of 23
7/29/2019 Business Statistics 4
1/23
Discrete Probability Distributions
Chapter-4
7/29/2019 Business Statistics 4
2/23
Probability Distribution
Probabilities tell you???
how likely certain events.
What probability does not tell.
overall impact of these events
and, what it means to you?
In this chapter we will see how to use
probability to predict long-term outcomes and
also measure the certainty of these predictions
7/29/2019 Business Statistics 4
3/23
Probability Distribution
Random Variables
Discrete Probability Distributions
Expected value and Variance Binomial Distribution
Poisson Distribution
Hypergeometric Distribution
7/29/2019 Business Statistics 4
4/23
Random Variables
A random variable is a numerical description of theoutcome of an experiment.
A discrete random variable may assume either a
finite number of values or an infinite sequence ofvalues.
A continuous random variable may assume any
numerical value in an interval or collection ofintervals. Eg:- Time, weight, distance, and temperaturecan be described by continuous random variables.
Which is a variable that
can take a set of values,
where each value is
associated with a
specific probability
7/29/2019 Business Statistics 4
5/23
Example: XYZ MartNumber of customers
visiting the store
No. of days this level was
Observed
Probability that Random
Variable will take on this
value
101 5 0.05
102 7 0.07
1038 0.08
104 9 0.09
105 10 0.1
106 12 0.12
107 12 0.12
108 11 0.11
109 10 0.1
110 9 0.09
111 7 0.08
Total 100 1.00
7/29/2019 Business Statistics 4
6/23
Example: XYZ Mart
0
0.02
0.04
0.06
0.08
0.1
0.12
0.14
101 102 103 104 105 106 107 108 109 110 111
Probability
Probability
7/29/2019 Business Statistics 4
7/23
Random Variables
Question Random Variable x Type
Family
size
x = Number of dependents
reported on tax return
Discrete
Distance from
home to store
x = Distance in miles from
home to the store site
Continuous
Own dogor cat
x = 1 if own no pet;= 2 if own dog(s) only;
= 3 if own cat(s) only;
= 4 if own dog(s) and cat(s)
Discrete
7/29/2019 Business Statistics 4
8/23
Discrete Probability Distribution
The probability distribution for a random variabledescribes how probabilities are distributed overthe values of the random variable.
We can describe a discrete probability distributionwith a table, graph, or equation.
7/29/2019 Business Statistics 4
9/23
Discrete Probability Distribution
The probability distribution is defined by aprobability function, denoted byf(x), which providesthe probability for each value of the random variable.
The required conditions for a discrete probabilityfunction are:
f(x) > 0
f(x) = 1
7/29/2019 Business Statistics 4
10/23
Discrete Probability Distribution
A tabular representation of the probability distribution for TV sale
Number
Units Sold of Days0 80
1 50
2 40
3 104 20
200
x f(x)0 .40
1 .25
2 .20
3 .054 .10
1.00
80/200
7/29/2019 Business Statistics 4
11/23
Discrete Probability Distribution
.10
.20
.30
.40
.50
0 1 2 3 4Values of Random Variable x (TV sales)
Probabi
lity
Graphical Representation of Probability Distribution
7/29/2019 Business Statistics 4
12/23
Discrete Uniform Probability
Distribution
The discrete uniform probability distribution is thesimplest example of a discrete probabilitydistribution given by a formula.
The discrete uniform probability function is
f(x) = 1/n
where:n = the number of values the random
variable may assume
the values of therandom variable
are equally likely
7/29/2019 Business Statistics 4
13/23
Expected Value
The expected value, or mean, of a random variableis a measure of its central location.
The variance summarizes the variability in thevalues of a random variable.
The standard deviation, , is defined as the positivesquare root of the variance.
Var(x) = 2 = (x - )2f(x)
E(x) = = xf(x)
7/29/2019 Business Statistics 4
14/23
Expected Value
expected number ofTVs sold in a day
x f(x) xf(x)
0 .40 .00
1 .25 .25
2 .20 .403 .05 .15
4 .10 .40
E(x) = 1.20
7/29/2019 Business Statistics 4
15/23
Expected Value
Variance and Standard Deviation
0
12
3
4
-1.2
-0.20.8
1.8
2.8
1.44
0.040.64
3.24
7.84
.40
.25
.20
.05
.10
.576
.010
.128
.162
.784
x - (x - )2 f(x) (x - )2f(x)
Variance of daily sales = 2 = 1.660
x
Standard deviation of daily sales = 1.2884 TVs
7/29/2019 Business Statistics 4
16/23
Binomial Distribution
It is associated with a multi-step experiment
Four Properties of a Binomial Experiment
3. The probability of a success, denoted byp, doesnot change from trial to trial.
4. The trials are independent.
2. Two outcomes, success and failure, are possibleon each trial.
1. The experiment consists of a sequence of nidentical trials.
7/29/2019 Business Statistics 4
17/23
Binomial Distribution
where:
f(x) = the probability of x successes in n trials
n = the number of trialsp = the probability of success on any one trial
( )!( ) (1 )!( )!
x n xnf x p px n x
Binomial Probability Function
Could x be a Continuous Random Variable?
7/29/2019 Business Statistics 4
18/23
Binomial Distribution
Example:-
Evans is concerned about a low retention rate foremployees. In recent years, management has seen aturnover of 10% of the hourly employees annually.Thus, for any hourly employee chosen at random,
management estimates a probability of 0.1 that theperson will not be with the company next year.
7/29/2019 Business Statistics 4
19/23
Binomial Distribution
Using the Binomial Probability Function
Choosing 3 hourly employees at random, what isthe probability that 1 of them will leave the companythis year?
f xn
x n xp px n x( )
!
!( )!( )
( )
1
1 23!(1) (0.1) (0.9) 3(.1)(.81) .2431!(3 1)!
f
Let: p = .10, n = 3, x = 1
7/29/2019 Business Statistics 4
20/23
DecisionTree
Binomial Distribution
1st Worker 2nd Worker 3rd Worker x Prob.
Leaves
(.1)
Stays(.9)
3
2
0
2
2
Leaves (.1)
Leaves (.1)
S (.9)
Stays (.9)
Stays (.9)
S (.9)
S (.9)
S (.9)
L (.1)
L (.1)
L (.1)
L (.1) .0010
.0090
.0090
.7290
.0090
1
1
.0810
.0810
.0810
1
7/29/2019 Business Statistics 4
21/23
Binomial Distribution
(1 )np p
E(x) = = np
Var(x) = 2 = np(1 p)
Expected Value
Variance
Standard Deviation
7/29/2019 Business Statistics 4
22/23
Binomial Distribution
3(.1)(.9) .52 employees
E(x) = = 3(.1) = .3 employees out of 3
Var(x) = 2 = 3(.1)(.9) = .27
Expected Value
Variance
Standard Deviation
7/29/2019 Business Statistics 4
23/23
Binomial DistributionHarish is in charge of the electronics section of a large
departmental store. He has noticed that the probability
that a customer who is just browsing will buy somethingis 0.3. Suppose that 15 customers browse in the
electronics section each Hour, then
1. What is the Prob. that at least one browsing customerwill buy something during a specific hour.
2. What is the Prob. that at least four browsing customer
will buy something during a specific hour.
3. What is the Prob. that no browsing customer will buy
anything during a specific hour.
4. What is the Prob. that no more than four browsing
customers will buy something during a specific hour.