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ANSWER FOR QUESTION 1
1 (a) (i) [KB0601 - Observation]
Score Criteria
3 Able to state any two observations correctly according to the criteria:
o Sample
o Time taken
o Become colourless
Sample answers:
1. Time taken for methylene blue to become colourless for sample P is 10 minutes.
2. Time taken for methylene blue to become colourless for sample R is 42 minutes
3. Time taken for methylene blue to become colourless for sample Q is 23 minutes
4. Time taken for sample P is 10 minutes that is shorter than time taken for sample R
that is 42 minutes to become colourless
2 Able to state any one observation correctly.
orAble to state any two incomplete observations ( any 2 criteria)
Sample answers:
1. Time taken for methylene blue to become colourless for sample P is
shorter
2. Time taken for methylene blue to become colourless for sample R that is longer
3. Time taken for sample P is shorter than time taken for sample R
4. Time taken for sample P is less 13 minutes from sample Q to become colourless
5. Time taken for sample P/Q/R is 10 minutes/ 23 minutes/42 minutes
1 Able to state any one idea of observation.(any 1criteria)Sample answers:
1. Different sample has different time taken
2. Time taken varied in this experiment
3. Sample P,Q and R has different time taken
4. Methylene blue become colourless
5.
0 Not able to response orwrong response.
1 (a) (ii) [KB0604 - Making inferences]
Score Criteria3 Able to make one logical inference for each observationbased on the criteria
o Sample
o Oxygen concentration
o Duration of time for methylene blue to become colourless
Sample answers:
1. In sample P, oxygen concentration is low, the methylene blue become colourless
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very fast/ less time taken
2. Oxygen concentration in sample R is high, the methylene blue become
colourless slow/ longer time taken
3. Oxygen concentration in sample P is lower than oxygen concentration in sample R,
the time taken for methylene blue to become colourless is shorter.
2 Able to make one logical inference for any one observation.
orAble to make one logical and incomplete inference base on 2 criteria for each
observation.
Sample answer:
1. In sample P, oxygen concentration is low
2. Oxygen concentration in sample R is high
3. When oxygen concentration is low, the methylene blue become colourless very
fast/ take a shorter time4. When oxygen concentration is high, the methylene blue become colourless
very slow/ take a longer time
1 Able to make an idea of inference with one criterion.
Sample answers
1. Oxygen concentration affect the time for the methylene blue to become
colourless
2. different sample has different oxygen concentration3. the longer the time the less oxygen in the water
0 Inference not corresponding to the observation or Not able to response or wrong
response.
(b)(i) [KB0603 Measuring Using Number]
Score Criteria
3 Able to record all the time taken with unit in the boxes given accurately
Sample answers
Sample time
P 10 minutes
Q 23 minutes
R 42 minutes
2 Able to record two reading with unit accurately
1 Able to record one reading with unit accurately
Able to record all the time taken without unit
0 Not able to response orwrong response.
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(b)(ii) [KB0606 Communicating]
Score Criteria
3 Able to tabulate a table and fill in data accurately base on three criteria:
o Table draw with labeled column.
o Sample
o Time taken with unit.
Sample answers :
Sample Time taken ( minutes)
P 10
Q 23
R 42
2 Able to tabulate a table base on two criteria
1 Able to Able to tabulate a table base on one criterion0 Not able to response orwrong response.
(b) (iii) [KB0607 Interprating Data]
Scor
e
Criteria
3 Able to state clearly and accurately the relationship between:
o time taken
o oxygen content
o BOD level
Sample answer:
1. The shorter time taken for methylene blue to become colourless, less oxygen inthe water and BOD level is high.
2 Able to state clearly but less accurate the relationship base on 2 criteria:
Sample answer:
1. The shorter time taken for methylene blue to become colourless, pollution level
is high.
2. When less oxygen in the water and the pollution level of the water is high.3. The shorter time taken for methylene blue to become colourless, less oxygen inthe water.
1 Able to state the idea of the relationship base on 1 criterion
Sample answer
1. The shorter time taken the more polluted the water
2. Oxygen level shows that the water is polluted
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0 Not able to response orwrong response.
(c) [KB061001 Controling Variables]
Variables How the variables are operated
Manipulated:
Water sample Water sample is collected from three different locations.
Responding variable
Time taken
Time taken for methylene blue to become colourless is recorded
by a stopwatch.
Fixed variable
Metlhylene blueconcentration / volume/
volume of water sample
o.1% of Methylene blue is used for all experiments/ 1 ml volume/
200 ml of water sample.
(d) [KB0611- Making Hypothesis]
Scor
e
Criteria
3 Able to state a hypothesis to show a relationship between the manipulated variable andresponding variable and the hypothesis can be validated, base on 3 criteria:
manipulated variable
responding variable
relationship
Sample answer :
1. The most polluted water has shortest time for methylene blue to becomecolourless.
2. Sample water P is most polluted has shortest time for methylene blue to
become colourless.
3. Sample water R is less polluted has longest time for methylene blue to becomecolourless,
2 Able to state less accurate hypothesis to show a relationship between manipulated
variable and responding variable base on 2 criteria.
Sample answer
1. The most polluted water is sample water P
2. Sample water R is least polluted3. The shorter time taken, the less oxygen in the water
4. The longer time taken, the more oxygen in the water
5. The different water sample has different time taken for methylene blue to
become colourless
1 Able to state idea of hypothesis to show a relationship between manipulated variable
and responding variable base on 1 criterion.
Sample answer
1. Time taken depends on oxygen level
2. Oxygen level affect the time taken for methylene blue to become colourless3. The less oxygen in the water, the more polluted the water.
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4. The more oxygen in the water, the less polluted the water
0 Not able to response orwrong response.
(e) [KB0608 Space and Time Relationship]
Score Criteria
3 Able to state clearly and accurately the relationship between increasing the time and
the level of pollution in the water base on criteria:
o Time taken
o Pollution level
o relationship
Sample answer:
1. The longer the time taken for methylene blue to become colourless the less
polluted water is been used.2. The shorter the time taken for methylene blue to become colourless the more
polluted water is been used.
2 Able to state clearly but less accurate the relationship between increasing the air
movement speed with the rate of transpiration base on 2 criteria
Sample answer:
1. The time taken for methylene blue to become colourless the shows the
pollution level
2. Water pollution affected the time taken methylene blue to become colourless
1 Able to state the idea of the relationship base on 1 criteriaSample answer:
1. Different time taken is recorded from different types of water used
2. Level of pollution can be detected by different time taken
0 Not able to response orwrong response.
(f) [KB0609 [Define operationally]
Score Criteria
3 Able to explain BOD base on experiment correctly according to the criteria:
o Amount of oxygen in the water sample
o used by microorganisms
o shown by time taken
Sample answer:
1. BOD is amount of oxygen in the water sample that used by microorganisms and canbe shown by time taken of methylene blue to become colourless.
2 Able to state BOD base on experiment:
Sample answer:
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1. BOD is amount of oxygen in the water and can be shown by time taken by methyleneblue to become colourless
1 Able to state the idea of BOD or the theoretical definition of BOD
1. Biological Oxygen Demand (BOD) is a measure of the oxygen used by
microorganisms to decompose waste2. BOD is amount of oxygen in the water
0 Not able to response orwrong response.
(g) [KB0605 Predicting]
by using water sample from chicken farm area
Score Criteria
3 Able to predict the result accurately.
o Expected time
o Compare to which
o Reason
Sample answer:
1. The time taken for methylene blue to become colourless is 5 minutes, less than watersample P, because chicken farm water can be contaminated with chicken faeces/ or any
other answer.
2 Able to predict the result less accurate:
Sample answer:
1. The time taken for methylene blue to become colourless is 5 minutes, because chickenfarm water can be contaminated with chicken faeces
2. The time taken for methylene blue to become colourless less than water sample P,because chicken farm water can be contaminated with chicken faeces
3. The time taken for methylene blue to become colourless is 5 minutes, less than watersample P.
1 Able to give idea of the result
1. time taken is shorter
2. water from this area is polluted
0 Not able to response orwrong response.
(i) [KB0602 Classifying]
Score Criteria
3 Able to arrange the 3 level of polluted water
Sample answer:
Types of water PollutedP Most
Q Moderate
R Least Most polluted least polluted
P Q R
2 Able to arrange the 2 level of polluted water
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1 Able to arrange the 1 level of polluted water
0 Not able to response orwrong response.
ANSWER FOR QUESTION 2
Problem statement
Score Criteria
3 Able to state the problem statement of the experiment correctly that include
criteria:
C 1: Manipulate variables
C 2: Responding variables
C 3: Relation in question form and question symbol [?]
Example :
Problem statement:
1. What is the population size / percentage coverage / density / frequency of
Mimosa pudica andImperata cylindrica in the school field?
2 Does the type of plant species affects the population size / percentage
coverage / density / frequency of the plants?
3. Which type of the plant species/ species Mimosa pudica orImperata
cylindrica has the highest percentage coverage/ population size?
2 Able to state the problem statement of the experiment with two criteria;
Example:
Problem statement:
1. Species Mimosa pudica andImperata cylindrica have different population
size/ percentage coverage/ density.
2. What is the percentage coverage/ population size / density of plants?
1 Tick Able to state the of problem statement with one criteria.
Example:
Problem statement:
1. Which plant is dominant?
0 No response or wrong response.
Aim
Score Criteria
Tick To estimate/ determine / study the population size / percentage coverage /
density / frequency ofMimosa pudica andImperata cylindrica in the school
field using the quadrat sampling technique.
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Hypothesis
Score Criteria
3 Able to state the hypothesis correctly according to the criteria:
C 1: Manipulate variables
C 2: Responding variables
C 3: Relationship of the variables
Example
1. The population size / percentage coverage / density / frequency of
species Mimosa pudica plant is higher than species Imperata cylindrica
in the school field.
2. Different plant species have different population size / percentage
coverage / density / frequency.
3. Plant species Mimosa pudica is more dominant than speciesImperata
cylindrica in this habitat.
2 Able to state the hypothesis with two criteria
Example:
1. Plant species affects population size / percentage coverage / density /frequency.
2. Species Mimosa pudica /Imperata cylindrica has the highest
population size / percentage coverage/ density / frequency.
3. Species Mimosa pudica is more dominant in the habitat.
1 Tick Able to state the idea of the hypothesis.0 No response or wrong response.
Variables
Score Criteria
Tick Able to state the three variables correctly
Example:
Manipulated variable:
Type of plant species/ species Mimosa pudica andImperata cylindrica / twoexample of plant species.
Responding variable:
Population size / percentage coverage / density / frequency of plants
Controlled variable : Quadrat size, school field.
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Materials and apparatus
Score Criteria
3
Tick
Able to state all functional materials/ 2 materials and 4 apparatus for the
experiment .
Materials : Plant species Mimosa pudica andImperata cylindrica B.
Apparatus : Plastic quadrat, marker pen, A4 Paper, graph paper.
2 Able to state 1 material and 2 apparatus for the experiment
1 Able to state 1 material and 1 apparatus for the experiment.
0 No response or wrong response
Bonus marks:technique and data = 2 marks
Technique :
Score Criteria
Tick
Bonus1
Able to state the action on responding variable with an apparatus.
Example:
Measure and record the area of each type of species using a quadrat 1m x 1m// Calculate the percentage coverage of plant // species Mimosa pudica and
Imperata cylindrica using the formula:
Total area covered by the species X 100%
Number of quadrats X area of one quadrat
// Calculate the density of plant species using the formula:Total number of organisms in all quadratsNumber of quadrats X area of one quadrat
// Calculate the frequency of plant species using the formula:No. of quadrat containing the species X 100%
Total number of quadrats
Procedure (Refer to procedure in example)
Score Criteria
3 Able to state fiveprocedures P1,P2,P3,P4 & P5 correctly:
P1 : How To Set Up The Apparatus
P2 : How To Make Constant The Control Variable
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P3 : How To Manipulate The Manipulated Variable
P4: How To Record The Responding Variable
P5 : Precaution
2 Able to state three of any procedures correctly
1 Tick Able to state two of any procedures correctly
0 No response or wrong response
Data
Score Criteria
Tick
Bonus
1
Able to tabulate the correct table with units
Example:
Plant
species
Number/ area of plant species
in the quadrat
1 2 3 4 5 6 7 8 9 1
0
Total
number/areaof plant
species(m2 )
Density/
percentagecoverage
area (%)
M.pudica
I.cylindrica
Conclusion
Score Criteria
Tick Able to rewrite the hypothesis correctly.
Example:and
1. The percentage coverage// population size of species Mimosa pudica
plant is higher than speciesImperata cylindrica in the school field? or
2. Different plant species have different percentage coverage// population
size . or
3. Plant Mimosa pudica is more dominant thanImperata cylindrica in this
habitat.Hypothesis is accepted.
Planning the experiment
Score Criteria
3 Able to plan the experiment based on 8-9 of the following criteria :
Statement of identified problem
Objective of study
Variables
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Statement of hypothesis
List of materials and apparatus
Technique used
Experimental procedures
Presentation of data
Conclusion
2 Able to plan the experiment based on 4-7 of the criteria :
1 Able to plan the experiment based on2-3 of the criteria :
0 No response or wrong response
Example of Procedure.
1 School field was chosen as the field study (P1)
2 Quadrats of size 1m x 1m was used. (P2)
3 Two plants species Mimosa pudica and Imperata cylindrica was identified (P3)
4 The quadrats were thrown at random in the school field (P1)
5 The area of (coverage) each plant species was counted// the number of
individual plant species in each quadrat was counted.
(P4)
6 If more than half of the squares in the quadrat are covered, the area of plant
species will be counted. The area is not counted if only less than half is
covered.
(P5)
7 Steps 5 to 7 was repeated for nine quadrats (P1)
8 The area covered by plant species / species Mimosa pudica and speciesImperata cylindrica / number of individual plant species studied in each
quadrat were recorded and tabulated in a table.
(P4)
9 The percentage coverage / density / frequency of plant species / speciesMimosa pudica and species Imperata cylindrica were calculated by using
this formula:
(P4)
Percentage coverage of plant species :
= Total area covered plant species in all quadrats X 100%
Total number of quadrats X area of a quadrat
// Frequency of species = Number of quadrat containing plant species X 100%Total number of quadrats
// Density of plant species = total number of individual species in all quadrats
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Total number of quadrats X area of a quadrat
PERATURAN PERMARKAHAN TAMAT
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