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ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and...

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1 ABAQUS Project Analysis of Human Body Stress Field in Femur Roxanne Su 12/12/06
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Page 1: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS ProjectAnalysis of Human Body

Stress Field in Femur

Roxanne Su12/12/06

Page 2: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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Outline

• Brief introduction• Basic assumptions• ABAQUS results and interpretations• Summary

http://www.3d4medical.com/view_rm_horizontal_image~aid~000009910.htm

Page 3: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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Introduction

• Build a homogeneous & an inhomogeneous model• Bone density

• Investigations of stress within femur bones• Relations of loading and cracking on the bone• Comparisons between the 2D and 3D model

Page 4: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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Assumptions

• Human body is complicatedCommercial package - 3D modelUse a simple 2D model

• Femur bone shape was sketched from a CT imageRoughly the same as femur bone

by photoshop by ABAQUS

Page 5: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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Assumptions• Bone density is estimated

*

Page 6: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS Results - Femur2D Homogeneous Model

Homogeneous femur modeldensity is the same inside the bone

Ebone = 2875ρ3; ρ=1ν = 0.3 [1]

[1] L. B. Querol et al., J of Biomechanics 36 897 2003

Stress is relatively low in this region.

•Apply a concentrated force on humeralhead while the diaphyseal part of the boneremains fixed.

Page 7: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS Results - Femur2D Inhomogeneous Model

• Inhomogeneous model, E depends on bone density [1]Ebone = 60+900ρ2, ρ<0.46 (g/cm3) [MPa]

Or Ebone = 2875ρ3, otherwise [MPa]ν = 0.3•Apply a concentrated force on humeral head while the diaphyseal part of the bone remains fixed.

[1] L. Belenguer et al., Statistical Finite Element Model for Bone Shape and Biomechanical Properties, 405 2006

• Bone relative density is roughly divided into 3 segments.ρ=1 E=2875 MPaρ=0.8 E=1472 MPaρ=0.5 E =359.4 MPa

Page 8: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS Results - FemurLoading and Crack 3D Model-1

Page 9: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS Results - FemurLoading and Crack 3D Model-2

ρ

σ

1 ρ, E2 ρ, σ3 ρ<0.4; σ is very small4 Results are not quite the same

Page 10: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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ABAQUS Results - FemurCracking and Loading 2D Model

ABAQUS

Partition

ρ=0.8 ρ=1.0

ρ=0.5

1ρ≈0.5, σ is very small

2 As ρ=1 area increases, high σ region expands.

3σ is highly dependent on ρ

4 Femur is estimated to fracture at the fixed end.

53D model would give a better simulation prediction.

Fixed End

Page 11: ABAQUS Project Analysis of Human Body - Mechanics Bone.pdfABAQUS Results - Femur Cracking and Loading 2D Model ABAQUS Partition ρ=0.8 1 ρ=0.5 1ρ≈0.5, σ is very small 2 As ρ=1

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Summary

• Build a simple 2D model

• Comparison between a 2D model and a 3D one

• Predict cracking AckowledgementHongtao Wang


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