1/ Thng k s ngi:

Tng

Nh hng

Restaurant

(m2)

Cn h

(m2)Shop Dch v Cn h

Phng

khch

(phng)

Tng1 & lng 1500 1496 11

Tng 2 16

Tng 3 16

Tng 4 16

Tng 5 16

Tng 6 16

Tng 7 16

Tng 8 16

Tng 9 16

Tng 10 16

Tng 11 16

Tng 12 16

Tng 13 16

Tng 14 16

Tng 15 16

Tng 16 16

Tng 17 16

Tng 18 16

Tng 19 16

Tng cng 0 0 1500 1496 283 0

Tiu chun

(m2/ngi)6 10 10 6 200 2

S ngi 0 0 150 250 1132 0

2/ Tnh ton nhu cu nc sinh hot hng ngy v b cha nc d tr ca cng trnh:

S th t Khu vc

Nhu cu s

dng nc tiu

chun

(l/ngi/ngy)

Tng din

tch hoc

s phng

(m2) hoc

khi tch

(m3)

Tng s

ngi

Khi tch

nc s

dng 1

ngy (m3)

T l c

tnh

1Phng cng

cng25 1500 150 3.75

(c tnh

10m2/ngi)

2 Dch v 25 1496 250 6.25(c tnh

6m2/ngi)

Ghi ch

BNG TNH H THNG CP NC SINH HOT

Ghi ch

3 Cn h 200 283 1132 226.4(c tnh 4

ngi/cn

h)

4Ngi phc

v25 10 0.25

(c tnh

10m2/ngi)

5 Bi u xe 2 3037 6.074 2l/m2/ngy

6D tr cho

gii nhit0

243 m3

486 m3

486 m3

Ngoi ra:

400 m3

Do chn khi tch b cha nc nh sau:

Stt Khi tch n v

1 886 m3

3 900 m3

3/ Tnh ton kt nc mi:

- Khi tch nc d tr cho h thng gii nhit trn tng mi: V = 0 m3

(h thng thng gi v iu ha khng kh cung cp)

S th t

Nhu cu nc

sinh hot 1

ngy(m)

30% nhu cu 1

ngy (m)

Nc

cha chy

trong 10

pht

Khi tch

nc d

tr trn

mi (m3)

Chn b

nc mi

(m3)

1 243.0 81.0 26.3 107.3 110.0

4/ Tnh ton h thng bm trung chuyn cp nc ln b nc mi:

a. Lu lng bm:

Lu lng bm: Qp= 1/3* Qngy*n

Bng tnh ton:

S th t

Nhu cu nc

sinh hot 1

ngy (m)

H s: n Qp (m3/h)Chn Qp

(m3/h)

S lng

bm (ci)

Lu lng 1

bm (m3/h)

1 243.0 1.30 106.0 110.0 1.0 110.0

b. ng knh ng:

Din gii Q(m3/h) V (m/s) D (mm) DN(mm)V(thc)

(m/s)

ng chnh 110.0 2 139.4714 150 1.73

c. Ct p bm:

- Ct p bm: H = (H1 + H2 + H3)*n

Ghi ch

Ghi ch

Ghi ch

M t Ghi ch

B cha nc thy cc: bao gm: nc thy cc d

tr cho sinh hot, nc gii nhit, nc cha chy

Chn khi tch b cha nc

Tng cng sinh hot cho 2 ngy

Tng cng b cha nc(1.5*sinh hot, gii nhit)

Nc d tr cho h thng cha chy: (vch tng, sprinkler, mng

ngn chy drencher)

350 cho bn tm

Tng cng sinh hot cho 1 ngy

n = 1.35

- Ct p tnh: H1 = 65 m

- H s mt p theo cng thc ca Hazen William : J = 6,824x(V/C)1,852

xD(-1,167)

Bng tnh ton:ng knh

ng (mm)V (m/s) L(m) C J Hf1

150 1.73 105 140 0.018 1.917

Tn tht cc b = (10% -20%)* tn tht trn chiu di ng (TCXD 33-2006, ph lc 14)Hf2 = 20% * Hf1 = 0.383 m

Do : tng tn tht: H2 = Hf1 + Hf2 = 2.300 m

- p lc yu cu u ra: H3 = 5 m

- p lc cn thit: H = (H1 + H2 + H3)*n = 98 m

=>Chn ct p bm: H = 100 m

Do , Thng s bm cp nc trung chuyn c chn nh sau:

Stt M t Qp (m3/h)Ct p

bm (m)

Cng sut

(kw)S lng

1

H bm trung

chuyn (bm

in)

110.0 100.0 58.9 2.0

5/ Tnh ton h thng bm tng p cp nc tng mi (cho 3 tng trn cng):

a. Tnh lu lng bm

- Lu lng: Q = a * 0.2 * N * 3.6

Bng 11mc 6.9, TCVN 4513:1988:a = 2.5

Bng tnh ton

Thit b Vi sen Bn tm nm Lavabo Bn cuVi nc

my gitu tiu Chu bp Ghi ch

ng

lng1.5 1.5 0.33 0.5 1 0.17 1

S lng 88 0 88 88 48 0 48

Tng ng

lng N132 0 29.04 44 48 0 48

Tng cng N

Lu lng

Qr (m3/h

)

Lu lng cha chy: Qc = 2*2.5*3.6 = 18 m3/h

Lu lng cp cho h nc nng:Qn= 0 m3/h

Vy lu lng bm: Q = Qr + Q c = 50.0 m3/h

b. Tnh ton ng knh ng:

Din gii Q(m3/h) V (m/s) D (mm) DN(mm)V(thc)

(m/s)

ng chnh 50.0 2 94.032 100 1.77

c. Tnh ct p bm:

o Trng hp cp cho sinh hot:

Ct p bm: H = (H1 + H2 + H3)*n

n = 1.2

Ct p tnh: H1 = 2 m

Ghi ch

Ghi ch

Ghi ch

1 chy+ 1 d phng (2 bm chy

lun phin)

301.04

31.3

H s mt p theo cng thc ca Hazen William : J = 6,824x(V/C)1,852

xD(-1,167)

Bng tnh ton:

ng knh

ng (mm)V (m/s) L(m) C J Hf1

100 1.77 50 140 0.031 1.527

Tn tht cc b = (10% -20%)* tn tht trn chiu di ng (TCXD 33-2006, ph lc 14)Hf2 = 20% * Hf1 = 0.305 m

Do : tng tn tht: H2 = Hf1 + Hf2 = 1.833 m

p lc yu cu u ra: H3 = 10 m

p lc cn thit: H = (H1 + H2 + H3)*n = 17 m

Chn ct p bm: H = 20 m

o Trng hp cp cho cha chy

- H1 = 21 m (p lc hng cha chy)

- Hf1 = H ma st dc ng, vi ng ng knh Dn100, lu lng 50m3/h th tn tht

trn 1 m chiu di l 0.031 m. Tng chiu di on ng tnh ton 50 (m)

Hf1 = 0.031 * 50 = 1.55 m

Hf2 = H ma st cc b = 10 %* Hf1 (Theo TCVN 4513 -1988, im 6.16)

Hf2 = 10 % * Hf1= 0.155 m

- H3 = H tn tht trn cun vi (Theo TCVN 4513 - 1988 im 6. 19)

H3 = Kp * Q2 * L= 0.012 * ((2.5)^2) * 20

= 1.5 m

=> H = (H1+H2+H3) *n

Chn h s : n = 1.2

Ct p bm l: Hb = 1.2* H =

= 29.0 m

Chn ct p bm: Hb= 30 m

Do , Thng s bm bin tn cp nc tng mi (cp cho 3 tng trn cng):

Stt M t Qp (m3/h)Ct p

bm (m)

Cng sut

(kw)S lng

1

H bm bin

tn (bm

in)

50.0 30.0 6.9 2.0

6/ Tnh ton ng knh ng cp ti cc tng v cc khu v sinh:

a. Thng k s lng thit b v sinh

No.Sanitary

wareWC lavabo Urinal

Kitchen

SinkShower Bath-tub Tap

1 N 0.5 0.33 0.17 1 1.5 1.5 1

Tn phngS lng

phngBn cu lavabo u tiu Chu bp

P. Tm

ng

Vi sen

Bn tm

nm

Vi

nc

Tng 19Cn h 16 24 24 0 16 24 0 16

Tng 17-18Cn h 32 64 64 0 32 64 0 32

Tng 13-16Cn h 64 128 128 64 128 0 64

Tng 9-12Cn h 64 128 128 64 128 0 64

Ghi ch

Ghi ch

1 chy+ 1 d phng (2 bm chy

lun phin)

Tng 5-8Cn h 64 128 128 64 122 3 64

Tng hm-4

Cn h 60 120 120 59 91 8 66

Tng s

lng thit b300 592 592 0 299 557 11 306

N 296 195.36 0 299 835.5 16.5 306

b. Tnh ton ng cp nc cc tng:

Tn phng Tng N Q(l/s) V(m/s) D(mm) Dn(mm) V(thc-m/s)

Tng 17-19

Tng 3 tng 301.04 8.68 1.50 85.81 100.00 1.10

Tng 13-16

Tng 4 tng 426.24 10.32 1.50 93.61 100.00 1.31

Tng 9-12

Tng 4 tng 426.24 10.32 1.50 93.61 100.00 1.31

Tng 5-8

Tng 4 tng 421.74 10.27 1.50 93.36 100.00 1.31

Tng hm-4

Tng 4 tng 373.10 9.66 1.50 90.54 100.00 1.23

Chn Dn100

Chn Dn100

Chn Dn100

Bng thng k thit b cc tng trn cng

Ghi ch

Chn Dn100

Chn Dn100

Lobby

1898 Chiu rng 8.666666667

1000 C. di 16.46666667

C. cao 1.4

din tch 142.7111111

khi tch 199.7955556

t l 1.733333333

c. rng o 5

c. di o 9.5

191

3089

H bi

Tap

1

1/ Tnh ton thng s cc b nc thi:

a. Tnh khi tch b t hoi khu nh khch:- Th tch b t hoi:

Wp = (Wn + Wc)*n

trong : Wn = N * q

q = 25 lit/ngi

Wc: th tch cn

- Lng cn trung bnh mt ngi thi ra l a = 0.5 l/person/day

- Thi gian gia hai ln ly cn trung bnh (ng ngi) T = 180 day

Thi gian gia hai ln ly cn trung bnh (t ngi) T = 1080 day

- m ca cn ti vo b W1 = 95 %

- m ca cn khi ln men W2 = 90 %

- H s k n vic gim th tch cn khi ln men b = 0.7

- H s k n vic li mt phn cn ln men c = 1.2

- S ngi N = ngi

- Nhu cu dng nc trung bnh q = l/ngi/ngy

- Bng tnh ton sau:

No. B t hoi N q W n W c W p /v

Unit1 Cn h 1132 25 28.3 42.7896 72 m32 Thng mi / dch v 300 25 7.5 11.34 19 m3

S b t hoi: n = 2

Khi tch 1 b t hoi: V = Wp/n = 45.5 m3 ~= 50 m3Chn khi tch mt b: V1 = 50 m3

- Chn b t hoi c 3 ngn, ngn 1: 50% th tch b, ngn 2= ngn 3 = 25% th tch b

2/ Tnh ton thy lc h thng thot nc thi sinh hot:

- Lu lng thot nc thi:

Q=Qc+Qdc (l/s)

trong :

Q: Lu lng thot nc thi(l/s)

Qc: Lu lng cp nc (l/s)

Qdc: lu lng ca thit b v sinh c lu lng ln nht (l/s)

- Tnh ton v chn ng knh ng thot nc thi theo TCVN 4478: 1987, mc: 6.8

- Tnh ton chn ng knh ng thng hi theo TCVN 4474: 1987, mc 5.11

a. Tnh ton ng thot nc thi ng:

Stt Thit b v sinh Bncu lavabo u tiu Chu bp Vi sen BT nm Vi nc

1 q(l/s) 0.9 0.33 0.3 1 0.2 1.1 0.07

2 N 4.5 1.65 1.5 5 1 5.5 0.35

Stt Tuyn thot Bncu lavabo u tiu Chu bp Vi sen BT nm Vinc NQc

(l/s)

Qdc

(l/s)Q(l/s) Dn

(mm)

1 Trc ng: mi tng - 1 v sinh

Tng 1& lng 2 2 0 2 2 2

Tng 2 2 2 2 2 3 2

Tng in hnh(3-19) 2 2 2 2 0 2

ng thot phn 38 38 0 38 38 38 171 6.54 0.90 7.44 150

ng thot nc thi sinh

hot38 38 3 38 130.5 5.71 1.10 6.81 150

Tng 15 64 64 0 32

Tng 14 128 128 128 0

Tng in hnh(5-13) #REF! #REF! #REF! #REF!

Tng 15 #REF! #REF! #REF! #REF! #REF!

Tng 14 #REF! #REF! #REF! #REF! #REF!

Tng in hnh(5-13) #REF! #REF! #REF! #REF! #REF!

52.1

47.7

Tng lu lng nc

thi tp trung cho 1 b t

hoi block 1:

199.5

van

toc4.0

A 0.05

0.064

0.252

Prepare by M&E engineer Approval by M&E Chief Approval by M&E Manager

Name : on Hng Hng Name : L Vn Xun Name : Tran Le Quang

Signature : Signature : Signature :

Ghi ch

TCVN 4474: 1987

Bng tnh ng thot nc thi ng

Lu lng v ng lng tng ng thot nc ca cc thit b v sinh

BNG TNH H THNG THOT NC THI SINH HOT

Bng tnh khi tch b t hoi

S lng

Q'tyW p (m3)

Ghi ch

Remark

1 91.0

1000)100(

])100([

2

1

xW

NbcWaTWC

1/ Tiu chun tham chiu

- TCVN 4513-1988 :Internal water supply. Design standard

- TCXD 33:2006 : Water supply. External networks and facilities. Design standard

- Other foreign standard

2/ Thng tin d n

tng cng: 19 tng + 1 tng hm

3/ Tnh ton thy lc

Lu lng nc ma mi

Q=k*F*q5/10000

trong

Q: lu lng thot nc ma (l/s)

F: din tch thot nc ma (m3)

F=Fmi + 0.3*Ftng

k = 2

q5 = 496 l/s/ha

stt M t 80 100 150 200

1

Lu lng phu thot

nc mi 5 12 35

2

Lu lng ng thot

ng 10 20 50 80

Dn S lng Q(l/s) Dn S lng Chn Q(l/s)

1 Tng mi 1735 0 172.112 100 15 180.00 100 9.00 15.00 300

2 Tng k thut 1350 2520 217.248 150 7 245.00 100 11.00 15.00 300

3 Tng cng 3085 2520 389.36 100 & 150 22 425.00 100 20.00 30.00 600.00

Chn s lng nh sau:

I

I

I

1 Tng mi 100 15.00 ci I 1 Tng mi 100 15 ng

2 Tng k thut 150 15.00 ci I 2 Tng k thut 100 15 ng

stt M t F Ftng Q (l/s)S ng

thot ma

(n)

q = Q/n

(l/s)Dn (mm) i

d/D A(m2)

V(m/s)

1 Thot nc ma 3085 2520 389.36 2 194.68 400 0.005 0.49 0.1909 1.02

ng

thot S lng n v Chi ch

Bng tnh ton ng thot nc ma nm ngang

ng thot nc ma

S lng phu thot nc ma mi S lng ng ng thot nc ma mi

Stt TngPhu

thu

S

lngn v Stt Tng

Stt Tng F Ftng Q (l/s)Phu thot sn

BNG TNH TON H THNG THOT NC MA

Bng thng s tiu chun lu lng thot nc ma

Ghi ch

(mc 9.10-TCVN 4474)

(mc 9.10-TCVN 4474)

Bng tnh ton lu lng thot nc ma mi