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Analysis of a Stochastic Predator-Prey Model in Polluted Environments Huajuan Zhou, Meng Liu * Abstract—In this paper, a stochastic predator-prey popula- tions model in polluted environments is proposed and investi- gated. We first study the existence, uniqueness and boundedness of the global positive solution. Then we establish the sufficient conditions for extinction, non-persistence in the mean and weak persistence in the mean of the predator and prey populations. The threshold between weak persistence in the mean and extinction for each species is obtained. Finally, we study the global asymptotic stability of the solution. Our results reveal that the more the number of random noises, the easier the species go to extinction. Index Terms—environmental pollution, stochastic noises, per- sistence, extinction. I. I NTRODUCTION E NVIRONMENTAL pollution by modern industry, a- griculture, and other human activities is one of the most important socio-ecological problems in the world today. The presence of toxicant in the environment is a great threat to the survival of the exposed living beings. This motivates scholars to analyze the survival of populations in polluted environments and to establish the persistence- extinction thresholds of the populations. In recent years, many scholars have studied the survival of populations with toxicants effect by establishing mathemat- ical models. Hallam and his colleagues did pioneering work in [1], [2], [3], where the authors studied some deterministic population systems with toxins effect and established the theoretical persistence-extinction thresholds for their models. From then on, many deterministic models in polluted envi- ronmrnts were proposed and analyzed. For example, Hallam and Ma [4], Ma et al. [5], [6], Freedman and Shukla [7], Wang and Ma [8], Buonomo et al. [9], Srinivasu [10] and He and Wang [11] proposed some single-species popula- tion models in polluted environments and established the persistence-and-extinction thresholds for their models. Liu and Ma [12] studied the persistence-and-extinction thresholds for two-species Lotka-Volterra models with toxins effect. Ma et al. [13] and Pan et al. [14] extended the threshold results in [12] to n-dimensional food chain model and n- dimensional factualistic system, respectively. Liu at al. [15], Manuscript received 21 April, 2016; revised 12 May, 2016. This work was supported by the National Natural Science Foundation of China (Nos. 11301207), Project Funded by China Postdoctoral Science Foundation (2015M571349 and 2016T90236), Natural Science Foundation of Jiangsu Province (No. BK20130411), Natural Science Research Project of Ordinary Universities in Jiangsu Province (No. 13KJB110002), Qing Lan Project of Jiangsu Province (2014), Science and Technology Support Plan Project of Huaian (HAR2015013), Natural Science Foundation of Heilongjiang Province (No.A201420). M. Liu is with the School of Mathematical Science, Huaiyin Normal University, Huaian 223300, PR China, and School of Mathematics and Statistics, Northeast Normal University, Changchun 130024, Peoples Re- public of China. E-mail: [email protected] H. Zhou is with Huaiyin Normal University. [16], Jiao et al. [17] and Li and Chen [18] considered the population models in polluted environments with pulse input of environmental toxins. However, in the nature world the growth of population is inevitably affected by the random interference factors ([19], [20]). Thus it is important to study stochastic population models in polluted environments and to reveal the effects of random noises on the dynamics of populations. In this area, Gard did pioneering work in [21], where he first proposed a stochastic single-species model with toxins effect and investigated the dynamics of the model by supposing that the concentration of toxicant in the organism is a constant. Be- sides, Liu and Wang [22] obtained the persistence-extinction threshold for a stochastic logistic model in polluted envi- ronments. From then on, stochastic population models in in polluted environments have received great attention and have been studied extensively owing to their theoretical and practical significance (see e.g., [23]-[29]). Especially, taking into account the fact that predator-prey model is one of the most important models in biomathematics and ecology, Wang [24] has investigated the following stochastic predator-prey model in polluted environments: dx 1 = x 1 [r 10 r 11 C 0 (t) a 11 x 1 a 12 x 2 ]dt + α 1 x 1 dB 1 (t), dx 2 = x 2 [r 20 r 21 C 0 (t)+ a 21 x 1 a 22 x 2 ]dt + α 2 x 2 dB 2 (t), dC 0 (t) dt = a 1 C e (t)+ d 1 θβ/a 1 (l 1 + l 2 )C 0 (t), dC e (t) dt = hC e (t)+ u(t), (1) where x 1 (t) represents the size of the prey population at time t; x 2 (t) stands for the size of the predator population at time t; r i0 > 0 is the growth rate of the species i; r i1 0 denotes the species i’s dose-response parameters for toxicant concentration in the body; C 0 (t) represents the concentration of toxicant in the organism at time t; a ii > 0 is the intra- specific competition coefficients of species i; a 12 > 0 stands for the capture rate; a 21 > 0 measures the efficiency of food conversion; B 1 (t) and B 2 (t) are two independent standard Brownian motions defined on a complete probability space (Ω, F , P ) with a filtration {F t } tR+ satisfying the usual conditions (i.e., it is right continuous and increasing while F 0 contains all P -null sets); α i (i =1, 2) stands for the intensity of the random noises; C e (t) is the concentration of toxicant in the environment at time t; a 1 C e (t) represents the organism’s net absorption amounts of toxicant from the environment; d 1 θβ/a 1 is the organism’s net absorption amounts of toxicant from the food; (l 1 + l 2 )C 0 (t) represents IAENG International Journal of Applied Mathematics, 46:4, IJAM_46_4_06 (Advance online publication: 26 November 2016) ______________________________________________________________________________________
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Page 1: Analysis of a Stochastic Predator-Prey Model in Polluted ... · From then on, stochastic population models in in polluted environments have received great attention and have been

Analysis of a Stochastic Predator-Prey Model inPolluted Environments

Huajuan Zhou, Meng Liu∗

Abstract—In this paper, a stochastic predator-prey popula-tions model in polluted environments is proposed and investi-gated. We first study the existence, uniqueness and boundednessof the global positive solution. Then we establish the sufficientconditions for extinction, non-persistence in the mean and weakpersistence in the mean of the predator and prey populations.The threshold between weak persistence in the mean andextinction for each species is obtained. Finally, we study theglobal asymptotic stability of the solution. Our results revealthat the more the number of random noises, the easier thespecies go to extinction.

Index Terms—environmental pollution, stochastic noises, per-sistence, extinction.

I. INTRODUCTION

ENVIRONMENTAL pollution by modern industry, a-griculture, and other human activities is one of the

most important socio-ecological problems in the world today.The presence of toxicant in the environment is a greatthreat to the survival of the exposed living beings. Thismotivates scholars to analyze the survival of populationsin polluted environments and to establish the persistence-extinction thresholds of the populations.

In recent years, many scholars have studied the survival ofpopulations with toxicants effect by establishing mathemat-ical models. Hallam and his colleagues did pioneering workin [1], [2], [3], where the authors studied some deterministicpopulation systems with toxins effect and established thetheoretical persistence-extinction thresholds for their models.From then on, many deterministic models in polluted envi-ronmrnts were proposed and analyzed. For example, Hallamand Ma [4], Ma et al. [5], [6], Freedman and Shukla [7],Wang and Ma [8], Buonomo et al. [9], Srinivasu [10] andHe and Wang [11] proposed some single-species popula-tion models in polluted environments and established thepersistence-and-extinction thresholds for their models. Liuand Ma [12] studied the persistence-and-extinction thresholdsfor two-species Lotka-Volterra models with toxins effect.Ma et al. [13] and Pan et al. [14] extended the thresholdresults in [12] to n-dimensional food chain model and n-dimensional factualistic system, respectively. Liu at al. [15],

Manuscript received 21 April, 2016; revised 12 May, 2016. This workwas supported by the National Natural Science Foundation of China (Nos.11301207), Project Funded by China Postdoctoral Science Foundation(2015M571349 and 2016T90236), Natural Science Foundation of JiangsuProvince (No. BK20130411), Natural Science Research Project of OrdinaryUniversities in Jiangsu Province (No. 13KJB110002), Qing Lan Project ofJiangsu Province (2014), Science and Technology Support Plan Projectof Huaian (HAR2015013), Natural Science Foundation of HeilongjiangProvince (No.A201420).

M. Liu is with the School of Mathematical Science, Huaiyin NormalUniversity, Huaian 223300, PR China, and School of Mathematics andStatistics, Northeast Normal University, Changchun 130024, Peoples Re-public of China. E-mail: [email protected]

H. Zhou is with Huaiyin Normal University.

[16], Jiao et al. [17] and Li and Chen [18] considered thepopulation models in polluted environments with pulse inputof environmental toxins.

However, in the nature world the growth of population isinevitably affected by the random interference factors ([19],[20]). Thus it is important to study stochastic populationmodels in polluted environments and to reveal the effects ofrandom noises on the dynamics of populations. In this area,Gard did pioneering work in [21], where he first proposeda stochastic single-species model with toxins effect andinvestigated the dynamics of the model by supposing that theconcentration of toxicant in the organism is a constant. Be-sides, Liu and Wang [22] obtained the persistence-extinctionthreshold for a stochastic logistic model in polluted envi-ronments. From then on, stochastic population models inin polluted environments have received great attention andhave been studied extensively owing to their theoretical andpractical significance (see e.g., [23]-[29]). Especially, takinginto account the fact that predator-prey model is one of themost important models in biomathematics and ecology, Wang[24] has investigated the following stochastic predator-preymodel in polluted environments:

dx1 = x1[r10 − r11C0(t)− a11x1 − a12x2]dt+ α1x1dB1(t),

dx2 = x2[−r20 − r21C0(t) + a21x1 − a22x2]dt+ α2x2dB2(t),

dC0(t)

dt= a1Ce(t) + d1θβ/a1 − (l1 + l2)C0(t),

dCe(t)

dt= −hCe(t) + u(t),

(1)

where x1(t) represents the size of the prey population attime t; x2(t) stands for the size of the predator populationat time t; ri0 > 0 is the growth rate of the species i; ri1 ≥ 0denotes the species i’s dose-response parameters for toxicantconcentration in the body; C0(t) represents the concentrationof toxicant in the organism at time t; aii > 0 is the intra-specific competition coefficients of species i; a12 > 0 standsfor the capture rate; a21 > 0 measures the efficiency of foodconversion; B1(t) and B2(t) are two independent standardBrownian motions defined on a complete probability space(Ω,F ,P) with a filtration Ftt∈R+ satisfying the usualconditions (i.e., it is right continuous and increasing whileF0 contains all P-null sets); αi(i = 1, 2) stands for theintensity of the random noises; Ce(t) is the concentrationof toxicant in the environment at time t; a1Ce(t) representsthe organism’s net absorption amounts of toxicant fromthe environment; d1θβ/a1 is the organism’s net absorptionamounts of toxicant from the food; (l1+ l2)C0(t) represents

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the reduction of poison due to the metabolism and excretion;Parameters a1, d1(≤ a1), θ, β, l1 and l2 are positive con-stants; a1 represents the per unit mass organism’s absorptionrate of toxicant from the environment; d1 stands for theper unit mass organism’s rate of toxicant from the food;θ represents the concentration of toxicant in the resources;β is the per unit mass organism’s intake rate of toxicantfrom the food; l1 and l2 are the decomposition and emissionrates of the toxicant in the organism, respectively; h > 0is the environment’s ability to clean up poison; u(t) ≤ U2

represents emission rate of environmental toxicant. Wang[24] has obtained the persistence-extinction threshold formodel (1).

Based on the study [24], we find some interesting prob-lems:(Q1) Model (1) assumes that the parameters r10 and r20 are

affected by independent random noises. However, inthe nature world, the random noises on r10 and r20may or may not correlate to each other ([19]). Forexample, rain may affect both x1 and x2. Thus whathappens if both r10 and r20 are affected by correlatedrandom noises?

(Q2) Boundedness is an important properties for populationmodels, which was not investigated in [24]. Then whenthe solution of the model is bounded?

(Q3) In the study of population models, the global asymp-totic stability of the solution is one of the most inter-esting topics. However, [24] did not consider globalasymptotic stability of the solution.

The aims of this paper are to study the above problems. Sup-pose that ri0 affected by n independent standard Brownianmotions, then we obtain the following stochastic model:

dx1 = x1[r10 − r11C0(t)− a11x1 − a12x2]dt

+ x1

n∑i=1

α1idBi(t)

dx2 = x2[−r20 − r21C0(t) + a21x1 − a22x2]dt

+ x2

n∑i=1

α2idBi(t)

dC0(t)

dt= a1Ce(t) + d1θβ/a1 − (l1 + l2)C0(t)

dCe(t)

dt= −hCe(t) + u(t)

(2)

with initial data

xi(0) > 0, C0(0) = Ce(0) = 0

where α1i, α2i are constants, Bi(t), (1 ≤ i ≤ n), are in-dependent standard Brownian motions defined on (Ω,F ,P).Clearly, if α11 = 0, α1i = 0, 2 ≤ i ≤ n, α21 = 0 andα2i = 0, 2 ≤ i ≤ n, then model (2) becomes model (1).

The rest of the paper is arranged as follows. In Section2, we show that for any given initial data, model (2) hasa unique global positive solution. Then in Section 3, weestablish the sufficient conditions for stochastic boundednessof the solution. We carry out the survival analysis for model(2) in Section 4. Sufficient conditions for extinction, non-persistence in the mean and weak persistence in the mean ofthe species are established. The threshold between extinction

and weak persistence in the mean is obtained for eachspecies. Afterwards, we investigate the global asymptoticstability of model (2) in Section 5. In the last section, wegive some conclusions.

II. EXISTENCE AND UNIQUENESS OF THE SOLUTION

C0(t) and Ce(t) are the concentrations of toxicant, hencewe must give some conditions under which 0 ≤ C0(t) <1, 0 ≤ Ce(t) < 1. In fact, the last two equations in model(2) are linear with respect to C0(t) and Ce(t), it is easy toobtain their explicit solutions, so we have

Lemma 1. For model (2), if 0 < a1 + d1θβ/a1 < l1 +l2, U2 ≤ h, then 0 ≤ C0(t) < 1, 0 ≤ Ce(t) < 1 for allt ∈ R+ a.s.

From now on, we always assume that 0 < a1+d1θβ/a1 <l1+ l2, U2 ≤ h. We concentrate on the following subsystemof model (2):

dx1 = x1[r10 − r11C0(t)− a11x1 − a12x2]dt

+ x1

n∑i=1

α1idBi(t)

dx2 = x2[−r20 − r21C0(t) + a21x1 − a22x2]dt

+ x2

n∑i=1

α2idBi(t).

(3)

System (3) is a population model, so we should firstgive some conditions under which (2) has a global positivesolution.

Theorem 1. For model (3), if aij > 0, then for any givenpositive initial value x(0) = (x1(0), x2(0)) ∈ R2

+, thereexists a unique solution x(t) = (x1(t), x2(t)) to model (3)a.s. (almost surely) and this solution does not leave R2

+ withprobability 1.a.s.

Proof: Since the coefficients of system (3) satisfy thelocal Lipschitz condition, so for any given initial conditionsx(0) = (x1(0), x2(0)) ∈ R2

+, there exists a unique local sat-urated solution x(t) = (x1(t), x2(t)) defined on t ∈ [0, τe],where τe is the time of the explosion ([30]). In order to provethis is a general solution, we only need to prove τe = ∞.Let n0 > 0 be sufficiently large such that all components ofx(0) are on [1/n0, n0]. For every integer n > n0, define thestopping time

τn = inft ∈ [0, τe] : xi(t) ≤1

nor xi(t) ≥ n,

where we always set inf ∅ = ∞. Obviously, τn increasesmonotonically with respect to n. Let τ∞ = lim

t→+∞τn, hence

τ∞ ≤ τe. Now we need to prove τ∞ = ∞. If it is false, wecan find a positive constant T > 0 and ε ∈ (0, 1) such that

P τ∞ < ∞ > ε.

Then there exists an integer n1 ≥ n0 satisfying

P τn < T > ε , n > n1 (4)

Define a function V (x) which is from R2+ to R+ as follows:

V (x) = a21(x1 − 1− lnx1) + a12(x2 − 1− lnx2).

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This function is non-negative because

u− 1− lnu ≥ 0, u > 0.

According to Ito’s formula, we can see that

dV (x(t)) = a21(x1 − 1)

[[r10 − r11C0(t)− a11x1

−a12x2]dt+n∑

i=1

α1idBi(t)

]+ 0.5a21

n∑i=1

α21idt

+a12(x2 − 1)

[[−r20 − r21C0(t) + a21x1

−a22x2]dt+n∑

i=1

α2idBi(t)

]+ 0.5a12

n∑i=1

α22idt

=

[0.5a21

n∑i=1

a21i + 0.5a12

n∑i=1

α22i − r10a21 + r20a12

+a21r11C0(t) + a12r21C0(t) + [r10a21 + a11a21−a12a21 − a21r11C0(t)]x1 + [−r20a12 + a12a21

+a12a22 − a12r21C0(t)]x2 − a11a21x21 − a12a22x

22

]dt

+a21(x1 − 1)

n∑i=1

a1idBi(t) + a12(x2 − 1)

n∑i=1

a2idBi(t)

= G(x)dt+ a21(x1 − 1)n∑

i=1

a1idBi(t)

+a12(x2 − 1)n∑

i=1

a2idBi(t),

(5)where

G(x) = 0.5a21

n∑i=1

a21i + 0.5a12

n∑i=1

α22i − r10a21

+r20a12 ++a21r11C0(t) + a12r21C0(t)+[r10a21 + a11a21 − a12a21 − a21r11C0(t)]x1

+[−r20a12 + a12a21 + a12a22−a12r21C0(t)]x2 − a11a21x

21 − a12a22x

22.

Obviously, there is a positive constant G1 > 0 such thatG(x) < G1. Substituting this inequality into (5) gives

dV (x(t)) ≤ G1dt+ a21(x1 − 1)n∑

i=1

a1idBi(t)

+a12(x2 − 1)n∑

i=1

a2idBi(t).

Therefore, ∫ τn∩

T

0

dV (x(t)) ≤∫ τn

∩T

0

G1dt

+

∫ τn∩

T

0

[a21(x1 − 1)

n∑i=1

a1idBi(t)

+a12(x2 − 1)n∑

i=1

a2idBi(t)

].

Taking the expectation on the both sides, we have

E(x(τn∩

T )) ≤ V (x(0)) +G1E(τn∩T )

≤ V (x(0)) +G1T.(6)

Let Ωn = τn ≤ T, then by (16), we have

P(Ωn) ≥ ε.

Note that for any ω ∈ Ωn, there is a i such that xi(τn, ω) = nor xi(τn, ω) = 1/n. Therefore, V (x(τn, ω)) does not lessthan

min

a21(n− 1− lnn), a12(n− 1− lnn),

a21

(1

n− 1 + lnn

), a12

(1

n− 1 + lnn

).

That is to say,

V (x(0)) +G1T ≥ E[1Ωn(ω)V (x(τn)))]

≥ εmin

a21(n− 1− lnn), a12(n− 1− lnn),

a21

(1

n− 1 + lnn

), a12

(1

n− 1 + lnn

),

where 1Ωn is the index function of Ωn. Letting n → ∞ givescontradictory.

∞ > V (x(0)) +G1T = ∞.

This completes the proof.

III. BOUNDEDNESS OF THE SOLUTION

In the previous section, we have shown that model (3) hasa unique global positive solution. Now let us show that thesolution is stochastically bounded.

Definition 1. Model (3) is said to be stochastically bounded,if for ∀ε > 0, there is a positive constant K such that

lim inft→+∞

Pxi(t) ≤ K ≥ 1− ε, i = 1, 2.

Theorem 2. Let (x1(t), x2(t)) be a solution to (3) withinitial value (x1(0), x2(0)) ∈ R2

+. If a22 > a21, then model(3) is stochastically bounded.

Proof: To begin with, let us show that for any p > 1,there exists Gi(p) such that

E[xpi (t)] ≤ Gi(p), i = 1, 2.

DefineV (x) = xp

1,

where p > 1. Applying Ito’s formula leads to

dV (x) = pxp1

[r10 − r11C0(t)− a11x1 − a12x2

+0.5(p− 1)n∑

i=1

α21i

]dt+ pxp

1

n∑i=1

α1idBi(t).

Making use of Ito’s formula again to etV (x) results in

d[etV (x)] = etV (x)dt+ etdV (x)

= etxp1dt+ etpxp

1

[r10 − r11C0(t)− a11x1 − a12x2

+0.5(p− 1)

n∑i=1

α21i

]dt+ petxp

1

n∑i=1

α1idBi(t).

Taking expectations on both sides, we can obtain that

E[etxp1] ≤ xp

1(0) + pE∫ t

0

esxp1(s)

[1/p+ r10

+0.5pn∑

i=1

α21i − a11x1(s)

]ds

≤ xp1(0) +

∫ t

0

esL1(p)ds

= xp1(0) + L1(p)(e

t − 1),

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where

L1(p) =

[1 + pr10 + 0.5p2

n∑i=1

α21i

]p+1

(p+ 1)p+1ap11.

Thus there exists a T > 0 such that

E[xp1(t)] ≤ 1.5L1(p)

for all t > T . At the same time, an application of thecontinuity of E[xp

1(t)] results in that there exist L1(p) > 0such that E[xp

1(t)] ≤ L1(p) for t ≤ T . Let

G1(p) = max1.5L1(p), L1(p),

then for t ≥ 0, we have

E[xp1(t)] ≤ G1(p).

On the other hand, similarly, we can show that

d[etxp2] = etxp

2dt+ etpxp2

[− r20 − r21C0(t)

+a21x1 − a22x2 + 0.5(p− 1)

n∑i=1

α22i

]dt

+petxp2

n∑i=1

α2idBi(t).

Taking expectations on both sides results in

E[etxp2] ≤ xp

2(0) + pE∫ t

0

esxp2(s)

[1/p+ a21x1(s)

+0.5pn∑

i=1

α22i − a22x2(s)

]ds

≤ xp2(0) + p

∫ t

0

esE[xp2(s)

[1/p− a22x2(s)

+0.5p

n∑i=1

α22i

]]+ a21E[xp

2(s)x1(s)]

ds

≤ xp2(0) + p

∫ t

0

esE[xp2(s)

[1/p− a22x2(s)

+0.5pn∑

i=1

α22i

]]ds+ pa21

∫ t

0

esE[xp+12 (s)

]ds

+pa21p+ 1

∫ t

0

esE[xp+11 (s)

]ds

= xp2(0) + pE

∫ t

0

esxp2(s)

[1/p+ 0.5p

n∑i=1

α22i

−(a22 − a21)x2(s)

]ds

+pa21p+ 1

∫ t

0

esE[xp+11 (s)

]ds

≤ xp2(0) +

∫ t

0

esL2(p)ds

+pa21p+ 1

G1(p+ 1)

∫ t

0

esds

= xp2(0) +

[L2(p) +

pa21p+ 1

G1(p+ 1)

](et − 1),

where

L2(p) =

[1 + 0.5p2

n∑i=1

α22i

]p+1

(p+ 1)p+1(a22 − a21)p.

The third inequality follows from the Yong inequality: for∀a, b ∈ R and ∀p, q, ε > o

|a|p|b|q ≤ |a|p+q +q

p+ q

[p

ε(p+ q)

]p/q|b|p+q.

Thus we get

lim supt→+∞

E[xp2(t)] ≤ L2(p) +

pa21G1(p+ 1)

p+ 1= L3(p).

Then there exists a T > 0 such that

E[xp2(t)] ≤ 1.5L3(p)

for all t > T . There also exists L3(p) > 0 such that

E[xp2(t)] ≤ L3(p)

for t ≤ T . Let

G2(p) = max1.5L3(p), L3(p)

,

then for t ≥ 0, we have

E[xp2(t)] ≤ G2(p).

Now we are in the position to show the stochasticboundedness of model (3). For ∀ε > 0, let K =√maxG1(2), G2(2)/ε, then by Chebyshev’s inequality,

we have

Pxi(t) < K

E[x2i (t)

]K2

= K−2E[x2i (t)

].

Therefore,

lim inft→+∞

Pxi(t) ≤ K

≤ K−2Gi(2) ≤ ε.

This completes the proof.

Theorem 3. The solution of model (3) has the property that

lim supt→+∞

lnxi(t)

ln t≤ 1, a.s., i = 1, 2. (7)

Proof: Define

W (x) = a21x1 + a12x2.

According to Ito’s formula, we have

et ln

(a21x1 + a12x2

)− ln

(a21x1(0) + a12x2(0)

)=

∫ t

0

eslnW (x(s)) +

1

W (x(s))

[a21x1(s)

×(r10 − r11C0(s)− a11x1(s)− a12x2(s)

)+a12x2(s)

(r20 − r21C0(s) + a21x1 − a22x2

)]ds

−∫ t

0

es

2W 2(x(s))

n∑i=1

α21ia

221x

21(s)ds

−∫ t

0

es

2W 2(x(s))

n∑i=1

α22ia

212x

22(s)ds

+n∑

i=1

Ni1(t) +n∑

i=1

Ni2(t),

(8)where

Ni1(t) =

∫ t

0

es

W (x(s))α1ia21x1(s)dBi(s),

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Ni2(t) =

∫ t

0

es

W (x(s))α2ia12x2(s)dBi(s).

Let

N(t) =n∑

i=1

(Ni1(t) +Ni2(t)).

Clearly, N(t) is a local martingale with quadratic variation:

⟨N,N⟩ =∫ t

0

e2s

W 2(x(s))

n∑i=1

[α21ia

221x

21(s) + α2

2ia212x

22(s)

]ds.

It then follows from the exponential martingale inequalitythat

P

sup0≤t≤µk

[N(t)− 0.5e−µk⟨N,N⟩

]> ρeµk ln k

≤ k−ρ,

where ρ > 1 and µ > 0 is arbitrary. In view of the Borel-Cantelli lemma, for almost all ω ∈ Ω, there exists a k0(ω)such that for every k ≥ k0(ω),

N(t) ≤ 0.5e−µk⟨N(t), N(t)⟩+ ρeµk ln k, 0 ≤ t ≤ µk.

Substituting this inequality into (8), we can observe that

et lnW (t)− lnW (0)

=

∫ t

0

eslnW (x(s)) +

1

W (x(s))

[a21x1(s)

×(r10 − r11C0(s)− a11x1(s)− a12x2(s)

)+a12x2(s)

(r20 − r21C0(s) + a21x1 − a22x2

)]ds

−∫ t

0

es

2W 2(x(s))

n∑i=1

α21ia

221x

21(s)ds

−∫ t

0

es

2W 2(x(s))

n∑i=1

α22ia

212x

22(s)ds

+ρeµk ln k + 0.5e−µk

∫ t

0

e2s

W 2(x(s))

×n∑

i=1

[α21ia

221x

21(s) + α2

2ia212x

22(s)

]ds

≤∫ t

0

eslnW (x(s)) +

1

W (x(s))

[a21x1(s)

×(r10 − a11x1(s)

)+ a12x2(s)

(r20 − a22x2(s)

)]− 1

2W 2(x(s))

n∑i=1

α21ia

221x

21(s)(1− es−µk)

− 1

2W 2(x(s))

n∑i=1

α22ia

212x

22(s)(1− es−µk)

ds

+ρeµk ln k.

It is easy to see that for arbitrary 0 ≤ t ≤ µk, there exists aconstant C independent of k such that

lnW (x) +1

W (x)

[a21x1

(r10 − a11x1

)+a12x2

(r20 − a22x2

)]− 1

2W 2(x)

n∑i=1

α21ia

221x

21(1− et−µk)

− 1

2W 2(x)

n∑i=1

α22ia

212x

22(1− et−µk)ds ≤ C.

In other words, for arbitrary 0 ≤ t ≤ µk, one can obtain

et ln

(a21x1(t) + a12x2(t)

)≤ C[et − 1] + ρeµk ln k + ln

(a21x1(0) + a12x2(0)

).

Consequently, if µ(k − 1) ≤ t ≤ µk and k ≥ k0(ω), then

ln(a21x1(t) + a12x2)

ln t≤ e−t ln(a21x1(0) + a12x2(0))

ln t

+C[1− e−t]

ln t+

ρe−µ(k−1)eµk ln k

ln t.

Letting k → +∞ results in

lim supt→+∞

ln(a21x1(t) + a12x2(t))

ln t≤ ρeµ.

Letting ρ → 1 and µ → 0 yields the desired assertion.

IV. PERSISTENCE AND EXTINCTION

In this section we shall consider the persistence andextinction of x1 and x2. To this end, let us introduce somenotations and recall an useful lemma. Set

y∗ = lim supt→+∞

y(t), y∗ = lim inft→+∞

y(t), ⟨y(t)⟩ = 1

t

∫ t

0

y(s)ds,

∆ = a11a22 + a12a21,

∆2 = a21

[r10 − 0.5

n∑i=1

α21i

]− a11

[r20 + 0.5

n∑i=1

α22i

],

Φ = a11r21 + a21r11.

Lemma 2. ([25]) Suppose that x(t) ∈ C[Ω × R+, R0+],

where R0+ = a|a > 0, a ∈ R.

(i) If there exist positive numbers λ0,T and λ ≥ 0 such that

lnx(t) ≤ λt− λ0

∫ t

0

x(s)ds+n∑

i=1

βiBi(t)

for all t ≥ T , where Bi(t)(i = 1, 2) are independentstandard Brownian motions, βi(1 ≤ i ≤ n) are constants,then

⟨x⟩∗ ≤ λ/λ0, a.s.

(ii) If there exist positive numbers λ0,T and λ ≥ 0 such that

lnx(t) ≥ λt− λ0

∫ t

0

x(s)ds+n∑

i=1

βiBi(t)

for all t ≥ T , where Bi(t)(i = 1, 2) are independentstandard Brownian motions, βi(1 ≤ i ≤ n) are constants,then

⟨x⟩∗ ≥ λ/λ0, a.s.

Definition 2. (i) x(t) is said to go to extinction iflim

t→+∞x(t) = 0.

(ii) x(t) is said to be non-persistent in the mean if ⟨x⟩∗ = 0(iii) x(t) is said to be weakly persistent in the mean if⟨x⟩∗ > 0.

Lemma 3. For model (3), if ∆2 > 0, then for i = 1, 2,

[lnxi(t)/t]∗ ≤ 0, a.s.

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Proof: Suppose that y1(t) is the solution of the follow-ing equation:

dy1 = y1[r10 − a11y1]dt+ y1

n∑i=1

α1idBi(t). (9)

y2(t) is the solution of the following equation:

dy2 = y2[−r20 + a21y1 − a22y2]dt+ y2

n∑i=1

α2idBi(t).

(10)By the stochastic comparison theorem ([31]), we get

x1(t) ≤ y1(t), x2(t) ≤ y2(t).

Now we are in the position to prove

[ln y1/t]∗ ≤ 0, [ln y2/t]

∗ ≤ 0.

By Lemma A.1 in [32], we have

limt→+∞

[ln y1(t)/t] = 0. (11)

Consequently,[lnx1(t)

t

]∗≤ lim sup

t→+∞

[ln y1(t)

t

]= 0.

According to Ito’s formula, one can observe that

ln

[y1(t)

y1(0)

]=

(r10 − 0.5

n∑i=1

α21i

)t− a11

∫ t

0

y1(s)ds

+n∑

i=1

α1iBi(t),

and,

ln

[y2(t)

y2(0)

]=

(− r20 − 0.5

n∑i=1

α22i

)t+ a21

∫ t

0

y1(s)ds

− a22

∫ t

0

y2(s)ds+n∑

i=1

α2iBi(t).

Hence

a21 ln

[y1(t)

y1(0)

]+ a11 ln

[y2(t)

y2(0)

]= ∆2t

−a11a22

∫ t

0

y2(s)ds+ a21

n∑i=1

α1iBi(t) + a11

n∑i=1

α2iBi.

(12)For arbitrarily given ε > 0, by (11), we can find a positiveconstant T such that

a21ln[y1(t)/y1(0)]

t< ε

for t > T . Substituting this inequality into (12) gives

a11 ln

[y2(t)

y2(0)

]> (∆2 − ε)t− a11a22

∫ t

0

y2(s)ds

+ a21

n∑i=1

α1iBi(t) + a11

n∑i=1

α2iBi(t)

> (∆2 − ε)t− a11a22

∫ t

0

y2(s)ds

+ a21

n∑i=1

α1iBi(t).

Since ∆2 > 0, we can use Lemma 2, hence

⟨y2⟩∗ ≥ ∆2 − ε

a11a22.

By the arbitrariness of ε, we can see that

⟨y2⟩∗ ≥ ∆2

a11a22.

So for arbitrarily given ε > 0, we can find a positive constantT1 such that

a11a22⟨y2(t)⟩ > a11a22⟨y2(t)⟩∗ − ε ≥ ∆2 − ε, t > T.

On the other hand, compute that

a21ln[y1(t)/y1(0)]

t+ a11

ln[y2(t)/y2(0)]

t

= ∆2 − a11a22⟨y2(t)⟩+ a21

n∑i=1

α1iBi(t)/t

+a11

n∑i=1

α2iBi(t)/t.

Hence

a21ln[y1(t)/y1(0)]

t+ a11

ln[y2(t)/y2(0)]

t

< ε+ a21

n∑i=1

α1iBi(t)/t+ a11

n∑i=1

α2iBi(t)/t

Taking the upper limit on both sides, we get

[ln y2(t)/t]∗ ≤ ε.

Therefore[ln y2(t)/t]

∗ ≤ 0.

This completes the proof.

Theorem 4. For the prey populations x1,

(i) if r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ < 0, then x1(t) goes to

extinction a.s.;

(ii) If r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ = 0, then x1(t) is non-

persistent in the mean;

(iii) If r10−0.5

n∑i=1

α21i−r11⟨C0⟩∗ > 0, then x1(t) is weakly

persistent in the mean a.s.

Proof: (i) According to Ito’s formula,

ln(x1(t)/x1(0))/t = r10 − 0.5

n∑i=1

α21i − r11⟨C0(t)⟩

− a11⟨x1(t)⟩ − a12⟨x2(t)⟩+n∑

i=1

α1iBi(t)/t,

(13)

ln(x2(t)/x2(0))/t = −r20 − 0.5

n∑i=1

α22i − r21⟨C0(t)⟩

+ a21⟨x1(t)⟩ − a22⟨x2(t)⟩+n∑

i=1

α2iBi(t)/t.

(14)Taking the upper limit on the both sides of (13) gives

[lnx1(t)/t]∗ = r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ − a11⟨x1⟩∗

− a12⟨x2⟩∗ < 0.

Therefore limt→+∞

x1(t) = 0 a.s.

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(ii) For arbitrarily given ε > 0, we can find a positiveconstant T1 > 0 such that

r11⟨C0(t)⟩ > r11⟨C0⟩∗ − ε, ∀t > T.

Substituting this inequality into (13) gives

ln(x1(t)/x1(0))/t ≤ r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ + ε

− a11⟨x1(t)⟩+n∑

i=1

α1iBi(t)/t.

Then by Lemma 2, we get

⟨x1⟩∗ ≤ [r10 − 0.5n∑

i=1

α21i − r11⟨C0⟩∗ + ε]/a11.

By the arbitrariness of ε, one can see that

⟨x1⟩∗ ≤ [r10 − 0.5n∑

i=1

α21i − r11⟨C0⟩∗]/a11. (15)

Notice that

r10 − 0.5n∑

i=1

α21i = r11⟨C0⟩∗

and ⟨x1⟩∗ ≥ 0, therefore ⟨x1⟩∗ = 0, a.s.(iii) By (13), we get

a11⟨x1⟩∗ + a12⟨x2⟩∗ ≥ r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ > 0.

That is to say ⟨x1⟩∗ > 0 a.s. In fact, for ∀ω ∈ ⟨x1⟩∗ = 0,we have ⟨x2(ω)⟩∗ > 0. Taking the upper limit on both sidesof (14), we have

[ln(x2(t, ω))/t]∗ ≤ −r20 − 0.5

n∑i=1

α22i − r21⟨C0⟩∗

− a22⟨x2(ω)⟩∗ < 0.

which is contradicted with

⟨x2(ω)⟩∗ > 0.

Therefore ⟨x1⟩∗ > 0This completes the proof.

Theorem 5. For the predator populations x2,(i)if ∆2 − Φ⟨C0⟩∗ < 0,then x2(t) goes to extinction a.s.;(ii) If ∆2 − Φ⟨C0⟩∗ = 0,then x2(t) is non-persistent in themean a.s.;(iii) If ∆2 −Φ⟨C0⟩∗ > 0,then x2(t) is weakly persistent a.s.

Proof: (i) Clearly, if

∆2

Φ< ⟨C0⟩∗ <

r10 − 0.5n∑

i=1

α21i

r11,

then

∆2

Φ<

r10 − 0.5

n∑i=1

α21i

r11.

By (14) and (15), it is easy to see that

[t−1 lnx2(t)]∗ ≤ a−1

11 [∆2 − Φ⟨C0⟩∗]− a22⟨x2⟩∗ < 0.

That is to say, limt→+∞

x2(t) = 0, a.s.

If r10 − 0.5

n∑i=1

α21i − r11⟨C0⟩∗ < 0, then by Theorem 4,

we have ⟨x1⟩∗ = 0. Hence according to (14),

[t−1 lnx2(t)]∗ ≤ −r20 − 0.5

n∑i=1

α22i − r21⟨C0⟩∗ + a21⟨x1⟩∗

− a22⟨x2⟩∗

= −r20 − 0.5

n∑i=1

α22i − r21⟨C0⟩∗ − a22⟨x2⟩∗

< 0

That is to say,

limt→+∞

x2(t) = 0, a.s.

(ii) Here we use reductio ad absurdum to prove (ii). If⟨x2⟩∗ > 0, then by Lemma 3, we get [t−1 lnx2(t)]

∗ = 0.By (14), we have

−r20 − 0.5n∑

i=1

α22i − r21⟨C0⟩∗ + a21⟨x1⟩∗ ≥ a22⟨x2⟩∗ ≥ 0.

For arbitrarily given ε > 0, we can find a positive constantT > 0 such that

r21⟨C0(t)⟩ > r21⟨C0⟩∗ − ε.

anda21⟨x1⟩ < a21⟨x1⟩∗ + ε

for all t > T . Substituting this inequality into (14) gives

ln(x2(t)/x2(0))/t ≤ −r20 − 0.5n∑

i=1

α22i − r21⟨C0⟩∗ + 2ε

+ a21⟨x1(t)⟩∗ − a22⟨x2(t)⟩+n∑

i=1

α2iBi(t)/t.

Then by Lemma 2, we get

⟨x2⟩∗ ≤−r20 − 0.5

n∑i=1

α22i − r21⟨C0⟩∗ + a21⟨x1⟩∗ + 2ε

a22.

By the arbitrariness of ε, we have

⟨x2⟩∗ ≤−r20 − 0.5

n∑i=1

α22i + a21⟨x1⟩∗ − r21⟨C0⟩∗

a22.

When (15) is used in this inequality, one can see that

⟨x2⟩∗ ≤ 1

a11a22[∆2 − Φ⟨C0⟩∗] = 0.

This is a contradiction, so we have ⟨x2⟩∗ = 0.(iii) Clearly,

a21t−1 ln(x1(t)/x1(0)) + a11t

−1 ln(x2(t)/x2(0))= ∆2 − Φ⟨C0(t)⟩ −∆⟨x2(t)⟩

+a21

n∑i=1

α1iBi(t)/t+ a11

n∑i=1

α2iBi(t)/t.

We take upper limit on both sides of the equation. Since∆2 > 0, then by Lemma 2, we have

⟨x2⟩∗ ≥ 1

∆[∆2 − ϕ⟨C0⟩∗] > 0.

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This completes the proof.

Theorem 6. For model (2) we have

(a) For prey populations x1, set b1 = r10 − 0.5

n∑i=1

α21i.

(i) if

b1 − r11

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]< 0,

then x1(t) goes to extinction a.s.;(ii) If

b1 − r11

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]= 0,

then x1(t) is non-persistent in the mean a.s.;(iii) If

b1 − r11

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]> 0,

then x1(t) is weakly persistent in the mean a.s.(b) For predator populations x2,

(iv) if

∆2 − Φ

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]< 0,

then x2(t) goes to extinction a.s.;(v) If

∆2 − Φ

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]= 0,

then x2(t) is non-persistent in the mean a.s.;(vi) If

∆2 − Φ

[a1

(l1 + l2)h⟨u⟩∗ +

d1θβ

(l1 + l2)a1

]> 0,

then x2(t) is weakly persistent in the mean a.s.

Remark 1.From Theorem 4,one can observe that x1 is

gong to extinction if and only if r11⟨C0⟩∗ + 0.5

n∑i=1

α21i >

r10;x1 is weekly persistent if and only if r11⟨C0⟩∗ +

0.5n∑

i=1

α21i < r10,That is to say r10−r11⟨C0⟩∗−0.5

n∑i=1

α21i

is the threshold between weak persistence and extinctionof x1. Similarly,from Theorem 5,we can observe that x2

is gong to extinction if and only if Φ⟨C0⟩∗ > ∆2;x2 isweekly persistent if and only if Φ⟨C0⟩∗ < ∆2.In other words,∆2−Φ⟨C0⟩∗ is the threshold between weak persistence andextinction of x2.

V. GLOBAL ASYMPTOTIC STABILITY

Definition 3. System (3) is said to be globally asymptoticallystable if

limt→+∞

|x11(t)− x12(t)| = limt→+∞

|x21(t)− x22(t)| = 0

for any two positive solution (x11(t), x21(t)) and(x12(t), x22(t)) of system (3).

Lemma 4. ([33]) Suppose that an n−dimensional stochasticprocess X(t) on t ≥ 0 satisfies the condition

E|X(t)−X(s)|α1 ≤ c|t− s|1+α2 , 0 ≤ s, t < ∞

for some positive constants α1, α2 and c. Then there exists acontinuous modification X(t) of X(t) which has the propertythat for every θ ∈ (0, α2/α1) there is a positive randomvariable h(ω) such that

P

sup0<|t−s|<h(ω),0≤s,t<∞

X(t)−X(s)

|t− s|θ≤ 2

1− 2−θ

= 1

In other words, almost every sample path of X(t) is locallybut uniformly Holder continuous with exponent θ.

Lemma 5. Let (x1(t), x2(t))T be a solution of (3) on t ≥ 0.

If a22 > a21, then almost every sample path of xi(t) isuniformly continuous, i = 1, 2.

Proof: The first equation in model (3) is equivalent tothe following stochastic integral equation

x1(t) = x1(0) +

∫ t

0

x1

[r10 − r11C0(t)− a11x1 − a12x2

]ds

+

∫ t

0

x1

n∑i=1

α1idBi(s).

Notice that

E∣∣∣∣x1

[r10 − r11C0(t)− a11x1 − a12x2

]∣∣∣∣p= E

[|x1|p

∣∣∣∣r10 − r11C0(t)− a11x1 − a12x2

∣∣∣∣p]≤ 0.5E|x1|2p + 0.5E

∣∣∣∣r10 − r11C0(t)− a11x1 − a12x2

∣∣∣∣2p≤ 0.5

G1(2p) + 32p−1

[|r10|2p + a11E|x1(t)|2p

+ a12E|x2(t)|2p]

≤ 0.5

G1(2p) + 32p−1

[|r10|2p + a11G1(2p) + a12G2(2p)

]= K2(p).

Moreover, in view of the moment inequality for stochasticintegrals one can obtain that for 0 ≤ t1 ≤ t2 and p > 2,

E∣∣∣∣ ∫ t2

t1

n∑i=1

α1ix1(s)dBi(s)

∣∣∣∣p≤ np−1

n∑i=1

E∣∣∣∣ ∫ t2

t1

α1ix1(s)dBi(s)

∣∣∣∣p≤ np−1

n∑i=1

[α21i]

p

[p(p− 1)

2

]p/2(t2 − t1)

p−22

∫ t2

t1

E|x1|pds

≤ np−1

n∑i=1

[α21i]

p

[p(p− 1)

2

]p/2(t2 − t1)

p2G1(p).

Then for 0 < t1 < t2 < ∞, t2 − t1 ≤ 1, 1/p+ 1/q = 1, we

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have

E(|x1(t2)− x1(t1)|p) = E∣∣∣∣ ∫ t2

t1

x1

[r10 − r11C0(t)

−a11x1 − a12x2

]ds+

∫ t2

t1

x1

n∑i=1

α1idBi(s)

∣∣∣∣p≤ 2p−1E

∣∣∣∣ ∫ t2

t1

x1

[r10 − r11C0(t)− a11x1 − a12x2

]ds

∣∣∣∣p+ 2p−1E

∣∣∣∣ ∫ t2

t1

x1

n∑i=1

α1idBi(s)

∣∣∣∣p≤ 2p−1(t2 − t1)

p/q

∫ t2

t1

E∣∣∣∣x1

[r10 − r11C0(t)− a11x1

− a12x2

]∣∣∣∣pds+2p−1np−1

n∑i=1

[α21i]

p

[p(p− 1)

2

]p/2(t2 − t1)

p/2G1(p)

≤ 2p−1(t2 − t1)p/q+1K2(p)

+2p−1np−1

n∑i=1

[α21i]

p

[p(p− 1)

2

]p/2(t2 − t1)

p/2G1(p)

≤ 2p−1(t2 − t1)p/2

[(t2 − t1)

p/2 + (p(p−1)2 )p/2

]K3(p)

≤ 2p−1(t2 − t1)p/2

[(1 + (p(p−1)

2 )p/2]K3(p),

where

K3(p) = maxK2(p), np−1

n∑i=1

[α21i]

pG1(p).

Then it follows from Lemma 4 that almost every samplepath of x1(t) is locally but uniformly Holder-continuous withexponent θ for every θ ∈ (0, p−2

2p ). Therefore almost everysample path of x1(t) is uniformly continuous on t ≥ 0. Inthe same way we can demonstrate that almost every samplepath of x2(t) is uniformly continuous.

Lemma 6. ([34]) Let f be a non-negative function definedon R+ such that f is integrable and is uniformly continuous.Then lim

t→+∞f(t) = 0.

Theorem 7. If

a11 − a21 > 0, a22 − a12 > 0 (16)

then system (3) is globally asymptotically stable.

Proof: Define

V (t) = | lnx11(t)− lnx12(t)|+ | lnx21(t)− lnx22(t)|,

then V (t) is a continuous and positive function on t ≥ 0. Adirect calculation of the right differential d+V (t) of V (t),and then applying Ito’s formula yieldsd+V (t)

= sgn(x11 − x12)

[dx11

x11− (dx11)

2

2x211

]−[dx12

x12− (dx12)

2

2x212

]+ sgn(x21 − x22)

[dx21

x21− (dx21)

2

2x221

]−[dx22

x22− (dx22)

2

2x222

]= sgn(x11 − x12)

− a11[x11 − x12]− a12[x21 − x22]

dt

+ sgn(x21 − x22)

a21[x11 − x12]− a22[x21 − x22]

dt

≤− a11|x11 − x12|+ a12|x21 − x22| − a22(t)|x21 − x22|

+ a21|x11 − x12|dt

= −(a11 − a21)|x11 − x12|+ (a22 − a12)|x21 − x22|

dt.

Integrating both sides leads to

V (t) ≤ V (0)−∫ t

0

[(a11 − a21)|x11(s)− x12(s)|

+ (a22 − a12)|x21(s)− x22(s)

]ds.

Consequently

V (t)+

∫ t

0

[(a11−a21)|x11(s)−x12(s)|+(a22−a12)|x21(s)

− x22(s)

]ds ≤ V (0) < ∞.

It then follow from V (t) ≥ 0 and (16) that

|x11(t)− x12(t)| ∈ L1[0,∞), |x21(t)− x22(t)| ∈ L1[0,∞)

Then the desired assertion follows from Lemmas 5 and 6immediately.

VI. NUMERICAL SIMULATIONS

In this section, let us introduced some numerical simu-lations to illustrate the main results by using the methodsmentioned in [35], [36]. For the sake of simplicity, we choosen = 2 and consider the following discretization equation:

x(k+1)1 = x

(k)1 + x

(k)1

[r10 − r11C0(k∆t)− a11x

(k)1

−a12x(k)2

]∆t+

x(k)1 α11ξ

(k)11

+x(k)1 α21ξ

(k)21 + 0.5α11x

(k)1

((ξ

(k)11 )2 − 1

)+0.5α21x

(k)1 ((ξ

(k)21 )2 − 1)

√∆t,

x(k+1)2 = x

(k)2 + x

(k)2

[− r20 − r21C0(k∆t) + a21x

(k)1

−a22x(k)2

]∆t+

x(k)2 α12ξ

(k)12

+x(k)2 α22ξ

(k)22 + 0.5α12x

(k)2

((ξ

(k)12 )2 − 1

)+0.5α22x

(k)1 ((ξ

(k)22 )2 − 1)

√∆t,

where ξ(k)11 , ξ(k)21 , ξ(k)12 and ξ

(k)22 , k = 1, 2, ..., n, are Gaussian

random variables. In the following figures, we always chooser10 = 0.8, r20 = 0.1, r11 = r21 = 1, C0(t) = 0.1 +0.05 sin t, a11 = 0.5, a12 = 0.4, a21 = 0.3, a22 = 0.5.

In Fig.1, we choose α211 = 0.2, α2

21 = 0, α212 = α2

22 =0.1. Then according to Theorem 2, the model is stochasticallybounded. See Fig.1.

In Fig.2, the values of parameters are the same with thesein Fig.1. Then according to Theorem 3, (7) holds. See Fig.2.

In Fig.3(a), we choose α221 = 1.4, then by Theorems 4

and 5, both x1 and x2 are extinct. See Fig.3(a). In Fig.3(b),we choose α2

21 = 0.4, then in view of Theorems 4 and 5,x1 is weakly persistent in the mean and x2 is extinct. SeeFig.3(b). In Fig.3(c), we choose α2

21 = 0.04, then according

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to Theorems 4 and 5, both x1 and x2 are weakly persistentin the mean. See Fig.3(c). By comparing Fig.1 and Fig.3(a),we can see that the more the random noises, the easier thespecies go to extinction.

In Fig.4, the values of parameters are the same with thesein Fig.1. Then according to Theorem 6, the model is globallyasymptotically stable, see Fig.4.

0 200 400 600 800 10000

0.2

0.4

0.6

0.8

1

1.2

1.4

Time

x1(t)

x2(t)

Fig. 1: Trajectories for model (3) with α211 = 0.2, α2

21 =0, α2

12 = α222 = 0.1. This figure shows that the model is

stochastically bounded.

0 200 400 600 800 1000−3

−2

−1

0

1

2

3

Time

ln x1(t)/ln t

ln x2(t)/ln t

Fig. 2: Trajectories for model (3) with α211 = 0.2, α2

21 =0, α2

12 = α222 = 0.1. This figure shows that (7) holds.

VII. CONCLUSIONS

In this paper, under the assumptions that r10 and r20are affected by n independent standard Brownian motions,we have proposed and investigated a stochastic predator-prey populations model in polluted environments. We haveestablished the existence, uniqueness and boundedness of theglobal positive solution. Sufficient conditions for extinction,non-persistence in the mean, weak persistence in the meanof the predator and prey populations have been established.The threshold between weak persistence in the mean and

0 10 20 30 40 500

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

Time

x1(t)

x2(t)

(a)

0 200 400 600 800 10000

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9

1

Time

x1(t)

x2(t)

(b)

0 200 400 600 800 10000

0.2

0.4

0.6

0.8

1

1.2

1.4

Time

x1(t)

x2(t)

(c)

Fig. 3: Solution of model (3). (a) shows that both x1 andx2 are extinct (α2

21 = 1.4); (b) shows that x1 is weaklypersistent in the mean and x2 is extinct (α2

21 = 0.4); (c)shows that both x1 and x2 are weakly persistent in the mean(α2

21 = 0.04).

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0 5 10 15 20 25 300

0.2

0.4

0.6

0.8

1

1.2

1.4

Time

x1(t)

z1(t)

x2(t)

z2(t)

Fig. 4: Plot of two solution trajectories for model (3) withtwo sets of initial conditions x1(0) = 0.6, x2(0) = 0.3 andz1(0) = 0.4, z2(0) = 0.2. This figure shows that model (1)is globally asymptotically stable.

extinction for each species has been obtained. We have alsostudied the global asymptotic stability of the solution.

Our results indicate that the random interference of theprey populations x1 is neither conducive to the survival ofx1 nor unfavorable to x2. However the random interferenceof the predator populations x2 is only not conducive to thesurvival of x2.

Our Theorems give some important and interesting bio-logical meanings. From Theorem 5 one can observe thatif the two species have the same concentration of toxicantin the body, the ability for x1 to resist the toxicant isstronger than that of x2. Theorem 5 shows that if the averagegrowth rate r10 − r11⟨C0(t)⟩ of prey populations is lessthan certain negative value for sufficiently large t, then bothpredator and prey populations are going to extinction. If the

average natural mortality rate r20 +0.5n∑

i=1

α22i + r21⟨C0(t)⟩

of predator populations is larger than the maximum num-ber of average ingestion rate of prey populations [r10 −

0.5

n∑i=1

α21i − r11⟨C0⟩]/a11, then predator populations are

going to extinction. Our results also reveal that the more therandom noises, the easier the species go to extinction. So inorder to conserve biological diversity, we have the followingsolutions:

(i) To reduce the intensity of the the random noises.(ii) To reduce the number of the random noises.(ii) To reduce the input of the toxicant.Some interesting problems deserve further investigation.

In Theorem 2 and Theorem 7, the conditions have somelimitations on aij . It is interesting to study whether theseconditions can be dropped. It is also of interest to investigateother multi-species systems (see e.g. [37], [38]).

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