Banking managgement system

7/28/2019 Banking managgement system

1/23

OF

BANKING

Submitted in the partial fulfillment of the Degree of Bachelor of Technology

(Integrated)

InComputer Science and Engineering

SUBMITTED BY:- GUIDED BY:-

Name Rajat Bajaj Miss Komal Walia

Regd. No 10904118

Rollno Rb1902 A25

SUBMITTED TO

Department of Computer Science and Engineering Lovely Professional UniversityPhagwara


2/23

ACKNOWLEDGEMENT

I take this opportunity to present my votes of thanks to all those guidepost who reallyacted as lightening pillars to enlighten our way throughout this project that has led to

successful and satisfactory completion of this study.

We are really grateful to our HOD ---------------for providing us with an opportunityto undertake this project in this university and providing us with all the facilities. We

are highly thankful to Miss Komal Walia for her active support, valuable time and

advice, whole-hearted guidance, sincere cooperation and pains-taking involvementduring the study and in completing the assignment of preparing the said project

within the time stipulated.

Lastly, We are thankful to all those, particularly the various friends , who have been

instrumental in creating proper, healthy and conductive environment and including

new and fresh innovative ideas for us during the project, their help, it would havebeen extremely difficult for us to prepare the project in a time bound framework.


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TABLE OF CONTENTS

1. Introduction

2. Proposed systemi. Description

ii. System requirements

3. Requirement Analysis

4. System Design

5. Source code

6. Testing

7. Future scope of project


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INTRODUCTION

In the existing system, most of the records are maintained on paper. It becomes veryinconvenient to modify the data. In the existing system, here is a possibility that the same

data in different registers may have different values which means the entries of the same

data do not match. This inconsistent state does not supply the concrete information which

poses a problem in the case information related to particular search record.Our project is very useful. User is no longer required to check his register in search of

records, as now it can be searched over the software by choosing some options. The user

need not to type in most of the information. He/she is just required to enter the desiredoptions. On the whole it liberates the user from keeping lengthy manual records. In a

nutshell, it abates the work load of an organization.

In todays world, no one likes to perform calculations on calculator or manually whencomputer is there. Every one wants his/her work to be done by computer automatically

and displaying the result for further manipulations.

This term paper project is just an application of the language C in developing

softwares.This is the program for keeping records of the bank ,that is the entire details of

the customer ,savings ,how much money he/she can deposit and withdraw from the bank,to open the new account ,create a new account ,display all account holders, balance

enquiry etc.


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PROPOSED SYSTEM

The following documentation is a project the BANKING . It is a detailed summary ofall the drawbacks of the old system and how the new proposed system overcomes these

shortcomings. The new system takes into account the various factors while designing a

new system. It keeps into the account the Economical bandwidth available for the new

system. The foremost thing that is taken care of is the Need and Requirements of theUser.

DESCRIPTION

Before developing software we keep following things in mind that we can develop

powerful and quality software

PROBLEM STATEMENT

o Problem statement was to design a module:

o Which is user friendly

o Which will restrict the user from accessing other users data.

o Which will help user in viewing his data and privileges.

o Which will help the administrator to handle all the changes.

FUNCTIONS TO BE PROVIDED:

The system will be user friendly and completely menu driven so that the users shall have

no problem in using all options.

o The system will be efficient and fast in response.

o

The system will be customized according to needs.o Create new account

o Search ,edit and display customer details

o Display account holders

o Deposit money

o Withdraw money

o Balance enquiry

SYSTEM REQUIRMENTS

Operating system: MS Windows XP or Windows VistaLanguage: C Language

Processor: Pentium IV Processor

RAM: 512 MBHard disk: 5 GB


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REQUIREMENT ANALYSIS

This process is adopted when management of the system development, Personnel decide

that the particular system needs improvement. The system development life cycle is the

set of activities, carried out by the analyst, designers and users to develop and implementa system. The systems that are present in the nature follow common life cycle pattern.

For example consider the raining system. Initially the rain falls into the river, river flows

into sea, the sea water evaporates to form vapors, the vapors form clouds which again

bring rain. Similarly consider a man made system initially a system is analyzed, designedand made operational by the efforts of system analysis. After successful operation or a

number of users, the system becomes less and less effective by change in the

environment. So these changes have to be incorporated in to the system by minor

modifications. So the general activities from the life cycle of the system are given below: Select ion and identification of the system to be studied

Preliminary study

Defining the system

Design and development of the system

Implementation of the system


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SYSTEM DESIGN

Then we began with the design phase of the system. System design is a solution, a HOWTO approach to the creation of a new system. It translates system requirements into

ways by which they can be made operational. It is a translational from a user oriented

document to a document oriented programmers. For that, it provides the understanding

and procedural details necessary for the implementation. Here we use Flowchart tosupplement the working of the new system. The system thus made should be reliable,

durable and above all should have least possible maintenance costs. It should overcome

all the drawbacks of the Old existing system and most important of all meet the userrequirements.

Welcome to the project on banking

Enter

your

choice

11?

Create account Customer details Deposit withdraw

Do you want tocontinue?

START

STOP

Balance enquir


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SOURCE CODE

# include

# include

# include # include //library header file

int dmenu(); //main menu

void dadd(); //add to listvoid dfind(); //search from the list

void dedit(); //edit the record

void ddel(); //delete from the listvoid ddisp(); //display all

void ddisp1();//display1void ddisp2();//display2

void dwith();void ddepo();

void dcurrent_with();

void dcurrent_depo();void deposit();

void withdrawal();

struct dnode {int num,bal,check;

char dlname[20], dfname[20], dtel[15];

struct dnode *dnext;};

typedef struct dnode node;

node *dstart, *dtemp;

int i=5000,chk=1,j=15000;int dmenu()

{

int dch;gotoxy(30,5);

printf(" BANKING DATABASE ");

gotoxy(30,6);

printf(" ================ ");gotoxy(3,24);

gotoxy(27,10);

printf(" 1. Create a new account");gotoxy(27,11);

printf(" 2. Search customer details");

gotoxy(27,12);printf(" 3. Edit customer details");


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gotoxy(27,13);

printf(" 4. Delete a customer");

gotoxy(27,14);printf(" 5. Display all account holders ");

gotoxy(27,15);

printf(" 6. Deposit money");gotoxy(27,16);

printf(" 7. Withdrawal money");

gotoxy(27,17);printf(" 8. Balance Enquiry");

gotoxy(27,18);

printf(" 9. Exit ");

gotoxy(27,21);printf(" Enter your choice(1-9):");

gotoxy(55,21);

scanf("%d", &dch);

return dch;}

void dadd(){

int type;

node *dptr,*dprev;dtemp=(node *)malloc(sizeof(node));

printf("\nWhich type of account you want to create?\n1->Savings\n2->Current\nenter

your choice : ");

scanf("%d",&type);if(type==1)

{

do{printf("\nYour Account No:");

dtemp->num=i;

printf("%d",dtemp->num);i++;

}while(i>10000);

printf("\nFirst name: ");

scanf("%s", dtemp->dfname);printf("Last name:");

scanf("%s", dtemp->dlname);

printf("Telephone No.: ");scanf("%s", dtemp->dtel);

a:

printf("Deposit Sum:");scanf("%d",&dtemp->bal);

if(dtemp->bal


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goto a;

}

dtemp->dnext=NULL;if(dstart==NULL) dstart=dtemp;

else {

dprev=dptr=dstart;while(strcmp(dtemp->dfname,dptr->dfname)>0){

dprev=dptr;

dptr= dptr->dnext;if (dptr == NULL) break;

}

if(dptr==dprev) {

dtemp->dnext=dstart;dstart=dtemp;

}

else if(dptr==NULL)

dprev->dnext=dtemp;else {

dtemp->dnext=dptr;dprev->dnext=dtemp;

}

}ddisp1();

}

else if(type==2)

{do{

printf("\nYour Account No:");

dtemp->num=j;printf("%d",dtemp->num);

j++;

}while(j>20000);printf("\nFirst name: ");

scanf("%s", dtemp->dfname);

printf("Last name:");

scanf("%s", dtemp->dlname);printf("Telephone No.: ");

scanf("%s", dtemp->dtel);

m:printf("Deposit Sum:");

scanf("%d",&dtemp->bal);

if(dtemp->bal


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dtemp->dnext=NULL;

if(dstart==NULL) dstart=dtemp;

else {dprev=dptr=dstart;

while(strcmp(dtemp->dfname,dptr->dfname)>0){

dprev=dptr;dptr= dptr->dnext;

if (dptr == NULL) break;

}if(dptr==dprev) {

dtemp->dnext=dstart;

dstart=dtemp;

}else if(dptr==NULL)

dprev->dnext=dtemp;

else {

dtemp->dnext=dptr;dprev->dnext=dtemp;

}}

printf("Your provided Cheque nos.%d to %d",chk,chk+19);

ddisp2();}

}

void dfind()

{node *dptr;

int no,num;

if(dstart==NULL) {printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();

return;}

printf("Enter the account No : ");

scanf("%d",&no);

dptr=dstart;while(dptr->num!=no)

{


}

if(dptr!=NULL){

if(dptr->num>=5000 && dptr->num


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if(dptr->num==no)

{

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);printf("\n\t\tYou are a SAVINGS account holder of our bank");

printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);printf("\n\t\tLast name:%s", dptr->dlname);

printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);printf("\n\t\t------------------------------\n");

}

}

else{printf("\n\n");

printf("\t\t------------------------------\n");

if(dptr->num==no)

{printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\n\t\tYou are a CURRENT account holder of our bank");printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);

printf("\n\t\tLast name:%s", dptr->dlname);printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);

chk=1;

printf("\n\t\tCheque nos:%d to %d",chk,chk+19);printf("\n\t\t------------------------------\n");

}

}}

else

{printf("No Matching Records Found .......\n");

}

getch();

}void deposit()

{

int no;node *dptr,*dprev;

if(dstart==NULL) {

printf("\n\t\t\tNO ACCOUNT DATABASE....\n");getch();

return;

}

printf("Enter your account no : ");


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scanf("%d",&no);

dptr=dstart;

while(dptr->num!=no){

dptr= dptr->dnext;

if (dptr == NULL) break;}

if(dptr!=NULL){

if(dptr->num>=5000 && dptr->numdlname);

printf("\nAccount No:%d \n",dptr->num);printf("First Name : %s\n",dptr->dfname);

printf("Last Name : %s\n",dptr->dlname);

printf("Phone Number : %s\n",dptr->dtel);printf("Your Balance : %d\n",dptr->bal);

printf("Deposit Amount:");

scanf("%d",&bal);

dptr->bal+=bal;printf("Your New balance:%d",dptr->bal);

getch();

}void dcurrent_depo()

{

node *dptr;int bal,ch;

printf("\t\t\n-----------------------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\nAccount No:%d \n",dptr->num);


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printf("First Name : %s\n",dptr->dfname);


printf("Phone Number : %s\n",dptr->dtel);printf("Your Balance : %d\n",dptr->bal);

printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");

scanf("%d",&ch);if(ch==1)

{

printf("Deposit Amount:");scanf("%d",&bal);

dptr->bal+=bal;

printf("Your New balance:%d",dptr->bal);

}else if(ch==2)

{

do{

printf("\nYour Check No:");dtemp->check=chk;

printf("%d\n",dtemp->check);chk++;

}while(chk>21);

printf("Deposit Amount:");scanf("%d",&bal);

dptr->bal+=bal;


}getch();

}

void withdrawal(){

node *dptr;

int no;if(dstart==NULL) {

printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();

return;}

printf("Enter the account No : ");

scanf("%d",&no);dptr=dstart;



}

if(dptr!=NULL)

{


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if(dptr->num>=5000 && dptr->numdlname);


printf("First Name : %s\n",dptr->dfname);printf("Last Name : %s\n",dptr->dlname);

printf("Phone Number : %s\n",dptr->dtel);

printf("Your Balance : %d\n",dptr->bal);

b:printf("Withdrawal Amount:");

scanf("%d",&bal);

if((dptr->bal-bal)bal-=bal;


getch();}

void dcurrent_with()

{node *dptr;

int no,bal,ch;

printf("\t\t\n-----------------------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);





16/23

printf("Phone Number : %s\n",dptr->dtel);

printf("Your Balance : %d\n",dptr->bal);

printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");scanf("%d",&ch);

if(ch==1)

{b:

printf("Withdrawal Amount:");

scanf("%d",&bal);if((dptr->bal-bal)bal-=bal;


}else if(ch==2)

{do{

printf("\nYour Check No:");

dtemp->check=chk;printf("%d\n",dtemp->check);

chk++;

}while(chk>21);

c:printf("Withdrawal Amount:");

scanf("%d",&bal);

if((dptr->bal-bal)bal-=bal;


}getch();

}

void dedit(){

node *dptr;

int no,bal;if(dstart==NULL) {


getch();

return;


17/23

}

printf("Enter number to Edit : ");

scanf("%d",&no);dptr=dstart;



}

if(dptr!=NULL) {printf("\t\t\n-----------------------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\nOld First Name : %s", dptr->dfname);

printf("\nNew First Name : ");scanf("%s", dptr->dfname);

printf("\nOld Last Name : %s", dptr->dlname);

printf("\nNew Last Name : ");

scanf("%s", dptr->dlname);printf("\nPhone Number : %s", dptr->dtel);

printf("\nNew Phone Number : ");scanf("%s", dptr->dtel);

printf("\nOld Balance : %d", dptr->bal);

m:printf("\nNew Balance : ");

scanf("%d", &bal);

if(balbal=bal;

}

else {printf("No Matching Records Found .......\n");

}

getch();

}void ddel()

{

node *dptr,*dprev,*dtemp;int no;

char dyn='n';

if(dstart==NULL) {printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();

return;

}


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printf("Enter your account no to delete : ");

scanf("%d",&no);

dprev=dptr=dstart;while(dptr->num!=no){

dprev=dptr;


}

if(dptr!=NULL){printf("\nDeleting Record.....Confirm [y/n]: ");

dyn=getch();

printf("\n\n---------------------------------------------------------");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);printf("\nAccount No : %d\n",dptr->num);



printf("Phone Number : %s\n",dptr->dtel);printf("Balance : %d\n",dptr->bal);

printf("---------------------------------------------------------");if(dyn=='y') {

if (dptr==dstart) {

dtemp=dstart->dnext;free(dstart);

dstart=dtemp;

}

else {dtemp=dptr->dnext;

free(dptr);

dprev->dnext=dtemp;}

printf("\n\n1 Record Deleted....");

}else

printf("\n\nRecord not Deleted....");

}

else {printf("\nNo Matching Records Found .......");

}

getch();}

void ddisp()

{node *dptr;

if(dstart==NULL) {


getch();


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return;

}

clrscr();printf("\t\t------------------------------\n");

for(dptr=dstart; dptr!=NULL; dptr=dptr->dnext) {

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);

printf("\n\t\tLast name:%s", dptr->dlname);printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);

printf("\n\t\t------------------------------\n");

}getch();

}

void ddisp1()

{printf("\n\n");

printf("\t\t------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);

printf("\n\t\tYou are a SAVINGS account holder of our bank");

printf("\n\t\tAccount number: %d",dtemp->num);printf("\n\t\tFirst name: %s", dtemp->dfname);

printf("\n\t\tLast name:%s", dtemp->dlname);

printf("\n\t\tTelephone No.: %s", dtemp->dtel);

printf("\n\t\tYour Balance: %d",dtemp->bal);printf("\n\t\t------------------------------\n");

getch();

}void ddisp2()

{

printf("\n\n");printf("\t\t------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);

printf("\n\t\tYou are a CURRENT account holder of our bank");

printf("\n\t\tAccount number: %d",dtemp->num);printf("\n\t\tFirst name: %s", dtemp->dfname);

printf("\n\t\tLast name:%s", dtemp->dlname);

printf("\n\t\tTelephone No.: %s", dtemp->dtel);printf("\n\t\tYour Balance: %d",dtemp->bal);

chk=1;

printf("\n\t\tCheque nos:%d to %d",chk,chk+19);printf("\n\t\t------------------------------\n");

getch();

}

void main()


20/23

{

int dch;

dstart=(node *)malloc(sizeof(node));dstart=NULL;

do{

clrscr();dch=dmenu();

clrscr();

switch(dch) {case 1: dadd();

break;

case 2: dfind();

break;case 3: dedit();

break;

case 4: ddel();

break;case 5:

ddisp();break;

case 6:

deposit();break;

case 7:

withdrawal();

break;case 8:

dfind();

break;}

}while(dch!=9);

}


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TESTING

Testing is the major control measure used during software development. Its basicfunction is to detect errors in the software. During requirement analysis and design, the

output is a document that is usually textual and no executable. After the coding phase,

computer programs are available that can be executed for testing purpose. This impliesthat testing not only, has to uncover errors introduced during coding, but also errors

introduced during previous phase. Thus the goal of testing is to uncover the requirements,

design and coding errors in the programs. So after testing the outputs of my project are asfollows:

ONE TYPE OF OUTPUT:-

BANKING DATABASE================

1. Create a new account

2. Search customer details

3. Edit customer details

4. Delete a customer

5. Display all account holders

6. Deposit money

7. Withdrawal money8. Balance Enquiry

9. Exit

Enter your choice(1-9): 1

Which type of account you want to create?

1->Savings

2->Current

enter your choice : 1

Your Account No:5001

First name: AKSHI

Last name:SHARMA

Telephone No.: 2251678

Deposit Sum:400

INSUFFICIENT FUND-Need a minimum of Rs.500/- to open an account

Deposit Sum:1000


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------------------------------

HELLO SHARMA WELCOME TO OUR BANK

You are a SAVINGS account holder of our bankAccount number: 5001

First name: AKSHI

Last name:SHARMA

Telephone No.: 2251678

Your Balance: 1000

------------------------------

SECOND TYPE OF OUTPUT:-

BANKING DATABASE

================

1. Create a new account

2. Search customer details

3. Edit customer details

4. Delete a customer

5. Display all account holders

6. Deposit money

7. Withdrawal money

8. Balance Enquiry9. Exit

Enter your choice(1-9): 7

Enter the account No : 5001

-----------------------------------------------

HELLO SHARMA WELCOME TO OUR BANK

Account No:5001First Name : AKSHI

Last Name : SHARMA

Phone Number : 2251678

Your Balance : 1000

Withdrawal Amount:300

Your New balance:700


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FUTURE SCOPE OF THE PROJECT

Our project will be able to implement in future after making some changes and

modifications as we make our project at a very low level. So the modifications that can

be done in our project are:-

This project can be implement only at small bank branches. It cannot be used for large

scale bank purposes.

Date post:	03-Apr-2018
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Banking managgement system

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