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1/52

P1203

SEAT No. :

7/23/2019 BBA(2013 Pattern)

2/52

P1204

SEAT No. :

7/23/2019 BBA(2013 Pattern)

3/52

P1205

SEAT No. :

7/23/2019 BBA(2013 Pattern)

4/52

7/23/2019 BBA(2013 Pattern)

5/52

7/23/2019 BBA(2013 Pattern)

6/52

7/23/2019 BBA(2013 Pattern)

7/52

7/23/2019 BBA(2013 Pattern)

8/52

P1206

SEAT No. :

7/23/2019 BBA(2013 Pattern)

9/52

P1207

SEAT No. :

8 1 2 4 1 5A= , B= , C

0 6 3 1 3 1

=

7/23/2019 BBA(2013 Pattern)

10/52

1 0 2 0 -1 2

A= , B= , C=

0 1 1 1 3 1

1 6 1

A= 2 3 3

3 3 2

1 2

1 2

1 2

2 40

2 3 60

and

, 0

x x

x x

x x

+