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Active circuits

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    Winter 2008 1

    Active Circuits

    Associate Prof. Dr. Soliman Mahmoud

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    Winter 2008 2

    Chapter1:

    Design of Compensated Finite Gain

    op-amp based Amplifiers for High

    Frequency Applications.

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    Objectives and outlines:

    1. Introduction

    Typical frequency response of the operational amplifiers

    The effect of finite GB of op-amp on the performance of op-amp

    amplifiers.

    Definitions: Error Function (S), Magnitude error () andPhase error ()

    2. The compensation of Non-Inverting Amplifier

    Passive Compensation

    Active Compensation

    3. The compensation of Inverting Amplifier

    Passive Compensation

    Active Compensation (Assignment 1)

    Design of Compensated Finite Gain op-amp based

    Amplifiers for High Frequency Applications.

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    1. Introduction

    The non-inverting and inverting finite gain amplifiers arebasic building blocks in the realization of active RC filtersand oscillators.

    The finite gain bandwidth product of the op-ampdegrades significantly the phase and magnitude of the

    conventional finite gain amplifiers.The purpose of this lecture is to introduce two methodsof compensated non-inverting and inverting finite gainamplifiers using passive or active elements.

    The compensated amplifiers have negligible phase andmagnitude errors up to an extended frequency range.

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    Typical frequency response of the operational amplifiers Av(S=j)

    ).........1)(1)(1(

    )(

    321

    SSS

    ASA vov

    Assuming the zeros are neglected

    Note: 1 is much lower than the

    rest of the break-frequencies,

    causing 1 to be the dominantinfluence in the frequency

    response.

    )1(

    )(

    1

    S

    ASA

    vo

    v

    SS

    GB

    S

    ASA

    tvo

    v

    1)(For 2 > >> 1,

    Where GB is the gain-bandwidth of

    the op-amp and t is the unity gain

    radian frequency

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    Vin

    Vout

    K R

    R

    A

    +

    -outin

    outout VKVA

    VVVAV

    1

    1)(

    t

    in

    out

    SKK

    A

    K

    K

    V

    V

    )1(1

    1)1(

    )1(1

    )1(

    The effect of finite GB of op-amp on the performance of op-amp amplifiers

    For Non-inverting Amplifier

    For ideal Amplifier )1( KV

    V

    Ain

    out

    Therefore, we define the error function

    (s) as follows:

    t

    SKS

    )1(

    1

    1)(

    Lett

    K

    1

    SS 1

    1

    )(

    jj

    1

    1)(

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    jj

    1

    1)(From the error function , we can define also:

    (a) Phase error : ()

    )(tan0)(tan)( 11

    1)()( for

    (b) Magnitude error : )(

    1)(1

    1)(

    2

    1)(21)( 2 for

    From (a) and (b), we note that the phase error is more dangerous than

    the magnitude error

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    Vin

    Vout

    K R

    A

    +

    -

    R)( VVAVout

    SK

    K

    AK

    K

    V

    V

    t

    in

    out

    )1(1

    1

    )1(1

    1

    The effect of finite GB of op-amp on the performance of op-amp amplifiers

    For inverting Amplifier

    For ideal Amplifier KV

    V

    Ain

    out

    Therefore, we define the error function(s) as follows:

    t

    SKS

    )1(

    1

    1)(

    Lett

    K

    1

    SS

    11)(

    jj

    1

    1)(

    ]1

    1

    1[0 outin

    out VK

    VK

    K

    A

    V

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    jj

    1

    1)(From the error function ,

    (a) Phase error : ()

    )(tan0)(tan)( 11

    1)()( for

    (b) Magnitude error : )(

    1)(1

    1)(

    2

    1)(21)( 2 for

    2 f

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    2. The compensation of Non-Inverting

    Amplifier(a) Passive Compensation (Wilson1976)

    VinVout

    K R

    R

    A

    +

    -

    C

    )(

    VVAVout

    )()1(1

    )1

    (1

    )1(2

    tt

    in

    out

    KCRS

    KS

    KKCRS

    KV

    V

    KSCRK

    VV

    A

    V outin

    out

    )1(

    )()1(1

    )1

    (1

    )(2

    tt

    KCRS

    KS

    KKCRS

    s

    ; second order error function

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    Note: For the error function

    2

    2

    1

    1

    1)(

    bSSa

    Sas

    ]3

    )[()()( 2

    3

    2

    3

    13

    21 baaa

    aa

    ]2[2

    )( 222

    1

    2

    baa

    The magnitude and phase errors are given as follows:

    Therefore the condition for minimum phase error is a1=a2 and in this case

    ][)( 23 ba

    ][)( 2 b

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    )()1(1

    )1

    (1

    )( 2

    tt

    KCRSKS

    K

    KCRS

    s

    Therefore, the design value of C for minimum phase error , we must force

    the coefficient of S in the Numerator and to be the same;

    t

    K

    K

    KCR

    1

    1 tKR

    KC

    2)1(

    Let

    1

    1

    K

    KRCK

    t

    2211)(

    SS

    Ss

    3

    )()(

    2)()(

    Note :The main disadvantages of the passive compensation is that the valueof C is determined in terms of t but t is sensitive to the process and

    temperature variation, hence active compensation is uses.

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    (b) Active Compensation

    VinVout

    K1R1

    R1

    A1

    +

    -+

    -

    K2R2

    R2

    Phase Corrector

    Vo1

    A2

    For op-amp 1: inVV

    1

    1

    1 K

    VV o

    For op-amp 2:outVV

    1

    22

    2

    1

    1

    1 oout V

    KV

    K

    KV

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    VinVout

    K1R1

    R1

    A1

    +

    -+

    -

    K2R2

    R2

    Phase Corrector

    Vo1

    A2

    Calculation of Vo1 :

    outo V

    A

    KV

    2

    21 )1(

    1

    1

    )1

    1

    1( 1

    22

    2

    2

    1ooutout

    o VK

    VK

    KV

    A

    V

    Calculation of Vout :

    ])1(

    1[1

    1

    1

    1

    2

    21

    1

    11

    A

    K

    V

    KVV

    KV

    A

    V outinoin

    out

    21

    21

    1

    1

    2

    2

    1 )1)(1()

    1(1

    )

    1

    (1)1(

    AA

    KK

    A

    K

    A

    K

    KV

    V

    in

    out

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    2

    21

    21

    1

    1

    2

    2

    )1)(1()

    1(1

    )1(1

    )(S

    KKS

    K

    SK

    s

    ttt

    t

    ; second order error function

    Therefore, the error function is given by:

    For minimum phase error:

    2

    2

    1

    1 )1()1(

    tt

    KK

    If A1 and A2 are matched (t1= t2) K1= K2

    Let

    2

    2

    1

    1 11

    tt

    KK

    221

    1)(

    SS

    Ss

    3)()(

    2)()(

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    3. The compensation of Inverting Amplifier

    (a) Passive Compensation (Wilson)

    Vin

    Vout

    K R

    A

    +

    -

    R

    C

    C/K

    (1)

    A

    Vout

    By applying KCL at

    node (1):

    01

    )()1

    )(( KRA

    VV

    K

    SC

    A

    VSC

    RA

    VV outout

    outoutin

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    )1()

    1(1

    1

    A

    KSCR

    A

    K

    SCRK

    V

    V

    in

    out

    RCK

    SK

    S

    SCRs

    tt

    )1()

    1(1

    1)(

    2

    ; second order error function

    Therefore;

    For minimum phase error: RCK

    t

    )1(

    tR

    KC

    )1(

    Let RCK

    t

    1

    221

    1)(

    SS

    Ss

    3)()(

    2)()(

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    Associate Prof. Dr. Soliman MahmoudElectronics and Electrical Engineering Department

    (b) Active Compensation (Assignment 1)

    Vin

    Vout

    K1R

    A1+

    -

    R

    +

    -

    K2R

    R

    Phase Corrector

    A2

    Show that:

    (a) The closed loop gain is given by:

    21

    21

    1

    1

    2

    2

    1 )1)(1()1(1

    )1(1

    AA

    KK

    A

    K

    A

    K

    KV

    V

    in

    out

    (b) Find the necessary condition for phase compensation and determine

    the resulting phase and magnitude errors of the compensated amplifier


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