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AIEEE 2012 Question Paper and Solution

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  • 7/31/2019 AIEEE 2012 Question Paper and Solution

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    (Pg. 1)

    Questions and Solutions

    PAPER - 1 : MATHEMATICS, PHYSICS & CHEMISTRY

    PART- A : MATHEMATICS

    1. The equation sinx sinxe e 4 0 has :

    (1) infinite number of real roots (2) no real roots

    (3) exactly one real root (4) exactly four real roots

    1. (2)

    esin x

    e-sin x

    4 = 0

    Let esin x = t

    t1

    t4 = 0

    t2

    4t 1 = 0

    t =4 16 4

    2

    t = 2 5

    esin x

    = 2 + 5 Not possible [2.7 < e < 2.8]

    esin x

    = 2 5 Not possible [Never Negative]

    2. Let a and b be two unit vectors. If the vectors c a 2b and d 5a 4b are perpendicular

    to each other, then the angle between a and b is :

    (1)6

    (2)2

    (3)3

    (4)4

    2. (3)

    c d = 0

    (a 2b) (5a 4b) = 0

    5 6a b 8 = 0

    a b =1

    2

    a b cos =1

    2

    cos =3

    3. A spherical balloon is filled with 4500 cubic meters of helium gas. If a leak in the balloon

    causes the gas to escape at the rate of 72 cubic meters per minute, then the rate (in meters per

    minute) at which the radius of the balloon decreases 49 minutes after the leakage began is :

    (1) 9/7 (2) 7/9 (3) 2/9 (4) 9/2

    Test Booklet

    Code - C

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    AIEEE 2012 Paper and Solution (2)

    (Pg. 2)

    3. (3)

    34R

    3= 4500

    R3

    = 3 1125 R = 15m

    dv

    dt= 2

    4 dr3 r

    3 dt= 72

    drdt

    = 218r (1)

    Also, 4500 72 49 = 34

    r3

    r = 9m

    dr

    dt=

    18

    81=

    2

    9m/minute

    4. Statement 1: The sum of the series 1 + (1 + 2 + 4 ) + (4 + 6 + 9) + (9 + 12 + 16) + + (361 +

    380 + 400) is 8000.

    Statement 2:n

    3 3 3

    k 1

    k (k 1) n , for any natural number n.

    (1) Statement 1 is false, Statement 2 is true.

    (2) Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation for Statement 1.

    (3) Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for

    statement 1.

    (4) Statement 1 is true, Statement 2 is false.

    4. (2)

    Statement 2:n

    3 3

    K 1

    K (K 1)

    2 3n(n 1) n(n 1)

    2 2= n

    3

    Statement 2 is correct

    Statement 1:

    (13

    03) + (2

    31

    3) + (3

    32

    3) + (20

    319)

    3= 8000

    Statement 1 is correct

    and statement 2 explain statement 1

    5. The negation of the statement

    "If I become a teacher, then I will open a school", is :

    (1) I will become a teacher and I will not open a school.

    (2) Either I will not become a teacher or I will not open a school.

    (3) Neither I will become a teacher nor I will open a school.

    (4) I will not become a teacher or I will open a school.

    5. (1)

    6. If the integral

    5tan x

    dx x a n sin x 2cos x k tan x 2 then a is equal to :

    (1) 1 (2) 2 (3) 1 (4) 2

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    (3) VIDYALANKAR : AIEEE 2012 Paper and Solution

    (Pg. 3)

    6. (4)

    5tanxdx

    tanx 2= x + a ln | sin x 2 cos x | + K

    Differentiating on both side

    5tanx

    tanx 2= 1 +

    a[cosx 2sinx]

    sinx 2cos

    5sinx

    sinx 2cosx =

    sinx 2cosx a(cosx 2sinx)

    sinx 2cosx

    Equating co-efficient of both side

    sinx

    5 1 2a ,

    cosx

    0 2 a

    a = 2

    7. Statement 1 : An equation of a common tangent to the parabola 2y 16 3 x and the ellipse

    2x2

    + y2

    = 4 is y = 2x + 2 3 .

    Statement 2 : If the line4 3

    y mx ,m

    (m 0) is a common tangent to the parabola

    2y 16 3 x and the ellipse 2x

    2+ y

    2= 4, then m satisfies m

    4+ 2m

    2= 24.

    (1) Statement 1 is false, Statement 2 is true.

    (2) Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

    (3) Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for

    Statement 1.

    (4) Statement 1 is true, Statement 2 is false.

    7. (2)

    Put y = 2 24 3

    mx in 2x y 4m

    2

    2 4 32x mx

    m= 4 2 2

    2

    482 m x 8 3 x 4

    m= 0

    y =4 3

    mxm

    is a tangent, discriminant of the above quadratic equation must be zero.

    28 3 =

    2

    2

    484 2 m 4

    m

    m4 + 2m2 24 = 0 (m2 + 6) (m2 4) = 0m = 2

    Statement (2) is a correct explanation of statement (1).

    8. Let

    1 0 0

    A 2 1 0 .

    3 2 1

    If u1 and u2 are column matrices such that Au1 =

    1

    0

    0

    and Au2 =

    0

    1 ,

    0

    then

    u1 + u2 is equal to :

    (1)

    1

    10

    (2)

    1

    11

    (3)

    1

    10

    (4)

    1

    11

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    AIEEE 2012 Paper and Solution (4)

    (Pg. 4)

    8. (4)

    AU1 =

    1 0 0 a

    2 1 0 b

    3 2 1 c

    =

    1

    0

    0

    a

    2a b

    3a 2b c

    =

    1

    0

    0

    a = 1; b = 2; c = 1

    U1 =

    1

    2

    1

    AU2 =

    1 0 0 x

    2 1 0 y

    3 2 1 z

    =

    0

    1

    0

    x

    2x y

    3x 2y z

    =

    0

    1

    0

    x = 0; y = 1; z = 2

    U2 =

    0

    1

    2

    U1 + U2 =

    1

    2

    1

    +

    0

    1

    2

    =

    1

    1

    1

    9. If n is a positive integer, then2n 2n

    3 1 3 1 is :

    (1) an irrational number

    (2) an odd positive integer

    (3) an even positive integer

    (4) a rational number other than positive integers

    9. (1)2n 2n

    3 1 3 1

    1 3 2n 1

    2n 1 2n 3

    C C C2 2n 3 2n 3 ......2n 3

    which is Irrational Number

    10. If 100 times the 100th

    term of an AP with non zero common difference equals the 50 times its

    50

    th

    term, then the 150

    th

    term of this AP is :(1) 150 (2) 150 times its 50th

    term

    (3) 150 (4) zero

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    (5) VIDYALANKAR : AIEEE 2012 Paper and Solution

    (Pg. 5)

    10. (4)

    Let first term a and common difference d

    100 [a + 99 d] = 50 [a + 49 d]

    a = 149 d

    Now,

    T150 = a + 149 d

    T150 = 0

    11. In a PQR, if 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P = 1, then the angle R is equal to :

    (1)5

    6(2)

    6(3)

    4(4)

    3

    4

    11. (2)

    P + Q + R =

    3 sin P + 4 cos Q = 6 . (i)

    4 sin Q + 3 cos P = 1 . (ii)

    squaring and adding (i) and (ii)

    9 + 16 + 24 sin (P + Q) = 37

    sin (P + Q) =1

    2

    P + Q =6

    ;5

    6

    if P + Q =6

    0 < sin P


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