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AP-C Objectives (from College Board Learning … Motion...AP-C 2D Motion - 1 - 1. a. i. ii. iii. b....

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AP-C 2D Motion - 1 - 1. a. i. ii. iii. b. c. i. ii. d. i. ii. Motion in two dimensions, including projectile motion AP-C Objectives (from College Board Learning Objectives for AP Physics) Determine components of a vector along two specified, mutually perpendicular axes. Determine the net displacement of a particle or the location of a particle relative to another. Students should understand the general motion of a particle in two dimensions so that, given functions x(t) and y(t) which describe this motion, they can determine the components, magnitude, and direction of the particle’s velocity and acceleration as functions of time. Write down expressions for the horizontal and vertical components of velocity and position as functions of time, and sketch or identify graphs of these components. Use these expressions in analyzing the motion of a projectile that is projected with an arbitrary initial velocity. Students should be able to add, subtract, and resolve displacement and velocity vectors, so they can: Determine the change in velocity of a particle or the velocity of one particle relative to another. Students should understand the motion of projectiles in a uniform gravitational field, so they can: Students should understand frames of reference, so they can: Analyze the uniform motion of an object relative to a moving medium such as a flowing stream. Analyze the motion of particles relative to a frame of reference that is accelerating horizontally or vertically at a uniform rate.
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AP-C 2D Motion

- 1 -

1.a.

i.

ii.

iii.

b.

c.

i.

ii.

d.i.

ii.

Motion in two dimensions, including projectile motionAP-C Objectives (from College Board Learning Objectives for AP Physics)

Determine components of a vector along two specified, mutually perpendicularaxes.Determine the net displacement of a particle or the location of a particle relativeto another.

Students should understand the general motion of a particle in two dimensions sothat, given functions x(t) and y(t) which describe this motion, they can determinethe components, magnitude, and direction of the particle’s velocity and acceleration as functions of time.

Write down expressions for the horizontal and vertical components of velocityand position as functions of time, and sketch or identify graphs of thesecomponents.Use these expressions in analyzing the motion of a projectile that is projectedwith an arbitrary initial velocity.

Students should be able to add, subtract, and resolve displacement and velocityvectors, so they can:

Determine the change in velocity of a particle or the velocity of one particlerelative to another.

Students should understand the motion of projectiles in a uniform gravitationalfield, so they can:

Students should understand frames of reference, so they can:Analyze the uniform motion of an object relative to a moving medium such as aflowing stream.Analyze the motion of particles relative to a frame of reference that isaccelerating horizontally or vertically at a uniform rate.

Vector Manipulation

- 2 -

vavg =ΔrΔt

1.a.b.c.

2.

Objectives

Determine components of a vector along two specified, mutually perpendicular axes.Determine the net displacement of a particle or the location of a particle relative to another.

Students should be able to add, subtract, and resolve displacement and velocity vectors, so they can:

Determine the change in velocity of a particle or the velocity of one particle relative to another.Students should understand the general motion of a particle in two dimensions so that, given functions x(t) and y(t) which describe this motion, they can determine the components, magnitude, and direction of the particle’s velocity and acceleration as functions of time.

The position vector, r, always has its tail at the origin and its head at the current position of the object. The position vector can be written as both r and s.

Position Vector

r (t)= x(t)i+ y(t) j=< x(t), y(t)>

v = limΔt→0

ΔrΔt=drdt=dxdti+ dy

dtj=< dx

dt, dydt>

a= d

vdt=d 2xdt2i+ d

2 ydt2

j=< d2xdt2, d

2 ydt2>

Vectors can be expressed as components along mutually perpendicular axes. Manipulating from one form to another is an important skill in analysis of vectors.

Vector Components

Graphic vector addition: Line up all vectors tip to tail, and draw a line from the starting point of the

first vector to the ending point of the last vector.

Analytic vector addition: Sum up all components separately (x-components, y-components, etc.)

Vector subtraction: Add the opposite of the vector.

Vector Addition and Subtraction

Projectile Motion

- 3 -

1.a.

b.

Objectives

Write down expressions for the horizontal and vertical components of velocity and position as functions of time, and sketch or identify graphs of these components.Use these expressions in analyzing the motion of a projectile that is projected with an arbitrary initial velocity.

Students should understand the motion of projectiles in a uniform gravitational field, so they can:

Horizontal acceleration is 0 (neglect friction)

Vertical acceleration is g (on Earth’s surface, 9.81 m/s2 down)

Utilize constant acceleration kinematic equations

Projectile Motion in a Uniform Gravitational Field

v = v0+ at

x = x0+ v

0t+ 1

2at 2

v 2 = v0

2 + 2a(x− x0)

Relative Velocity

- 4 -

1.a.b.

Objectives

Analyze the uniform motion of an object relative to a moving medium such as a flowing stream.Analyze the motion of particles relative to a frame of reference that is accelerating horizontally or vertically at a uniform rate.

Students should understand frames of reference, so they can:

vAC = vAB+ vBC

velocity of water with respect to groundvelocity of boat with respect to watervelocity of boat with respect to ground

A sailor wants to sail his boat due north. The speed of the boat relative to the water is 20 km/h and the water flows from west to east at 9 km/h. In which direction should the boat head? How fast does the boat travel relative to the ground?

Example Problem (2D)

vBG =vBW +

vWG

vBW = 20 km hrvWG = 9 km hrvBG = (20 km hr)

2−(9 km hr)2 =17.9 km hr

θ= tan−1 oppadj( )= tan−1 9kmhr

17.9kmhr( )= 26.7°


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