifugal force is used to provide the driving force in

some filters.

These machines are really centrifuges fitted with a

perforated bowl that may also have filter cloth on it.

Liquid is fed into the interior of the bowl and under the

centrifugal forces, it passes out through the filter

material.

Page 46: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

Centrifugal filters

Page 47: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

4. clarrification

Filtration that use gravitational force only as the driving for

It has low energy requirement

Simple and low cost

Need large amount of processing time

Page 48: บทที่ 7 การกรอง Filtrationnuristianah.lecture.ub.ac.id/files/2016/09/kp2_Filtration.pdf · Filtration area 2 = 0.01 m A Solution density 2 = 1,062 kg/m Solution

THANKS FOR YOUR ATTENTION

The best person is one give something useful always

Nur Istianah-KP2-2016


Recommended