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Masters Theses Student Theses and Dissertations
1969
An analysis of an audio amplifier utilizing an operational amplifier An analysis of an audio amplifier utilizing an operational amplifier
and negative feedback and negative feedback
Anthony Francis Lexa
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Recommended Citation Recommended Citation Lexa, Anthony Francis, "An analysis of an audio amplifier utilizing an operational amplifier and negative feedback" (1969). Masters Theses. 6954. https://scholarsmine.mst.edu/masters_theses/6954
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ANA .. LYSIS OF AN AUDIO At,JFLI?IER UTILI7.ING AN
OPEPATIONAL .ANP~.IFIEF AND NEGATIVE FEEDBACK
BY
ANTHOI\ry FR .. <\NCI S LEXA \ C\ ~s--\
A
THESIS
submitted to the faculty of
TBE UNIVERlSTY OF !1ISSQUl~I - ROLLA
in partic:l ft.:liullment of the reqnirements for the
Degree of
}'fASTER OF SCIENCE IN FLEC:TRICA.L ENGINEERING
Rolla, Hissouri
1969
ii
An audio a~plifier utilizing a monolithic operational
amplifier is analyzed. The analysis is a block diagram
approach where the amplifier is divided into three parts;
operational amplifier, power amplifier, and feedback
network. A Fourier series analysis is used to describe the
distortion and signal components of the amplifier out;put.
The results of this analysis demonstrate the advantage of
large negative feedback on frequency response and har
monic distortion. Using relatively few passive components
a high quality audio amplifier is constructed with an out
put power of 15 watts RMS power and negligible harmonic
distortion.
ACKNOWLEDGE}lliNTS
The author wishes to express his gratitude to his
advisor, Dr. Ralph s. Carson~ Professor of Electrical
Engineering~ for his guidance and assistance in this
Master's thesis.
Thanks are also due to Mr. Patrick Vennari for his
programming assistance.
iii
iv
TABI~E OF CONTENTS
ABSrfRA Cjf. . • • • • . • • • • • • • • . . • . • . • • • • • . • . • • • • . . • • • .. • . . . • • . • i i
4~CKNOWl..JEDGE?1ENTS. • • • • • • • • • • • • • • • • • • • • . • • • • • • • • • • • • • . • • • iii
LIST OF FIGURES. • • • . . . . . . . . • . . . . . • . . . . . . . • • . . . . . • • . . • • . vi
LIST OF TABI~ES. . . . . . . . . . . . . . • . . . . • . . . . • . . . . . . . . . . . . . . . . viii
LIST OF SYmOLS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ix
I • INTRODTJCTION. . . • • . . . . . . • . • . • • . • • . . . . • . • • • • . . • . • 1
II.
A. The Integrated Monolithic Operational Amplifier. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1
B. Audio Amplifier Using The Operational Amplifj_er.................................. 2
C. Method Of Solution......................... 5
DESCRIPTION OF POWER AMPLIFIER ................ .
A. Transistor Model Used For Power Amplifier Simulation ................................ .
B • ,.... • A t" . S :tmp ~ L.cy~ng s sump ~ons ................... .
C. Node Voltage Equations For PovJer Amplifier.
D. Solution Of Equations ..................... .
E. Block Diagram Of The Power Amplifier ...... .
7
7
14
15
18
21
III. ADAPTATION AND DESCRIPTION OF OPERATIONAL
IV.
A}1PJ_, ·rF I ER • • • • • • • • • • • • • • . • • • • • • • • • • • • • • • • • • • • • • • 3 0
A. Open-I ... oop Gain............................. 32
B. Frequency Compensation..................... 33
C B • • . ~as 1.ng ................................... .
D. Feedback Network .......................... .
COMPUTATION OF AMPLIFIER CHARACTERISTICS ...... .
34
36
41
A. Block Diagram Of The Audio Amplifier....... 41
B. Output Signal And Output Distortion........ 41
c. Adaptation Of Power Amplifier Analysis..... 46
v.
VI.
v
D. Audio .. tunp lifier Analysis Progr.am. . . . . . . . . . 52
EXPERI}lliNTAL VERIFIC~TION .................... .
A. Objectives ............................... .
59
59
B. Equipment. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59
C. Results................................... 61
DISCUSSION AND CONCLUSIONS •................... 67
BIBLIOGRA.PHY. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 76
APPENDICES. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 78
I. Least Square Curve Fit Of The Form y = y 0 ( exp (kx) - 1 ) .........•...•....•....
II. Newton-Raphson Method For A System Of Equations . .............................. .
III. Power Amplifier Analysis Program ....... .
IV. Derivation Of Fourier Series For Waveform Of Crossover Distortion ................. .
v. Audio Amplifier Analysis Program ......... .
78
81
85
Qq ..,_
101
VITA. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. ,. . . . 119
LIST OF FIGURES
Figure
1
2
3
4
5
6a
6b
7
8
9a
9b
Sirtlplified Block Diagram Of Audio Amplifier ..... ,
Schematic Diagram Of The Pcn·Jer Amplifier ........ .
Equivalent Model Of Tr2nsistor .................. .
Actual And Model Transistor Characteristics ..... .
Po·_,;er Amplifier Using Tra.._1sistor Nodels ......... .
Verification Of Po\·7er Am?lifier Frequency Independence (Theoretical) ................. .
Verification Of Power A~plifier Frequency Independence (Ac cua 1 ) .......•...• , •.....•...
Appi:cximate Haveform Of C;:-c:-.. ssover Distortion .....
Block Diagram Of Po·wer A:np lifier ................ .
'HLP.leform Of Distortion Signal J d 0 (Theoretical) ..
\.·Javeform Of Distortion Signal, d 0 (Actual) ...... .
10 Operationa.l Amplifier Schematic And Equivalent
vi
Page
3
8
10
11
16
19
20
22
25
27
28
Circuit . ........................ ~ . . . . . . . . . .. . . . 31
11
12
13
11+
l5b
16
1'7
18
Frequency Response Of Operational Amplifier ..... .
Exte.c:aal Circuitry Of Operational Amplifier. ..... .
Feedback Net-c;vork .....•..•..........•.............
Ba;;; ic Feedback .Amplifier ........................ .
Schematic And Block Diag1.·a:n Of Audio A!nplifier (Schematic) ................................... .
Schematic And Block Diagram Of Audio Amplifier (Block Diagram) . ........................... .
Theoretical Frequency Response Curve ............ .
Theoretical Plot Of Per Cent Total Ha rrnonic Distortion Versus Frequency ................ .
Theoretical Plot Of Per Cent Total Harmonic Distortion Versus Output Power ............. .
32
35
38
39
42
43
56
57
58
Figure
19
20
21
22
Pictorial Diagram Of Test Setup And Equipment ....
Experimental Frequency Response Curve ........... .
Experimental Plot Of Per Cent Total Harmonic Distortion Versus Frequency ................ .
Experimental Plot Of Per Cent Total Harmonic Distortion Versus Output Power ............. .
vii
Page
60
64
65
66
Table
1
2
3
4
5
LIST OF TABLES
Transistor Model Parameters ..................... .
Fundam~ntal Power Content Of Power Amplifier Output ....................................... .
Results Of Power Amplifier Analysis Program ..... .
Results Of Audio Amplifier Analysis Program ..... .
Results Of Experimental Analysis Of Audio A1nplifier . ................................... .
viii
Page
13
50
5!
55
63
LIST OF SYHBOLS
input signal to audio amplifier (sinusoid)
maximum value of e. ].
output signal from audio amplifier
E0 •.. maximlli~ value of e 0
. . .
input signal to power amplifier (sinusoid)
maximum value of e 1
output signal from power amplifier
maximum value of e2
feedback ratio
Q1 •·A transistor 2N 3904
Q2 transistor 2N 3906
Q3 transistor 2N 3791
Q1~ transistor 2N 3'715
Vee DC power supply voltage
Ra base limiting resistor
CB base lead capacitor
R1 load resistor ......
R. input resistor ].
Rf feedback resistor
cf feedback capacitor
ix
I 0 reverse bias saturation current for an ideal diode
transistor base current
empirically found constant describing transistor input characteristic
transistor turn on voltage
voltage across ideal diode in transistor model
X
vbe voltage from base to emitter in transistor model
Ic
vee
hFE
hoe
vl
v2
v3
v4
v5 T
A2
Bk
do
0 ok
de
0 ck
Eok
Zin
zout
. . .
. . .
transistor collector current
voltage from collector to emitter
h parameter DC current gain
h parameter output conductance
voltage at node 1 in power amplifier
voltage at node 2 in power amplifier
voltage at node 3 in power amplifier
voltage at node 4 in power amplifier
voltage at node 5 in power amplifier
peried of signal
amount of time that power amplifier output signal is near zero - delay time
radian frequency of input or output signal
radian frequency of positive and negative sinusoidal pulse for the approximate waveform of crossover distortion
gain of power amplifier
coefficients of Fourier series representing crossover distortion
theoretical distortion signal
coefficients of Fourier series which represents d
0
theoretical distortion in output of audio amplifier
coefficients of Fourier series ~vhich resprsents de
coefficients of Fourier series which represents output of audio amplifier.
input inpedance of operational amplifier
output indedance of operational amplifier
PLOAD •••
DTOT ••.
Xi
mid-band gain of operational amplifier
frequency dependent gain of operational amplifier
upper cutoff radian frequency for operational amplifier
power delivered to load
per cent total hannonic distortion
I. Intro8uction
A. The Integrated Monolithic Operational Amplifier
The recent development of the monolithic integrated
operational amplifier has caused a great change in circuit
design theory. It is now possible to design circuits
around the operational amplifier as a basic building block
and use relatively few additional passive components. The
operational amplifier characteristically is a high gain
device. Because of thisJ negative feedback can be e~ployed
to provide good stability and increased bandwidth.
The techniques used for the manufacture of these
integrated_....mQ;HF~- circuits are repeated operations
of maski.ngJ photo etching, and dopant diffusion on a
single wafer of silicon. Because of this type of fabrica
tion, it is actually easier to make a transistor or
diode than it is a resistor or capacitor. So it is
des:trable for the ratio of active to passive components to
be much higher in an integrated circuit as compared to a
discrete circuit of sirniliar function. This fact results
in the use of differential amplifiers in integrated
circuits. Coupling capacitors are not needed because the
differential amplifier is a DC amplifier. Hith this type-
l
of design a high ratio of active to p~ssive components can
be achieved. A more detailed descri.ption of the operational
amplifier circuitry will be discussed in Section III.
The use of differential amplification offers a number
of advantages~ such as, DC amplification, good stability,
ir.1munity to interference signals, and wide versatility to
~ention a few. However~ these advantages are dependent on
how well the two devices are matched. Since the transis-
tors are made from the same silicon chip and are physically
close to one another in the integrated circuit, they are
very closely matched in performance and temperature.
Therefore with these characteristics, the integrated
operational amplifier is attractive for circuit design.
Also, as manufacturing techinques are perfected , the cost
will be lowered making the integrated circuit economically
a tt·~.·ac t i ve.
B. At.idio Amplifier Using The Operational Amplifier
I
The circuit which this thesis v.,ill amalyze is an audio
a1nplifier using the type of operational amplifier discussed
above. The audio amplifier has three basic functional
divisions: operational amplifier, power amplifier, and
feedback network. The simplified block diagram is given
in figure 1.
The operational amplifier is a Motorola MC 1433
monolithic integrated operational amplifier. The power
amplifier is a complementary class B amplifier using two
complementary silicon driver transistors and two comple
mentary silicon power transistors. The function of this
2
feed-oaci< ~------------~ -----· --~ network
ei() \ e ./0
Figure 1. Simplified Block Diagram of Audio Amplifier
w
circuit is to give the necessary power gain to drive the
load. The audio amplifier will produce 15 watts (&"'1S)
power into a four ohm load. This circuit will be discussed
more fully in Section II. The feedback network is a R-C
network which determines the amount of feedback from out
put to input.
There are many advantages to this type of audio
amplifier design. One, there are fewer discrete components
than a similiar audio amplifier of the same po~7er rating.
The operational amplifier replaces many front end stages
of standard transistor design, where each of these stages
require many passive elements for biasing and signal
coupling. This causes simpler layout and fewer connections
resulting in higher reliability. Two, the load is directly
coupled to the output of the amplifier. Normally an out
put transformer would be used, which is often a limiting
factor in an audio amplifier's fidelity. Three, the
frequency response is DC to beyond the audio range because
of the operational amplifier's differential amplification
and wide bandwidth. The power amplifier uses wide bandwidth
trans is tors wh:l.ch do not limit the frequency response.
Therefore, the upper cutoff frequency is adjustable by
selection of the passive elements used. Four, the amplifier
has high efficiency because the power amplifier is class
B. Also the operational amplifier's power requirement is
very small. Five, the amplifier has a very low level of
distortion. This is probably the most favorable advantage
of this type of audio amplifier design. Because of the
operational amplifier's high gain a large amount of negative
feedback is used. As ~vill be shown in Section IV, this
feedback results in a reduction in harmonic distortion by
approximately a factor equal to the gain of the operational
amplifier. In d high-quality audio amplifier the harmonic
distortion must be kept to very low level (less than 1 per
cent).
C. Method Of Solution
The audio amplifier will be studied by analyzing each
o:r the three functional blocks listed above sepa.rately and
then combining the results to describe the entire amplifier.
The power amplifier will be analyzed first. The
most prominent source of this distortion in the entire
amplifier is crossover distortion in this stage due to the
~lass B operation.
5
To analyze this circuit a transistor model is formulated
and used to describe the response of the power amplifier.
The digital computer is used to solve a set of five
simultaneous non-linear equations. \\Tith this information
a block diagram representation of the power amplifier can
be made consisting of an ideal amplifier in series with a
distortion signal generator. This ntodel discription of the
power amplifier makes a ·description of the entire amplifier
possible.
Next the operational amplifier will be studied. An
expression \·.7hich describes the gain as a function of
frequency will be found. Biasing and frequency stabilita
tion by use of external circuitry will be discussed. \·Jith
this information it is kno~n how the operational amplifier
will function in. the audio amplifier.
6
By using the information. concerning the operational
amplifier, a description of the feedback network is deter
mined. The usual symbol for the transfer function describing
how much of the output is returned to the input is~-
So a description of the feedback network is actually a
determination of$.
Using the information of the above three sections the
entire audio amplifier can be described. This description
is derived from a Fourier series of the distortion in the
power amplifier. Knowing the distortion introduced, the
gain of the operational and power amplifiers, and~, the
per cent harmonic distortion in the output signal can be
determined. By varying the input signal level (and thereby
the output power) and frequency, an evaluation of the
audio amplifier can be made.
Finally, experimental data of the same factors above
will be taken and correlation of theoretical and experimen
tal results will be discussed.
II. Description Of Power Amplifier
A. Transistor Model Used For Power Amplifier Simulation
Figure 2 is the schematic diagram of the power
amplifier used in the audio amplifier. As was discussed
earlier, this is a class B complementary power amplifier.
All the transistors are silicon. Ql and Q2 are 210 mw
complementary driver transistors. Q3 and Q4 are 150 w
complementary transistors.
In order to evaluate the response of this circuit, a
transistor model was formulated. Since this is a class B
amplifier with no bias, the models must be accurate in
the cutoff region because the point of operation moves
fcom cutoff into the active region and back again as the
input signal varies around zero. The majority of the
distortion in .the power amplifier is due to crossover
distortion which is caused by operation in the nonlinear
region of cutoff.
The model used for this purpose is a "modified h
parameter" model. The output circuit for the transistor
model is a dependent current generator whose current is
equal to hFE Ib. In parallel with the generator is a
conductance h . This, so far, is identical to a standard oe h parameter equivalent circuit. The input circuit is
composed of an ideal diode in series "t-Jith a "battery 11
equal to the turn-on voltage, V~- The current through
7
I
+V cc 0
rff'J l--r-Q3
_LCs~ I . v I -
I I,L -----~ o---, i > R
I I '- L
nput
· RB Q4 9 L I ~~ ~ +Cs ~
~ -vee \,..
Figure 2. Schematic Diagram of Power Amplifier
Ql Q2
Q3 Q4
CB RB vee
2N3904 2N3906 2N3791 2N3715 0.1 mfd 20 ohms 15 volts
(X)
the diode is described by the diode equation:
( K v I Id = I 0 e be - 1)
where: Id = diode current
I 0 = saturation current at reverse bias
K - empirically determened constant
Vb~ = actual voltage across ideal diode
Figure 3 shows the transistor equivalent circuit
described above. Notice in the equivalent circuit the
use of a battery, V~. It should be stressed that Vy is not
an actual battery in the equivalent circuit but simply a
transposition factor. In order to fit the actual input
characteristics with the diode equation the starting point
on the horizontal base voltage axis must be shifted to the
right (increasing voltage) by an amount Vt . Thus Vt is
a transposition factor of Vbe. Therefore, in figure 4 for
the model input characteristics, the exponential equation
starts at v"6 0
In order to find the values of V'6 , K, hFE' and h 0 e
for a particular transistor a photograph of the input
9
(Ib vs Vbe) and output (Ic vs Vee) characteristics is taken.
From the output characteristic hFE and h 0 e are determined
and K and Vy is obtained fram the input characteristic.
I is found by measuring the current with the base emitter 0
junction reversed biased.
Measurement of one of the four transistors used in
the audio amplifier is demonstrated in figure 4. The
definitions of the parameters are:
b~--oc f"j.
'---!
tl -' e-~ ···-o ~
+
vt base +j L- ·-l o- il I
Ib ; ! I I vbe
o-
where:
Vbe \:7
T J
I (1\. "Jj hfe1b
I I .
I emitter
Ib = I 0 (exp(K Vb~) - 1)
vbe= vb~ + v'6 I0 ~I0 (exp(K(Vbe·V~)) - 1)
Figure 3. Equivalent Model Of Transistor
collector ·----{) l _.. + I
~hoe Vee ;
I
I o
t-' 0
Input · Charactertsttcs actual . (2N3906)
IIOdel
.,. ~1 •10
• . ' ·• ... Output
Cbaractertsttca Ic
(aa) I
J • ,
, '•
hFE -
hoe -
Ic !1:,--
Ic
vee
V - constant ce - (DC current gain)
Ib = constant (output admittance)
V - turn on voltage = voltage at which Ib
increases such that transistor goes into
the active region.
K -- empirically determined constant from input
characteristic data using a least sq~~are
fit. (Refer to Appendix I)
! 0 - current with base=emitter junction reversed
biased.
As can be seen from figure 4 a point must be choosen
on the output characteristic where the hFE and h 0 e can
12
be measured. If the point of measurement is changed the
values of hFE and h 0 e will also change. Therefore, an
approximation must be made. The points of measurement are
taken approximately in the center of the region of
operation. This is a compromise betv1een the extreme regions
of saturation and cutoff. Table I lists all of these
measured ct.'\nstants and points of measurements.
Once these constants are known a set of idealized
model characteristics can be formed. This is also done in
figure 4. In the left column the actual photo character
istics are given, in the right column are the idealized
characteristi_cs obtained from the measured parameters.
Measurement in this fashion of all the transistors yields
IC I ----~--------T ____________ l ____ T__ ' --------1 j !Type 'I hFE 1 hoe l K : Vt 1 Io I points of measurement ;
t -----+ _4 !----+ I , --------Ql 2N3904- 167. o : 2 .xlo -u j 28.18078 1 o. 5 , o.l+ra 1 hFE Ib = 0.1 rna
lQ2 I 2N3906 165.0 I s.xlO-~-!30~940291--o.-sl O.lJ.ra I hoe at vee= s.o volts
~31-2N3"791 i 66. 7 j • 025 " ~-il: 91+ 721 I 0. 0 il.O,...a ~~hF;- Ib = 30. rna
}E 2N3'Tl5 I 56.7 I .020-v- j 12.2167U 0.0 11.~ hoe at Vee = 10 volts
Table 1. Transistor Model Parameters
j--l
w
Table I which lists all the parameters. With these
parameters and the transistor model the power amplifier
can be analyzed.
B. Simplifying Assumptions
Refering to figure 2, notice the capacitors from Q3
and Q4 bases to ground. The assumption will now be made
that t-7e c:-.=m neglect the GB capactors in this analysis.
14
The justification stems from the considerations that
CB is a 0.1 mfd capacitor designed only to attenuate high
frequency (mech higher than the audio spectrum). Therefore,
CB at audio frequencies does not present a low enough
impedance to attenuate the audio signal. Also notice that
the transistor models have no capacitance in the equivalent
circuits. The upper frequency cutoff from the transistors
themselves "'.vas neglected because the gain-bandwidth products
of the power transistors is 4 MHZ minimu.-rn and 250 HHZ for
for the driver transistors. With these gain-bandwidth
products it is easily shown that the transistors are not
frequency limited in the audio range.
This assumption is verified experimentally later in
this section. For the time being, by using these assump
tions, the power amplifier analysis can be greatly simpli-
fied.
C. Node Voltage Equations For Po'tJer Amplifier
With the above assumptions, the power amplifier of
figure 2 can be redrawn using the equivalent transistor
models just discussed but neglecting the effect of CB.
Figure 5 is the power amplifier circuit using the equi
valent models.
The transistor parameters Vt, K, hFE and h 0 e are
subscripted to match the number of the transistor Ql, Q2,
Q3, or Q4. Also the nodes of the circuit are numbered Vl,
V2, V3, V4, and V5. It should be noted here that the
transistor model is a representation for frequencies
15
from DC to the upper lim{t on the audio range (20,000 KHZ).
Therefore the Q3 and Q4 emitters are connected to the power
supplies and not AC ground since this is a DC model.
The circuit can be solved by writing the node voltage
equations. The base currents, which are exponential
functions of the base-emitter voltages, can be expressed
by substituting the voltage difference bet1;veen the proper
two nodes for Vbe" In this fashion the node voltage
equations can be written expressing the base currents as
exponential functions of the node voltages.
With these considerations we can now writ·e the
equations for all five nodes.
+Vee
e1 = input signal ( E1 sinwt) i,_eJ i r--· I :J. r ·-\ ,..,..
1_, (1 l '-. hoe3 .sz \.__'II _) ~ I Q3 ~E3Ib~ V ,+ _I I 2 R b3 ·~ ~ I
l B /v-o---tf\r, I _ c3 ~ v4 '>h3 ~FElib.~ h I' j < oel
1 v,. ' ( ~ Ql ? v l. \ +
+ \ ~---·--- R ' e
. ~~2Ib v i lb2 ±--.J I ~ hoe2 ~b4 ~ * 1>4+ -~ h 41b4
b2 - RB ~ Q4 !e4 1 oe
-~cc
e2 = output signal
Figure 5. Power Amplifier Usi.ng Transistor Models
1-' m
For node 1:
1o1 (hFE1 + 1) (exp(K1 Vbe1) - 1)
-!02 (~E2 + 1) ( exp (K2 Vbe2) - 1)
+!03 (hFE3 + 1) (exp(K3 Vbe3) - 1)
-Io4 (hFE4 + l) (exp(K3 Vbe4) - 1)
+(V2 - Vl) hoel -(vl.- V3) hoe2 +(Vee
-(Vl + v ) h ee oe4
For node 2:
For node 3:
-v3 + v5 = o
For node 4:
For node 5:
-(Vl I~) = 0
vbe2 = vl - el - vl2
vbe3 = vee - v4 - v~3
vbe4 = v5 - vee - v~4
- Vl) hoe3
(1)
(2)
(3)
These equations describe the response of the power
amplifier using the equivalent transistor model discussed
in Section II - A.
17
13
D. Solution of Equations
In order to solve the five simultaneous non-linear
equations, the well known NewtonRaphson interative techniq~e
was used. (Refer to Appendix II) A program was written to
solve the equations assuming a sinusoidal input voltage.
The reason for a sinusoidal input will become apparent
later in this discussion.
The period of the sinusoid is broken into 200 seg
rnents and the equations solved for each of these segments.
Knowing the node voltages, the base currents, collector
currents, base-emitter voltages, and collector-emitter
voltages can be found by substituting back into the
proper equations. At each time increment the computer
calculates all of the above variables. Appendix III lists
the power amplifier analysis program, flow chart, the
actual program, and a sample of the output.
The only input variable into the program is the rnaxi.mum
value of the input sinusoid, E1 . From the previous assump
tions the output waveform from the computer should describe
the actual circuit.' s wavefonn for any frequency in the
audio range.
To verify this, figure 6 compares the theoretical
waveform fran the equivalent model circuit to the actual
response of the power amplifier for three different
frequencies. Figure 6-a is the theoretical response
plotted by the computer. Figure 6-b is the actual response
19
Theoretical Response Using Transistor Models
10 sinw t (volts)
r :x, ' ·r •-:: J .,.. t ! I t : ..-.- t I _l 1 .._,~, l j " I
10;; ~~~ +
t
!/ :s 0 tl:+-~-+-~+-1-+-•-· > -+:· ~-+;_c-+++-+ ~-+ +' + ,_ + ++-· <-+--+ ' + -c + ,_ ~- ',"
~.; t ll~k \: //
-s.r- \ / t ' f ~ / -- -----------------
-10.1 Figure 6-a. Verification of Power Amplifier Frequency
Independence (Theoretical)
Act~al Po~r Amplifier Response
all verticle scales 5 volts/division
input (e1 )=lOsin w t for all cases
time(lO a/division)
20KHZ
20
Figure 8-b. verification of Power Amplifier Frequency
Independence (Actual)
21
at various frequencies. In all cases an input voltage
peak of 10 volts was used. From the observation of figure 6
it can be seen that the output signal appears to represent
a sinusoid except for a "flat" region near the zero volt
age poj_nt. This is commonly called crossover distortion.
As can be seen from figure 6 the theoretical computer
description is a good approximation at low frequencies
(up to 10KHZ), but deviates at 20KHZ. This deviation,
for now, will be neglected and discussed in Section VI.
E. Block Diagram Of The· Power Amplifier
Thus far, the response of the power amplifier has
been obtained by use of the transistor models. Now, in
order to use this information in an overall analysis of
the audio amplifier it must be placed into a usable form,
such as a Fourier series.
Therefore, let us derive the Fourier series for a
general waveform of crossover distortion. The first step
is to make an approximate waveform of crossover distortion
so that the form of the Fourier series is reasonable.
Refering to figure 7, an approximate waveform is described.
The positive and negative sides of the waveform are assumed
to be sinusoids of a reduced frequency of the over all
periodic waveform with the zero regions at the crossover
point.
. -, ..:::__
r-=., . --{ f.-
rc c . ,..-, '-.J'
----, L........
cc ij_J
> c (.()
V"l 0 cc u
f(t) 1.0.,.
1
.f.. i
T
5 ! . -!
r
I
I I
I i
------...... / "'
// """ / \,
\ \
I
\ \
\
\ \
\
\ I . ( \ ~- I \ ~T.l · : \ I
0 • 0-~H+-t++-+-H-++++++H+t+h·' 1-+·H+++-r++++H+t-+t-i h->~•-H-1-;'- f+ H d+-H-+++·H-i H·i 1 t++ H-H+t·H-I++f I; H-H t t +I i-'-'
! I I I + ~\ I, T -- ----- -f-.... I r T :\/! c· I I r 1 1: 1 L 1 I I i \ I
I - 5' • T
T i I
t i
T
-1. QL
Figure 7.
\ ~ \ /
\ I \ I
\ . \ I \ : \ I
I ~'-'
Approximate Waveform of Crossover Distortion 1\) 1\)
Mathematically let
T = period of waveform
7' = "delay" time
Then the approximate signal is
0
sin w't
f(t) = 0
sin w't
0
' 27r ~vhe ... -e. r ,, = --.. · .......... T-2?"
J: <t < T-7' 2 2
T-r t T+r -< <-2 2 T+r .y - <t< T--2 2
,.,. T- ..1.. < t < T 2
For this signal the Fourier series is: 00
(6)
f(t) = [ Bk sin(27rkt/T) k=l k = 1,2,3 ...
(7)
where: Bk = (4/T) cos ( ~...,) [sin (b (T21'll sin(a(T2?')) -2b 2a
sin (b ( ; ) ) sin(a( J> J 2b + 2a
+(4/T) sin(w~r) [cos (b (T2 7')) cos (a (T~ ?" ) )
2b +-2a
-r' _ cos(a( J )) J cos (b (2))
2b 2a
(See Appendix IV for derivation)
a = 2?T('I' (k+l) - 2k r l (9) - T(T-2 )
b 27r(T (~-:ll__:_ 2k U (10) = - f('f-2--J
23
(8)
Figure 7 is actually a computer summation using the
above Fourier series with the series truncated at 50
harmonics. This explains the rounded edges near the zero
values. Notice that the peak value is normalized to a
peak value of one. Therefore multiplying all of the
Fourier coefficients by a gain factor will adjust the
output peak to the proper level.
24
To find the Fourier series of the output waveform of
the power amplifier all that need to be known are the
average ma.ximurn value of the waveform, 'land T . Since the
frequency is not a variable in the power amplifier, T andr
cannot be specified, therefore the ratio ofrto Tis
used in their place.
At this point the output waveshape and Fourier series
is known. This information can be used to form an
equivalent block diagram representation of the power
amplifier shown in figure 8.
Figure 8 represents the power amplifier by an ideal
amplifier with a gain ~· and a distortion signal, d 0 ,
being added to the output. If the input is assumed to be
a sinusoid and the Fourier series of the output is known,
the form of d can easily be found. 0
First assume
1 ) e 1 = E 1 sin w t
2) normalized Fourier series representing _s,
crossover distortion = L Bk sin k t k=l
;:--· (\v e+ \ 1
·--------------.
Power Amplifier
'-------·-----~
u e2 peak to peak
el peak to peak
_j--- ideal amplifier
o--- .
e~/ LJ.n = A2
1 --~
-~---·-----
----o -f\
___ )/\v ~
1-
Equivalent Block Diagram of the Power Amplifier
Figure 8. Block Diagram of Power Amplifier
25
iiJhere:
-- -·
peak~~ peak value of ~utput peak to peak va 1.ue or: input
As defined by figure 8:
A2el + do = e2 (12)
And 00
26
d 0 = e2 - e 1A2 = E1A2 L Bk sin kwt - A2E 1 sin t.ut (13) k=l Distortion d 0 can also be represented by a F · · - . our1er ser1es
d =~D k sin kwt (14) 0 k·l 0
Then for the first harmonic:
D01 = A2E1 (B 1-l) (15)
And for the remaining harmonics:
(16)
where:
k = 2,3,4,5 .....
Combining the two expressions 15 and 16, d can be 0
expressed as: 00
sin wt + E 1~ LBk sin k~ k=Z
(17)
Using tl1e info~1nation from the computer analysis of
the power amplifier and the Fourier series for crossover
distortion, d 0 and e2 can be computed. Figure 9 shows d 0
and e2 . Figure 9-a is the theoretical computer results
and figure 9-b is actual photograph response, when e 1 has
a peak value of 10 volts. d 0 was photographed by filtering
out the fundamental component of the output signal. Again,
since the theoretical result, figure 9-a uses only the
first 50 terms in the Fourier series and is calculated at
10. J..
I I
r i
-t-
5·T +
Figure 9-c:t.
27
Theoretical Computer Respollse
input(e 1 ) - 10 sino>t
f I f":E • ·H ++++ -l-..f-t--+1 ;.; t -t ·t +- t -1 1--, t-..t ;.- +! ~ + ; i t , r- r ; 1 ' r ~ ~ • ~ J ~ / ~
waveform of D1_stortion Signal, d 0
(Theoretical)
/(//
/ I
,/
*
Actual Power Amplifier Response
input (e1 ) == 10 sinw t
upper channel: outp~t(e2 ) vs time verticle scale: 5volts/division
lower channel: distortion signal(d0 ) vs time*
The verticle scale is not given because the distortion analyzer, used to filter out the fundamental, has a non-calibrated ~utput. This photograph is given primarily for a qualitative insight and not formeasurement purposes.
Figure 9-b. waveform of the Distortion Signal, d 0
(Actual)
28
discrete increments of time~ the distortion signal will
not be a perfectly smooth line.
In Stlffifi1ary~ this section has analyzed the power
amplifier by use of equivalent transistor models. From
these models~ node voltage equations could be written
and solved by numerical techniques. The non··dependence on .
29
frequency in the audio range was assumed and experimentally
verified. Then the Fourier series of amplifier output was
derived for the general case of any input signal level.
Hith this info·.cmation~ the power amplifier was represented
by an ideal amplifier with a distortion signal being added
to the output.
The next step is to investigate the performance of the
operA-tional amplifier.
30
III. Adaptation And Description Of O~erational Amplifier
The next functional block of the audio amplifier is
the operational amplifier. In this section the operational
amplifier will be investigated as to how it functions in
this particular configuration. The operational amplifier's
gain as a function of frequency, frequency stability, and
biasing will be discussed in that order.
One of the characteristic features of an operational
amplifier is its very high open-loop gain. It is because
of this. high gain that feedback can be used and all the
benefits of feedback obtained.
The dev~ce used in this circuit is the MC 1433
Motorola integrated operational amplifier. Figure 10 gives
the schematic and equivalent circuit of the operational
amplifier as given in the Motorola specification sheet.
Note that this circuit is not a circuit of discrete
elements but is fabricated on a silicon chip by planar
methods of photo etching and dopant diffusing. Figure
10 is sho~m to give the reader a better idea of the
operational amplifier. No attempt will be made to analyze
this circuit, but rather the amplifier will be viewed
simply as a high-gain amplifier as depicted in the
equivalent circuit. Also in figure 10 are some of the
pertinent p&rameters describing the operational amplifier.
The function and use of the various leads will be explained
as we proceed.
Motorola MC 1433 Monolithic Operational Amplifier
CIRCUIT SCHEMATICS
r~~f!_~J~T-1~ ____________ ~ _v~]~Y~A~~~J~T-., , o o c I G---
INPUT A~ '
INVERTING j I
'------------- ----1--1----------- __ _.J
V- 6 0 C 6 OUTPUT LAG
CIRCUIT SCHEMATIC
(taken from Motorola specification sheet) typ
F v+
G GAIN ADJ.
OUTPUT LAG
D l K C
EQUIVAlENT CiRCUIT
max unit
E
z. l.U
input impedance output impedance open loop gain
min 300 600 - kilo-ohm
zout A vol 20K
100
50K
150 ohm
Figure 10. Operational Amplifier Schematic and Equivalent Circuit
w 1-'
A. Open-Loop Gain
The first specification of an operational amplifier
is its open-loop gain, AVOL" Normally, the larger this
numbe:e is t:he better the operational amplifier performs.
32
If the open-loop gain is large, more feedback can be applied
and distortion is reduced and the frequency response extended.
For the operational amplifier in this discussion, the
minimum value of 20,000 will be used for gain. The minimum
value is used because our calculations should then reflect
the worst case.
The operational amplifier does have an upper cutoff
point. This point is essentially determined by the
external circuitry used for frequency stability. This
circuitry will be given later. For now, let us say that
the upper cutoff frequency, f 0 , for the case of interest
is approximately 500 HZ. Figure 11 is the Bode plot of
the operational amplifier as given in the specification
sheet for the case of interest. The gain is given in
decibels.
:O'j _ ____;2o t.. o~·..::o::;:o:!:o:J..)_.;__ _____ .....,.v.> __ o
~Co
~ -q: '0 \fl
Q.. 0 .do () ......,
~ZoL ~ 0
I
Figure 11 I
•• Frequency Response ..•
I
I I 1 I
i I soo IICIIC
of Operational
Ft2CQUENCY
~0 ICIII /MJKI/l
Amplifier
33
From figure 11 it can be seen that the gain expression
can simply be expressed as:
Then
(18)
Therefore we describe the open-loop gain magnitude of the
operational amplifier by equation 18.
B. Frequency Compensation
Now consideration will be given to the frequency
stability of the operational amplifier. By frequency
stability it is meant that the operational amplifier does
not become unstable over all of the frequencies of interest.
In other words, the phase shift is restricted so that at
high frequencies negative feedback does not turn into
positive feedback and cause oscillations. Again, by use
of the specifications sheet, values for these compensa
tion networks are given.*
* For a detailed analysis of these networks see "A High
Voltage Monolithic Operational Amplifier"; Wisseman, L.L.
Motorola Application Note - AN - 248.
It is beyond the scope of this paper to do an analysis of
these frequency compensation networks because it requires
considerable investigation of the operational runplifier
itself. Figure 12 shows the operational amplifier with all
of its supporting circuitry.
Network R1 and c1 j_s an intermediate stage frequency
conpensation network which couples two stages inside the
operational amplifier. Network ~' c2 , and c3 is also
a frequency stabilization network which serves as a path
for the output signal to be returned to the internal
circuit of the operational amplifier. These networks
determine the cutoff frequency of the operational amplifier
and keep it stable over the audio range. Generally speaking
£0 can be extended greater than 500 HZ but at the cost of
less stability. These networks perform well and essentially
eliminate high frequency instability.
C. Biasing
The operational amplifier also has biasing require
ments. From figure 12 it can be seen that the operational
amplifier has two inputs, one inverting and one non
inverting. It is desirable to have the DC bias currents
flowing into these two inputs as equal to one another as
possible. This is necessary to maintain the balance of the
differential amplifier stage in the operational amplifier.
Without this balance the output voltage has a non-zero
R ,...._-------~ I I
I 1 l L' __jl I
I __ j: I di I
I
+I I
~ ein
-~
. < I l J i K~Fc,~~ I ~--l j ' I
---"'~ I peration ' E,
~f1mp1~- J1----l I L,-' I
l J C~_! C4::,:: ~ R3 _if y I C2 'r
&~ cc ~ ¢ ~c3
~ Figure 12. External Circuitry of Operational Amplifier
R. = 11 kJl 1.
Rf = 100 k.st
cf = 39pf
R1 = lO..R.
R2 = 910.5l
R3 = 10 k.2.
c1 = 0.1 mfd c -· 10 pf 2 -c - 200 pf 3 -c4 :.-:: 0.1 mfd
v 15 .. CC= VOltS
w \Jl
value for a zero voltage input.
To accomplish this~ resistor R3 is included. It can
be shown that if R3 = Ri Rf Ri+Rf
the input offset current
36
will be minimized. * Input offset current is defined as the
difference between the bias currents in each of the inputs.
The capacitor c4 acts as an AC short which places the
non-inverting lead (A) at ground potential. The input
voltage then is applied between the inverting lead (B)
and ground.
D. Feedback Network
The final functional block for analysis is the
feedback loop. Let us define ~as the feedback ratio~ which
is the ratio of ho\•7 much of the output is fed back intb
the input . ~ ~ as will be shown~ essentially determines
the gain of the entire amplifier as long as the gain of
the operational amplifier is large. Th~refore this
quantity is quite important and is found in all of the
gain and distortion equations in Section IV.
To derive~~ two assumptions must be made. First we
shall assun1e that the input impedance of the operational
amplifier is very high~ so that we can neglect the input
current of the cperational amplifier. Refering to figure 10,
* Blair~ K. "Getting More Value Out Of An Integrated
operation<.:tl A:nplifier Data Sheet" ; Motorola Application
Note - AN - 273.
it Shows a typical value of z. = 600 KS1.which J"ustifies ~n
our assumption. For the second assumption refer to figure
13. Since the open-loop gain (A1 A2 ) is very large~ the
value of e will be essentially zero in comparison to e. g ~
or e . 0 Note that since we are primarily interested in
the signal only~ the distortion from the power amplifier
was temporaily neglected.
Using these two assumptions ? can be found. Apply
Kirchhoff's current law at node eg.
Since
then
!in = If from asswnption 1
--·---
eo - e 8A1A2
e eg - 0
AlA2
~
e - e g 0
0 by assumption 2
Therefore by neglecting e : g 1
(19)
To relate equation 19 to standard feedback theory
refer to figure 14 which shows in block diagram form the
basic feedback amplifier. If A'?>>7 1 the gain expression is
1 simply - e . Now equate equations (19) to equation (20).
1 - T-
or for magnitude Ri
1ar = t" Rf {21)
37
38
,~~ f,_f ___,..., ..1-f_. I
.---------~--.~~~--------~
Rf
.!.i~ R. ~ o-----l\,'\lv-·-..... --~
J +l e. 1.
-I e -1
e
~~ ·-- -------·-----0
in
Assume:
1) z. - 00 1.0
so that rb--o
2) A1A2 --0
so that eo --·-- e ~ 0
AlA2 g
Figure 13. Feedback Network
39
+ + ;I 0-
t --o
t __ j f t e. e. +~eo Ae. +APe e
I ~ ~ 0 10 I I 0-·-- 0
A 1 -e~--- = -r...;....--A~ ~ _ ~ (20)
asst:une: A~>"> 1
Figure 14. Basic Feedback Amplifier
Equation 21 is then, the expression for I~ I. The
reason why this particular feedback network was used will
become clear in the next section.
40
IV. Computation. Of Amplifier Characteri sti.cs
Now that the three basic pa~ts of ~he audio amplifier
are mathematically described, a qualitative investigation
can begin.
!~1
First the audio amplifier will be assembled using the
equivalent block diagrams of the power amplifier,
operational amplifier and feedback network. Then the form
of the output signal and output distortion will be derived.
With these equations the theoretical response of the
amplifier will be fully described.
A. Block Diagram Of The Audio Amplifier
Figure 15-a is the total audio amplifier schematic
with the power amplifier fully drawn, all the operational
amplifier circuitry and the feedback network included.
Figure 15-b is the same audio amplifier using (1) the
power amplifier equivalent block diagram, (2) the oper
ational amplifier with the gain expression of equation 18
and (3) the block diagram of the feedback network,~ . Let
us now derive the expressions for the output signal and
output diEtortion.
B. Output Signal And Output Distortion
Refering to figure 15-b we can write the output
·~~ l CB
I ~
J+Vcc
+ _j
... , R k ~·Q2 B 4 ·----.---1\/\l\t ~ Q
r., J.._ l6. VBT
~
Figure 15-a. Schem&tic and Block Diagram of Audio &~plifier (Schematic)
\ \
R~ ~ e
-!=' 1\)
feedback network r·-:;~
1 e . I
i _j
~· 1 I oper~~~ona i powetf. ~pl1t1er · ampl1 1er
~ : \A~ i ; I A2 I +
e.+He +d ) 1 0 c el
e . = E . sin wt 1 1
e = E sin wt 0 0
Figure 15-b. Schematic and Block Diagram of Audio Amplifier (Block Diagram)
4=' w
expressions. First the assumption will be made that since
there is distortion~ d0 ~ inside the loop, there will be
distortion~ de~ at the output. d 0 repiesents open-loop
distortion and de represents closed-loop distortion. Also
for the analysis e 1 and e 0 are assumed to be sinusoids and
the distortion signals are described by a Fourier series.
The two signals at the output can now be equated. The
signal component will be separated from the distortion
component.
A1A2 ei + (3A 1A2 e 0 + ~A1A2dc + d 0 = e 0 + de (22)
where:
signal distortion
A1A2 ei = e 0 (1 - (3A1A2 )
eo -e.
l.
Al =
AlA2 l - ~A1A2
(23) d c
AVOL / (1 + j (w/ w 0 )) (18)
A2 - gain of power amplifier determined from
computer analysis (A2 is not a function of
frequency)
Now substitute equation 18 into 23 and 24.
(25)
do - -,_-- ~ A:....2_,..A-V-OL_/...,...,...,( lr---::+---.j -r( \X)-::-:::'7-r-w'o)")- (26)
(24)
44
From 25 it can be seen that at low frequencies if
A2AvoL >> 1 the gain expression reduces to -1/(3, which "Jas
demonstrated before (equation 20). Also one of the bene
fits of feedback can be seen in that the upper cutoff
frequency of the amplifier with feedback has been extend-
45
ed. The cutoff frequency of the close loop amplifier , uuCL,
now equals: (1-A2~AvoL)w0 . Therefore the frequency
response of the audio amplifier is greatly increased by
feedback.
The other advantage of feedback can be recognized in
equation 26 where the distortion in the output is equal to
the distortion in the loop, d , reduced by a factor of 0
~A2AVOL" Thus, since the factor is indeed large ( 2Xl03 ),
the distortion in the output is greatly reduced. This is
very desirable in audio amplification.
Again it should be stressed that ei and e 0 represent
sinusoid signals and d 0 and de represent non-sinusoidal
distortion signals described by a Fourier series.
From equation 14:
00
do =[ Dok sin kl.llt
k=l
d can be similiarly be expressed as: c
00
de =L Dck sin kwt (27)
k=l
where: k = 1,2,3 ...
Since the frequency of th~ fundamental component
(k=l) of the distortion signal equals the frequency of ei
or e 0 , the Fourier series representing the output can be
expressed as:
00
e + d =[Eok sin k~ (28) 0 c k=l
where: eo - Eo sin oJt
00
and: "d c - L D -k=l ck
sin kUo)t
so that: Eol = E + 0cl 0
Eok = 0 ck 0 ,
k = 2,3,4. 0 0
Expression 28 is useful in determining the harmonic
content of the final output signal.
C. Adaptation Of Po\ver Amplifier Analysis
In order to find the distortion signal, d 0 , informa
tipn from the power amplifier analysis must be obtained
first. Specifically this information is in the form of
A2 (power amplifier gain) and ~T (ratio of delay time to
waveform period). When A2 and 1/T are computed a specific
input voltage e 1 must be given. (e1 = input voltage to
power amplifier). Therefore in order to use the analysis
of power amplifier and the analysis of the entire audio
amplifier together there must be a relation between e 1 in
figure 8 and e 1 in figure 15-b.
To find this relationship it will be ne~essary to refer
to both figure 8 and figure 15-b. For the first step
the two output voltages will be equated.
(29).
47
e2 is not~sinusoid, but is represented by a Fourier series.
From equation 28 the Fourier series of the right side of
the equation is known. Since the purpose of this deriva
tion is to determine the relationship of e 1 , which is a
sinusoid, only the fundamental of the output will be
investigated. All of the harmonics (2nd, 3rd, 4th, 5th,
etc.) are grealty reduced due to the feedback, but the
fundamental is passed through the amplifier without reduction,
but actually gain. Therefore we shall rewrite equation 29
considering·only the fundamental harmonic.
e2 ,lst harmonic
where: E - peak to peak value of 1st harmoni~ of e2 • 21
Now the assumption must be made that Del can be
neglected in comparison to E 0 . We know that:
or
1 - (3A1A2
A2E1 (B 1 - 1)
1 - ?A1A2
from equation 24
from equation 15
where B1 is the first harmonic coefficient for normalized
crossover distortion.
Since (B 1-1) is very near to zero and this is further
reduced by the factor of the open-loop gain, the assump-
tion is valid.
Now_. rewriting equation 30 we have
E2 sin wt = E sinu.~t (31) 1 0
inserting equation 11 for E2 we have 1
Er~2B1 = Eo
or rearranging
E El =~
A2Bl (32)
48
Therefore it has been demonstrated that the fundamental
of the power amplifier output is essentially equal to e 0
and that the input and output of the power amplifier are
related by expression (32).
Normally the characteristic of the audio amplifier
(frequency response, per cent distortion in the output
signal, etc.) are eval~ated at some partic~lar power
output. The assumption will be made that the distortion
components in the output are of such low level that their
contribution to the total power delivery to the load is
negligible. The
p LOADRMS
power, E2
0
=2~
then, can be simply found by
(33)
where E is peak value of the output sinusoid (e = E sinwt). 0 0 0
Or we can use the fundamental of the output of the power
amplifier as described by equation (31).
p LOADRMS - (34)
To find E2 we can use the Fourier series of cross-1
over distortion. If the average peak value and ratio of
"l'T is kno~·m, B1 (magnitude of the fundamental) can be
found.
Mathematically:
where:
Eeak to peak value of e 2- ~
B1 = normali~ed magnitude of fundamental for e2
( r IT must be known)
Substituting 35 into 34:
(36)
Tl!e quantity (BJ. I 2 RL)_, as a function of "l'T has been
calculated and listed in table 2. (See equation 8 for
equation of Bk) Using this table and the power amplifier
analysis program_, the fundamental power content can be
49
found. Given an input voltage level to the power amplifier,
el, the output e2 will have an average peak value E2 and
a '1/T. Squaring E2 and using "r"IT in table 2, the power
the fundamental can be found by using equation (36). To
fing a particular power level this process is repeated
until the level is found to the desired accuracy.
in
The output power levels which will be used are 15, 12.5,
10, 7.5_, 5, 2.5, and 1 watt. By using the process described
above, table 3 was generated by using the power amplifier
gain of the power amplifier, A2 .
At this point the necessary information about the power
50
r B1 B2 1 -'f
2lr L
0.0 1.0000 0.1250· -
.01 0.9897 0.1224 ·--~- --------
.015 ~~9844 o. 1211 --
.020 0.9789 0.1198 f--- --1--·
.025 0.9733 0.1184 ----------·-
.030 0.9676 0.1170 ----------!----------- --
.035 Oo9618 0.1156 --- -----· --
.040 0.9558 0.1142 --·- ----- ---- ------- -- ·----------- -----
.045 0.9497 0.1127 ------ ------·--·- -
.050 0.9435 0.1113
Table 2. Fundamental Power Content of Power Amplifier Output
I I i I Fundamental ' Nominal I r
E E2Av E2AV2
1 ..:!_ I
1 Peak I B, I A2 = E2 Power Into Power I I T 8-"- l -y-· 4 Ohms I
I I 1 I
(Watts) I (Volts) (Volts) (Volts )I 1 (Watts) I
3.650 !2.964 8. 787. ·?_~_? ______ !14~ .8122--j-~-0035 1.0 -i --
5-321 14.620 21.35 .030 .1170 .8682 . 2.497 2.5 - ··-·· --- ·-f------- ---------- -----~ .. ----
7.170 6.458 141.704 l· o2o . 119s I . goo6 4. 996 5.0 ---
' -+ --8.588 7.869 61.92 '· 015 .1211 . 9163 7. 498
I 7·5 I ~ -- ---~ ·-·- ~·- .. ---- -------~--· ·--
g.81 9.086 82.55 .015 .1211 .9262 9.997 10.0 - ------- ------·
10.887 10.16 103.2 .015 .12~-9331 12.497 12.5 -
15=d 11.80 11.07 1122.5 .010 .1224 .9380 14.996 I -------- -~---~---L
Table 3. Results Of Power Amplifier Analysis Program
LT'I ......
amplifier has been obtained in tabular form in table 3.
And since the relation between e2 and e 0 is known, we can
proceed to find the characteristics of the entire audio
amplifier.
D. Audio Amplifier Analysis Program
From equations (25) and (26) the audio amplifier
gain and distortion are known. To find d , d must be c 0
kno"t>m. By using table 3 and equation 17, d can be 0
calculated. To perform these calculations a program
was written. Again, the audio amplifier will be examined
at the constant power levels of 15, 12.5, 10, 7.5, 5, 2.5,
and 1 watt.
So that these power levels are maintained, the output
voltage, e , is a fixed value in the program, adjusted so 0
that it yields the desired power output. From the gain
expression equation (25), the input voltage, ei, can be
found. Also by using equation (26) the output distortion
can be calculated. These results will take the form of a
52
Fourier series describing the output, e 0 + de. This series
is used to calculate the per cent harmonic distortion in
the output. To do this, all of the harmonic amplitudes
must be normalized with respect to the fundamental. Then
for per cent distortion for a particular harmonic multiply
by 100. This process is shown below.
Al = amplitude of fundamental of output signal
A2 - amplitude of 2nd harmonic
A3 - amplitude of 3rd harmonic . . . A so= amplitude of 50th harmonic
A2 Al ~ 100 = D2 = per cent 2nd harmonic distortion
.!3. Al x 100 = D3 = pe~ cent 3rd harmonic distortion
Aso • Al · x 100 = n50 = per cent 50th harmonic distortion
To find the per cent total harmonic distortion, the square
root of the sum of the squares of the individual per
centa.ges is found as follows:
per cent total harmonic distortion = ...( D2 + D3 ... n5~ Note that the Fourier series was truncated at 50 terms
because the magnitudes beyond the 50th harmonic are
negligible.
53
Since the gain and distortion expressions are functions
of frequency through A1 and~(see equations (18) and{21))
the characteristics of the audio amplifier must be calcul-
ated at various frequencies. Therefore, there are two
independent variables, power output and frequency; and two
dependent variables, per cent total harmonic distortion and
voltage gain. How these quantities will be plotted is
shown below.
voltage gain vs frequency at specified power
per cent total harmonic distortion vs frequency
at specified power
per cent total harmonic distortion vs power
at specified frequency
The audio amplifier analysis program is written so
that for a particular output voltage, (thereby fixing the
output power level) the voltage gain and per cent harmonic
distortion is calculated for a range of frequencies over
the entir~ audio spectrum (10 HK to 50 KHZ). Table 4
gives the results from this program. The program itself
and flow chart is described more fully in Appendix v.
With the tabulation of the theoretical results in
table 4, plots describing the performance of the audio
amplifier can be drawn. This is done in figures 16, 17,
and 18.
In summary, this section had described the entire audio
amplifier in a usable block diagram form. Then using
54
standard feedback theory, the expressions for output gain
and distortion were derived. To find the distortion signal,
d , the operation of the power amplifier had to be described 0
both outside and inside the audio amplifier. This meant,
specifically, relating e2 to (e 0 +de)· This essentially
integrated the two programs into one. Tables 3 and 4 give
the results at specific output power levels. The three
figures 16, 17, and 18, which sum up these results in
graphical form are the theoretical response of the audio
amplifier.
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Table 4. Results of Audio Amplifier Analysis Program
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Figure 18. Theoretical Plot of Per Cent Total Harmonic
Distortion versus Output Power
58
V. Experimental Verification
A. Objectives
In order to evaluate the validity of the theoretical
description above, experimental data must be taken and
compared to the theoretical results. The form of this
comparison will be essentially the same as the plots of
figures 16, 17, and 18.
59
Hopefully, there will be a correspondence between the
theoretical and experimental data. However, due to equip
ment limitations and simplifing assumptions throughout the
analysis,. we can expect variation between the experimental
and calculated data.
B. Equipment
Figure 19 gives a block diagram of the test setup to
measure the response of the audio amplifier.
The measurements can be divided into frequency response
(gain vs frequency) and per cent total harmonic distortion
verses power or frequency. For the frequency response
measurements no equipment limitations exist. The voltage
gain is the ratio of the input and output voltages read on
the VTVM's. The desired output power can be obtained by
maintaining the output voltage at the desired level.
A problem does exist in the measurement of distortion.
audio oscillator
Instrument
power supply
band Qass filter
digital frequen meter
\}
audio oscillator band pass filter digital frequency meter VTVM oscilloscope distortion meter
I \J "----.-.r--
----" c;- Jt L-.---;-t- '1'-''-·----l i
~1 \7\
_I. ' '
1 '! distortion) oscilloscop, 1/TVlo! I , meter I I I 1~-~
~
Type
Electro model EFB Hewlett-Packard model 200 CD wide range oscillator Krohn-Hite model 3103 Hewlett-Packard model 5245 L electronic counter Hewlett-Packard model 400 D vacuum tube volt meter Tektronics model 516 oscilloscope General Radio model 1932-A distortion and noise meter range: 50HZ to 19KHZ accuracy: ± 5 per cent of full scale of each range, + a maximum residual distortion of 0.05 per cent below 7500HZ, and 0.10 per cent above 7500HZ.
Figure 19. Pictorial Diagram of Test Setup and Equipment
0')
0
61
Full-scale deflection on the General Radio distortion meter
at its lo\'Jest scale is 0. 3 per cent. When the audio oscil
lator output is directly fed into the distortion analyzer
a reading of approximately 0.15 per cent is measured.
Therefore, the audio oscillator itself is introducing
distortion. From our theoretical results the distortion
in the output of the audio amplifier (0.01 per cent) is
far below the level introduced by the oscillator. To
measure this level of distortion is practically impossible.
Since the generally accepted maximum level of distortion
(2.0 per cent)* is well above the values discussed here,
measurement and calculations of distortion at such low
levels is purely academic. However, to reduce the distor-
tion from the audio oscillator, an adjustable band pass
filter is used as shown in figure 19. With this filter the
per cent distortion from the oscillator with the filter is
approximately 0.06 per cent. This is as close to a pure
sinusoid as can be expected. Therefore we can expect the
distortion level measurement to be never less than approxi-
mately 0.06 per cent because this is the level introduced
by the oscillator.
C. Results
Using the setup of figure 19 and following the data
outline in table 4 (theoretical results), the experimental
*Tremaine, Howard M., The Audio Encyclopedia, pg. 346.
results were obtained. The results are tabulated in
table 5.
And again in the same fashion of figures 16,17, and
18, the experimental results of table 5 are plotted in
figures 20, 21, and 22.
From these six plots (figures 16, 17, 18, 20, 21, and
22) a comparison between the theoretical and experimental
data can be made.
62
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* db = 20 Log10 (Av)
Table 5. Results of Experimental Analysis Of Audio Amplifier
0)
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"I I I I J I I I I 'II , • I I ' I I I \ I I• I I ; I : I I I ' I I J,., •1. I 1· 1 '·· .1. 1 ·1···1· 1. j •• 1 ... 1. 1 , _,_LLJ, .... ILL .. j~~.l 1 ... 1 ... 1 ,.,.,. 1 .. 1 1 1·• I 1 1 .·0 •'I 'l I 1 ; I ' I I I! ,·' l I I ! I I i :I' I j I I I I i j I ' 1 1 ,I' '
50 100 1KHZ 10KHZ Frequency
Figure 21. Experimental Plot of Per Cent Total Harmonic
Distortion versus Frequency 0'> vi
.s s:: 0
"N • 7 .u ~ 0 .u Cll.6
"N e::l
c:J ·a. 5 0
~ Cll.4 p::
rl Cll .u.3 0
E-4
.o 1
Figure 22.
5 Output Power
10 15
Experimental Plot of Per Cent Total Harmonic Dlstortion versus Cuput Po"ii'1er
66
67
VI. Discussion And Conclusions
A comparison will now be made between the theoretical
and experimental data. This data has been plotted as
described in Sections IV and v. Ideally~ the two sets of
plots should exactly agree but in the actual case there are
discrepencies. An attempt will be made to explain the
sources of these errors.
First let us examine the frequency response plots.
The theoretical data (figure 16) yields a low-frequency
gain of 19.16 db and the upper cutoff frequency of
approximately 40 KHZ for all of the output power levels.
For the experimental data (figure 20) the low frequency
and 3 db point is 19.17 db and approximately 40KHZ for
1 watt output power; 19.50 db and approximately 35KHZ for
15 watts. For all cases~ experimental and theoretical~ the
gain is down approximately 1 db at 20 KHZ. This demonstra
tes that the amplifier is well within the bandwidth require
ments for high quality audio amplifier (gain deviation +
3 db from 20 HZ to 20 KHZ). The one watt level agrees
very closely. with the theoretical results. At 15 watts the
measured gain is approximately + 0.3 db from the theoretical
value and the 3 db frequency is 35 KHZ rather than 40 KHZ.
These small differences can be ignored and the theoretical
results accepted as a close description of the actual case.
Now let us examine the plots of per cent total harmonic
distortion versus frequency. From the theoretical data~
figure 17, the per cent distortion is reduced. This is
quite a unique characteristic. Usually the distortion is
greatest at maximum power output. This characteristic can
be accounted for by examining the response of the power
amplifier which is the source of the distortion present.
The power amplifier analysis is summarized in table 3.
Notice that the ratio ?/'T is greatest for small input
voltage swings. Physically this means that if the input
voltage is small, a considerable section of the output
signal will be in the crossover point, near zero volts,
until the driver transistor turns on. Since the turn-on
voltage of the driver transistors in the equivalent model
circuit is 0.5 volts, the output will not move from zero
until the input signal is greater than 0.5 volts. The
larger the ratio 1JT, the more distortion is contained in
the output. Therefore, as the input voltage increases,
17T decreases, thus reducing the distortion in the output.
Another feature of figure 17 is the general increase
of the per cent distortion as frequency increases. This
is very easily explained by considering equation 24 which
is the expression for the output distortion, de. Both
A1 and ~are functions of frequency described by equations
18 and 21 respectively. If we consider d 0 fixed for a
fixed output power, by substitution of equations 18 and 21
into equation 24, it can be shown that the output distor
tion d increases as frequency increases. Or more simply, , c
the product ~Al decreases as frequency increases.
68
Figure 21 is the experimental measurement of per
cent distortion versus frequency and should be the same as
figure 17. However, upon investigation there is consider
able deviation between the two (note the vertical scale
change). To compare the two plots let us first discuss the
low frequency portion of figure 21. From 50 HZ to 1 KHZ
the distortion levels are relatively constant. Note that
the curve starts at 50 HZ because that is the low frequency
limit on the distortion analyzer. Also, it can be seen
that just as in the theoretical plot, the 1 watt output
power has the highest distortion and the 15 watt has the
lowest distortion . This then agrees with theory; the
higher the power, the lower the distortion. However, the
1nagnitude of the per cent distortion is a full order of
magnitude less in the experimental data than was predicted.
This at first, seems to indicate that theory is in error,
but there is an explaination. Recalling from Section V,
that the audio oscillator with the bandpass filter has a
distortion level of approximately 0.06 per cent, we see
that the input test sinusoid has a distortion level of 0.06
per cent. Also from the manufacturer's specifications of
the distortion analyzer the full scale accuracy is ± 5
per cent + the residual distortion of the analyzer itself .
This residual distortion is 0.05 per cent below 7500HZ
and 0.10 per cent above 7500HZ. (See figure 19 for the
full distortion analyzer specifications). Therefore, even
without the amplifier considered, there are two sources
of distortion; the audio oscillator and the distortion
analyzer.
With these considerations the level of distortion
measured seems to be consistant with the predicted values.
There simply are no instruments available that can measure
distortion levels on the order of .005 per cent.
70
Next the section of the plot from 1 KHZ to 19 KHZ will
be examined. It is in this section that the most serious
deviation from the expected values takes place. Also
note that figure 21 stops at 19 KHZ, this is because the
upper frequency limit on the distortion analyzer is 19KHZ~
The theoretical data, figure 17, however evaluates the per
cent distortion up to 50 KHZ.
First let us compare the distortion curves for one
watt. At 19 KHZ, theory predicts 0.316 per cent and the
measured value is 0.42 per cent. Again, considering the
extrane01.:..s distortion introduced (oscillator and distor
tion analyzer) as discussed above, this seems to be a
tolerable deviation.
From theory, if the power level increases we can
expect a drop in distortion. However, just the reverse
happens in the actual experimental data. For 5, 10, and
15 watts output power, the measured distortion level is
0. 1!3 per cent, o. 56 per cent, and 0. 73 per cent at 19 KHZ
respectively. These deviations cannot be explained by the
above considerations.
To justify these results we must examine more closely
71
the simplifying assumptions made previously. First, in the
audio amplifier analysis in Section IV, the method of
analysis assumed that if the input was a pure sinusoid, the
output would be composed of a fundamental signal and many
harmonics. These harmonics were considered to be the
distortion in the output signal. The magnitudes of these
harmonics are small compared to the magnitude of the funda
mental. Therefore, the assumption was made that the harmonics
themselves would not generate further distortion, since the
output is fed back to the input through fJ. t"1hi.le this is
generally a good assumption, there actually is further
distortion generated by the original distortion signals at
the output. second, the operational amplifier was assumed
to be distortion free and actually is not. To analyze
this source of distortion is beyond the scope of this paper
and will just be mentioned. Third, the power amplifier was
analyzed on the basis of transister models which were a
good approximation of the transistors used. However as can
be s~en from figure 4, the actual transistor character
istics can change considerably as the point of operation
changes. Thus, the value of hFE' for instance, might be 100
near cutoff and 50 near saturation. Although median values
were choosen, it can be seen that the theoretical power
amplifier response will deviate from the actual case. And,
to analyze the waveform of crossover distortion, the Fourier
series of an approximate waveform was found. Figures 6 and
7 show the actual waveform photographs and approximated
72
signal. As can be seen, the approximation is close except
at the higher frequencies. This then, would seem to be
another cause of the resulting deviation between the
measured and predicted values of distortion.
While all of the above sources of error contribute to
discrepancy found between figures 17 and 21, they do not
explain why there is such a large difference (e.g., at 15
'vatts, 19KHZ: theoretical - .069 per cent; experimental
0.73 per cent).
The author has concluded that high frequency oscilla
tions are the primary cause of the deviation from the
predicted values. Since the operational amplifier is a very
high gain device it is very susceptiable to these high
frequency oscillations. These oscillations are caused from
excessive lead inductance, excessive power supply impedance,
and grounding loops. To reduce these effects, the circuit
layout used leads as short as possible and two 1.0 mfd
bypass capacitors were placed from the supply leads to
ground. For best results the circuit should be fabricated
on a printed circuit board to get lead lengths to a
minimum. The experimental tests used the amplifier con
structed on standard vector board with the two power
transistors on a heat sink. Also during the distortion
measurements, diagramed in figure 19, the distortion
analyzer, VTVM, and oscilloscope were connected across the
load. This added approximately 100 pf across the load mak
ing it still more susceptible to oscillation. During the
73
experimental measurements these high frequency oscillations
could be observed on the oscilloscope as a broadening of
the trace near the v;avefonn peaks. This effect was more
noticeable at higher power levels which was demonstrated
in the distortion measurements. To avoid pickup of noise
signals and 60HZ hum, shielded cable was used for the
input and output leads.
The frequency compensation networks, Cf and CB all
contribute to reduce these oscillations. Their values had
to be choosen on two criteria; frequency response and
per cent distortion. The distortion could be reduced, but
only at the cost of poorer frequency response. The values
cl1oosen v.1ere a compromise between reasonable distortion /"'') ; / r:·· v ; <.- (_,
levels and good frequency response. As given before, as ~
long as the distortion is less than 2.0 per cent, the ~
amplifier is considered to be a high quality audio amplifier.
Returning to figure 21, the effect of a rise in distor
tion for a rise in power at high frequency, can be explained
on basis of these oscillations. At low power levels, the
voltages and currents are also at low levels and the
oscillation is at a minimum. However the reverse happens
as output power is increased. These effects therefore, are
not shown in t:he theoretical results simply because the
model system does not include thses operational difficulties
(power supply impedance, lead inductance, etc.).
Considering all of the factors above, the theoretical
model describes the distortion levels for audio amplifier
accurately only for low frequencies. It does however,
give a general approximation at higher frequencies when
the limitations discussed above are considered.
Figures 18 and 22 contain no new information but
simply hold frequency constant and vary the output power
level. The same considerations for figures 17 and 21
apply here.
Considering this last section, a general evaluation of
this analysis can be made. First it has been demonstrated
that a high quality audio amplifier can be constructed
using fewer components than previously possible before
thG advent of the monolithic operational amplifier.
74
Second the block diagram analysis is a straight forward
approach utilizing common Fourier series analysis and
transistor modeling. The equations describing the amplifier
are very similiar to those found in standard feedback theory.
Third, the use of the operational amplifier as a '~lock
gain'' is shown in this analysis. This type of design is
very favorable because the response can be determined
quickly by just analyzing the feedback network. Fourth,
the theoretical results of the analysis are reasonably
accurate for low frequency and a good approximation for
high frequency when the high frequency oscillations are
considered.
To make the analysis more accurate would entail consider-
ably more detail which would lose the present simplicity.
Therefore the audio amplifier and analysis described, can
75
be considered to be very useful.
BIBLIOGRAPHY
1. Ehrsam, B. (1967) Audio Power Generation Using IC Operational Amplifiers. 'Hotorola Application Note AN-275, pg. 1-8.
2. Blair, K. (1967) Getting More Value Out Of An Intergrated Operational Amplifier Data Sheet. Motorola Application Sheet AN-273, pg. 1-12.
3-
4.
5-
6.
Wisseman, L.L.and J.J. Robertson (1966) High Perfor. mance Operational Amplifiers. Motorola
Application Note AN-204, pg. 1-16.
Wisseman, L.L. (1967) A High Voltage Monolithic Operational Amplifier. Hotorola Application Note AN-248, pg.l-12.
Stern, L. (1967) Analyzing Linear IC's, Part I. Motorola Monitor, Vol. 5, No. 2. pg. 12-19.
Hartin, T. L. (1963) Electronic Circuits. Prentice -Hall, Inc., pg. 247-283; 392-432.
76
7- Joyce, M.V. and K.K. Clarke (1961) Transistor Circuit Analysis. Addison- Wesley Publishing Co, Inc., pg. 28-65.
8.
g.
10.
11.
12.
13.
Chausi, M.S. (1965) Principles And Design Of Linear Active Circuits. McGraw-Hill Book Company, pg. 357-415.
Chirlian, P.M. (1965) Analysis And Design Of Electronic Circuits. McGraw-Hill Book Company, pg. 84-147: 401-443.
Lindmayer, J. and C.Y. Wrigley (1965) Fundamentals Of Semiconductor Devices. D. Van Nostrand Company, Inc., pg.29.
Javid, M. and E. Brenner (1963) Analysis, Transmission, And Filtering Of Signals. McGraw-Hill Book Company, pg. 40-75·
Johnson, c. L. (1956) Analog Computer Techniques. McGraw-Hill Book Company, pg. 7-12.
Conte, s. D. (1965) Elementary Numerical Analysis. MCGraw-Hill Book Company, pg. 19-48.
14.
15.
16.
17.
McCracken, D. D. and W. s. Darn (1964) Numerical Methods And Fortran Programming. John Wiley and Sons, Inc. pg. 263-283.
77
Scott, H. H. (1949) The Measurement Of Audio Distortion. N.A.B. Engineering Handbook. pg. (5-4-01) - (5-4-06).
Tremaine, H. M. (1959) The Audio Encyclopedia. BobbsMerril Company, Inc., pg. 346.
Standard Mathematical Tables (1964) The Chemical Rubber Company, pg. 328-329.
APPENDIX I
LEAST SQUARE CL~VE FIT OF THE FORM y = y 0 (exp(kx) - 1)
Gi··.;en a known constant, y 0 , and a set of data (y 1 , x 1 ;
y2,x2 ;y3 .x3 . · .x.. ·Y· · · .y ,x ) • let us derive the expression - 1· 1 n n ·
for k using the least square method. First,the assumption
will be made that for the values of interest,the above
equation can be approximated by y = y 0 (exp(kx)). Using
this equation greatly simplifies the analysis.
The next step is to take the natural logarithm of both
sides of the simplified equation thusly.
ln(y) = ln(y ) + kx 0
Now the square of the difference factor, S, is found.
S == t: ( 1 n ( y. ) - ln ( y ) - kx. ) 2
i=l 1 0 1
To find the minimum of S,the derivative with respect to k
is found. n
2 [ (ln(y.) - ln(y ) - kx.) x. = 0 0 1 1.
i=l 1
Solving for k, the result is: n Jl ... ~(ln(yj_)) (x. )= ln(y 0 ) .L 1.=1 . 1. 1=1
n
x. 1
11
+ k L (x. )2 . 1 1. 1.=
J_"; (ln(yi))(xi)- ln(y0 ) ~ i=l k = _1= 1 ----·-- -----
This, then, is the equation
f; i=l
for k.
(x. )2 1.
The program to calculate k is now listed.
conversion into Fortran is given in table form.
x. 1.
The variable
Notice that
the value of vb (x.) is converted to Vb~ by subtracting V--t· e 1.
79
Also, once the value of k is determined it is inserted into
the exact equation originally being fitted and y calculated
for a range of x so that the resulting curve can be compared
to the actual data.
Variable Conversion Table
least square derivation
Section II variables
1 ? .. 4 r;::
1 -,
l J 1 ? J ') , /"
l r; 16 1 7 t p. 1 9 ;:>(
vbe Ib Io K
v?f ::::::.1 ?· ·:~,-:-- ,Trr·c=~-? r>'\r~r:S=l50
'! I ·-• '- 1\ <:: J ,~: ' v f 2 ,- ) 9 X ( ? .') } f) ,, 1 r r == 1 , 1+ I(V=:TT
C' ;-:- ". :) c 1 , 1 r_ l qr-~.-, (l,'~·l :; ' /' r• ( l • t' , -, I 1)'1 -y ''-=, 1 ,,
~-· <; r ' V (~ "· ;.• r... { Y f I ) , Y C T I , r == 1 , "-i l
7 y ( .. l = y ( .• ) -\1 r, I' '/fl. - I :;> J T F c ) ' -:_ ' ' l 'J(~TC (',/1.;) . ! r: T T 1 ( , , ':) -~ } { V ( J l , X { T ) 9 T = 1 , "J ) ~lt;'t_YY:=f'· ')IJ ·-~X == ,-SttqYSt!=':· ,")("' ? J -:: 1 , ,, Y}=~l"r{v(.J))~Y(J)
7 SIJ'.'I_YY = Sl~'-'LYY+Xl [)"1 <. V-= 1' N '<?= Y(k'}
~ 'I I '··' y ~ s! I •• X + X ? nn ·4 , = 1. "'' X ' = X { I_ ) :::: Y ( L )
Fortran variables
X(I)
Y(I) sc B
VGAMA
"1 27 ?J 2 1f .,~
4 S I I ~ ' X ~ r"' == <:: t __ 1 ' ' Y <:: 0 f X '"l, ~-=- ( '1.'"1 vv.. - /.l nt,( sc }'T '3tJ'·1Y) I ( st_r~xs'.))
?{-_, ?7 ?P ?'! '3C -:1 1 ~? ?, "'l,
? '+ ~'1 '"l.f, 37 11'1 .,_q l~C·
1,!D 1 T!= ( -), ')r) !(!I
·> !') T T i:: ( ) • t. -~ , s (. ' J"l ' v G !l. \A~ :._, =' r r r c ')_, ? ') ,
l r_
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81
APPENDIX II
NEv7TON-RAPHSON HETHOD FOR A SYSTEM OF EQUATIONS
In order to solve the five simultaneous non-linear
equations (Section II, equations 1,2,3,4,and 5) the Newton
Raphson iterative technique was used.
The derivation for the approximation algorithm will now
be derived. Let the five equations have the following no
tation.
A(Vl,v2,v3,v4,v5) = Iol (~El + l)(exp(K1 vbe1)- 1)
-Io2 (hFE2 + 1)(exp(K2 Vbe2)- 1)
+Io3 (~E3 + 1)(exp(K3 Vbe3)- 1)
-Io4 (~E4 + l)(exp(K4 Vbe4)- 1)
+(V2 - Vl) hoe1 - (V1 - V3) hoe2
+(Vee- Vl) hoe3 - (Vl +Vee) hoe4
-vl/~
B(Vl,V2,V3,VJ~,V5) = RB ~E1 Io1 (exp(Kl Vbe1)- 1)
+~ (V2 - V1) hoe1 -V4 + V2
c(vl,v2,v3,v4,v5) = RB hpE2 Io2(exp(K2 vbe2)- 1)
+ RB (V1 - V3) hoe2 - V3 + V5
D(Vl,v2,v3,v4,v5) = Ra Io3 (exp(K3 vbe3) - 1) -v4 + v2
E(Vl,v2,v3,v4,v5) = RB Io4 (exp(K4 vbe4) - 1) -v3 + v5
where: vbe1 = e1 - vl - v~1
vbe2 = v1 - el -v~2
vbe3 = vee - V4 - V}3
vbe4 = v5 - vee - v~4
82
Let V10 ,V20 ,V30 ,V40 ,V50 be an approximation to the solutio~
of the five equations. Now expand the equations about the
above approximation using the Taylor's series and neglecting
the higher order terms since vJe make the assumption that
the initial approximation is relatively close to the actual
sol1.1tion. To simplify notation let:
A ~ A(V1 ,v2 ,v3 ,v4,v5 ) etc
d;)A _ . JA _ ~ V 1 - A 1 , ~ V 2 - A2
Ao ~ A j vlo'v2o'v3o'v4o'v5o
etc
etc
etc ~-~I 1 vlo' v2o' v3o' v4o' v5o
The expansion is:
A~ Ao + Al(Vl-Vlo) + A2(V2-V2o)
+ As(vs-vso)
B = Bo + Bl(Vl-Vlo) + B2(V2-V2o)
+ B5(V5-v5o)
c - Co + cl(vl-vlo) + c2(v2-v2o)
+ c5(v5-v5o)
+ A3(V3-V3o) + A4(V4-V4o)
~ 0
+ B3(V3-v3o) + B4(V4-v4o)
~ 0
+ C3(V3-V3o) + C4(V4-V4o)
~ 0
D = Do + Dl(Vl-Vlo) + D2(V2-V2o) + D3(V3-V3o) + D4(V4-V4o)
+ Ds(v5-v5o) ~ o
By transposing the first term on the left side of the
h "d system of equations is formed. equations to the rig t sL e,a
To solve this system of equations Cramer's rule is used.
::::::
-B 0
-c 0
-Do D2 D3 04 D5
-Eo E2 E3 E4 E5
Al A2 A3 A4 A5
Bl B2 B3 B4 B5
cl c2 c3 c4 c5
Dl D2 D3 04 D5
El E2 E3 E4 E5
Det 11 ::::::
I Jacobian I
From this we can see that the next approximation is:
I Det 1 I vl = vlo + 1Jacobian1
This same process is repeated to obtain the next approx-
imation for v2,v3,v4, and v5.
v :::::: 2
Al -Ao A3 A4 A5
Bl -Bo B3 B4 B5
jJacobianj !Jacobian!
83
84
Al A2 -A 0 A4 A5
Bl B2 -B 0 B4 B5
cl c2 -c 0 c4 c5
Dl D2 -D 0 D4 D5
El E2 -E E4 E5 !net 3 v3 = v3o+
0 = v3o + Jacobian I !Jacobian I
Al A2 A3 -A 0 A5
Bl B2 B3 -B 0 B5
cl c2 c3 -c 0 c5
Dl D2 D3 -D 0 D5
El E2 E3 -E E5 + IDe!= 4 v4o+
0 v4o v =
4 = l I !Jacobian! Jacobian
Al A2 A3 A4 -A 0
Bl B2 B3 B4 -B 0
cl c2 c3 c4 -c 0
Dl D2 D3 D4 -D 0
El E2 E3 EJ+ -E +I
Det 5 I 0
v5 = v +- = v5o 5o I !Jacobian I
Jacobian
These then, are the recursion formulas which generate
successive approximations until the desired accuracy is
obtained.
The actual equations for all of the partial derivatives
and deterrninent expansions are listed in the program
described in appendix III.
APPENDIX III
PO,.JER AHPLIFIER ANALYSIS PROGRAM
The function of this program is to find the response
of the power amplifier by solving the five non-linear
equations given in Section II (equations 1,2,3,4,and 5).
The proceedure by which these equations will be solved
is the Newton-Raphson iterative method. The recursion
formulas are given in Appendix II. In order to meet the
requirements for Fortran coding "there must be a variable
name change. This is given below in tabular form.
SYl1BOL
Kl,~'K3,K4
1ol' 1o2' 1o3' 1o4
V¥1, Vy2, V'(3' V3'4
~El'hFE2'hFE3~hFE4
hoel'hoe2'hoe3'hoe4
RB
~ vee
El
vb~l,vbe2'vb~3 ,vb~4 vbe 1, vbe2 ,vbe3 , vbe4
;)A -:..v = A1, etc r:) 1
Det 1, etc Jacobian
1b1' 1b2' 1b3' 1b4
FORTRAN SYMBOL
Ql,Q2,Q3,Q4
SCl,SC2,SC3,SC4
VGAMAl, VGAl'1A2, VGANA3, VGA1.1A4
HFEl,HFE2,HFE3,HFE4
HOEl,HOE2,HOE3,HOE4
RB
RL
vee El
VBEl, VBE2, VBE3, VBE4 VBE5,VBE6,VBE7,VBE8
A1, etc
DET1, etc
AJAKE CB 1, CB2, CB3, CB4
SY1<:BOL (continued)
1cl' 1 c2' 1c3' 1c4
vcel'vce2'vce3'vce4
FORTRAN SYMBOL CCl.CC2,CC3,CG4
VCEl,VC~2,VCE3,VCE4
86
As was shown in Appendix II,the evaluation of the five equations, twenty five derivatives and and six determinents is necessary for each iteration. For clarity all of these equations are listed. Notice that the equations are in Fortran coding form.
A= (SCl)*(HFEl +l)*(EXP(Ql*(VBEl))-1) - (SC2 )* (HFE2 +1 )* (EXP (Q2.* (VBE2)) -1) +(SC3)*(HFE3 +l)*(EXP(Q3*(VBE3))-1) -(SC4)*(HFE4 +l)*(EXP(Q4*(VBE4))-l) +(V2'"'Vl )*HOE1- (Vl-·V3 )*HOE2+(VCC-Vl )*HOE3- (Vl+VCC) *HOE4- (Vl/RL)
Al = (SCl )* (HFEl+l )* ( -Ql )* (EXP (Ql* (VBE1))) -(SC2)*(HFE2+1)*(Q2)*(EXP(Q2*(VBE2))) -HOE1-HOE2-HOE3-HOEl~- (1/RL)
A2 = HOEl A3 = HOE2 A4- (SC3)*(HFE3)*(-Q3)*(EXP(Q3*(VBE3))) AS= (-SC4)*(HFE4)*(Q4)*(EXP(Q4*(VBE4))) B = (RB*HFEl*SCl)* (EXP(Ql* (VBE1) )-l.)+RB (V2-Vl).
-V4+V2 Bl - (RB*HFEl*SCl)*(-Ql)*(EXP(Ql*(VBEl)))~RB*HOEl
B2 = l+RB*HOEl B3 = 0
B4 = -1
BS = 0 C = (RB*HFE2·:+sC2 )* (EXP (Q2·* (VBE2)) -1 )+RJ3X"(Vl-V3)
*HOE2-V3+V5 Cl = (RB*HFE2'*SC2 )* (Q2 )* (EXP {Q2* {VBE2)) )+RB*HOE2
C2 = 0 C3 = -RB·*HOE2-1 C4 = 0
cs = 1
D = (RB*SC3)*(EXP(Q3*(VBE3))-l)-V4+V2 Dl = 0
D2 = 1
D3 = 0
D4 = (SC3*RB)*(EXP(Q3*(VBE3)))*(-Q3)-1 DS = 0
E = (RB*SC4)*(EXP(Q4*(VBE4))-l)-V3+V5 El = 0
E2 = 0
E3 = -1
E'+ = 0 E5 = (RB*SC4)*(Q4)*(EXP(Q4*(VBE4)))+1
•
Notice that many of the equations are equal to zero.
This fact reduces the size of the determinent expansions
considerably. These expansions are given below.
DETl = B2*D*"A4* ( C3*E5+1) -B2*D4*A * ( C3*E5+1) -B2*D4
*E*(A3-C3*A5)+D*A2*(C3*E5+1)-A*(C3*E5+1)+
DET2 =
DET3 -
DET4 =
C* (A3*E5+A5) -E* (A3-C3*A5 )+B2*D4*C* {A3*E5+A5)
+B*C3*E5* (A2*D4-A4 )+B* (A2*D1~-A4)
-D*Bl*A4*(C3*E5+1)-D*Al*(C3*E5+l)+D*Cl*{A3
*E5+A5)+D4*Bl*A*(C3*E5+1)-D4*Bl*C*(A3*E5+A5)
+D4*Bl*E*(A3-A5*C3)-D4*B*Al*(C3*E5+l)+D4*B
*Cl*(A3*E5+A5)
-E*Cl *AS* (B2*D4+1 )+E*Al * (B2.*D4+1) -E*Bl * (A2*D4-A4 )+ES*Cl*A2* ( -B-*D4-D )-E5*Cl*B2*
( ~A-*D4+D*A4 )+E5*Cl* (A+B*AJ+ )-E5*C*Al* (B2
*D4+l)+E5*C*Bl*{A2*D4-A4)
-A5*(-Bl*C+B*Cl)-(Al*B+A*Bl)-D*A5*(-Cl*B2)
-D* (Al*B2-A2*Bl) -E*Bl* (A3-C3*A5) -E5.*A3* ( -Bl
87
*C+Cl·x-B) -E5*C3* ( -Al*B+A*Bl)+E5*D*Cl*B2*A3
-E5*D*C3*(Al*B2-Bl*A2)
DET5 = -Cl*A2*(D+B*D4)+Cl*B2*(-A4*D+A*D4)+Cl*(A4
*B+A)-C*(Al*Bl*A4)-C*D4*(Al*B2-A2*Bl)-E*A4
*Bl*C3-E*(Al*C3-Cl*A3)+(E*D4*Cl*B2*A3)
(E*D4*C3)*(Al*B2-Bl*A2)
AJAKE= -Cl*A5*(B2*D4+1)-(-Al-Bl*A4)+D4*(Al*B2-Bl*A~)
+(E5*Bl*A4*C3)+E5*(Al*C3-Cl*A3)-E5*D4*Bl
*A2*C3+E5*D4*B2*(Al*C3-Cl*A3)
The flow chart of the program is now given. Since
this program uses standard techniques no further explain-
ation is given.
POvJER AMPLIFIER ANALYSIS PROGRAM FLOW CHART
S I <:; T. ~-.·., Q ·. P 11. f.i i\ ''4 F T F R S ---·
P.JPf7P 0 2- 1 ( • 0 !.;.( 2 9 0~= llaP1',721 () t. .. = J. ? • 2 , h 7 5 SC l==C •'+!:'"-6 <; r ;:- = c • 4 F - 6 ') r ·:l = l • C F - A c; r 1, = 1 • ( r- A vr;,•. ·.• !' 1 =C. '5 VG"· '-'/\ ?=r • c; vr:".v.t~=c. o v r, r. '-~ " 4::: c • o Hi=t:l=lf7. t .. p::: i: 2 = i t:- c; • I·H· r 'l= f16 • 7 1-r= F i. = 5 6 • 7 ! ln F 1 == ? • r- 4 qn r ?: t:; F- 4 t-mr?=: o?5 ul)r4=.C·::>f
L _____ ._
r; JC CI!TT \'f.lll[S
f'Ul,= ?C. ?L = '• • VCC=l".
I"'f'UT \ll'l T/\G[ El
El=lf .0
DPOGP/\~ C~NSTANTS
I-=RQn):·=5.[-S PI==~.lttlS03 f '.! l T I ·~ L /-.. P P F f'J Y. I \A .1\ T I n~~ <; VJ=('• V2== 1'·. tt V~=-1'+.4 V4-=l4.4 vr::.=-!'•.4
~·J".J= ?C C• !\1 f\1 fJ = ~ J ~~ + 1 KTP1="0 KH-~::=l"C R. = r • c:
88
+
r -'·---...... i
v 1 ;-(' • 4 v?c=1'"· I. ·-'--1t •• t V -, ... . I
V4=1'·· ~4 V5-:::-llj. ··
I
----
K TD?} -Vfl, l II{ 1 • r > -- "c 2 '< r r. ? V. ( -',T)=. i':<Tt'?)
:_, T l == \• ( · ' ' ·;.; ? ) \I ( · ' · 1 ( I· 1<. l · • .. . Tl-\ •• Q...,) 1/ I /, • ' . -- ' ; r; v: T /' •I",T)-:::\, ., TD?) Vf • ,_\,, .~,v. · . ( 1--. T I -- • ' V. 'y·)-r . I rr.: ~- ·T -i> 2-1 KTf r:-K
-~---- ---~
-·_S2_ II\PFGY1 =V1 ~ P 1:' n X?= V 2 1\.-,rr-:v:?,.-=V""'· f.\CH: 0Y4=:\!4 ,~ p:: n y 5 = \1'3 Vrtf 1= VIr·!-Vl--\1'";1\M/\.1 VF';: /='Jl-V T"'-V~AM/\2 v~E~=vrr-v4-vraMa~ VQF~=VR+Vr~-VGA~A~ 'l =-(S~-1l>:·(!iFF1+1.l*(EV.P(0!~:'fV?.':l ) 1-1.1
- ( ' r 7 l ·~ ( } d=- f- ? + 1 • ) * ( c 'l( p ( o ? ,:, f v o c ? l ) _ ~ • ) • f s r: -;;, l .;, t 1- · J-:. r= '2 + 1 • l :!< ( ::: x o t n ? '" ( v r.. c ~ ) ) - 1 • 1
90
- ( ~ r t, l :': ( l .t c c /_. + 1 • ) >!' ( [ X p ( C) I+ >~< ( V !1.1.: 4 ) \ - l • ) + ( V ? - V 1 ) >!: H(} f l - ( \1 1 - V l ) ":< H f' F ':'? + { V (. C- V l } :< q '1 ~ ~~- ( V 1 + V r C ) *I l ,-, F '+ - ( V 1/ R I )
.'\ 1 = ( ~ C 1 } ~:: ( J-l r.-! 1 ·f- 1 • ) >:: ( - rJ ] ) ;':: { ::::: X D ( (' 1 '~ ( V PC l ) ) ) .. . - ( 5' C ? ) * { H f-= [ :;> + l . ) >!< { n. ? ) >!< { f: X P ( ~) :2 ,~, ( V R 1::: ? } ) )
, -l 4 n [ 1 - fl J' ~ ? - HG r= '3 -1--J C1 F 't- ( 1 • I r L l I J\.2=-l.l 0 ;:::1 .. 11--,-.;..wr'·:::z 1 •, /+ -::-c ( <: C 3 ) ~ { f ~ F ;:~ -~ ) * ( -f) 3 ) * { :: X 0 ( 0 3 >~ ( V ~ F '2 ) ) )
~~~=f-SC4)~fHF~4)*(0~)~(~YP(04*(VqF4 ))) / '::>, = f P n ,:, HF [ l ::: S r l ) >:< ( f X P ( 0 1 '~' ( V" F 1 l ) -1 • ) ; -t c r. ':< ( V ;:_ - V 1 l i<! 1 r• E l - V t.. + V :> i Ll l = ( F' :""1. ~:< f.J r r: 1 ::< Sr. 1 ) * ( - Q 1 ) * ( F X 0 { ') 1 ::::< ( V P ::: 1 l ) ) - P fl. t.< ~ '] E l : ·-~ ~~ = 1 • + P '"'- ''< 1-1 n E 1 ! r. = f ~- t) o~· ! l r c: ? ~-: <: r ? ) >:< ( E X ::> { r::; ? ,::: ( V ~ C 2 ) ) - 1 • ) [ + C' ~ '!: ( \f 1 - \' 7~ l o:< 1-l!i r ? - V -~ + V 5 I c 1 ·= { c• D ,:, ~ ~ f- r: / ;;: s r: ~ ) * ( (J 2 , ~:: { c \: p ( 0 ? * { v q r:= 2 ) ) ) + p R -!,: J ! 0 E 2 · (' -:> = - C'- ~J, o~: 1-W' I= ? - 1 ! < ~ ( ':' r- '~: <:: r ~- ) o:: f r; ~ ( 0 ~ >:' ( v ~~ F ~) l- 1. • , - \jiL + v? !~4=fsr~*c~l~(FVP(0;~(V0 ~~l}J*(-83)-l. ~=( 0 P*Sr~)*{FXD(04*(V~c4))-1.)-V~+V5 r-:; = ( c r. ~ c:: c t. ) ,:, ( r- 4} ~· ( E '< o ( n t~ ;}: r v q F £, l l 1 ._ 1 • ,~Ti~,7*r~~4*(C3*[~+1.) _,2*,4*A*CC3~E~•l.l - 0 ?*n4*~*(A1-C~*4~1+0*~?*(C3*F5•l.l-~*(C~*E5+1.J
I• f*(1~*f~ +~~) - F*('~ -C3*~5)+92*D4*C*{f3*E5+A~) + P*C~~r-5*(A?*D4-A4l +R*f42*~4 -~4) .D~T?= -n*f1*~4*(C3*F~+!.l-n*1l*fC3*r~t-1.J+n*Cl*{~J*ES+ft5)
+ f"' 1• ::< P. l ~- !\ 0:: ( c ?. >!< F 5 -f- 1 • l - fl 4 >!d\ l '!.< c * ( 1\ 3 '~: !:: 5 + ,.._ t:; l + 'J 4 1,: ·~ 1 * r: * (,"J':!-•\r:,:,r~l- ~~+"::~~~·t\1~· (r·3*F5 +l.l + r;/lt.•R-:'r:l,:<f,'\"::,*f'::S+ 11·~)
OET~= -~~fl*A~*CR?*D4+1.l~E*4l*(R?*n4+1.)-F*~l*(~~*D~-~4) · + !-= r::, ~ C ~ ,:~ ll 7 :::: f - P. >:' n 4- D l - r- l) ::: C l .:~ ~ ? *- { - 1\ -::' 0 ~ + r: -!:< !'.t+ l + F 5 ;"' C 1 * (t+P~~~J-F~*C*Al*(P2*~~+1.l+~5~C*Pl*C'\?*n4-A4) nF~~~-~~*(-~l*C+B*Cll-(-~l*R+~*ql)-D*~~*f-Cl*q7)-n*
{A]hP? -~?*nll-E*R]*( A~-C3*A51 -F5~~3*{-Rl*C+Cl*Rl -r~~r:~*(-~l*q+'\*~l'+~~*D*Cl* R? *6~ -f5*D*C1*(hl*R2-'<J~~"?) ') r: T r:; = - ( [ 1 ~.,_ !\ ? l ':< { f' + !3 ~:<~) 4 l +- ( C 1 >:: r\ ?. ) * ( - f. 4 '~ n + '\ >:' Q 4 ) + r: l ,q ~ 4 * B + ~ ) -(r}*f~J+ql*~41-CC*04J*(Al*~?-'\?*Rll-([*h4*~l*f~)-lEl* (A]*(~-Cl~~?)+Cr*D4*Cl*~~*A~)-(E*P4*C~)*(Al*~?-Rl*A?l
~ ,J /'1 I( F = - ( 1 >:c f, r:: ~~ ( q ? '!'f)/+ + 1 • ) - ( - '\ 1 - 81 -,:, l':A l + n .'... ~: ( -~ l >:< ~?- o, 1 >:<A 2 ) •CFS *~1 *~4 ~C3) +F~*f~l*C~- Cl*A~l -F5* D4*~l*'~*C3
+ r:: "· ,., ;) 1 .. ,;- 1'.1, ? * ( "· 1 :!< c 3 -c. 1 ,~ l\ '3 ,
Vl = Vl -f {!1 [: 11 I AJ.~t<.F. , \f?. = ,, ..... , . (f)C:T? I o'tj!\I(F )
\o L ... -V? = \/? + rr:r:: T 1 I !'\J/\KE )
~ \! t ... ~- (('!(:T4 I hJAI.(I.: l V5 + ( OE f"l I AJ!\K~ ,
1"
c ,/
+ II. I) 5 { v?- t. p R 0 X 2 ,
-'=Q,PnR
L __ _ [ l(l{[:~r -----·---
1<=1 , \JNNl
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1 (, '• u)s l ~f. lA7 ; r- r ln0 l 7~') 111 l 7? 171
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't1 P T T r ( -, , "), r. ) V P. F ') , V P ~ 6 , V f\ t: 7 , '' ('\ F P l.l'? T T F ( ?- • l 7 C' } :F' TT~ (::-, ~C·l VfFl,VCf:7,Vrr:l,V(.f'+ ltJD T T c ( ?, • h r, ) • .• J\'..' 1 T !=' ( "), • •1• ( ) C 0 1. , ( !~ 2 , C a, 3, CRt+ !.Jf' T T r ( ~ , 7,- I ;.: r.; r T r r -\ , :-v· > c c 1 , r r ~ , r: r: ~; , r: r 4
71 '-\1<=1(1<+1 r.t.t I FXTT
1:• rn;.;:.~rr f///, 1 JTrPI\TT Vi~=•,Ttt,/, 1 TT~1r TNC.Pf;•1FNT=•,T4, 1 I' ' ~·q jlr'- ~ I) () r: T 1 '1 r I) T ~ n c, '::' ' J !!\
? c r r~ r I~ t : ( I I ' ~ 1 ( ' ' v T !\) ' ' T .> p ' • v 1 ' ' T /l 6 ' ' "? ' ' T L, It ' ' v "), ' ) '1 :~ ~ ; 1 r .·. ~ t, r ( t, c: 1 P • ,'l }
'~ :-, r-: r; ::- ~' f. T cr. r 1 ? • '• ) t:; (' c f 11 ~1 AT ( // , To , ' \ln. F- l ' , T "> 7 , t V n, r? ' , T 4 ":l. • 1 \f "-1-= \ ' , T 6 i. , ' \m r: It ' ) (. ,: c n t: •.· "' r f I I ' r 'l ' ' r "' 1 ' • T ? .,. • ' r : ~ ? ' ' r ~.. -~ • , r £1 ~ ' ' T ,) ? ' , 1 R 4 ' l 7 (o rn ~;.A f, T f // 'T ,, ' ' T r 1 I • T? 7' ' T r:? I 'T 1., -~' ' T r -~ • 'T f: ~' • I ('• ' ) h J r r r 11 r-. T ( 1 I , T 1 r , • v 4 • • T .., g , ' v s ' l
1 l (' r-:n f' '~ t\ T { ! I /I l 1 2 C r: n R M /1 T ( I I, T a , ' \1( i: l 1 , T 2 7 , ' V C r:? ' , TIt l , t V f F 1 ' , T b 3 , ' V C f 4 '
E\10
/()fiT !I.
~
OUTPUT SAMPLE
IT~?l\Tlr1~1S= 1( 1IMf 1NCPF~rM~= ?5 NlH~R[P. 'lf TJ!!E STFDS= 200
VIN n.707IC66C~ 01
V4 0.1412~6?0F 02
\!'1fJ :) • 7rl6l ""J.4CF or
vrFl . 0.707756ACF 01
!R1 o.?c~col~CF-a?
1 (. J G. 'V-tP3033Ci=-01
Vl O.A3'5045~0E C'l
v~ -n.t4?4~GlOF 02
\/~f"/' -r .??:.,..,,--~,_.or- cr;
vr~? r.?03Q?A58F C'
T0.2 -~.?coq~qQJ[-0~
Tr.? ~.1G13040JE-0l
V? 0.1347A010E 02
V~F~ r.R7S~7~R8c 0S
vr [~ 1 1 .RA495't6~F 01
rq3 ').14q3'113CJ:-01
Tr.~ n.25104?0CF 01
v~ -O.l4042410F 02
V~F4 o.7~4oanooF 00
VCE4 0.211~0440E C?
I fVt n.t~130' .. r·rE-Ol
TC4 0.trot4o~rF 01
\0 CD
APPENDIX IV
DERIVATION OF FOURIER SERIES FOR WAVEFORM OF
CROSSOVER DISTORTION
Using figure 7 and equation 6, the Fourier series
can be found by using the definition of the Fourier series
for an odd function.
For an odd function, f(t):
f(t) = Bk sin (2~kt/T)
T/2 where: Bk = (4/T) ! 0 f(t) sin(2ykt/T) dt
Substituting for f(t): T/2 [ ' r J Bk = (4/T)J0 sin UJ(t- ~ sin(2rrkt/T) dt
Nhere: I 2~
w = T-2 1-' .
Since the value of f (t) = 0 for; 0 < t < -2 and
T:_ r < t < T+ '1"" , new limits can be used. Also f ( t) 2 2
can be expanded thusly.
Bk = (4/T) cos(~1 )
- (4/T) sin ( ~·r)
Using integral forms:
f sin (rot) sin(nt) dt =
! sin(rot) cos(nt) dt
for both cases
Bk becomes:
sin (2~kt/T) dt
sin (2~kt/T) dt
sin(m-n)t 2(m-n)
cos(m-n)t 2{m-n)
sin(m+n)t 2(m+n)-
cos(m+n)t:__ 2(m+n)
100
(T-1)/2 Bk = (4/T)cos(w'r)( sin(b~ _ sin(at))
2 2b 2a 'Yj2
(T-?")/2 -(4/T)sin(~r)(- co~~bt) _ cos(at))
2a '"'72
where: a = m+n =
b = m-n =
Now substitute limits:
27T(Tfk+l) - 2k'i) T T-27)
27T(Tfk-l) - 2kr) T T-2'1)
sin(b C-f-)) - - 2b
T-r +(4/T)sin(w~"f)( cos(b( 2 ))
2b
T-....,..cos (a ( 2 ) )
+ 2a
)
cos Cb c-f-)) 2b
_ cos (a(-f)) ) 2a
This then is the expression for the Fourier coefficients
for the waveform of crossover distortion .. v1hich is the same
as equation 8 in Section II.
APPENDIX V
AUDIO AMPLIFIER ANALYSIS PROGRAH
To describe this program the first requirement is
to give the conversion from the symbols used in this
paper to the Fortran symbols. The definitions of the
terms used in the program output are also given.
SYMBOL FORTRAN SYMBOL
Eo E0
A2 A2
r;T DELRAT
Rf RF
R. RI ].
cf CF
71" PI
A Al vol
f == uJ.,. FREQ0
0 . 271" I 0MGA uJ
r TAU
T TI
f FREQ
Al (kw) AV(I)
B (kw) BETA(I)
Bk C0D(I)
AlA2 GAIN(I) l-(3Al~
101
Ei
El
pout
Av
Av db
0 ok
0 ck
coefficients of Fourier series describing the audio amplifier output
f(t) using C0D(I) as the Fourier coefficients (normalized)
f(t) using DISLP(I) as the Fourier coefficients = d
0
f(t) using DIS0(I) as the Fourier coefficients = d
c
f(t) using E0Ur(I) as the Fourier coefficient = d +e
c 0
ei = E1 sin t
total harmonic distortion contained in the output of the power amplifier without feedback = e2
total harmonic distortion in audio amplifier output = e + d
0 c
EIN
El
PefWER
VGAIN
DBGAIN
DISLP(I)
DIS~(I)
E0UT (I)
SC0D (I)
SDISLP(I)
SDIS0 (I)
SE0UT (I)
SEIN(I)
DISTl
DIST2
102
Once the circuit parameters have been specified (eg: R. ~,
Rf,Cf,Avol'etc. ),the only input data is E0 ,A2 , and 7/T.
From this,the program will calculate the remaining vari-
ables.
So that the data points are evenly spaced on the log
103
frequency axis~ the increments in frequency are obtained
by r~peated multiplication of the last frequency increment
by a constant. To demonstrate this~ if it is desired to
have ten frequency increments from 10 HZ to 50 KHZ the
multiplier is 2.57. It works like this:
FREQUENCY INCREMENT
1st
2nd
3rd
9th
lOth
10 HZ 25.7 HZ 66.0 HZ
19031.1 HZ 48909.9 HZ
MuLTIPLY BY
2.57
2.57
2.57
2-57
This yields the desired results of equal spacing on
the log frequency axis, but has the disadvantage of having .
large gaps in the latter end of the scale; for example
from the increment from nine to ten. To avoid this, the
program is set up such that two frequencies can be choosen
at will. Therefore the program gives results at twelve
points in frequency; two of which are arbitrary and ten
of which follow the equal increment frequency sweep. The
two arbitrary frequency points are 30 KHZ and 40HKZ.
The program flow chart is given along with the actual
program and output sample.
FLOW CHART c (1 = n. 1 ? -? i\?=- Q?"?~ 'i F l n. ~ T,· - ;·. I" 1 r::
- - f·- - -' • ' :J OF=1 F~
PI=iir~;t.r. c~==~c.r-!2
Pic:-?.14J':-C1 I\ 1 =-?C( ('-r • FP~=.-:-:r=r::,.c.
c:p ~=0= ~c;:--:::r.
--------------~~------l-= __ 1_,,~_?_. ________ -J
~--------------·'~---------------TI=l./FI')f:0 r~u=r.f:t Pt:.T::e•rr OHG'"I~f?.~~rr J/fTI-2.*T\UJ T!_ I"=(TT-T!\ll)/?. r:q T''=T/I!J/?.
·--------------<:~· _______ r_=~J._s_,~_· _____ =r~ I
.'\ = f { ? • •:: :·) J ) ::~ { T I ~ { S + J • ) - ( ? • '~ S ::::: T f1 I J ) ) ) I ( ( T T ) ~' ( T T - ? • * f -"1 tJ J J 0 -= ( f ? • ::: ;.' T ) ':'- { T T i,< ( ~ - J .. l - ( ? • ::< s 0~ f l'J. u ) ) ) I f ( T T ) t,.· { T T - 2 • * T 'I u ) )
104
r: r> r~, f ! ' ::- f '~ • I i T ) t.< C ( 0 S ~ f t; . ~ r, !'. * T \ i ! ) I 2 • ) ) 'i< ( f t) I r,, ( Q, * T l ! ·.~ ) l I f ? • * 11 l -( ~ T ' · ( ') :!• T I. l f.' ) ) I { ? • ::: t ) - ( <; I r-! ( fl '/• tJ, ! _ I '' ) ) I { ? • ::: P, ) + ( S T '! C !'. "' ~~ L J '·' ) } I ( 'l • * " ) )
+ { 'i- • I T 1 ) ·~ f S I ~' ( ( r ~'' r~ ,~ ;~ T !\ 1_1 ) I 7 • ) ) ::< ( ( C n S t 0 * T L I '·~ J ) I { ? • :':: q ) + < r: r -~ s < r· ,., T '_ r , ~ , , 1 f 2 • -1:: A ' - c c , } s ( :~ ;~ ~~ L r : ·1 , , 1 c 2 • ":' ~ , - c c r 1 s < A~, ~ t I • ~ 1 l 1 ( ? • * !\ 1 J S= S + 1.
---··----------------.-----------------
[ -- ·< . yl<;O 1 t V ( J } = ( !I 1 ) I ( ~ Q R T ( 1 • + ( F R f7 ~1 ::!< c -R-.r::-Q-~--_X_*_Y_l_/_( _c_R_f:_(._1_C_*_F_Q-~--;m}ll
~-,:,Y+l. =~ -- f
J
105
.------- = < ~~~.50 --
11 L T :.r r 1 ~ ( "_ 1 1 c F ) ,:. s L~ o T t 1 • -~ 4 • ,x n r ;, o r ''< c F =:< c ~ ~ r. F :i: ~=: F * Y =>: v ,., F .':' r r. * r- ~~ F Q 3 Y=V+1. -~-----·-~--
---=---:_____ =T"O ? ~ r,11 I\' {I l = ( :~" ( T l*f\? l I ( 1 .-'\\I( I) '~fl.7·c:QE Tl-; r!) l Z=7+1.
J T l\ = r. n 1 r, -" I "! ( 1 ) 1 ;: r f- r· l 1 r {\ 7 :.!=_ con ( 1 > l " \·' t: r = ( :: r·, ::. F n l I q •
Lvr:~,r~·-==ffl/FIN ,... , 0"C,~P 1 =?·= .~<:''llf'<;lC{·\?t:.(V ,!'!..I ·'ll
~-'\frP=J ./ 0 f:T/I{K) J L I I --------~
-~ T F P , t. V ( '< l , S ft.. f ~-J ( K l , K
~
.I=2, ')("·
-~-~ 11 I ~ n ( T ) = n I <; l P f I ) I f 1 • - \ V C ! l ~'I\ 7 * q C: T .1\ ( I ) _l J
l
------""il ED tiT f I l =r_' T ~r C!) ~
----,~~---,----J
+
r--~------..., I r·:1r·.•r T~Jtlr l -· . . ·-
CAt L r: ,~ 1. L r ''-t t r i'.L L
- <:; u ._.' J n ( r: n'"' • T f , ~ (: ~-~ S 1/'•qJ o C r ! 5 t r- , T I , S r'l I <: L 1J l s! _i ·-1 u r c ~' r s IJ , T I • S ·'"'~ T S ,, l ~IJ''I!P ( ff 1 t1T, f T, S r'"'f IT l
q"=! •
106
+
[-;:R !'=Q=4~000.
L. _ _____,
Sl)1'1S 0 l)TTI''F 'StF4 UPfV.Y.1 .Ul
PT=~.l41_')r:J X= 1.' /l r,r. • T(JJ=X ·----
' ( r , =:: s 1 ~~ f c v * 2 • ~: r r ::': T c '- J ' 1 r "'-' ' , ~=SUi~+7_ ~-----------,-- ---------~
t If L l = SU'1 f(L+l)=T(t )+Y
r QET'JPN' --==r -J HJr I
107
S\.l'''J T <;=·'"'· C:
Y = l ( <:: T r: ~! l\ I f i + 1 } IS T G ~,. fJ. L ( 1 ) ) ~ l 0 (' • ) * ( ( C, I G t] A, L ( I + 1 l Is I c ~~ 1\l ( 1 ) l * 1 0 0 • )
.----__J_l --··-
1 ENn 1
108
1
? 'l,
4
') I-,
7
R
fl
1 ('
l 1 1? J ~
"· l" 11-. 17 1 R 10 2f'
AUDIO AMPLIFIER ANALYSIS PROGRAM 1\.J A iA r F 1 7 f"'l, .,, '-. , I I ._, F = 0 ? , P 1\ r; r- S ;,: 1 ':' C L F X 1\ T 0 NV
"' r M r-t ,' s T n "'' r, n n ( 5 ,.., ; , n T s L r> f s ,-. > , n r <:. n \ s c l , r. n 1 n < s o ) ., s r. nrH 1 o o l , lS!')l'-;LP( 1n01 ,SDTSP(l\C•l ,S[IlUT( lCCl ,~V(~C·l ,BETA{')(}) ,GAIN('50)
r r. svsn:,1 Vfl,r~t.'\RI !-S r c
r
r r r
r r r
r
r r (
r
r
'lUTI'lllT VflLTA\,( (1-\1\Xl r.n;:::n. 13r.7 f\7:.~"~.0?7r.,
nr-LI~'"T (f"\Ftl\V RATinl =TI\U/i>f:O f(lf) ~[i PJI.T='i,'1l'l
r.trr.1 1 lT Vfii_UFS
r.: F =' 1 • r r; ::o T -=- l 1 r. C •" • CF:-:-)f',r-1?
C""'S'""' r~ f) l -= ~ • lit 1 r, () 1
~[)CDIITTnf'J<\I t,'l.flllFTFR CO"J<:THJTS - nPt:~J Lnoo GAlN fiNO UPPER r • 11tH ~ r- !) r: r; 11 r "-! r v ~ 1 =- ?C ( ; ., • Fr';. '10: r. r.r 1
f'" " I= f) :: ~ ,- r r , .• r-n r, ' ':': 1 ' l ) T T :: l • /I· P r· "' T t-, I I = n !- L o 1\ T ::: T T , 1 •·• r "' = ' ., • ::: P r l 1 ( l r - 2 • * r .~ ,_ 1 , Tl T '·' :-: ( T T- T .~ II ) I? • ~~ l T •• :::-: T ~. ' I I ? • ·~ ::.~ ' T i= ( -.~,, 4 t l ·.~ o I T F ( • , 1 ~; t F P F o , T I , T fl ' 1 , q r , R I , r. F •,~o I r r ( 1, 4,.. l
J0!1 142
1-' 0 \0
?1 77 -., t.. ?4 2S
26
?7 ?~ /tl "30
·:q 3? 33 34
.,C) 1f, -:q 3P
,,., 4r 41 !....'? It"·
'•4 lt c; 4~ 't 7 4?.
c r;;:.;~:r::p.'\TF Ci:t-Ft=-tt.lH 1 T~. nF r-r1w1fr-~~ c-.r.nrr:s r:r1\ cRnssnvFF nrc;rn~nir:r-~ r
r r: r
' r (
r r r
r r c r
r
S= 1 • r \')q l ~ = 1 ' 5 ::. "'= { ( ? • ~, P ! l ~~ { T 1 :::, ( <::. + 1 • l - ( 7 • ~:~ s ~:~ T :-, t ~ l i ' : ( ( r ·~ 1 * ( T I - ., • ~:, T r, t 1 l l ",-= ( ( ? • t.~ o T ) >!': ( T I >:~ f S- i .. ) - ( .? ~ >:: C', :~: T !:. I I J ) ! I r ( T T } "' ( T t - 7 • >:: T fl t' ) ) r. n D ( T l '""' r !., • 1 T "! ) ::< ! r: r! \) f ' c •·· "': l '1.= T ~ ll i 1? • ) l ~:= ( { s I f·i ( n ;-: T 1 T r1 ) ) 1 ( ? • * !l ) -
1 I S 1 j\~ I f, '~ T I T 't ) ·, I ( ? .. ':: 1\ ) - I S t t : I \-\ •:' '-' I_ \ "- ) 1 I ( ? • ~< n. ) + i <; 1 N ( A :t.= n. L J ~" ) ) I I / • * /\ ) ) + ? ( t.,. • I T r I * ( ' i '\l ( ( r1 · ., r~ t ·:< T 1'1. I J l I ? • \ ' ':' ( ( C t 1 S ( f~ ~~ T L T "-" l l I ( 2 • * H l + ~ ( r n S ( ~ ~ ;-L T ~.~ J J I ( 2. *A ) - ( C fl ~ f ,q '!:: 11 f T M ) } I ( ? • "«A ) - ( C n S ( /1 * R l T M 1 J I ( ? • * 1\ ) J
1 S=~+-1.
~HU=PJ'.TF (;tdN nF ClPf-P.~T!r]!,!I\L l\',1DLIFTFP FOR l<:T ~0 HARMONT(.S
'<= 1 • '!n l 1 T = 1 , r; c ~ II f I I -= ( fl. 1 I I ( S n R T ( 1 • + ( r: q F n ·:, r I? r: 0 * X"" X } I ( F r r: () r * Fr~ E 0 n l ) J
)1 X=X+~.
12
13
14
r; U! F P AT E ~ ~ T 1\ F rJ R I S T r:; n 1·1 fl 0 :"! fl "J l C S
V: 1 • r-,n l 7 T ~ 1 , rj ('
~ET~fi)=(PJ/RFl*SORT(l.+4.*PT*PI*CF*CF*~F*RF~Y*Y*FREQ*FRfQ) Y=Y+1.
r,plf=PJ\TF r;AI~! F~CTOR Fno IST 5C H.~ 0 i'10NTf:S
7 = , • 'lfl l ~ T = 1 ' t; (I
r, ~. l 'l I f ) = ( !11J ( I l ):' .\ 2 ) I { J. • - ·' V ( T ) * 1\ 7 ~' f1 [ T 1\ ( T ) l 7:7_~1.
r. ll I r II I .!\T C P.! r II T V n L T A r; F ( "1 " X ) , E 1 C ·~ !\ X l , P n \" F R I N T n 4 0 H M L 0 A D , V11LT/'Gr r./\f".i :\f\!f) VOLT"GF: r./\PJ on.
r. T r,'= Ffl j:.,\ T ,,, ( l ) ~1=(rn)/lt?*(~'l(1 )) ~>~-w ,= P =! c:: IV' r- rn n~ .. vr.'l Tfi'=FI'/~ jr·: n ,, r: .\ T \' = ? i't • '' '\ I n r. l C ( 1\ R <; { V r. ft, Y "' l ) \,1 ;) 1 T r: ( l • 1 :> : J) r il , [ 1 , F P! , ;> n W '- R , V r. ~ P! , n f1 r; " I r-: ·.:oyrr (-:1,,7'.) nn J 4 K = 1 , r; 0 ATEl=1./f1Ff/\(~) ~~p ! T F ( 3, -:~, r. ) '\ T F f\ , A V ( l< I , r, 1\ Pl ( K ) , K ........
l-1
0
4Q c:;o '51
52 5?
54 5 e:,
56 ')7 5R C) ('I
6(• 61
o? 6~ A4 61.)
1-,1..,
1-,7 r,p. 1--.9 1n 71 T? 7"3
74 7r"i 76 77 78 70 q(')
,. \.
r.
c (. (
r. ( r
r.
\:.[l'JEf'I\TF. OJST\WTJfiN I"lSPH- t!lOP, fHSLP
OT SL Pf l l=l:l_,::f\?:>:.(\.00( l l-l. J DO 2 T =?, sn
7 f1I SLP( I l=F1 *1\?~~Cfll){ ll
GFNEPATF Cn~PONENTS OF OUTPUT SIGNAL
nn 3 I=l,c:;c. 3 fH S rl( T l = n T c; I. P C T l I ( 1 • -:\ V ( I 1 :t.: 1\? ~ p, E L1 ( I ) )
GtNFPt.Tt: niJTPUT l\NO 0\JTf>UT Ill ST\lR,Tl(lN
~nuT<ll=Fn+nrsnCll f)n t+ I = ? • '1 r
'+ ~ntJT( Tl=~"I~n( I l wo T T r f?, '+ 0 l 1rJ Q I T E ( ., ' r; C! ) ')f) 7 ~1= l' ')('
7 W ~~ T T F { 1 , () 0 ) I. 00 ( '1. ) , 0 1 c; l D ( i'A l , D l S fJ p .. q , F. OUT ( ~~ ) , M p:: (L-?l 15,l",lt1
C FPJll FfTl llSI~G 1ST 5n HfiRMONICS r.
r
15 C~LL f..'\ll. Cl\ I L C t'.l L
q P·~IIP <roo, r T, ~r ern (' l JVU D ( [H S L P, T T, Sn T <;t P) ~ !J •,~ \ Jf' ( n T S q , T I , S f)J S rn S II~~ II o ( F n U T , T T , S F: 0! JT )
1.·! r. r r F { "J, , '! r. l 1-j R 1 T F ( ? , 7 C } ~=!. !')f"' n r-.1 = 1 , ] cr. S i-= P! = F P 1 * S T f'.' ( C ? • .:~ P I ,>t f Q f- ')>:<! T '~ ;:? l 11< !\ • l t .. rpJTF (J,ROJ <\COf1nl),SI)ISLPCNl,Sni~non, SFOUT fNJ,SFIN,N
~ Q:=-r.'+l. 1 6 C n ~H I f\! U r-
r Fn1f1 TnT/\1 H~D')rJf'IIC DISTnPTTfJ"l WITH ANI) ~JTTHi1UT FFFOBAC:I( ,. (1'\IL H.~,.,nrqrn11,nJI\Tll ~J\ll Hf'll;lny<; n:ntiT,[)I<\TZ) ',~ o I T ~='" r ~ , t, ' l ':•I o T T ~ r 1 , 1 ·"' n ) n l s T 1 '"'o I ; r < ., , 1 1 n , n I s T? \~P l T ~ I .,, ' t.. ~· )
IF (l-2) lR, 0 ,17 ..... ...... 1-'
~~ so rn ~ ql Q FRF0=1r. 8~ r,(l Tfl '5 R~ 17 FQEQ=~R~0*?.57 Rr-. 5 CfJf\iTT!'JIIr f'.7 C~LL C:'(TT ~ P l v != 0 P 1·1/'. T ( ' F r F n I J t= ~1r V = ' , I= 1 0 • 4 , I , ' n != q I iJ fl ( '; r C l = • , E 1 R • '1 ., I ,
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VITA
Anthony Francis Lexa was born on July 19,1945 in
St. Louis, Missouri. He received his primary and secondary
education also in St. Louis. He received his Bachelor of
Science Degree in Electrical Engineering in Jm~e of 1967
from the University of Nissouri at Rolla. He has been
enrolled in the Graduate School of the University of
Missouri at Rolla as a graduate assistant since September
of 1967.