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8/9/2019 Basic Background tutorial in Electricity
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Basic Background 001
Electricity
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24/06/2010BK 0013
The definition of the Ampere
The ampere is that constant current which, if
maintained in two straight parallel conductorsof infinite length, of negligible circular cross-
section, and placed 1 metre apart in vacuum,
would produce between these conductors a
force equal to 2 × 10 7 Newton per metre of length
See http://www.gor donengland.co.uk/conver sion/sidef.htm f or more def initions
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Did that definition help ?
For most of you, probably not
Unf ortunately despite its precision, the
def inition is not very helpf ul
We need to get a f eel f or electricity
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24/06/2010BK 0015
Basic Principles
Electricity is dynamic
It moves to do its work
We shall start
considering water
Here is a bucket containing 10 litres of
water
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A tank of water
Six 10 litre buckets of water f ill the tank completely
How much water is now in the tank ?
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24/06/2010BK 0017
Exercise 01
Please calculate the volume of water now
in the tank
Check your answer by clicking above
Move to the next slide when you are
ready
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24/06/2010BK 0018
Measuring Water Flow
At f ir st the water is static, it is not f lowing
Get a stopwatch ready Open the tap - what happens to the water ?
Time the water f lowing out of the tank
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24/06/2010BK 0019
Calculating the flow-rate
The water in the tank empties in 30 seconds
The volume of water held by the tank is 60 litres What is the f low-r ate ?
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24/06/2010BK 00110
Exercise 02
Please calculate the r ate that water now
leaves the tank Give your answer in litres per second
Check your answer by clicking above
Move to the next slide when you are ready
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24/06/2010BK 00111
Slowing down the flow of water
How could we halve the r ate of f low of water
f rom the tank ? An easy method would be to close the tap
partially
Write down any other methods that you think
could limit the f low of water f rom the tank
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24/06/2010BK 00112
Electricity, not water
The next f ew slides depict electrons as small
balls that we can put in a bucket We cannot do this in reality, but the
explanation holds true f or the f low of electricity
Please allow your thoughts to suspend belief
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24/06/2010BK 00113
Replacing water with electrons
Now we shall ref ill the tank
with electrons instead(take the water out f ir st!)
Use the bucket to f ill the tank
Turn the tap on and allowelectrons to f low through the piping
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24/06/2010BK 00114
A flow of electrons = current
Electrons f low analogously to water
We observe the f low of electrons, counting as they pass the tap
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24/06/2010BK 00115
Rate of electron flow = amp
As with the water we observe the number of
electrons f lowing past the tap We have counted a certain number of
electrons per second
Electricity f lows in electrons per second
We call this amperes ( amps )
Amps = number of electrons per second
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24/06/2010BK 00116
The Electron ± a charge carrier
An electron is a tiny unit of char ge
It carries a small amount of electricity The unit of electrical char ge is the coulomb
One electron carries 1.6 X 10-19 coulombs
6.25 X 1018
electrons make 1 coulomb That¶s 6 ¼ million million, million electrons
Rather a lot of electrons
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24/06/2010BK 00117
Amps, coulombs, electrons
1 ampere = a f low of 1 coulomb per second
1 ampere = 6.25 X 1018 electrons per second Amps are theref ore a measure of the f low of
electrons in a circuit per second
The amp is of ten seen in circuit diagr ams using
the letter I
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Review
Make sure that you under stand the principle of
the f low of electrons being ref erred to ascurrent
The f low of electrons in any circuit is
responsible f or the oper ation of that circuit
When you are ready, we will move on to the
volt
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24/06/2010BK 00119
The Volt
Electrons don¶t like moving around
A f orce is needed to move them The f orce is known as the volt
More volts make more amps (electrons) f lowaround a circuit per second
Think of a battery as an electron pump Twice the number of volts push twice the number of electrons per second
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Potential Difference ( p.d. )
Volts create a potential diff erence (voltage)
across a circuit or component Here the p.d. is 1.5 volts
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Exercise 03
Please calculate the current so we can
work out the number of electrons that the battery moves per second
Check your answer by clicking above
Move to the next slide when you are ready
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24/06/2010BK 00122
625,000,000,000,000,000 electrons
The volts in the battery push a huge number of
electrons around our circuit per second That number is so high it becomes unwieldy
and diff icult to work with
Theref ore we measure the f low of electrons in
amps, not electrons per second
A f low of electrons is known as current
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Electrons do the work
A bulb lights because electrons f low through it
Volts push the electrons Manufacturer s of ten specif y current i.e. the number of electrons per second the device requires
We need to choose the volts caref ully to avoidpushing too many electrons into our device at once
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24/06/2010BK 00124
Voltage summary
Volts push electrons around a circuit
More volts means more current (amps) Be sure to under stand this bef ore moving on
When you are ready, we will move on to
Resistance
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Resistance
Hit the pipe with a hammer, it narrows
The r ate of f low of water reduces
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24/06/2010BK 00126
Slowing the flow of water
Why does the water¶s f low r ate reduce?
We have made it diff icult f or the water to f low Narrowing a water pipe is analogous to
resistance in electrical circuits
We have created resistance to the f low of
water
We need to compare this to electricity
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24/06/2010BK 00127
Electrical Resistance
Electrons f low through metal easily
Carbon is har der f or electrons to tr avel through Carbon f or ms basis of most resistor s
Unit of resistance is the ohm ;
Amps = volts/ resistance
How can we r aise the amps ?
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24/06/2010BK 00128
Operating an LED
Requires around 35 m A
An LED has little resistance Put an LED across 12v battery - disaster
We must regulate the f low of electrons
Use a resistor in series with the LED Resistor will make lif e diff icult f or electrons
f lowing in the circuit and reduce the f low r ate
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24/06/2010BK 00129
Calculate the Resistance
Use the Ohms Triangle to calculate resistance
Use a f inger to cover the R symbol Resistance = V/I
Resistance = volts/ amps OR
;= V/I
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24/06/2010BK 00130
Exercise 04
Calculate the required resistor value
12 volts is available f rom the battery 35 milliamps is needed in the LED
Use Ohm¶s Triangle if you cannot remember
the f or mula f or resistance
Check your answer by clicking above
Move to the next slide when you are ready
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24/06/2010BK 00131
Conclusion
Amps measures number of electrons per
second that f low in a circuit Each electron carries char ge - coulombs
Coulombs per second = amps
Electrons per second = amps
Volts pump the electrons
Ohms resist the movement of electrons
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The End
Thank YouThank You
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Answer 001
6 X 10 = 60 litres of water
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24/06/2010BK 00134
Answer 002
60 litres of water f low through the
tap in 30 seconds
The r ate of f low of water is
60 litres/30 seconds
= 2 litres per second
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24/06/2010BK 00135
Exercise 03
Current = V/I
= 1.5 / 15 = 0.1 amp Remember that 1 amp is 6.25 x 1018 electrons
The number of electrons f lowing is
0.1 x 6.25 x 1018
= 6.25 x 1017
per second OR 625,000,000,000,000,000 electrons per second
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24/06/2010BK 00136
Exercise 04
12 volts is divided by 35 milliamps
12/ 35 x 10-3 = 342.86 ohms (approximately) Thus we need a resistor of 343 ; (or more) to
limit the f low of electrons in the circuit
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References
http://www.bsimotor s.com/resistor .jpg