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Chapter 2Table of Contents
Copyright ©2016 Cengage Learning. All Rights Reserved.
(2.1) Electromagnetic radiation
(2.2) The nature of matter
(2.3) The atomic spectrum of hydrogen
(2.4) The Bohr model
(2.5) The quantum mechanical model of the atom
(2.6) Quantum numbers
(2.7) Orbital shapes and energies
(2.8) Electron spin and the Pauli principle
(2.9) Polyelectronic atoms
Chapter 2Table of Contents
Copyright ©2016 Cengage Learning. All Rights Reserved.
(2.10) The history of the periodic table
(2.11) The aufbau principle and the periodic table
(2.12) Periodic trends in atomic properties
(2.13) The properties of a group: The alkali metals
Chapter 2
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Questions to Consider
Why do we get colors?
Why do different chemicals give different colors?
Section 2.1Electromagnetic Radiation
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Electromagnetic Radiation - Characteristics
One of the ways by which energy travels through space
Three characteristics:
Wavelength (λ) is the distance between two peaks or troughs in a wave
Frequency (ν) points to the number of waves (cycles) per second that pass a given point in space
Speed
The speed of light is 2.9979×108 m/s
Section 2.1Electromagnetic Radiation
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Relationship between Wavelength and Frequency
There exists an inverse relationship between λ and ν
1/
or
=
λ
λ c
n
n
The way I remember this…
n=c/l
Section 2.1Electromagnetic Radiation
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Figure 2.1 - The Nature of Waves
Section 2.1Electromagnetic Radiation
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Figure 2.2 - Classification of Electromagnetic Radiation
Section 2.1Electromagnetic Radiation
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Interactive Example 2.1 - Frequency of Electromagnetic Radiation
The brilliant red colors seen in fireworks are due to the emission of light with wavelengths around 650 nm when strontium salts such as Sr(NO3)2 and SrCO3 are heated. Calculate the frequency of red light of wavelength 6.50× 102
nm.
Solution
We can convert wavelength to frequency using the equation:
= or =c
λ cλ
n n
Section 2.1Electromagnetic Radiation
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Interactive Example 2.1 - Frequency of Electromagnetic Radiation
Where c = 2.9979×108 m/s. In this case λ = 6.50 × 102 nm
Changing the wavelength to meters, we have
26.50×10 nm9
1m×
10 nm
7
8
= 6.50×10 m
and
2.9979×10 m= =
cν
λ
7
/ s
6.50×10 m
14 1 14= 4.61×10 s = 4.61×10 Hz
Section 2.1Electromagnetic Radiation
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Pickle Light
On applying an alternating current of 110 volts to a dill pickle, a glowing discharge can be observed
The Na+ and Cl– ions in the forks cause the sodium atoms to get into an excited state
When the atoms reach their ground state, they emit visible light at 589 nm
Section 2.2The Nature of Matter
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An Introduction
Max Planck observed that energy can be gained or lost only in whole-number multiples of hν
Where h is Planck's constant with a value of 6.626 ×10–34 J · s
The change in energy for a system ΔE can be represented by the equation , where
n is an integer
h is Planck’s constant
ν represents the frequency of electromagnetic radiation
ΔE = nhn
Section 2.2The Nature of Matter
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Quantized Energy
Planck also observed that energy can be quantized and can occur only in discrete units called quanta
A system can transfer energy only in whole quanta
This proves that energy does have particulate properties
Section 2.2The Nature of Matter
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Interactive Example 2.2 - The Energy of a Photon
The blue color in fireworks is often achieved by heating copper(I) chloride (CuCl) to about 1200°C. Then the compound emits blue light having a wavelength of 450 nm. What is the increment of energy (the quantum) that is emitted at 4.50 × 102 nm by CuCl?
Solution
The quantum of energy can be calculated from the equation:
ΔE = hn
Section 2.2The Nature of Matter
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Interactive Example 2.2 - The Energy of a Photon
The frequency ν for this case can be calculated as follows:
So,
A sample of CuCl emitting light at 450 nm can lose energy only in increments of 4.41×10–19 J, the size of the quantum in this case
82.9979×10 m= =
c
λn
7
/ s
4.50×10 m
14 1= 6.66×10 s
34Δ = = 6.626×10 J.sE hn 146.66×10 s 1 19= 4.41×10 J
Section 2.2The Nature of Matter
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The Concept of Photons
Electromagnetic radiation is a stream of “particles” called photons
The energy of each photon can be expressed by:
Where h is Planck’s constant, ν is the radiation frequency, and λis the radiation wavelength
photon = =hc
E hλ
n
Section 2.2The Nature of Matter
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The Photoelectric Effect
The phenomenon whereby electrons are emitted from the surface of a metal when light strikes it
Characteristics:
No electrons are emitted by any given metal below a specified threshold frequency, ν0
When ν < ν0 , no electrons are emitted, regardless of the intensity of light
When ν > ν0 , the number of electrons increases with the intensity of light
When ν > ν0 , the kinetic energy of emitted electrons increases linearly with the frequency of the light
Section 2.2The Nature of Matter
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The Photoelectric Effect
Minimum energy required to remove an electron = E0 = hν0
When ν > ν0 , the excess energy that is required to remove the electron is given as kinetic energy (KE):
Where
m is the mass of the electron
v is the velocity of the electron
ν is the energy incident of the photon
ν0 is the energy required to expel the electron
2electron 0
1KE = =
2mv h hn n
Section 2.2The Nature of Matter
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The Photoelectric Effect
Greater intensity of light means that more photons are available to release electrons, which gave rise to the equation:
The theory of relativity signifies that energy has mass
This equation can be used to calculate mass associated with a quantity of energy
The mass of a photon of light with wavelength λ is given by:
2E = mc
= = =2 2
E hc / λ hm
c c λc
Section 2.2The Nature of Matter
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Dual Nature of Light
The phenomenon whereby electromagnetic radiation (and all matter) exhibits wave properties and particulate properties
de Broglie’s equation allows for the calculation of the wavelength of a particle
hλ =
mv
Section 2.2The Nature of Matter
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Diffraction
It is the result of light getting scattered from a regular array of points or lines
This scattered radiation produces a diffraction pattern on bright and dark areas
Scattered light can:
Interfere constructively and produce a bright area
Interfere destructively to produce a dark spot
This phenomenon occurs best when the spacing between scattering points is similar to the wavelength of the diffracted wave
Section 2.2The Nature of Matter
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Figure 2.6 - A Diffraction Pattern of a Beryl Crystal
Section 2.3The Atomic Spectrum of Hydrogen
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Significance of the Hydrogen Emission Spectrum
Continuous spectrum occurs when white light is passed through a prism
Contains all the wavelengths of visible light
Hydrogen emission spectrum is called a line spectrum
Displays only a few lines, each line corresponding to discrete wavelengths
Indicates that the energy of the electron on the hydrogen atom is quantized
Section 2.3The Atomic Spectrum of Hydrogen
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Significance of the Hydrogen Emission Spectrum
Change in energy from a high to lower level of a given wavelength can be calculated by:
Δ = =hc
E hλ
n
Change in energy Frequency of light emitted
Wavelength of light emitted
Section 2.3The Atomic Spectrum of Hydrogen
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Figure 2.7 - (a) Continuous Spectrum and (b) Line Spectrum
Section 2.3The Atomic Spectrum of Hydrogen
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Concept Check
Why is it significant that the color emitted from the hydrogen emission spectrum is not white?
How does the emission spectrum support the idea of quantized energy levels?
Section 2.4The Bohr Model
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Quantum Model for the Hydrogen Atom
Electron in a hydrogen atom moves around the nucleus only in certain allowed circular orbits
Bohr’s model gave the hydrogen atom energy levels consistent with the hydrogen emission spectrum
The expression for the energy levels available to the electron in the hydrogen atom can be expressed as:
Where n is an integer and Z is the nuclear charge
2182.178×10 J
2
ZE =
n
Section 2.4The Bohr Model
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Figure 2.9 - Electronic Transitions in the Bohr Model for the Hydrogen Atom: Part (a)
(a) An energy-level diagram for the first three electronic transitions
Section 2.4The Bohr Model
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Figure 2.9 - Electronic Transitions in the Bohr Model for the Hydrogen Atom: Part (b) and (c)
(b) An orbit-transition diagram, which accounts for the experimental spectrum
(c) The resulting line spectrum on a photographic plate
Section 2.4The Bohr Model
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Quantum Model for the Hydrogen Atom
When the hydrogen atom returns to its lowest possible energy state, it is called the ground state
When the electron falls from n=6 to n=1, ΔE can be computed by:
The negative sign indicates that the atom has lost energy and is in a more stable state
18 201 6
18
ΔE = energy of final state energy of initial state
= = 2.178×10 J 6.050×10 J
= 2.117×10 J
E E
Section 2.4The Bohr Model
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Quantum Model for the Hydrogen Atom
The energy lost is taken away from the atom by the emission of a photon whose wavelength can be calculated from:
ΔE, the change in energy of the atom, is equal to the energy of the emitted photon
Δ = or λ =Δ
c hcE h
λ E
34(6.626×10 J= =
Δ
hcλ
E
. s 8)(2.9979×10 m / s 18
)
2.117×10 J
8= 9.383×10 m
Section 2.4The Bohr Model
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Interactive Example 2.4 - Energy Quantization in Hydrogen
Calculate the energy required to excite the hydrogen electron from level n = 1 to level n = 2. Also calculate the wavelength of light that must be absorbed by a hydrogen atom in its ground state to reach this excited state.
Solution
Using the equation with Z = 1, we have:2
182.178×10 J2
ZE =
n
218 18
1 2
218 19
2 2
1= 2.178×10 J = 2.178×10 J
1
1= 2.178×10 J = 5.445×10 J
2
E
E
Section 2.4The Bohr Model
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Interactive Example 2.4 - Energy Quantization in Hydrogen
The positive value for ΔE indicates that the system has gained energy
The wavelength of light that must be absorbed to produce this change is:
19 18 18Δ = = 5.445 × 10 J 2.178 × 10 J = 1.633×10 J2 1E E E
34(6.626×10 J= =
Δ
hcλ
E
. s 8) (2.9979×10 m / s18
)
1.633×10 J
7= 1.216×10 m
Section 2.4The Bohr Model
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Importance of the Bohr Model
The model correctly fits the quantized energy levels of the hydrogen atom
It postulates only certain allowed circular orbits for the electron
As the electron becomes more tightly bound, its energy becomes more negative relative to the free electron
The free electron is at infinite distance from the nucleus
As the electron is brought closer to the nucleus, energy is released from the system
Section 2.4The Bohr Model
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Energy Change Between Levels in a Hydrogen Atom
The general equation for the electron moving from ninitial to nfinal can be derived by using the following equation:
2182.178×10 J
2
ZE =
n
final initial
final initial
2 218 18
2 2final initial
18
2 2final initial
Δ = energy of level energy of level
=
1 1 = ( 2.178×10 J) 2.178×10 J
1 1 = 2.178×10 J
E n n
E E
n n
n n
Section 2.4The Bohr Model
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Drawbacks of the Bohr Model
This model only works for hydrogen
Electrons do not move around the nucleus in circular orbits
Section 2.5The Quantum Mechanical Model of the Atom
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Erwin Schrödinger and Quantum Mechanics
Standing waves are stationary waves that do not travel along any length
Only certain orbits have a circumference into which whole number wavelengths of standing electron waves will fit
Other waves produce destructive interference of the standing electron wave
The mathematical representation for a standing wave is:
ˆ =H E
Section 2.5The Quantum Mechanical Model of the Atom
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Erwin Schrödinger and Quantum Mechanics
ψ represents the wave function, which is a function of the coordinates of the electron’s position in 3-dimensional space
represents an operator
A specific wave function is termed as an orbital
Wave function does not provide information about the pathway of the electron
H
Section 2.5The Quantum Mechanical Model of the Atom
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Heisenberg Uncertainty Principle
There is a fundamental limitation to just how precisely we can know both the position and momentum of a particle at a given time
Mathematically, this principle can be represented by:
Where
Δx is the uncertainty in a particle’s position
Δ(mν) is the uncertainty in a particle’s momentum
h is Planck’s constant
Δ . Δ( )4
hx mv
Section 2.5The Quantum Mechanical Model of the Atom
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Physical Meaning of the Wave Function
The square of the function, represented as a probability distribution, indicates the probability of finding an electron near a particular point in space
The intensity of color is used to indicate the probability value near a given point in space
The more time the electron visits a particular point, the darker the negative becomes
This diagram is known as an electron density map
Section 2.5The Quantum Mechanical Model of the Atom
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Figure 2.12 - Probability Distribution for the 1s Wave Function - Part (a) and (b)
(a) The probability distribution for the hydrogen 1s orbital in three-dimensional space
(b) The probability of finding the electron at points along a line drawn from the nucleus outward in any direction
Section 2.5The Quantum Mechanical Model of the Atom
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Physical Meaning of a Wave Function
A radial probability distribution graph plots the total probability of finding an electron in each spherical shell versus the distance from the nucleus
Probability of finding an electron at a particular position is greatest near the nucleus
Volume of the spherical shell increases with distance from the nucleus
The size of the 1s orbital can be stated as the radius of the sphere that encloses 90% of the total electron probability
Section 2.5The Quantum Mechanical Model of the Atom
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Figure 2.13 - Radial Probability Distribution
(a) Cross section of the hydrogen 1s orbital probability distribution divided into successive thin spherical shells
(b) Radial probability distribution plot
Section 2.6Quantum Numbers
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An Introduction to Quantum Numbers They express the various properties of the orbital
Principal quantum number (n) has integral values and is related to the size and energy of the orbital
Angular momentum quantum number (l or l) has integral values from 0 to n – 1
It is related to the shape of atomic orbitals (sometimes called a subshell)
Magnetic quantum number (ml) has integral values +l to -l
It is related to the orientation of the orbital in space relative to the other orbitals in the atom
Electron spin quantum number (ms) can be + ½ or – ½
It means that the electron can spin in either of the two opposite directions
Section 2.6Quantum Numbers
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Interactive Example 2.6 - Electron Subshells
For principal quantum level n = 5, determine the number of allowed subshells (different values of l), and give the designation of each
Solution
For n = 5, the allowed values of l run from o to 4 (n – 1 = 5 – 1 )
Thus, the subshells and their designations are:
l = 0 l = 1 l = 2 l = 3 l = 4
5s 5p 5d 5f 5g
Section 2.7Orbital Shapes and Energies
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An Introduction
Areas of zero probability are called nodal surfaces or nodes
The number of nodes increase as n increases
The number of nodes for the s orbital is given by n – 1
Section 2.7Orbital Shapes and Energies
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Figure 2.14 - Representations of the Hydrogen 1s, 2s, and 3s Orbitals
Section 2.7Orbital Shapes and Energies
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p Orbitals
Not spherical like s orbitals
Have two lobes separated by a node at the nucleus
Labelled as per the axis of the xyz coordinate system
Section 2.7Orbital Shapes and Energies
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The d Orbitals
Do not correspond to principal quantum levels n = 1 and n = 2
First level occur in level n = 3
They possess two fundamental shapes:
dxz , dyz , dxy , and dx2
– y2
Have four labels that are centered in the plane that appears in the orbital label
dz2
Possesses a unique shape with two lobes that run along the z axis and a belt centered in the xy plane
d orbitals, where n>3, appear as 3d orbitals and have larger lobes
Section 2.7Orbital Shapes and Energies
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Figure 2.17 - Representation of the 3d Orbitals - Part (b)
(b) The boundary surfaces of all five 3d orbitals, with the signs (phases) indicated
Section 2.7Orbital Shapes and Energies
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f Orbitals and Degenerates
The f orbitals first occur in level n = 4
These orbitals are not involved in bonding in any compounds
All orbitals with the same value of n have the same energy and are said to be degenerate
In the ground state, the single hydrogen electron can be found in the 1s orbital
This electron can be excited to higher-energy orbitals
Section 2.7Orbital Shapes and Energies
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Figure 2.18 - Representation of the 4f Orbitals in Terms of Their Boundary Surfaces
Section 2.8Electron Spin and the Pauli Principle
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Electron Spin
Electron spin quantum number (ms) can be + ½ or – ½
It means that the electron can spin in either of the two opposite directions
Pauli exclusion principle states that in a given atom no two electrons can have the same set of four quantum numbers
An orbital can hold only two electrons, and they must have opposite spins because only two values of ms are allowed
Section 2.8Electron Spin and the Pauli Principle
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Figure 2.20 - The Spinning Electron - Part (a) and (b)
• Spinning in one direction, the electron produces the magnetic field oriented as shown in (a)
• Spinning in the opposite direction, it gives a magnetic field of the opposite orientation, as shown in (b)
Section 2.9Polyelectronic Atoms
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An Introduction
Polyelectronic atoms are those atoms with more than one electron
Electron correlation problem
Since the electron pathways are unknown, electron repulsions cannot be accurately calculated
When electrons are placed in a particular quantum level, the orbital levels vary in energy as follows:
Ens < Enp < End < Enf
Section 2.9Polyelectronic Atoms
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The Penetration Effect
A 2s electron on average is closer to the nucleus (penetration) than one in the 2p orbital
This causes an electron in a 2s orbital to be attracted to the nucleus more strongly than an electron in a 2p orbital
The 2s orbital is lower in energy than the 2p orbitals in a polyelectronic atom
The same occurrence can be noticed in other quantum levels
Section 2.9Polyelectronic Atoms
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Figure 2.22 - Part (b) The Radial Probability Distribution for the 3s, 3p, and 3d orbitals
Section 2.10The History of the Periodic Table
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The periodic table was originally constructed to represent the patterns observed in the chemical properties of elements
Mendeleev’s periodic table:
Emphasized on how the table could help estimate the existence and properties of unkown elements
Rectified several values of atomic masses
The current periodic table lists elements by their atomic number rather than atomic mass
Section 2.11The Aufbau Principle and the Periodic Table
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Aufbau Principle
As protons are added one by one to the nucleus to build up the elements, electrons are similarly added to hydrogen-like orbitals
Example - An oxygen atom has an electron arrangement of two electrons in the 1s subshell, two electrons in the 2s subshell, and four electrons in the 2p subshell
Section 2.11The Aufbau Principle and the Periodic Table
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Orbital Diagrams
They represent the number of electrons an atom has in each of its occupied orbitals
Example - The orbital diagram of oxygen:
O: 1s22s22p4 1s 2s 2p
Section 2.11The Aufbau Principle and the Periodic Table
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Section 2.11The Aufbau Principle and the Periodic Table
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Hund’s Rule
The rule states that the lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allowed by the Pauli principle in a particular set of degenerate orbitals
Unpaired electrons are represented as having parallel spins
Example - The orbital diagram for neon:
Ne: 1s22s22p6 1s 2s 2p
Section 2.11The Aufbau Principle and the Periodic Table
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Valence Electrons
They are electrons in the outermost principal quantum level of an atom
Example - For the sodium atom, the valence electron is that in the 3s orbital
Inner electrons are termed core electrons
The elements in the same group on the periodic table have the same valence electron configuration and display similar chemical behavior
Section 2.11The Aufbau Principle and the Periodic Table
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Section 2.11The Aufbau Principle and the Periodic Table
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Groups in the Periodic Table
Transition metals are those whose configuration is obtained by adding electrons to the five 3d orbitals
The configuration for chromium is:
Cr: [Ar]4s13d 5
After lanthanum, the lanthanide series occurs, which corresponds to the filling of the seven 4f orbitals
The actinide series corresponds to the filling of the seven 5f orbitals
Section 2.11The Aufbau Principle and the Periodic Table
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Main-Group or Representative Elements
The labels for Groups 1A, 2A, 3A, 4A, 5A, 6A, 7A, and 8A indicate the total number of valence electrons
Each member of these groups has the same valence electron configuration
Section 2.11The Aufbau Principle and the Periodic Table
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Figure 2.29 - The Orbitals Being Filled for Elements in Various Parts of the Periodic Table
Section 2.11The Aufbau Principle and the Periodic Table
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Interactive Example 2.7 - Electron Configurations
Give the electron configurations for sulfur (S) and cadmium (Cd)
Solution
Sulfur is element 16 and resides in Period 3, where the 3p orbitals are being filled
Since sulfur is the fourth among the “3p elements,” it must have four 3p electrons
Its configuration is:
S: 1s22s22p63s23p4 or [Ne]3s23p4
Section 2.11The Aufbau Principle and the Periodic Table
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Section 2.11The Aufbau Principle and the Periodic Table
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Interactive Example 2.7 - Electron Configurations
Cadmium is element 48 and is located in Period 5 at the end of the 4d transition metals
It is the tenth element in the series and thus has 10 electrons in the 4d orbitals, in addition to the 2 electrons in the 5s orbital
The configuration is:
Cd: 1s22s22p63s23p64s23d104p65s24d10 or [Kr]5s24d10
Section 2.12Periodic Trends in Atomic Properties
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Commonly Observed Periodic Trends
Atomic radius
Ionization energy
Electron affinity
Section 2.12Periodic Trends in Atomic Properties
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Atomic Radius
Atomic radii can be obtained by measuring the distance between atoms in chemical compounds
They are also called covalent atomic radii due to the manner in which they are determined
Since nonmetallic atoms do not form diatomic molecules, atomic radii are estimated from their covalent compounds
Metallic radii are obtained by calculating half the distance between metal atoms in solid metal crystals
Section 2.12Periodic Trends in Atomic Properties
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Atomic Radii Trends
The atomic radius decreases in going across a period from left to right
Effective nuclear charge increases
Valence electrons are drawn closer to the nucleus, decreasing the size of the atom
Atomic radius increases in going down a group
Orbital sizes increase in successive principal quantum levels
Section 2.12Periodic Trends in Atomic Properties
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Interactive Example 2.8 - Trends in Radii
Predict the trend in radius for the following ions:Be2+, Mg2+, Ca2+, and Sr2+
Solution
All these ions are formed by removing two electrons from an atom of a Group 2A element
In going from beryllium to strontium, we are going down the group, so the sizes increase:
Be2+ < Mg2+ < Ca2+ < Sr2+
↑ ↑
Smallest radius Largest radius
Section 2.12Periodic Trends in Atomic Properties
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Section 2.12Periodic Trends in Atomic Properties
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Ionization Energy
It refers to the energy required to remove an electron from a gaseous atom or ion
The atom or ion is assumed to be in its ground state
The energy required to remove the highest-energy electron of an atom is called the first ionization energy (I1)
The value of I1 is generally smaller than that of I2, which is the second ionization energy
+( ) ( )X X + eg g
Section 2.12Periodic Trends in Atomic Properties
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Ionization Energy Trends in the Periodic Table
While going across a period from left to right, the first ionization energy increases
Electrons added to the same principal quantum level cannot completely shield the increasing nuclear charge and are generally more strongly bound from left to right on the periodic table
While going down a group from top to bottom, the first ionization energy decreases
The electrons being removed are farther from the nucleus
Section 2.12Periodic Trends in Atomic Properties
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Figure 2.34 - The Values of First Ionization Energy for the Elements in the First Six Periods
Section 2.12Periodic Trends in Atomic Properties
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Interactive Example 2.10 - Ionization Energies
Consider atoms with the following electron configurations:
1s22s22p6
1s22s22p63s1
1s22s22p63s2
Which atom has the largest first ionization energy, and which one has the smallest second ionization energy? Explain your choices.
Section 2.12Periodic Trends in Atomic Properties
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Interactive Example 2.10 - Ionization Energies
Solution
The atom with the largest value of l1 is the one with the configuration 1s22s22p6 (this is the neon atom), because this element is found at the right end of Period 2
Since the 2p electrons do not shield each other very effectively, l1 will be relatively large
The other configurations given include 3s electrons, which are effectively shielded by the core electrons and are farther from the nucleus than the 2p electrons in neon
Thus l1 for these atoms will be smaller than for neon
Section 2.12Periodic Trends in Atomic Properties
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Interactive Example 2.10 - Ionization Energies
The atom with the smallest value of l2 is the one with the configuration 1s22s22p63s2 (the magnesium atom)
For magnesium, both l1 and l2 involve valence electrons
For the atom with the configuration 1s22s22p63s1 (sodium), the second electron lost (corresponding to l2) is a core electron (from a 2p orbital)
Section 2.12Periodic Trends in Atomic Properties
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Electron Affinity
It refers to the energy change associated with the addition of an electron to a gaseous atom
While going across a period from left to right, electron affinities become more negative
Electron affinity becomes more positive in going down a group
Electrons are added at increasing distances from the nucleus
– –X + e) ( )X(g g
Section 2.12Periodic Trends in Atomic Properties
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Concept Check
Explain why the graph of ionization energy versus atomic number (across a row) is not linear.
Where are the exceptions?
Section 2.12Periodic Trends in Atomic Properties
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Concept Check
Which of the following would require more energy to remove an electron?
Why?
Na Cl
Section 2.12Periodic Trends in Atomic Properties
Copyright ©2016 Cengage Learning. All Rights Reserved.
Section 2.12Periodic Trends in Atomic Properties
Copyright ©2016 Cengage Learning. All Rights Reserved.
Concept Check
Which of the following would require more energy to remove an electron?
Why?
Li Cs
Section 2.12Periodic Trends in Atomic Properties
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Concept Check
Which element has the larger second ionization energy?
Why?
Lithium Beryllium
Section 2.12Periodic Trends in Atomic Properties
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Section 2.12Periodic Trends in Atomic Properties
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Concept Check
Which of the following should be the larger atom?
Why?
Na Cl
Section 2.12Periodic Trends in Atomic Properties
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Concept Check
Which of the following should be the larger atom?
Why?
Li Cs
Section 2.12Periodic Trends in Atomic Properties
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Section 2.12Periodic Trends in Atomic Properties
Copyright ©2016 Cengage Learning. All Rights Reserved.
Concept Check
Which is larger?
The hydrogen 1s orbital
The lithium 1s orbital
Which is lower in energy?
The hydrogen 1s orbital
The lithium 1s orbital
Section 2.13The Properties of a Group: The Alkali Metals
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Information in the Periodic Table
The number and type of valence electrons primarily determine the chemistry of an atom
Electron configurations can be determined from the organization of the periodic table
Certain groups in the periodic table have special names
Elements in the periodic table are basically divided into metals and nonmetals
Elements that exhibit both metallic and nonmetallic properties are termed metalloids of semimetals
Section 2.13The Properties of a Group: The Alkali Metals
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Figure 2.37 - Special Names for Groups in the Periodic Table
Section 2.13The Properties of a Group: The Alkali Metals
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Section 2.13The Properties of a Group: The Alkali Metals
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Figure 2.37 - Special Names for Groups in the Periodic Table (Contd.)
Section 2.13The Properties of a Group: The Alkali Metals
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The Alkali Metals
Li, Na, K, Rb, Cs, and Fr are the most chemically reactive of the metals
Hydrogen exhibits a nonmetallic character due to its small size
Going down a group:
Ionization energy decreases
Atomic radius increases
Density increases
Melting and boiling points decreases smoothly