c Programming

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C Programming lab

SUBJECT CODE: 210

NAME: bhumika bhateja

B.TECH(COMPUTER SCIENCE) II SEM

TEACHER: MR. JAWED AHMed

DATE OF SUBMISSION: 08 april 2013

1. While purchasing certain items, a discount of 10% is offered if the quantity purchased is

more than 1000. If quantity and price per item are input through the keyboard, write a

program to calculate the total expenses.

2. If his basic salary is less than Rs. 1500, then HRA=10% of basic salary and DA=25% of basic. If

his salary is either equal to or above Rs. 1500, then HRA=Rs. 500 and DA=50% of basic. If the

employees salary is input through the keyboard write a program to find his gross salary.

3. The marks obtained by a student in 5 different subjects are input through the keyboard. The

student gets a division as per the following rules:

Percentage above or equal to 75 Honors

Percentage above or equal to 60 First Division

Percentage between 50 and 59 Second Division

Percentage between 40 and 49 Third Division

Percentage less than 40 Fail

Write a program to calculate the division obtained by the student.

4. If a number 972 is entered through the keyboard, your program should print Nine Seven

Two. Write a program such that it does this for any positive integer.

5. Write a program that, for all positive integers i,j,k, and l from 1 through 500, finds and prints

all possible combinations of i , j,k and l such that i+j+k=l and i

12. Write a program to enter the numbers till the user wants and at the end it should display the

count of positive, negative and zeros entered.

13. Write a program to receive an integer and find its octal, hexadecimal and binary equivalent.

14. Write a program to generate all combinations of 1, 2 and 3 using for loop.

15. Write a program to print all prime numbers from 1 to 300. (Hint: Use nested loops, break

and continue).

16. Write a program to print the multiplication table of the number entered by the user.

17. Write a program to check whether number entered through keyboard is palindrome or not.

18. Write a program to print Fibonacci Series from 1 to 100.

19. Write a program to compute and display the sum of all integers that are divisible by 6 but

not divisible by 4 and lie between 0 to 100. The program should also count and display the

numbers of such values.

20. Write a program to compute the real roots of a quadratic equation

ax2 +bx +c =0

The roots are given by the equations

x1= -b + (sqrt(b2-4ac)/2a)

x2= -b - (sqrt(b2-4ac)/2a)

The program should request for the values of the constants a, b and c and print the values of

x1 and x2. Use the following rules:

(a) No solution, if both a and b are zero

(b) There is only one root, if a=0 (x=-c/b)

(c) There are no real roots, if b2-4ac is negative

(d) Otherwise, there are two real roots

Test your program with appropriate data so that all logical paths are working as per your

design. Incorporate appropriate output message.

21. Given a number, write a program using while loop to reverse the digits of the number. For

example, the number 12345 should be written as 54321. Also find the sum of all digits, even

digits and odd digits.

22. An electric power distribution company charges its domestic consumers as follows:

Computation Units Rate of Charge

0-200 Rs. 0.50 per unit

201-400 Rs. 100 plus Rs. 0.65 per unit excess of 200

401-600 Rs. 230 plus Rs. 0.80 per unit excess of 400

601 and above Rs. 390 plus Rs. 1.00 per unit excess of 600

The program reads the customer number and power consumed and prints the amount to be

paid by the customer.

23. Write a program to input ten numbers from keyboard and find the sum of all even numbers

and odd numbers.

24. Write a program to find HCF (Highest Common Factors) of two numbers.

25. Write a program to compute the value of Eulers number (E) that is used as the base of

natural logarithms. Use the following formula.

E=(1/0!)+(1/1!)+(1/2!)+..+1/n!

1. #include #include

main() // Made By Bhumika Bhateja

{

int qty,price,total=0,dis=0;

clrscr();

printf("Enter Price: Rs. ");

scanf("%d",&price);

printf("\nEnter Quantity: ");

scanf("%d",&qty);

if(qty>1000)

dis=0.1*price*qty;

total=(qty*price)-dis;

printf("\nDiscount: Rs. %d",dis);

printf("\n\nTotal Expense: Rs. %d",total);

getch();

}

Enter Price: Rs. 700

Enter Quantity: 1200

Discount: Rs. 84000

Total Expense: Rs. 756000



{

clrscr();

int salary;

float gross,hra,da;

printf("Enter your basic salary: Rs. ");

scanf("%d",&salary);

if(salary



{

clrscr();

float m1,m2,m3,m4,m5,per,tot;

printf("Enter marks in 1st subject: ");

scanf("%f",&m1);

printf("Enter marks in 2nd subject: ");

scanf("%f",&m2);

printf("Enter marks in 3rd subject: ");

scanf("%f",&m3);

printf("Enter marks in 4th subject: ");

scanf("%f",&m4);

printf("Enter marks in 5th subject: ");

scanf("%f",&m5);

tot=m1+m2+m3+m4+m5;

per=tot/5;

printf("Percentage: %f%\n",per);

if(per>=75)

printf("Division: Honors ");

if(per=60)

printf("Division: First Division ");

if(per=50)

printf("Division: Second Division ");

if(per=40)

printf("Division: Third Division ");

if(per

Enter marks in 1st subject: 84 Enter marks in 2nd subject: 89 Enter marks in 3rd subject: 92 Enter marks in 4th subject: 78 Enter marks in 5th subject: 81 Percentage: 84.800003% Division: Honors

(Screen Clears)

Enter marks in 1st subject: 68 Enter marks in 2nd subject: 45 Enter marks in 3rd subject: 56 Enter marks in 4th subject: 48 Enter marks in 5th subject: 34 Percentage: 50.200001% Division: Second Division



{

clrscr();

int number,rev=0,d;

printf("Enter number: ");

scanf("%d",&number);

while(number>0)

{

d=number%10;

rev=d+rev*10;

number/=10;

}

while(rev>0)

{

d=rev%10;

rev/=10;

switch(d)

{

case 1: printf("One "); break;

case 2: printf("Two "); break;

case 3: printf("Three "); break;

case 4: printf("Four "); break;

case 5: printf("Five "); break;

case 6: printf("Six "); break;

case 7: printf("Seven "); break;

case 8: printf("Eight "); break;

case 9: printf("Nine "); break;

case 0: printf("Zero "); break;

default: printf("Wrong choice");

}

}

getch();

}

Enter number: 972 Nine Seven Two (Screen Clears) Enter number: 842 Eight Four Two



{

clrscr();

int i,j,k,l;

printf("Combinations are: ");

for(i=1;i



{

clrscr();

int a,b,c,d,i=0,k=0,l=0,base;

int A[30],ar[30],arr[30];

printf("\nEnter any Decimal Number: ");

scanf("%d",&a);

d=c=a;

printf("\n Enter Base: ");

scanf("%d",&base);

if(base==2)

{

while(a>0)

{

b=a%2;

A[i]=b;

++i;

a=a/2;

}

printf("\nBinary Conversion: ");

for(int j=i-1; j>=0; --j)

printf("%d",A[j]);

}

if(base==8)

{

while(c>0)

{

b=c%8;

ar[k]=b;

++k;

c=c/8;

}

printf("\nOctal Conversion: ");

for(j=k-1; j>=0; --j)

printf("%d",ar[j]);

}

if(base==16)

{

while(d>0)

{

b=d%16;

arr[l]=b;

++l;

d=d/16;

}

printf("\nHexadecimal Conversion: ");

for(j=l-1; j>=0; --j)

{

switch(arr[j])

{

case 10: printf("%c",65);

break;


break;


break;


break;


break;


break;

default: printf("%d",arr[j]);

}

}

getch();

}

Enter any Decimal Number: 64

Enter base: 2

Binary Conversion: 1000000

(Screen Clears)


Enter base: 8

Octal Conversion: 100

(Screen Clears)


Enter base: 16

Hexadecimal Conversion: 40



{

clrscr();

char i;

printf("Enter character: ");

scanf("%c",&i);

if(i>=65&&i=97&&i=48&&i=0&&i=58&&i=91&&i=123&&i



{

clrscr();

int f=1,num,i;


scanf("%d",&num);

for(i=1;i



{

clrscr();

int a,b,i,res=1;

printf("Enter 1st number: ");

scanf("%d",&a);

printf("Enter 2nd number: ");

scanf("%d",&b);

for(i=0;i

10. #include

#include


{

clrscr();

int i=0;

while(i

11. #include

#include


{

clrscr();

int i,sum,d,j;

printf("Armstrong numbers are: ");

for(i=1;i0)

{

d=j%10;

sum=sum+(d*d*d);

j/=10;

}

if(sum==i)

{

printf("%d ",i);

}

}

getch();

}

Armstrong numbers are: 1 153 370 371 407

12. #include

#include


{

clrscr();

int a[100],i=0,j,cntp=0,cntn=0,cntz=0;

char ans;

do

{

printf("\nEnter number: ");

scanf("%d",&a[i]);

i++;

printf("\nDo you want to continue (y/n): ");

scanf("%s",&ans);

}while(ans=='y');

for(j=0;j0)

cntp++;

if(a[j]

Enter number: 10

Do you want to continue (y/n): y

Enter number: -90


Enter number: 0


Enter number: 78


Enter number: -39

Do you want to continue (y/n): n

No. of postivie nos: 2

No. of negative nos: 2

No. of zeros: 1

13. #include

#include


{

clrscr();

int a,b,c,d,i=0,k=0,l=0;

int A[30],ar[30],arr[30];

printf("\nEnter any Decimal Number: ");

scanf("%d",&a);

d=c=a;

while(a>0)

{

b=a%2;

A[i]=b;

++i;

a=a/2;

}

printf("\nBinary Conversion: ");

for(int j=i-1; j>=0; --j)

printf("%d",A[j]);

while(c>0)

{

b=c%8;

ar[k]=b;

++k;

c=c/8;

}

printf("\n\nOctal Conversion: ");

for(j=k-1; j>=0; --j)

printf("%d",ar[j]);

while(d>0)

{

b=d%16;

arr[l]=b;

++l;

d=d/16;

}

printf("\n\nHexadecimal Conversion: ");

for(j=l-1; j>=0; --j)

{

switch(arr[j])

{


break;


break;


break;


break;


break;


break;

default: printf("%d",arr[j]);

}

}

getch();

}





(Screen Clears)





14. #include

#include


{

clrscr();

int i,j,k;

printf("All combinations are: ");

for(i=1;i

15. #include

#include


{

clrscr();

int i,j;

printf("Prime numbers are: ");

for(i=1;i

16. #include

#include


{

clrscr();

int i,num,m;


scanf("%d",&num);

printf("Multiplication table: ");

for(i=1;i

17. #include

#include


{

clrscr();

int number,rev=0,d,temp;



temp=number;

while(number>0)

{

d=number%10;

rev=d+rev*10;

number/=10;

}

if(temp==rev)

printf("Palindrome ");

else

printf("Not a Palindrome ");

getch();

}

Enter number: 121

Palindrome

(Screen Clears)

Enter number: 123

Not a Palindrome

18. #include

#include


{

clrscr();

int a=1,b=2,i,c;

printf("Fibonacci series: ");

printf("%d %d ",a,b);

for(i=3;i

19. #include

#include


{

clrscr();

int i,sum=0,cnt=0;

printf("Numbers are: ");

for(i=0;i

20. #include

#include

#include


{

clrscr();

int a,b,c,d;

float x1,x2;

printf("\nEnter the value of a: ");

scanf("%d",&a);

printf("\nEnter the value of b: ");

scanf("%d",&b);

printf("\nEnter the value of c: ");

scanf("%d",&c);

d=b*b-4*a*c;

if(d==0)

{

printf("\nBoth roots are equal");

x1=-b/(2*a);

x2=x1;

printf("\n\nFirst Root x1= %f",x1);

printf("\n\nSecond Root x2= %f",x2);

}

if(d>0)

{

printf("\nBoth roots are real and different");

x1=(-b+sqrt(d))/(2*a);

x2=(-b-sqrt(d))/(2*a);

printf("\n\nFirst Root x1= %f",x1);

printf("\n\nSecond Root x2= %f",x2);

}

else

printf("\nNo Solution");

getch();

}

Enter the value of a: 1

Enter the value of b: 3

Enter the value of c: 2

Both roots are real and different

First Root x1= -1.000000

Second Root x2= -2.000000

(Screen Clears)

Enter the value of a: 1

Enter the value of b: 1

Enter the value of c: 1

No Solution

21. #include

#include


{

clrscr();

int number,rev=0,d,sum=0,sume=0,sumo=0;



while(number>0)

{

d=number%10;

sum=sum+d;

if(d%2==0)

sume=sume+d;

else

sumo=sumo+d;

rev=d+rev*10;

number/=10;

}

printf("Reversed Number is: ");

printf("%d",rev);

printf("\nSum of digits is: ");

printf("%d",sum);

printf("\nSum of even digits is: ");

printf("%d",sume);

printf("\nSum of odd digits is: ");

printf("%d",sumo);

getch();

}

Enter number: 4326

Reversed Number is: 6234

Sum of digits is: 15

Sum of even digits is: 12

Sum of odd digits is: 3

22. #include

#include


{

clrscr();

int custno,powercons;

float amount;

printf("Enter customer number: ");

scanf("%d",&custno);

printf("Enter power consumed: ");

scanf("%d",&powercons);

if(powercons=201 && powercons=401 && powercons=601)

amount=390+(powercons-600);

printf("Amount to be paid is: Rs. ");

printf("%f",amount);

getch();

}

Enter customer number: 201

Enter power consumed: 250

Amount to be paid is: Rs. 132.500000

(Screen Clears)

Enter customer number: 104

Enter power consumed: 560

Amount to be paid is: Rs. 358.000000

23. #include

#include


{

clrscr();

int a[10],i,sume=0,sumo=0;

for(i=0;i

24. #include

#include


{

clrscr();

int a, b, x, y, t, hcf;

printf("Enter 1st number: ");

scanf("%d",&x);

printf("Enter 2nd number: ");

scanf("%d",&y);

a = x;

b = y;

while (b != 0)

{

t = b;

b = a % b;

a = t;

}

hcf = a;

printf("HCF of %d and %d = %d\n", x, y, hcf);

getch();

}

Enter 1st number: 10

Enter 2nd number: 5

HCF of 10 and 5 = 5

(screen Clears)

Enter 1st number: 12

Enter 2nd number: 36

HCF of 12 and 36 = 12

25. #include

#include


{

clrscr();

int n,i,f,j;

float sum=1;

printf("Enter the value of n: ");

scanf("%d",&n);

for(i=1;i0;j--)

f=f*j;

sum=sum+(1.0/f);

}

printf("Sum is: %f",sum);

getch();

}

Enter the value of n: 5

Sum is: 2.716667

(Screen Clears)

Enter the value of n: 3

Sum is: 2.666667

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