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Exercice 2

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Correction Ex2.

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Example – Quantity of ondensate

Pop stands for effective or gauge pressure

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The schematic below shows the different states

Air compressor

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F1 = 

  .y   . r (

 

)

F1 = 2720 × 35,68 × 0.8 = 76849,79 g/h =^ 76,85 l/h

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• After compression ,

New Air flowrate = = 2720/11.5= 236.5 m3/h

Condensate form: F3F3 = F1 – F2 = 76850 – ( 236.5 x 51.2 x 1) = 64.87 l/h

F2 = New

  .y   . r2 (

 

)

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=  ̇  3@3

= F2 − F = 10.6 l/h

Total condensate quantity = F3 + F5 ≅ 76 L/H

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Compressed air Quality / Qualité Air comprime