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Balancing Redox Reactions

Date post: 30-Dec-2015
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Balancing Redox Reactions. Steps :. Assign oxidation numbers Write half reactions Balance electrons to determine coefficients needed. Problem 1:. +2 -2 0 0. 2HgO  O 2 + 2Hg. Hg +2 + 2e -  Hg 0. Reduction. O -2  O 0 + 2e -. Oxidation. Problem 2:. - PowerPoint PPT Presentation
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Balancing Redox Balancing Redox Reactions Reactions
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Page 1: Balancing  Redox  Reactions

Balancing Redox Balancing Redox ReactionsReactions

Page 2: Balancing  Redox  Reactions

StepsSteps::

1. Assign oxidation numbers

2. Write half reactions

3. Balance electrons to determine coefficients needed

Page 3: Balancing  Redox  Reactions

2HgO O2 + 2Hg+2 -2 0 0

Hg+2 + 2e- Hg0 Reduction

Problem 1:

O-2 O0 + 2e- Oxidation

Page 4: Balancing  Redox  Reactions

2KClO3 2KCl + 3O2

+1 +5 -2 +1 -1 0

6e- + Cl+5 Cl-1 Reduction

Problem 2:

3(O-2 O0 + 2e-) Oxidation

Page 5: Balancing  Redox  Reactions

2HCl + Zn ZnCl2 + H2

+1 -1 0 +2 -1 0

2e- + 2H+1 H20 Reduction

Problem 3:

Zn0 Zn+2 + 2e- Oxidation

Page 6: Balancing  Redox  Reactions

2Ag NO3 + Cu Cu(NO3)2 + 2Ag+1 +5 -2 0 +2 +5 -2 0

2e- + 2Ag+1 2Ag0 Reduction

Problem 4:

Cu0 Cu+2 + 2e- Oxidation

Page 7: Balancing  Redox  Reactions

4NH3 + 3O2 2N2 + 6H2O -3 +1 0 0 +1 -2

12e- + 3O20 6O-2 Reduction

Problem 5:

4N-3 2N20 + 12e- Oxidation

Page 8: Balancing  Redox  Reactions

3Mg + 2Al(NO3)3 2Al + 3Mg(NO3)2

0 +3 +5 -2 0 +2 +5 -2

6e- + 2Al+3 2Al0 Reduction

Problem 6:

3Mg0 3Mg+2 + 6e- Oxidation

Page 9: Balancing  Redox  Reactions

3Ca + 2Al3+ 3Ca2+ + 2Al 0 +3 +2 0

6e- + 2Al+3 2Al0 Reduction

Problem 6:

3Ca0 3Ca+2 + 6e- Oxidation

Page 10: Balancing  Redox  Reactions

2Fe3+ + Sn2+ 2Fe2+ + Sn4+

2e- + 2Fe+3 2Fe+2 Reduction

Problem 7:

Sn+2 Sn+4 + 2e- Oxidation

Page 11: Balancing  Redox  Reactions

2HNO3 + 3MnCl2 + 6HCl 2NO + 3MnCl4 + 4H20+1 +5 -2 +2 -1 +1 -1 +2 -2 +4 -1 +1 -2

6e- + 2N+5 2N+2 Reduction

Problem 8:

3Mn+2 3Mn+4 + 6e- Oxidation

Page 12: Balancing  Redox  Reactions

K2(Cr2O7) + 14HCl 3Cl2 + 7H2O + 2CrCl3 + 2KCl+1 +6 -2 +1 -1 0 +1 -2 +3 -1 +1 -1

6e- + Cr2+6 2Cr+3 Reduction

Problem 9:

6Cl-1 3Cl20 + 6e- Oxidation


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