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Automatic Control - Manisa Celal Bayar University

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Automatic Control EEM 3117 Laplace Transformation Dr. Sezai Taskin Department of Electrical&Electronics Engineering Faculty of Engineering, Manisa Celal Bayar University
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Page 1: Automatic Control - Manisa Celal Bayar University

Automatic ControlEEM 3117

Laplace Transformation

Dr. Sezai TaskinDepartment of Electrical&Electronics Engineering

Faculty of Engineering, Manisa Celal Bayar University

Page 2: Automatic Control - Manisa Celal Bayar University

Laplace Transform

Introduction

The study of signals and systems can be carried out in terms of either a time-domain or a

transform-domain formulation.

Both approaches are often used together in order to maximize our ability to deal with a

particular problem arising in applications.

This is very much the case in controls engineering where both time-domain and transform-

domain techniques are extensively used in analysis and design.

The transform-domain approach to signals and systems is based on the transformation of

functions using the Fourier, Laplace, and z-transforms.

10/13/2020

Page 3: Automatic Control - Manisa Celal Bayar University

10/13/2020

Page 4: Automatic Control - Manisa Celal Bayar University

Laplace Transform

10/13/2020

Stability is assessed by determining the location of

the poles in the Laplace domain (s-plane). Values in

the s-plane are made up of real (σ) and imaginary

(jω) components. If the real portions of system poles

are negative, the system is considered to be stable.

Page 5: Automatic Control - Manisa Celal Bayar University

Laplace Transformation

The Laplace transform of a function f(t), defined for all real numbers t ≥ 0, is the function F(s), defined by: L

F(s)

0

[ ( )] ( ) ( ) stf t F s f t e dt

L

Page 6: Automatic Control - Manisa Celal Bayar University

Why s-domain?

• We can transform an ordinary differential equation into an algebraic equation which is easy to solve.

• It is also easy to analyze and design interconnected (series, feedback etc.) systems.

6

Page 7: Automatic Control - Manisa Celal Bayar University

Unit step function

Slides 2 7

1 0( ) ( )

0 0

tf t u t

t

0

0

[1]

0 1

1

st

st

e dt

e

s

s s

s

L

1[1]

sL

Page 8: Automatic Control - Manisa Celal Bayar University

Exponential function

Slides 2 8

( )

0 0

( )

0

( )

[ ]

( )

0 1

( ) ( )

1

at

at at st s a t

s a t

f t e

e e e dt e dt

e

s a

s a s a

s a

L

1[ ]ate

s a

L

Page 9: Automatic Control - Manisa Celal Bayar University

Frequency shift

Slides 2 9

1[1]

sL 1

[ 1]ates a

L

[ ( )] ( )ate f t F s a L

Page 10: Automatic Control - Manisa Celal Bayar University

Sine and cosine functions

Slides 2 10

2 2[cos ]

st

s

L 2 2

[sin ]ts

L

Page 11: Automatic Control - Manisa Celal Bayar University

Impulse function

Slides 2 11

( )f t

0 0

[ ( )] ( ) 1st st

t

t t e dt e

L

Page 12: Automatic Control - Manisa Celal Bayar University

Unit ramp

Slides 2 12

0( ) ( )

0 0

t tf t u t

t

udv uv vdu (integration by parts)

0

2

0 00

[ ]

1

st

st st st

t e t dt

e t e et d dt

s s s s

L

1

![ ]n

n

nt

s L

similarly

Page 13: Automatic Control - Manisa Celal Bayar University

Differentiated function

Slides 2 13

[ ( )] ( )f t F sL

( )( ) (0)

df tsF s f

dt

L

1

2 ( 1)

( )( ) (0)

(0)..... (0)

nn n

n

n n

d f ts F s s f

dt

s f f

L

Page 14: Automatic Control - Manisa Celal Bayar University

Integrated function

Slides 2 14

0

( )( )

t F sf t dt

s

L

2nd shifting theorem

( ) ( )asf t a e F s L

Page 15: Automatic Control - Manisa Celal Bayar University

Solution of differential equations using Laplace Transformation

Slides 2 15

DifferentialEquation

TransformedEquation

Transformed Solution

Solution

Laplace Transformation

Algebraic Manipulation

Inverse Laplace

ParticularIntegral

Complementary function

Page 16: Automatic Control - Manisa Celal Bayar University

Example

Slides 2 16

2 2

00

2

2 5

5( ) (0) 2 ( )

5( )

( 2)

5( ) 5

2

2.5(1 )

t tt t

t

dxx

dt

sx s x x ss

x ss s

x t e dt e

e

Transformed Solution

Transformed Equation

Page 17: Automatic Control - Manisa Celal Bayar University

Convolution integral

Slides 2 17

1 2 1 2( ) ( ). ( ) ( ) ( ) ( )F s F s F s f t f t f t

Ex:

2

2

1 20

2( ) 2

0 0

2 2

1 1 1( )

3 2 ( 1) ( 2)

( )

( ) ( )

( 1)

t t

t

t tt t

t t t t

F ss s s s

f t e e

f f t d

e e d e e d

e e e e


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