Lecture 3 31/10/2012
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Introduction to IR
Vibrational modes in IR spectroscopy (Stretching and Bending)
Schematic representation of IR spectrometer
The IR spectrum (scale, band intensity, FGs region, Fingerprint
region)
Chemical bonds vs IR absorption
Interpretation of IR spectrum
http://www.chem.ucalgary.ca/courses/350/Carey5th/Ch13/ch13-ir-1.html
A chemical bond is compared with two weights connected by a spring as derived from “Hooke’s law”.
That the total amount of energy is proportion to the frequency of vibration, that is;
E oscillation a hνosc.
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http://en.wikipedia.org/wiki/Hooke's_law
Therefore frequency of absorption is
proportional to the square root of the force
constant for the bond divided by the reduced
mass
K is force constant in dynes/cm and
m is the reduced mass
m = m1m2/m1 + m2 masses of atom in grams
Or
m = M1M2/(M1 + M2)(6.02 ×1023)
masses of atoms in amu. 11/2/2012 Organic Spectroscopy
The smaller the atom the better the overlap and the higher the frequency of absorption For a stronger bond (larger K value), v increases,
for heavier atoms attached (larger m value), v decreases.
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Molecules absorb infrared light when one of six
possible bonding vibrations occurs:
Recall
Bonds can have
◦ symmetrical and asymmetrical; stretching,
◦ scissoring, rocking, wagging and twisting.
The energies of the peaks must be matched to
known bond vibrations.
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The C-H stretching and bending energies
are clearly visible but the C-C bands are not
seen, as they are either too weak or too low
in energy.
For a molecule to be IR active the vibration
must result in a change of dipole moment
during the vibration.
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Homonuclear diatomic molecules such as
Hydrogen (H2), Nitrogen (N2) and Oxygen
(O2) have zero dipole moment.
No infrared absorption are observed.
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For heteronuclear diatomic molecules
such as carbon monoxide (CO) and
hydrogen chloride (HCl) are IR active.
They possess a permanent dipole
moment, because bond stretching
leads to a change in dipole moment
( Dipole Moment = Charge x Distance
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Usually symmetrical vibrations are weak or
not visible.
Larger changes in dipole moment of bond
lead to more intense IR absorption
It is not necessary for a compound to have
a permanent dipole moment to be infrared
active.
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In the case of carbon dioxide (CO2) the
molecule is linear and centrosymmetric and
therefore does not have a permanent dipole
moment.
This means that the symmetric stretch will
not be infrared active.
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However, in the case of the
asymmetric stretch a dipole moment
will be periodically produced and
destroyed resulting in a changing
dipole moment and therefore infrared
activity
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C OO C OOC OO
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http://chemwiki.ucdavis.edu/Physical_Chemistry/Spectroscopy/Vibrational_Spectroscopy/Vibrational_Modes
If there is an absence of major functional
group bands in the region 4000-1300 cm-1
(other than C–H stretches), the compound is
probably a strict hydrocarbon.
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Aromatics, alkyl halides, carboxylic
acids, amines, and amides show
moderate or strong absorption bands
(bending vibrations) in 900-650 cm-1.
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Absorption frequencies Typical bonds
3700-2500 cm-1
2300 –2000 cm-1
1900- 1500 cm-1
1400- 650 cm-1
Single bonds to hydrogen
Triple bonds
Double bonds
Single bonds (other than
hydrogen)
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Look for a carbonyl in
the region
1760—1609 cm-1
Is an O-H band
also present?
A carbonylic acid
group
Is a C-O band
also present?
An ester
Is an aldehydic
C-H band also
present
An aldehyde
Is an N-H band
also present?
An amide
Are none of the
rest present?
A ketone
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Other structural
features from 4000—
1300 cm-1
Are there C-O
stretches?
An ether
(or an ester if there is
a carbonyl band too)
Is there a C=C
stretching bands?
An alkene
Are there aromatic
stretching band?
An aromatic
Are there –NO2 band?
A nitro compound
Is there a CC triple
bond band?
An alkyne
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It has few strong absorption bands whose
spectrum has the various CH stretch bands
that all hydrocarbons show near 3000 cm-1.
There is a weak alkene CH stretch above
3000 cm-1.
This comes from the C & emdash; H bonds on carbons 1 and 2,
the two carbons that are held together by the double bond.
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http://webbook.nist.gov/cgi/cbook.cgi?ID=C592416&Type=IR-SPEC&Index=1#IR-SPEC
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The strong CH stretch bands below 3000
cm-1 the CH2 and CH3 groups.
There is an out-of-plane CH bend for
the alkene in the range 1000-650 cm-1.
There is also an alkene C=C double
bond stretch at about 1650 cm-1.
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http://www.chem.ucalgary.ca/courses/350/Carey5th/Ch13/ch13-ir-1.html
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Frequency cm-1 Bond Functional group
3640–3610 (s,
sh)
O-H strength, frequency, free
hydroxyl
Alcohols, phenols
3500–3200 (s,b) O-H strength, frequency, H-bonded Alcohols, phenols
3400–3250 (m) N-H stretch 1o, 2o amine, amide
3300–2500 (m) O-H stretch Carboxylic acids
3330–3270 (n,s) -CC-H: C-H stretch Alkynes (terminal)
3100– 3000 (s) C-H stretch aromatic
3000– 2850 (m) =C-H stretch alkenes
2830– 2695 (m) H-C=O: C-H stretch aldehyde
2260– 2210 (w) CN stretch nitriles
2260– 2100(w) -CΞC stretch alkynes
1760– 1665 (s) C=O stretch Carbonyl (general)
1760–1690 (s) C=O stretch Carboxylic acids
1750–1735 (s) C=O stretch esters, saturate aliphatic
1740–1720 (s) C=O stretch aldehydes, saturate aliphatic
1730–1715 (s) C=O stretch a,b-unsaturated esters
1715 (s) C=O stretch ketones, saturated aliphatic
1710–1665 (s) C=O stretch a,b-unsaturated aldehydes,
ketones
1680–1640 (m) -C=C– stretch alkenes
Typical absorption frequencies of some FGs
a) Give the IUPAC names of the following compound 1 to 5.(start slide show and click on numbers, then
go to # 3. Group Frequencies)
b) Which one of these compounds best match the given IR spectrum Q?
c) Give reason to why it does match.
d) Why each of the rest do not comply with the spectrum? Suggest their absorption patterns and frequencies
OH
O
O OH O
(1) (2) (3) (4) (5)
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IR spectrum Q
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a) Find the number of vibrational modes for the following molecules:
NH3, C6H6, C10H8, CH4, C2H2(linear).
b) State which of the following vibrations are IR active: N2, CO, CO2
(stretching), HCl
c) Calculate the vibrational frequency of CO given the following data:
mass of C = 12.01 amu, mass of O = 16 amu, the force constant k
= 1.86X103kgs-2.
d) Calculate the vibrational energy in Joules per mole of a normal
mode in question 3, in its ground state of n=0.
e) Assuming the force constant to be the same for H20 and D2O. A
normal mode for H20 is at 3650 cm-1. Do you expect the
corresponding D2O wave number to be higher or lower?
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http://chemwiki.ucdavis.edu/Physical_Chemistry/Spectroscopy/Vibrational_Spectroscopy/Vibrational_Modes
Organic Spectroscopy
Different chemical bonds give rise to characteristic IR absorption
frequencies and intensities.
The energy required for bond vibration depends on the size (mass)
of the atoms and bond strength.
Strong bonds absorb at higher frequencies
Frequency of absorption is proportional to the square root of the
force constant (K) for the bond divided by the reduced mass (m)
Homonuclear diatomic molecules have zero dipole moment hence
they are infrared inactive.
It is not necessary for a compound to have a permanent dipole
moment to be infrared active
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