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CAD/CAE for Power
Electronics
Course no. 2
Design and modelling aspects of the
main DC-DC converters
Content
1. DC, RMS
2. Main unidirectional single-stage DC-DC Converters (Design Aspects)
3. Chopper with R load
4. Chopper with RLE load
5. Step-down (buck) converter6. Step-up converter (Boost)
7. Buck-Boost converter (inverted voltage)
8. Flyback converter (isolated buck-boost converter)
9. Buck-Boost uk converter
10.Comparison of switch utilizations
11.Effects of parasitics
12.References
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DC, RMS
DC value (average) of a signal (voltage, current):
T1 T1
- -
DCT 0
DCT 0
,
0
21RMS dtvV
021
RMS dtiI
If a waveform can be divided into n harmonics:
2)(
2)2(
2)1(
2 ... nRMSRMSRMSDCRMS VVVVV
2)(
2)2(
2)1(
2 ... nRMSRMSRMSDCRMS IIIII
Problems
Determine the DC and RMS values of the following signals:
a) b) c)
d) e) f)
g)
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Answers
a) ;2 m
RMSm
DC
II
II
b)TTII
TTII mRMS
mDC
00 ;2
c)T
TUU
T
TUU mRMSmDC
00 ;
d)T
TUU
T
TUU mRMS
mDC
00
3;
2
e)3
;2
m
RMS
m
DC
II
II
f)3
;2
mRMS
mDC
UU
UU
g) AIAI RMSDC 18.143;17.8
Problem
Calculate the power losses of an IGBT during conduction,
on CE0iC
M
Im
t
on
CE0
TM
m
0
Solution: IC(DC)=3.8A; IC(RMS)=6A; Pd=5.22W
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Chopper with RLE load
Voltage transfer function, for CCM:
DVV
The PWM switching period:
o
io
i o
o
oDC
Step-down (buck) converter
L
io DVV i o
Current transfer function (CCM):L
oDC
o
DII io /S
S
D
LC
o
+
i o
C
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LC design basics*
Boundary between CCM and DCM (L-design 1):
fRDLb
2)1(
Maximum current ripple through L (L-design 2):
fL
DDVI iL
)1(
Voltage output ripple (C-design):
2min8
)1(
LfV
VDC
o
o
* with ideal components (neglecting the voltage drops on the components)
Problem
Design L and C for a buck converter with the following
specifications: Vi=2025V, Vo=10V, Pn=100W, Pmin=10W,
f=25kHz.
, m n
L-current ripple condition: IL0.5A
C-voltage ripple condition: Vo10mV
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Step-up converter (Boost)
L
VV 1 i o
Current transfer function CCM :
D1 LiDC
io IDI )1( S
C
o
LC design basics*
Boundary between CCM and DCM (L-design 1):
DRDLb
2
)1( 2
Maximum current ripple through L (L-design 2):
fL
DVI iL
Voltage output ripple (C-design)
RfV
DVC
o
o
min
*with ideal components
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Problem
Design L and C for a boost converter with the following
specifications: Vi=1218V, Vo=24V, Pn=120W, Pmin=12W,
= .
The converter must operate in CCM, for PPmin
L-current ripple condition: IL0.5A
C-voltage ripple condition: Vo50mV
Buck-Boost converter (inverted voltage)
L
i
VD
V o
Current transfer function CCM :D1
L
io ID
I
1S
S
D Io
Vi Vo RL C
iLC C
+ o
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LC design basics*
Boundary between CCM and DCM (L-design 1):
RDLb)1( 2
Maximum current ripple through L (L-design 2):
DVI iL
Voltage output ripple (C-design)
DVC omin
o
*with ideal components
Problem
Design L and C for a buck-boost converter with the following
specifications: Vi =1636V, Vo= -24 V, Pn=120W, Pmin=12W,
f=25kHz.
The converter must operate in CCM, for PPmin
L-current ripple condition: IL0.8A
C-voltage ripple condition: Vo50mV
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Flyback converter (isolated buck-boost converter)
Voltage transfer function, for CCM:
1 VnDD
V it
o
21/NNnt
L (magnetizing inductance) design:
RDn )1( 22
fmb
2
C design:
DV
RfVomin
Buck-Boost converter (uk)
Voltage transfer function (CCM): iC1
io VD
DV
1
IL1
S-on S-off 0
Current transfer function (CCM):tvC1
- L2
io ID
I 0 t
iS
L1 iL1 IoC1iC1
+
L2 iL2
t0
L1 L2
Vi S Vo RCD
S D
0
Vi
t
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LC design basics*
Boundary between CCM and DCM (L1, L2-design 1):
RDLb)1(
1 RDLb )1(2
Maximum current ripple through L (L1, L2-design 2):
1
DVI iL 2
DVI iL
Voltage output ripple (C-design)
1 2
2min
)1( VDC o
DVC imin1
2o
*with ideal components
C1
Problem
Design L and C for a uk converter with the following
specifications: Vi =1636V, Vo= - 24V, Pn=120W, Pmin=12W,
f=25kHz.
, m n
L-current ripple condition: IL1,20.8A
C-voltage ripple condition: Vo10mV, VC12V
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Comparison of switch utilizations
Assumptions:
-The converters operate in CCM;
- e components are ea an the converter losses are neglected;
-The current ripple in the inductor is negligible, iL(t)=IL;
=- o o
1Buck
PSUR o
SUR 0.8 (1-D) (D)
switch
utilization
0.4
.Buck-Boost
(D(1-D))ratio
0
0.2pkpk
. . . .D
Effects of parasitics
The output capacitor includes a series resistance, rC, known as
equivalent series resistance (ESR) and is due to the dielectric
losses and physical resistances of leads and connections;
The high-frequency current ripple that flows through capacitor
produces additional voltage drop on ESR;
o u ons o re uce vo age r pp e on :
reducing the current ripple => higher L;
- ,
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L-design aspects
L acts as energy storage element in switched-mode converters and
as filter to smooth out the current harmonics;
same values of ripple current and filtering requirement;
The magnetic core losses depends with the square of frequency;
The coil stray capacitance will cancel the inductor effect above a
certain frequency (i.e. the coil starts to behave as a capacitor);
Therefore L-desi n is a tradeoff between switchin fre uenc and
inductor size.
References
1. N. Mohan, T.M. Undeland, W.P. Robbins, Power Electronics
Converters A lication and Desi n John Wile & Sons 2003
2. M. H. Rashid, Power Electronics. Circuits, Devices and Applications
3rd edition, Pearson Education, 2004, USA.
3. M.H. Rashid, Power Electronics Handbook 3rd edition, Butterworth-Heinemann, 2010, USA.
4. R. W. Erickson, Fundamentals of Power Electronics, Springer, 2001.
5. S. M. Sharkh, M.A. Abu-Sara, Power Electronics converters for
Microgrids, Wiley, 2010, USA.
6. M.C. Brown, Practical Switching Power Supply Design, Academic
ress, , .
7. H. More, Matlab for Engineers, Prentice Hall, 2008.. . ,
(Romanian version), Transilvania University Press, 2008.