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Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

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Acid-Base Titrations
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Page 1: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acid-Base Titrations

Page 2: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Introduction to Acids and Bases

Chapter 8

Page 3: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Name Acids Base

Definition Example Definition Example

Arrhenius An H-containing compound that increases H+ concentration in water

HClHNO3

HBrHFAcetic acid

An OH-containing compound that increases OH- concentration in water

KOHNaOH

Bronsted-Lowry

Proton donor Terminal alkynes

Proton acceptor NH3

Lewis Electron pair acceptor

Fe3+ and other transition metal cations

Electron pair donor

There are three (3) definitions of acids and bases: 1. Arrhenius, 2. Bronsted-Lowry and 3. Lewis.

Page 4: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

There are three (3) definitions of acids and bases: 1. Arrhenius, 2. Bronsted-Lowry and 3. Lewis.

acidbase acid

acidbase conjugate acid

Conjugate acid-base pairs differ by only one proton.

base

conjugate base

Page 5: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

There are three (3) definitions of acids and bases: 1. Arrhenius, 2. Bronsted-Lowry and 3. Lewis.

Lewis Acids:Any species that accepts electron pairs. (H+ CO2,

Mn+)

Arrhenius Bases:LiOH,

Mg(OH)2

Arrhenius Acids:

HCl, H2SO4

Bronsted Bases:H2O, NH3, HS-

Bronsted Acids:

H2O, HS-,

H2PO4-

Lewis Bases:Any species with

a lone pair

Page 6: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acids and Bases undergo neutralization reactions.

NaOH + HCl NaCl + H2O

Na+ + OH– + H+ + Cl– Na+ + Cl– + H2O H+ + OH– H2O

Page 7: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acids and Base strengths are defined by how much H3O+ or OH- is produced by a given concentration

Strong Acid Weak Acid

Page 8: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acids and Base strengths are defined by how much H3O+ or OH- is produced by a given concentration

percent ionization =

Ionized acid concentration at equilibrium

Initial concentration of acidx 100%

For a monoprotic acid HA

[H+]eqx 100% [HA]0 = initial concentration

Percent ionization = [HA]0

Page 9: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Weak acids and bases are in equilibrium with their original species.

CH3COOH + H2O H3O+ +CH3COO–

Kc =H3O

+[ ] CH3COO

−[ ]

H2O[ ] CH3COOH[ ]Kc << 1

Kc H2O[ ] =H3O

+[ ] CH3COO

−[ ]

CH3COOH[ ]

Ka =H3O

+[ ] CH3COO

−[ ]

CH3COOH[ ]

Page 10: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Weak acids and bases are in equilibrium with their original species.

NH3 + H2O NH4+

+OH–

Kc =NH4

+[ ] OH

−[ ]

H2O[ ] NH3[ ]Kc << 1

Kc H2O[ ] =NH4

+[ ] OH

−[ ]

NH3[ ]

Kb =NH4

+[ ] OH

−[ ]

NH3[ ]

Page 11: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Ka and Kb tells us something about the relative acid/base strengths

Page 12: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Ka and Kb tells us something about the relative acid/base strengths

Page 13: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Water can act both as an acid and a base (AUTOIONIZATION)

Kc =H3O

+[ ] OH

−[ ]

H2O[ ]2

Kc H2O[ ]2

= H3O+

[ ] OH−

[ ]

Kw = H3O+

[ ] OH−

[ ]

The ion-product constant (Kw) is the product of the concentration of H3O+ and OH– ions at a particular temperature

At 250CKw = [H3O+][OH-] = 1.0 x

10-14

Page 14: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

The p-scale conveniently handles a wide range of concentrations

]log[ 3 OHpH

]log[ OHpOH

KwpKw log KapKa log

Page 15: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Solving weak acid ionization problems:

1. Identify the major species that can affect the pH.

• In most cases, you can ignore the autoionization of water. [H3O+] from water is negligible in comparison to [H3O+] from the weak acid.

• Ignore [OH-] because it is determined by [H+].

2. Use ICE to express the equilibrium concentrations in terms of single unknown x.

3. Write Ka in terms of equilibrium concentrations. Solve for x by the approximation method. If approximation is not valid, solve for x exactly.

4. Calculate concentrations of all species and/or pH of the solution.

Page 16: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

ExercisesWhat is the pH of a 0.5 M HF solution (at 25°C,

Ka = 7.1 x 10-4)?

What is the pH of a 0.05 M HF solution?

What is the pH of a 0.122 M monoprotic acid whose Ka is 5.7 x 10-4?

Page 17: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Complete the following table:

Parameter

An NaOH solution

A 0.30 M HNO3

pH 9.52

pOH

[H3O+]

[OH-]

Page 18: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Complete the following table:

Parameter

An NaOH solution

A 0.30 M HNO3

pH 9.52 0.52

pOH 4.48 13.48

[H3O+] 3.0 x 10-

10M0.30 M

[OH-] 3.3 x 10-5

M3.3 x 10-14 M

Page 19: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Exercises

What is the pH, [H3O+], [OH-] of 7.52 x 10-4 M CsOH?

What is the pOH, [H3O+], [OH-] of 1.59 x10-3 M HClO4?

What is the [H3O+], [OH-] and pOH in a solution with a pH of 2.77

What is the [H3O+], [OH-] and pH in a solution with a pOH of 11.27

Page 20: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

ExercisesChloroacetic acid has a pKa of 2.87. What are

[H3O+], pH, [ClCH2COOH], [ClCH2COO-] in 1.05 M [ClCH2COOH]

A 0.735 M of weak acid is 12.5% dissociated. Calculate [H3O+], pH, [OH-], pOH of solution. Calculate Ka of acid

Page 21: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

BuffersChapter 9

Page 22: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers solutions are solutions that resist changes in pH

Page 23: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers contain appreciable amounts of a weak acid and its conjugate base

HA/ A–

NH4Cl/NH3

H3PO4/NaH2PO4

NH4SH/Na2SHCOOH/HCOOK

HBr/KBrH3IO3/Li2HIO3

NaOH/Na2O

Page 24: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

What do we mean by appreciable?o A 50-mL solution of 0.25 M Acetic

acid.o A 50-mL solution of 0.25 M Sodium

Acetateo A solution containing 0.125 M Acetic

acid and 0.125 M AcetateHA / A–

+ acid+ base

** If we take the ratio of base to acid or acid to base, it should be within 10% of each other

Buffers contain appreciable amounts of a weak acid and its conjugate base

Page 25: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers work because there are weak acids and weak bases present to counter-act small

amounts of acid/bases.

Page 26: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

The effectivity (and pH) of the buffer is dependent on the ratio between the weak

acid and its conjugate base

Ka =H3O

+[ ] A

−[ ]

HA[ ]

−log Ka( ) = −logH3O

+[ ] A

−[ ]

HA[ ]

⎝ ⎜ ⎜

⎠ ⎟ ⎟

−logKa = −log H3O+

[ ] − logA−

[ ]

HA[ ]

pKa = pH − logA−

[ ]

HA[ ]

pH = pKa+ logA−

[ ]

HA[ ]

Henderson-Hasselbach Equation:

Page 27: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

The effectivity (and pH) of the buffer is dependent on the ratio between the weak

acid and its conjugate base

pH = pKa+ logA−

[ ]

HA[ ]

o A 0.25 M Acetic acid buffer with pH 4.74

o A 0.25 M Acetic acid buffer with pH 5.10

o A 0.25 M Acetic acid buffer with pH 4.40

** If we take the ratio of base to acid or acid to base, it should be within 10% of each other

0.1<A−

[ ]

HA[ ]<10

1 pKapHBUFFER RANGE

Page 28: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

The effectivity (and pH) of the buffer is dependent on the ratio between the weak

acid and its conjugate base

o A buffer for pH 10.00

o A buffer for pH 4.00

o A buffer for pH 7.00

The closer the pH of the buffer to the pKa the better

Page 29: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

The effectivity (and pH) of the buffer is also dependent on the total amount of weak acid

and conjugate base.

pH = pKa+ logA−

[ ]

HA[ ]

o A 1.00 M Acetic acid buffer with pH 4.74

o A 0.30 M Acetic acid buffer with pH 4.74

o A 0.10 M Acetic acid buffer with pH 4.74

o A 0.030 M Acetic acid buffer with pH 4.74

Page 30: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffer Capacity is the measure of the ability of a buffer to resist pH Changes

pH = pKa+ logA−

[ ]

HA[ ]

1 pKapH

GOOD BUFFER RANGE+ appreciable amounts (High Concentration)…

Page 31: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers work through a phenomenon known as the common ion effect

What is the common ion effect?This effect occurs when a reactant

containing a given ion is added to an equilibrium mixture that already contains that ion, and the position of equilibrium shifts away from forming more of it

Page 32: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Preparation of Buffers

1. Choose the conjugate acid-base pair2. Calculate the ratio of the buffer

component concentrations3. Determine the buffer concentration4. Mix the solution and adjust pH

Page 33: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers can be prepared using a weak acid and the salt of its conjugate base (or a weak base

and the salt of its conjugate acid).

Example 1Preparing a pH 10.00 carbonate buffer. How many grams of Na2CO3 must one add to 1.5 L of freshly prepared 0.20 M NaHCO3 to make the buffer? Ka of HCO3

- is 4.7 x 10-11

Example 2Prepare a 50-mL of 0.12 M Acetic acid buffer with equal concentrations of acetic acid and acetate from 3.00 M acetic acid stock solution and sodium acetate salt

Page 34: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Buffers can also be prepared by using a weak acid (or weak base) then add a strong

base (or acid) to desired pH.

5.0 g of CH3COONa is dissolved in 100. mL of water. How many mL of 0.50 MHCl should be added to form a buffer with pH 4.90? Will diluting the final mixture to 500 mL affect the pH of the buffer? What is affected by dilution?

Page 35: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acid-Base TitrationsChapter 10

Page 36: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

In an acid-base reaction, the key parameter that changes in the system is pH.

Example:

A 40.00 mL sample of 0.1000 M HCl solution was titrated with 0.1000 M NaOH solution.

Calculate the pH when the following volume of the NaOH is added.

a) 0.00 b) 10.00c) 20.00d) 30.00e) 35.00

f) 39.00g) 40.00h) 41.00i) 45.00j) 50.00

Page 37: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

In an acid-base reaction, pH is monitored through colored indicators.

Page 38: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acid-base indicators are usually weak acids (HIn) which have different color than its conjugate

base (In-).

acidic

basic

change occurs

over ~2 pH units

Page 39: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

Acid-base indicators are usually weak acids (HIn) which have different color than its conjugate

base (In-).

Page 40: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

40 mL of 0.1000 M HCl

TITRATION OF A STRONG ACID BY A STRONG BASE

Page 41: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A WEAK ACID BY A STRONG BASE

REGION 1: Before addition (weak acid)

REGION 2: Before Equivalence point (buffer)

REGION 3: At Equivalence point (weak base)

REGION 4: After Equivalence point (strong base)

Page 42: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A WEAK ACID BY A STRONG BASE

EXAMPLE in Book: Titration of 50.00 mL of 0.0200 M MES (pKa = 6.27) with 0.1000 M NaOH

REGION 1: Before addition (weak acid)

REGION 2: Before Equivalence point (buffer)

REGION 3: At Equivalence point (weak base)

REGION 4: After Equivalence point (strong base)

Page 43: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A WEAK BASE BY A STRONG ACID

REGION 1: Before addition (weak base)

REGION 2: Before Equivalence point (buffer)

REGION 3: At Equivalence point (weak acid)

REGION 4: After Equivalence point (strong acid)

Page 44: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A WEAK BASE BY A STRONG ACID

Example in Book: Titration of 25.00 mL of 0.08364 M pyridine (Kb = 1.6 x 10-9) with 0.1067 M HCl.

REGION 1: Before addition (weak base)

REGION 2: Before Equivalence point (buffer)

REGION 3: At Equivalence point (weak acid)

REGION 4: After Equivalence point (strong acid)

Page 45: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A POLYPROTIC SYSTEMS

Page 46: Acid-Base Titrations. Introduction to Acids and Bases Chapter 8.

TITRATION OF A POLYPROTIC SYSTEMS


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