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Analyses of Covariance
• Comparing k means adjusting for 1 or more other variables (covariates)
• Ho: u1 = u2 = u3 (Adjusting for X)
• Combines ANOVA and regression– uy = uk + X
• Assumptions are same as ANOVA + regression– Y normally distributed, constant variance across groups
– Slope the same for each group
SAS Code
PROC GLM; CLASS group; MODEL chol12 = group cholbl/SS3 SOLUTION; MEANS group; LSMEANS group; ESTIMATE ‘Adjusted Mean Dif' group 1 -1;RUN;
Adjusted Means ComputationObservations
YBAR(A)i = YBARi – XBARi – XBAR)
1) If then adjusted mean equals unadjusted mean
2) If mean of X is same for all group then adjusted mean equals unadjusted mean
Computing the Adjusted Means
12-mo Avg. Baseline Avg.Diuretic 231.7 230.7Placebo 219.7 224.9Total 227.0
=0.894 Regression slope of 12-month cholesterol onbaseline cholesterol
YBAR(A) (Diur) = 231.7 – 0.894 (230.7 – 227.0)= 231.7 – 0.894 (3.7) = 228.4
YBAR(A) (Plac) = 219.7 – 0.894 (224.9 – 227.0)= 219.7 – 0.894 (-3.7) = 221.6
6.8
Summary of Analyses of Continuous Variables
• Y is continuous variable
• Estimate a single mean • Compare 2 means
• Compare k means 1, 2, 3, … k
• Model means as function of 1 or more variables (LR)– Y = X + X
Analyses of Binary Outcomes
• Much of bio-medical data relates to analyses of binary outcomes:– Cancer (yes/no)– Survival (yes/no)– Had side-effect (yes/no)– Currently smoke cigarettes
• Social Sciences:– Divorced (yes/no)– Return to prison (yes/no)
• Political:– Favor a candidate (yes/no)– State has capital punishment (yes/no)
Analyses of Binary Variables
• Y has two outcomes (yes/no or 1/0)
• Estimate a single proportion • Compare 2 proportions
• Compare k proportions 1, 2, 3, … k
• Model probability as function of 1 or more variables – Y = X + X
Binary Outcomes
• Binary outcomes (Y=0 or 1) can be thought of in terms of probabilities:P (Y=1) = P (Y=0) = (1 –
• The ratio of the P(Y=1) to P(Y=0) is the odds
Odds (Y=1 versus Y = 0) = P(Y=1)/P(Y=0) = (1 –
Example
• Y = 1 indicates your horse winning the raceP (Y=1) = 0.20
P (Y=0) = (1 – 0.20) = 0.80
• What is the Odds of winning versus losing.
Odds = P(Winning)/P(Losing) = 0.20/0.80 = 0.25 or ¼
In gambling terms the odds are 4 to 1.
Relationship Between Probability and Odds
Odds (o=0.95 19.00
0.50 1.00
0.40 0.67
0.30 0.43
0.20 0.25
0.15 0.18
0.10 0.11
0.05 0.053
0.01 0.0101
For small values the probability and the odds are close in value
Comparing Two Groups With Binary Outcomes
1 = probability of Y=1 for group 1
2 = probability of Y=1 for group 2
Ways to summarize the probability differences:
1) 1- 2 difference in probabilities
2) 1/ 2 ratio of probabilities (Relative Risk)
3) (1/(1-1)/ ratio of odds (Relative Odds)
(2/(1-2)
Example
Group 1: SmokersGroup 2: Non-smokersY = 1 indicates cough upon awakening
0.30
0.20
= 0.10
= 0.30/0.20 = 1.50
= (.30/.70)/(.20/.80) = 0.429/0.250 = 1.71
Interpretation of Relative Risks
Group 1: SmokersGroup 2: Non-smokers
• RR = 1.50• There is a 50% increased risk of cough for smokers compared to non-smokers.
• Smokers are at a 50% increased risk of cough compared to non-smokers
Interpretation of Relative RisksChanging the Reference Group
Group 1: Non-SmokersGroup 2: Smokers
• RR = 0.67 (1/1.50 or .20/.30)• There is a 33% decreased risk of cough for non-
smokers compared to smokers.• Non-smokers are at a 33% lower risk of cough
compared to smokers.
Results: During follow-up, 477 major cardiovascular events were confirmed in the aspirin group, as compared with 522 in the placebo group, for a nonsignificant reduction in risk with aspirin of 9 percent (relative risk, 0.91; 95 percent confidence interval, 0.80 to 1.03; P=0.13). With regard to individual end points, there was a 17 percent reduction in the risk of stroke in the aspirin group, as compared with the placebo group (relative risk, 0.83; 95 percent confidence interval, 0.69 to 0.99; P=0.04), owing to a 24 percent reduction in the risk of ischemic stroke (relative risk, 0.76; 95 percent confidence interval, 0.63 to 0.93; P=0.009) and a nonsignificant increase in the risk of hemorrhagic stroke (relative risk, 1.24; 95 percent confidence interval, 0.82 to 1.87; P=0.31). As compared with placebo, aspirin had no significant effect on the risk of fatal or nonfatal myocardial infarction (relative risk, 1.02; 95 percent confidence interval, 0.84 to 1.25; P=0.83) or death from cardiovascular causes (relative risk, 0.95; 95 percent confidence interval, 0.74 to 1.22; P=0.68). Gastrointestinal bleeding requiring transfusion was more frequent in the aspirin group than in the placebo group (relative risk, 1.40; 95 percent confidence interval, 1.07 to 1.83; P=0.02).
NEJM March 2005: A Randomized Trial of Low-Dose Aspirin in the Primary Prevention of Cardiovascular Disease in Women
Relationship Between Relative Risk and Relative Odds
• RO = RR x (1-2) / (1-1)
• If 1 and 2 are small (<0.10) then
– RO ~ RR
– Because of this relative risk and relative odds are sometimes interpreted in the same way
Example RR = 2.0 and RR=0.5
• RR = 2.012 Odds Ratio
0.20 0.10 2.250.10 0.05 2.110.05 0.025 2.05
• RR = 0.512 Odds Ratio
0.10 0.20 0.440.05 0.10 0.470.025 0.05 0.49
Why Use Ratios
• In most cases the probability of an event is dependent on length of timetime)
• Using ratios removes time as a factortprob. of developing lung cancer for smokers
tprob. of developing lung cancer for non-smokers
– RR = tt
• Using differences does not remove time as a factorDIF = tt
Comparing Studies With DifferentFollow-up Time
• Study 1 follows patients for 5 years:5prob. of developing lung cancer for smokers
prob. of developing lung cancer for non-smokers
– RR =
• Study 2 follow patients for 30 years:30prob. of developing lung cancer for smokers
30prob. of developing lung cancer for non-smokers
– RR =
Hypothesis TestingConfidence Intervals
• Ho: 1 = 2
• Ha: 1 ≠ 2
• Estimate 1 with p1 = number with condition/total in group 1
• Estimate 2 with p2 = number with condition/total in group 2
• p1-p2 is point estimate of 1 - 2
Proportions for two groups
95% CI for difference in proportions:
2
22
1
11
21
)1()1(
96.1)(
n
pp
n
ppSE
SEpp
Proportions for two groups
Example• 50 men with 13 smokers• 50 women with 10 smokers
p1 = 13/50 = 0.26, p2 = 10/50 = 0.20
SE = sqrt(0.003848 + 0.0032) = 0.084
95% CI for difference = 0.06 ± 1.96*0.084
0.06 ± 0.165
(-0.105, 0.225)
We do not have evidence that the proportion of smokers is different for men and women