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Winter 2008 1
Active Circuits
Associate Prof. Dr. Soliman Mahmoud
8/10/2019 Active circuits
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Winter 2008 2
Chapter1:
Design of Compensated Finite Gain
op-amp based Amplifiers for High
Frequency Applications.
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
Objectives and outlines:
1. Introduction
Typical frequency response of the operational amplifiers
The effect of finite GB of op-amp on the performance of op-amp
amplifiers.
Definitions: Error Function (S), Magnitude error () andPhase error ()
2. The compensation of Non-Inverting Amplifier
Passive Compensation
Active Compensation
3. The compensation of Inverting Amplifier
Passive Compensation
Active Compensation (Assignment 1)
Design of Compensated Finite Gain op-amp based
Amplifiers for High Frequency Applications.
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
1. Introduction
The non-inverting and inverting finite gain amplifiers arebasic building blocks in the realization of active RC filtersand oscillators.
The finite gain bandwidth product of the op-ampdegrades significantly the phase and magnitude of the
conventional finite gain amplifiers.The purpose of this lecture is to introduce two methodsof compensated non-inverting and inverting finite gainamplifiers using passive or active elements.
The compensated amplifiers have negligible phase andmagnitude errors up to an extended frequency range.
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
Typical frequency response of the operational amplifiers Av(S=j)
).........1)(1)(1(
)(
321
SSS
ASA vov
Assuming the zeros are neglected
Note: 1 is much lower than the
rest of the break-frequencies,
causing 1 to be the dominantinfluence in the frequency
response.
)1(
)(
1
S
ASA
vo
v
SS
GB
S
ASA
tvo
v
1)(For 2 > >> 1,
Where GB is the gain-bandwidth of
the op-amp and t is the unity gain
radian frequency
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
Vin
Vout
K R
R
A
+
-outin
outout VKVA
VVVAV
1
1)(
t
in
out
SKK
A
K
K
V
V
)1(1
1)1(
)1(1
)1(
The effect of finite GB of op-amp on the performance of op-amp amplifiers
For Non-inverting Amplifier
For ideal Amplifier )1( KV
V
Ain
out
Therefore, we define the error function
(s) as follows:
t
SKS
)1(
1
1)(
Lett
K
1
SS 1
1
)(
jj
1
1)(
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
jj
1
1)(From the error function , we can define also:
(a) Phase error : ()
)(tan0)(tan)( 11
1)()( for
(b) Magnitude error : )(
1)(1
1)(
2
1)(21)( 2 for
From (a) and (b), we note that the phase error is more dangerous than
the magnitude error
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
Vin
Vout
K R
A
+
-
R)( VVAVout
SK
K
AK
K
V
V
t
in
out
)1(1
1
)1(1
1
The effect of finite GB of op-amp on the performance of op-amp amplifiers
For inverting Amplifier
For ideal Amplifier KV
V
Ain
out
Therefore, we define the error function(s) as follows:
t
SKS
)1(
1
1)(
Lett
K
1
SS
11)(
jj
1
1)(
]1
1
1[0 outin
out VK
VK
K
A
V
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
jj
1
1)(From the error function ,
(a) Phase error : ()
)(tan0)(tan)( 11
1)()( for
(b) Magnitude error : )(
1)(1
1)(
2
1)(21)( 2 for
2 f
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
2. The compensation of Non-Inverting
Amplifier(a) Passive Compensation (Wilson1976)
VinVout
K R
R
A
+
-
C
)(
VVAVout
)()1(1
)1
(1
)1(2
tt
in
out
KCRS
KS
KKCRS
KV
V
KSCRK
VV
A
V outin
out
)1(
)()1(1
)1
(1
)(2
tt
KCRS
KS
KKCRS
s
; second order error function
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
Note: For the error function
2
2
1
1
1)(
bSSa
Sas
]3
)[()()( 2
3
2
3
13
21 baaa
aa
]2[2
)( 222
1
2
baa
The magnitude and phase errors are given as follows:
Therefore the condition for minimum phase error is a1=a2 and in this case
][)( 23 ba
][)( 2 b
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
)()1(1
)1
(1
)( 2
tt
KCRSKS
K
KCRS
s
Therefore, the design value of C for minimum phase error , we must force
the coefficient of S in the Numerator and to be the same;
t
K
K
KCR
1
1 tKR
KC
2)1(
Let
1
1
K
KRCK
t
2211)(
SS
Ss
3
)()(
2)()(
Note :The main disadvantages of the passive compensation is that the valueof C is determined in terms of t but t is sensitive to the process and
temperature variation, hence active compensation is uses.
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
(b) Active Compensation
VinVout
K1R1
R1
A1
+
-+
-
K2R2
R2
Phase Corrector
Vo1
A2
For op-amp 1: inVV
1
1
1 K
VV o
For op-amp 2:outVV
1
22
2
1
1
1 oout V
KV
K
KV
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
VinVout
K1R1
R1
A1
+
-+
-
K2R2
R2
Phase Corrector
Vo1
A2
Calculation of Vo1 :
outo V
A
KV
2
21 )1(
1
1
)1
1
1( 1
22
2
2
1ooutout
o VK
VK
KV
A
V
Calculation of Vout :
])1(
1[1
1
1
1
2
21
1
11
A
K
V
KVV
KV
A
V outinoin
out
21
21
1
1
2
2
1 )1)(1()
1(1
)
1
(1)1(
AA
KK
A
K
A
K
KV
V
in
out
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
2
21
21
1
1
2
2
)1)(1()
1(1
)1(1
)(S
KKS
K
SK
s
ttt
t
; second order error function
Therefore, the error function is given by:
For minimum phase error:
2
2
1
1 )1()1(
tt
KK
If A1 and A2 are matched (t1= t2) K1= K2
Let
2
2
1
1 11
tt
KK
221
1)(
SS
Ss
3)()(
2)()(
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
3. The compensation of Inverting Amplifier
(a) Passive Compensation (Wilson)
Vin
Vout
K R
A
+
-
R
C
C/K
(1)
A
Vout
By applying KCL at
node (1):
01
)()1
)(( KRA
VV
K
SC
A
VSC
RA
VV outout
outoutin
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
)1()
1(1
1
A
KSCR
A
K
SCRK
V
V
in
out
RCK
SK
S
SCRs
tt
)1()
1(1
1)(
2
; second order error function
Therefore;
For minimum phase error: RCK
t
)1(
tR
KC
)1(
Let RCK
t
1
221
1)(
SS
Ss
3)()(
2)()(
8/10/2019 Active circuits
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Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department
(b) Active Compensation (Assignment 1)
Vin
Vout
K1R
A1+
-
R
+
-
K2R
R
Phase Corrector
A2
Show that:
(a) The closed loop gain is given by:
21
21
1
1
2
2
1 )1)(1()1(1
)1(1
AA
KK
A
K
A
K
KV
V
in
out
(b) Find the necessary condition for phase compensation and determine
the resulting phase and magnitude errors of the compensated amplifier