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Angles of Triangles

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Angles of Triangles. 3-4. Support Beams. Classify the triangular shape of the support beams in the diagram by its sides and by measuring its angles. EXAMPLE 1. Classify triangles by sides and by angles. SOLUTION. - PowerPoint PPT Presentation
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Page 1: Angles of Triangles

Angles of TrianglesAngles of Triangles3-43-4

Page 2: Angles of Triangles

EXAMPLE 1 Classify triangles by sides and by angles

SOLUTION

The triangle has a pair of congruent sides, so it is isosceles. By measuring, the angles are 55° , 55° , and 70° . It is an acute isosceles triangle.

Support Beams

Classify the triangular shape of the support beams in the diagram by its sides and by measuring its angles.

Page 3: Angles of Triangles

EXAMPLE 2 Classify a triangle in a coordinate plane

SOLUTION

STEP 1 Use the distance formula to find the side lengths.

Classify PQO by its sides. Then determine if the triangle is a right triangle.

OP = y2 – y1( )2x2 – x1( )2 +

= 2 – 0( )2(– 1 ) 0( )2 +– = 5 2.2

OQ = y2 – y1( )2x2 – x1( )2 +2= – 0( )6 0( )2 +– 3 = 45 6.7

Page 4: Angles of Triangles

EXAMPLE 2 Classify a triangle in a coordinate plane

PQ = y2 – y1( )2x2 – x1( )2 +

3 – 2( )26( )2 +–= (– 1 ) = 50 7.1

STEP 2 Check for right angles.The slope of OP is 2 – 0

– 2 – 0 = – 2.

The slope of OQ is 3 – 0 6 – 0

= 21 .

1The product of the slopes is – 22 = – 1,

so OP OQ and POQ is a right angle.

Therefore, PQO is a right scalene triangle.ANSWER

Page 5: Angles of Triangles

GUIDED PRACTICE for Examples 1 and 2

1. Draw an obtuse isosceles triangle and an acute scalene triangle.

obtuse isosceles triangle

B

A C

acute scalene triangleP

Q

R

Page 6: Angles of Triangles

GUIDED PRACTICE for Examples 1 and 2

2. Triangle ABC has the vertices A(0, 0), B(3, 3), and C(–3, 3). Classify it by its sides. Then determine if it is a right triangle.

SOLUTION

STEP 1 Use the distance formula to find the side lengths.

AB = y2 – y1( )2x2 – x1( )2 +

= 3 – 0( )2( 3 ) 0( )2 +–

BC = y2 – y1( )2x2 x1( )2 +2= – 3( )–3

3( )2 +– 3

= 18 4.2

= 400 20

Page 7: Angles of Triangles

GUIDED PRACTICE for Examples 1 and 2

AC = y2 – y1( )2x2 – x1( )2 +

= 3 – 0( )2 0 )(–3( )2 +– = 18 4.2

STEP 2 Check for right angles.

The slope of AB is 3 – 0 3 – 0

= 1.

The product of the slopes is 1(– 1) = – 1,

so AB AC and BAC is a right angle.

The slope of AC is 3 – 0 – 3 – 0 = .– 1

Therefore, ABC is a right Isosceles triangle.ANSWER

Page 8: Angles of Triangles

EXAMPLE 3 Find an angle measure

SOLUTION

STEP 1 Write and solve an equation to find the value of x.

Apply the Exterior Angle Theorem.(2x – 5)° =70° + x°Solve for x.x = 75

STEP 2Substitute 75 for x in 2x – 5 to find m∠JKM.2x – 5 = 2 75 – 5 = 145

ALGEBRA Find m∠JKM.

The measure of ∠JKM is 145°.ANSWER

Page 9: Angles of Triangles

EXAMPLE 4 Find angle measures from a verbal description

ARCHITECTURE

The tiled staircase shown forms a right triangle. The measure of one acute angle in the triangle is twice the measure of the other. Find the measure of each acute angle.

SOLUTION

First, sketch a diagram of the situation. Let the measure of the smaller acute angle be x° . Then the measure of the larger acute angle is 2x° . The Corollary to the Triangle Sum Theorem states that the acute angles of a right triangle are complementary.

Page 10: Angles of Triangles

EXAMPLE 4 Find angle measures from a verbal description

Use the corollary to set up and solve an equation.

Corollary to the Triangle Sum Theoremx° + 2x° = 90°Solve for x.x = 30

So, the measures of the acute angles are 30° and 2(30°) = 60° .

ANSWER

Page 11: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

SOLUTION

STEP 1 Write and solve an equation to find the value of x.

Apply the Exterior Angle Theorem. (5x – 10)° = 40° + 3x°Solve for x.2x =50

Find the measure of 1 in the diagram shown.3.

x=25

Page 12: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

STEP 2 Substitute 25 for x in 5x – 10 to find 1.5x – 10 = 5 25– 10 = 115

1 + (5x – 10)° = 180

1 + 115° = 180°1 = 65°

So measure of ∠1 in the diagram is 65°.ANSWER

Page 13: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

SOLUTION

A + B + C = 180°

x + 2x + 3x = 180°

6x = 180°

x = 30°

B = 2x = 2(30) = 60°

C = 3x = 3(30) = 90°

x

2x 3x

4. Find the measure of each interior angle of ABC, where m A = x , m B = 2x° , and m C = 3x°.°

Page 14: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

5. Find the measures of the acute angles of the right triangle in the diagram shown.

SOLUTION

Use the corollary to set up & solve an equation. Corollary to the Triangle Sum Theorem(x – 6)° + 2x° = 90°

3x = 96

Solve for x.x = 32

Substitute 32 for x in equation x – 6 = 32 – 6 = 26°.

So, the measure of acute angle 2(32) = 64°ANSWER

Page 15: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

6. In Example 4, what is the measure of the obtuse angle formed between the staircase and a segment extending from the horizontal leg?

A

B C Q

2x

xSOLUTIONFirst, sketch a diagram of the situation. Let the measure of the smaller acute angle be x° . Then the measure of the larger acute angle is 2x° . The Corollary to the Triangle Sum Theorem states that the acute angles of a right triangle are complementary.

Page 16: Angles of Triangles

GUIDED PRACTICE for Examples 3 and 4

Use the corollary to set up and solve an equation. Corollary to the Triangle Sum Theoremx° + 2x = 90°

Solve for x.x = 30

So the measures of the acute angles are 30° and 2(30°) = 60°

ACD is linear pair to ACD.

So 30° + ACD = 180°.Therefore = ACD = 150°.ANSWER


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