bombas usp.docx

7/24/2019 bombas usp.docx

1/20

Ubicacin 1. (Alado del quiosco)

Se encontraron 3 bombas:

Bomba 1:


2/20

Maraca: hidrostal.

Modelo: A1E-0.8M.

El caudal dela bomba es de 2.4 l/s ane!o 1"

Calculo del NPSH.

(P+ZY)PV

PO=1X105pa

H2

O=9810N/m3

z=1.20m

Determino PV (Psaturacin).

TH0

o=25.7 (de latabla termodinamica)

# $ %&a"

2' 3.1()1

2'.* &+

4.24613.169125.7253025

=PV3.1691


3/20

30 4.24(1 PV=3.3198kpa

Prdidas !ara material de acero "al#ani$ado.

Perdidas !rimarias.

Lr=0.606m

Dr=0.02545.06x 104

m2

Velocidad:

v=

!=

2.4X103

m3/"

5.06x104

m2

V=4.74m /"

%e&nolds:

=V X D

# =

4.74m

" x0.0254 m

1x106

m2

"

=120396=1.2x 105$

%u"osidad relati#a.

e

d=

0.15x103

m

0.0254m =5.90x103 0.0059

%=0.029

'cuacin de darc& eisbac*.

&%=% x l xV

2

2x ' x D

0.029x 0.606m x 4.74

2

m2

/"2

2x 9.81m"2x 0.0254

&%=0.792m


4/20

Perdidas secundaria.

+ codos de 900

k=3020.023=1.38

&L=(V2

2' =1.38

4.742 m2/"2

29.81m/"2

&L=1.58m

&T2=&%+&L=2.37 m

Prdidas !ara material de !#c.

&L=(V2

2' =

20.554.742 m2/ "2

29.81m/ "2

&L=1.25m

&T2=&%+&L=2.41m

=&T1+&T2

=4.78m

Perdidas !rimaria.=2.4x 103 m3/ "

Dr=0.0254

V=4.74


5/20

=2.451m

%u"osidad relati#a

e

d

=0.00015x10

3

0.0254

=5.90x105

%=0.0105

'cuacin de dara& erbac*.

&%=% x L x V

2

2x ' x D=

0.0105x2.451m x 4.742

m2/"2

2x9.81m

"2x 0.0254m

&%=1.16

Calculo NPSH

(P0+ZY)Pv

9810N/m3+(1.20m )(4.78m)

1x105Pa

9810N/m3

(10.20m1.20m4.78m )0.338m

NP)H=3.88m


6/20

Bomba +:

Maraca: hidrostal.

Modelo: A1E-1.4M.

El caudal dela bomba es de 2.' l/s ane!o2"

Calculo del NPSH.

(P +ZY)PV

PV=3.3198 kpa

H2

O=9810N/m3

z=1.12m

Determino PV (Psaturacin).

# $ %&a"

2' 3.1()1


7/20

2'.* &+

4.24613.169125.7253025

=PV3.1691

30 4.24(1 PV=3.3198

kpa


Perdidas !rimarias.

Lr=0.52m

Dr=0.02545.06x 104

m2

Velocidad:

v=

!=

2.5X103

m3 /"

5.06x104

m2

V=4.94m /"

%e&nolds:

=V X D

#

=4.94

m

" x0.0254 m

1x106

m2

/"

=120376=1.2x 105

%u"osidad relati#a.

e

b=

0.15x 103

m

0.0254 m =5.90x103 0.0059

%=0.029


&%=% x l xV

2

2x ' x D

0.029x 0.52m x 4.942

m2

/"2

2x9.81m

"2x 0.0254


8/20

&%=0.738m


1 codos de 900

k=0.69

&L=(V2

2' =

0.694.942 m2/"2

29.81m /"2

&L=0.858m

&T2=&%+&L=1.60m

Perdidas !rimaria.

Dr=0.0254

V=4.94

=2.50m

%u"osidad relati#a

eb=0.00015

x10

3

0.0254 =5.90x 105

%=0.0105


&%=% x L x V

2

2x ' x D=

0.0105x2.50m x 4.942

m2

/ "2

2x9.81m

"2x0.0254m

&%=1.285m

Calculo NPSH


9/20

(P0+ZY)Pv

(10.20m1.12m2.88m)0.338m

NP)H=5.86 m

Bomba ,:

Maraca: hidrostal.

Modelo: A1E-1.4M.

El caudal dela bomba es de2.' l/s ane!o 2"

Calculo del NPSH.


10/20

(P+ZY)PV

PV=3.3198kpa

H2

O=9810N/m3

z=1.05m

Determino PV (P saturacin).

TH0

o=25.7 (de latabla termodinamica)

# $ %&a"

2' 3.1()1

2'.* &+

4.24613.169125.7253025

=PV3.1691

30 4.24(1 PV=3.3198 kpa


Perdidas !rimarias.

Lr=0.33m

Dr=0.02545.06x 104

m2

Velocidad:

v=

!=2.5X10

3m

3 /"5.06x10

4 m2

V=4.94m /"

%e&nolds:


11/20

=V X D

# =

4.94m

" x0.0254 m

1x106

m2/"

=120376=1.2x 105

%u"osidad relati#a.

e

b=

0.15x 103

m

0.0254 m =5.90x103 0.0059

%=0.029


&%= % x l xV2

2x ' x D 0.029x 0.33m x 4.94

2

m

2

/"2

2x 9.81m

"2x 0.0254

&%=0.468m


1 codos de 900

k=0.69

&L=(V2

2' =

0.694.9 42 m2/"2

29.81m /"2

&L=0.85m

&T1=&%+&L=1.32m

Prdidas !ara material de !#c.

Perdidas !rimaria.

Dr=0.0254

V=4.94


12/20

=2.50m

%u"osidad relati#a

e

b

=0.00015x 10

3

0.0254

=5.90x 105

%=0.0105


&%=% x L x V

2

2x ' x D=

0.0105x2.50m x4.942

m2/ "2

2x9.81m

"2x0.0254m

&%=1.285m

Perdidas secundarias.

2 codos de 900(pvc) ,

Calculo NPSH

(P0+ZY)Pv

(10.20m1.05m1.43m)0.338m

NP)H=7.38m

Ubicacin N-+


13/20

Bomba 1Marca:$edrollo

Modelo:m'1

El caudal de la bomba es ' l/s ane!o 1"

Calculo de NPSH:

(P0+ZY)Pv

Datos "enerales:

P0=1*105Pa

a'+a=9810N/m3

, -04' m


14/20

Determinando

PV=)at+racion

Ta'+a=25.6 , tiliando tabla termodinmica"

# $ %&a"

2' 3.1()1

2'.( &+

4.24613.169125.6253025

=PV3.1691

30 4.24(1 PV=3.2983 kpa

Prdidas !ara materiales de aceros "al#ani$ados

Perdidas Primarias:

LT=0.285m

Dr=0.0381

!=1.14x 103


15/20

Velocidad:

V=

!=5x10

3m

3

"

1.14x103

m2

V=4.38m /"

%e&nolds:

-e=VD

. =

4.38m "0.0381m

1x 106

m2 "

-e=1668781.6x105

%u"osidad %elati#a:

e

D=

0.15x103

m

0.0381m =3.93x 103=0.0039

%=0.028

'cuacin de Darc& /eisbac*:

&%=%LV2

2 'D=

0.0280.285m4.38m2"2

29.81m "20.0381m

&%=0.204 m

Perdidas Secundarias:

Se encuentra 1 codo )0

k=0.69

&L=(V2

2' =

0.694.382m2 /"2

2

9.81

m /"

2

&L=0.674m

&T1=&%+&L=0.878m


16/20

Prdidas !ara materiales de PVC

Perdidas !rimarias:

Datos:

Dr=0.03811.14x103

m2

5 , 4.38 m /"

LT=0.85m

%u"osidad %elati#a:

e

D=

0.0015x103

0.0381=3.93x105=0.0000393

%=0.01

'cuacin de Darc&:

&%=%LV2

2 'D=

0.010.85m4.382 m2"2

29.81m "20.0381

& %=0.218m

Perdidas Secundarias:

k=0.55

&L=(V2

2' =

0.554.382m2/"2

29.81m /"2


17/20

&L=0.53m

&T2=&%+&L=0.748m

Calculo NPSH:

(P0+ZY)Pv

(10.20m1.45m1.6m )0.336m

NP)H=7.79m

Bomba +:

Marca:idrostal

Modelo:A1E-0.(M

El caudal de la bomba es 2.2 l/s Ane!o 2"

Calculo del NPSH:

(P0 +ZY)Pv

Z=0.55

PV=3.2983(pa


18/20

Perdida !ara materiales de acero "al#ani$ado

Perdidas !rimarias:

Datos:

LT=0.290m

Dr=0.02545.06x 104

m2

Velocidad:

V=

!=

2.2x 103

m3

"

5.06x104

m2=4.34m /"

%e&nolds:

-e=

VD

. =

4.34 m"0.0254m

1x106 m2"

-e=1102361.1x 105

%u"osidad %elati#a:


19/20

e

D=5.90x 103=0.00590

%=0.029

'cuacin de Darc&:

&%=%LV2

2 'D=

0.0290.290m4.3 42 m2"2

29.81m "20.0254

& %=0.317m

Perdidas Secundarias

&L=(V2

2' =

0.694.342 m2/"2

29.81m /"2

&L=0.662m

&T1=&%+&L=0.979m

=&T1+&T2=1.55m

Perdida !ara materiales de PVC

Perdidas Primarias:

Dr=0.0254

Vr=4.34

LT=1.45

%u"osidad %elati#a:e

D=

0.0015x103

0.0254=0.000059

%=0.0105

'cuacin de Darc& 0 /eisbac*


20/20

& %=%LV2

2 'D=

0.01051.45m4.342 m2"2

29.81m"20.0254m

&%=0.575m

Calculo de NPSH

(P0+ZY)Pv

(10.20m0.55m1.55m )0.336m

NP)H=7.76 m

Date post:	20-Feb-2018
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