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Balancing Chemical Reactions

Date post: 16-Jan-2016
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Balancing Chemical Reactions. Balancing Chemical Reactions. Balancing Chemical Reactions Sodium metal plus water Na (s) + H 2 O (l) → NaOH + H 2 (g) Burning Magnesium metal in air Mg (s) + O 2 (g) → MgO (s) & – Al + O 2 → Al 2 O 3 Burning Candle wax - PowerPoint PPT Presentation
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Balancing Chemical Reactions
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Page 1: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 2: Balancing Chemical Reactions

Balancing Chemical Reactions

• Balancing Chemical Reactions• Sodium metal plus water

– Na (s) + H2O (l) → NaOH + H2 (g)

• Burning Magnesium metal in air– Mg (s) + O2 (g) → MgO (s) & – Al + O2 → Al2O3

• Burning Candle wax– C40H82 (s) + O2 (g) → CO2 (g) +H2O (g)

Page 3: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 4: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 5: Balancing Chemical Reactions

Balancing Chemical Reactions

More Hydrogen atoms on the right than on the left.The only place to get more Hydrogen is from H2O

Page 6: Balancing Chemical Reactions

Balancing Chemical Reactions

Now you have more Oxygen on the left than on the right.Multiply the NaOH by 2

Page 7: Balancing Chemical Reactions

Balancing Chemical Reactions

Now Hydrogen and Oxygen are balanced but Sodium is not.Multiply the Na on the left by 2

Page 8: Balancing Chemical Reactions

Chemical Reactions

Page 9: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 10: Balancing Chemical Reactions

Balancing Chemical Reactions

Note one oxygen on the right and two on the leftMultiply the left by 2

Page 11: Balancing Chemical Reactions

Balancing Chemical Reactions

After multiplying we see that oxygen is balanced but Now magnesium is not, Multiply Mg by 2.

Page 12: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 13: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 14: Balancing Chemical Reactions

Balancing Chemical Reactions

Note there are 3 Oxygen on the right and 2 on the left.The simplest factor for 3 and 2 is 6 so 6 divided by 3 is2 so multiply Al2O3 by 2 and 6 divided by 2 is 3 so multiplyO2 by 3.

Page 15: Balancing Chemical Reactions

Balancing Chemical Reactions

After doing the multiplication only Al is left unbalancedMultiply Al by 4 to finish.

Page 16: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 17: Balancing Chemical Reactions

Balancing Chemical Reactions

Page 18: Balancing Chemical Reactions

Balancing Chemical Reactions

Odd number of Oxygen on the right and even on the left.Multiply the hydrocarbon on the left by 2.

Page 19: Balancing Chemical Reactions

Balancing Chemical Reactions

80 Carbons make 80 CO2164 Hydrogen's make 82 waters.

Page 20: Balancing Chemical Reactions

Balancing Chemical Reactions

After multiplying out the reactants you end up with 242 Oxygen'son the right that you can get from 121 Oxygen molecules on the left.

Page 21: Balancing Chemical Reactions

Balancing Chemical Reactions


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