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Home > Documents > Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2...

Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2...

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What do you think? Distance Point Line Plane Segment Ray Midpoint Bisector Vertex Angle Perpendicular Congruent
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Bellringer! Solve the following equations 1. P – 1 = 5P + 3P – 8 2. -8 = -(y + 4) 3. (2 + 6 x 2 + 2 – 4) x 2 = ? 4. (5 + 16) ÷ 7 – 2 = ?
Transcript
Page 1: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Bellringer!

• Solve the following equations1. P – 1 = 5P + 3P – 82. -8 = -(y + 4)3. (2 + 6 x 2 + 2 – 4) x 2 = ?4. (5 + 16) ÷ 7 – 2 = ?

Page 2: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Chapter 1 Vocab and overview

Page 3: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

What do you think?• Distance

• Point

• Line

• Plane

• Segment

• Ray

• Midpoint

• Bisector

• Vertex

• Angle

• Perpendicular

• Congruent

Page 4: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Definitions

• Point- indicates location has no size • Line- straight path that goes on and on

forever in both directions. • Plane- flat surface with no end and no

thickness• Segment- part of a line with two end points• Ray- part of a line with one end point that

never ends on the other side

Page 5: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Vocabulary

• Coordinate• Distance• Congruent segments- segments of exactly

the same length• Midpoint- point in the middle of a segment• Segment bisector- point, line, ray, or segment

dividing a segment into two even pieces.

Page 6: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Lets see

Page 7: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

1. Name a point in the figure.2. Give two names for a line in the figure.3. Give two names for the plane in the figure.

Bell Ringer Page 2 top 4 lines

Page 8: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Intersection- set of all points two figures (lines, planes, shapes) share

Page 9: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Intersection- set of all points two figures (lines, planes, shapes) share

Page 10: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

WE DO• Name a

1. Point

2. Line

3. Plane

4. Ray

5. Segment

6. Intersection

Page 11: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Segment Addition Postulate

• If A B and C are colinear then AB + BC = AC

Page 12: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Lets Try it

Page 13: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

WE DO!!1. If AD = 12 and AC = 4y

– 36, Find the value of y. Then find AC and DC

2. IF ED = a + 4 and DB = 3a – 8, find ED, DB, and EB.

Page 14: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Vocabulary• Angle

• Side• Vertex

• Acute

• Right

• Obtuse

• Straight

Page 15: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Parts of an Angle

Page 16: Bellringer! Solve the following equations 1.P – 1 = 5P + 3P – 8 2.-8 = -(y + 4) 3.(2 + 6 x 2 + 2 – 4) x 2 = ? 4.(5 + 16) ÷ 7 – 2 = ?

Types of Angles


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