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1 | Page CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy Chapter 6: Differential Equations 6.2: Integration by Recognition 1 4 u 2 1 4 8 ) 24 3 u 9 ) 21 2x u 2 cos ) 18 2 4 3 2 2 4 2 2 2 x x dx x x x x x x dx dx x x What you'll Learn About How to integrate a product by recognizing that one of the pieces contains the derivative of the other
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1 | P a g e

CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy

Chapter 6: Differential Equations 6.2: Integration by Recognition

14u 2148 )24

3

u 9

)21

2xu 2cos )18

243224

2

22

xxdxxxxx

x

x

dx

dxxx

What you'll Learn About How to integrate a product by recognizing that one of the pieces contains the

derivative of the other

2 | P a g e

dxxA 5

2 ) dxxB 14 )

12 ) 2

dxxxC 13 )3132

dxxxD

dxtttD 84232 ) 32

25 )

2

dxx

xE

3 | P a g e

cossin )

sin )

57cos )

4

32

xdxxF

dxxxE

dxxD

4 | P a g e

sectan ) 2 xdxxG

dxx

x

sin34

cos )58

16

1 )

81

1 )

22 dx

xK dx

xJ

5 | P a g e

81

2 )

2 dx

x

xI

dxx

xNdx

x

xM

dxx

xL

9

32

2

ln )

20

4 )

20

4 )

6 | P a g e

2

0

4

3

4

3 )66

cot )64

dxe

e

xdx

x

x

7 | P a g e

check then and

trig theof tiveantideriva theTake -Function Trig

check then and trig theof tiveantideriva theTake

- Function TrigPolynomial

abovecategory first theinto fall these-

cotxcscxor tanxsecx ess Unl

check then and rulepower

theusing functions trig theof one of tiveantideriva theTake

- Function TrigFunction Trig

check andr denominatot tha

on uppower thebump then and

top the toupr denominato theFlip-

1not ispower whosefunction trig

function trig

a

x

aarctan

a

1

x

constant22

check andnumerator theof tiveantideriva theTake-

angle theof derivative theishat function t polynomial

function trig

8 | P a g e

check then and rulepower theusing

functions polynomial theof one of tiveantideriva theTake

- Function PolynomialFunction Polynomial

check andr denominatoon that uppower thebump

then and top the toupr denominato theFlip-

1not ispower hosefunction w polynomial

bottom theof derivative isnumerator

check andnumerator theof tiveantideriva theTake-

top theofpart of derivative theishat function t polynomial

function polynomial

check and ator)ln(denomin down the Write-

powerfirst the toisquantity hosefunction w

bottom theof derivative theishat function t

If the denominator’s quantity is to the first, the antiderivative is either

arctangent or natural log (ln)

9 | P a g e

CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy

Chapter 6: Differential Equations 6.3: Tabular Integration

Proof of Integration by

Parts

uvdx

dFind .1

2. Integrate both sides

3. Solve for udv

Use ultra violet minus super vdu to integrate the following

.

xxe .2

Use tabular integration to integrate the following

xxe .2

What you'll Learn About How to integrate a product by that cannot be done by recognition

10 | P a g e

Use tabular integration to integrate the following

-x2ex .6

2

cx .8 2 xos

11 | P a g e

Solve the initial value problem using tabular integration

0 xand 2y sin2dx

dy .11 xx

0-1)(y 22dx

dy .16 xx

12 | P a g e

Use tabular integration to integrate the following

xdxlnx .10 2

Use ultra violet minus super vdu to integrate the following

xdxlnx .10 2

13 | P a g e

Use tabular integration to integrate the following

dxxA arcsin .

dxxex 2cos .19

14 | P a g e

Top Heavy Integrals

dxx

xxA

2

.

dxx

xB

5 .

dxx

xxC

2 .

3

15 | P a g e

CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy

Chapter 6: Differential Equations 6.5: Partial Fractions

dxxx

xA

4

12 )

2

dxxx

xB

103

16 )

2

What you'll Learn About How integrate a fraction when the denominator can be factored and the numerator

is not the derivative of the denominator

16 | P a g e

dxxx

C 132

2 )

2

dxx

xD

1

5 )

2

3

17 | P a g e

xx

xE

3

32(x)f )

18 | P a g e

1

9 )

2xF

1

9 )

2x

xG

1

9 )

2x

xH

1

9 )

2xI

19 | P a g e

CALCULUS: Graphical,Numerical,Algebraic by Finney,Demana,Watts and Kennedy

Chapter 6: Differential Equations 6.5: Logistic Growth Fractions

I am sick (Initial Value). Eventually everyone gets sick(Max). So what happens to

the rate of people getting sick. People will get sick quickly, then it will be harder to

find people that aren't sick yet (rate slows down-point of inflection) and eventually

everyone gets sick.

This is similar to a rumor spreading or facebook/twitter accounts.

yet)sick (Not peoplehealthy :P-M

peoplesick the toalproportiondirectly :kp

sick getting people ofgrowth of rate

)(

dt

dP

PMkPdt

dP

Remember directly proportional is just like P = 8.50h (Your pay is

directly proportional to the amount of money you make which can

change) That 8.50 is your k.

What you'll Learn About How to recognize a logistical growth differential equation

20 | P a g e

In 1985 and 1987, the Michigan Department of Natural Resources

airlifted 61 moose form Algonquin Park, Ontario to Marquette County in

the Upper Peninsula. It was originally hoped that the population P would

reach carrying capacity in about 25 years with a growth rate of

)1000(0003. PPdt

dp

Solve the differential equation with the initial condition P(0) = 61.

21 | P a g e

24. Which of the following differential equations for a population P could model

the logistic growth shown in the figure above?

0.0002P08.0dt

dP )

.000208.0dt

dP D) 0002.08.

dt

dP )

0002.08.dt

dP B) 0008.002.

dt

dP )

2

22

22

PE

PPC

PPPPA

21. The number of moose in a national park is modeled by the function M that

satisfies the logistic differential equation .05 11000

dM MM

dt

, where t is

the time in years and M(0)=50. What is the lim ( )?t

M t

A) 50 B) 200 C) 500 D) 1000 E)

2000

22 | P a g e

84. The rate of change, ,dP

dt of the number of people on an ocean beach is

modeled by a logistic differential equation. The maximum number of people

allowed on the beach is 1000. At 10 A.M., the number of people on the

beach is 400 and is increasing at the rate of 200 people per hour. Which of

the following differential equations describes the situation.

1000200dt

dP )

10001200

1

dt

dP D) 1000

3

1

dt

dP )

10010002

1

dt

dP B) 1000

200

1

dt

dP )

PPE

PPPC

PPPA

26. The population P(t) of a species satisfies the logistic differential equation

4 ,2000

dP PP

dt

where the initial position P(0)=1500 and t is the time in years.

What is ?)(lim tPt

A) 2500 B) 8000 C) 4200 D) 2000 E) 4000

Let g be a function with g(4) = 1, such that all points (x, y) on the graph of g

satisfy the logistic differential equation 3 2 .dy

y ydx

b) Given that g(3) = 1, find lim ( ) and lim ( ).x x

g x g x

c) For what value of y does the graph of g have a point of inflection?

Find the slope of the graph of g at the point of inflection. (It is not

necessary to solve for g(x).)

23 | P a g e

A population is modeled by a function P that satisfies the logistic differential

equation

1 .10 15

dP P P

dt

a) If P(0) = 3, what is the lim ( )?

tP t

If P(0) = 20, what is the lim ( )?t

P t

b) If P(0) = 3, for what value of P is the population growing the fastest?

Rogawski

8. If y(x) is a solution to 3 (10 )dy

y ydx

with y(0) = 3 then as x,

A) y(x) increases to

B) y(x) increases to 5

C) y(x) decreases to 5

D) y(x) increases to 10

E) y(x) decreases to 10

9. If y(x) is a solution to 4 (12 )dy

y ydx

with y(0) = 10 then as x,

A) y(x) decreases to

B) y(x) increases to 6

C) y(x) increases to 12

D) y(x) decreases to 12

E) y(x) decreases to 0

16. If 3 (10 2 )dy

y ydt

with y(0) = 1 then, y is increasing the fastest when

A) y = 1.5

B) y = 2.5

C) y = 3

D) y = 4

E) y = 5

18. If 3 (10 2 )dy

y ydt

with y(0) = 1, then the maximum value of y is

A) y = 1

B) y = 2.5

C) y = 5

D) y = 10

E) Never attained; has no maximum value

24 | P a g e

Princeton Review (p. 806)

25. Given the differential equation 650

dz zz

dt

, where z(0) = 50, what is the

?)(lim tzt

A) 50 B) 100 C) 300 D) 6 E)

200

25. Given the differential equation 650

dz zz

dt

, where z(0) = 50, then z is

increasing the fastest when z =

A) 150 B) 100 C) 300 D) 50 E) 100

Other Rate type problems

Rogawski

11. The rate at which a certain disease spreads is proportional to the quotient of

the percentage of the population with the disease and the percentage of the population

that does not have the disease. If the constant of proportionality is .03, and y is the

percent of people with the disease, then which of the following equations gives R(t),

the rate at which the disease is spreading.

) R(t) .03y

.03B) R(t)

dr .03)

dt (1 )

yD) R(t) .03

(1 - y)

dr) .03

dt

A

dy

dt

RC

R

E R

25 | P a g e

12. The rate of change of the volume, V, of water in a tank with respect to time, t

is directly proportional to the square root of the time, t, it takes to empty the tank .

Which of the following is a differential equation that describes this relationship.

dV) ( ) ) ( ) )

dt

dV dV) )

dt dt

A V t k t V t k V C k t

kD E k V

V

B

16. Let P(t) represent the number of wolves in a population at time t years, when

0t . The population P(t) is increasing at rate directly proportional to 500 divided

by P(t), where the constant of proportionality is k. Write the differential equation

that describes this relationship.

23. If P(t) is the size of a population at time t, which of the following differential

equations describes exponential growth in the size of the population.

2

2

dP dP dP) 200 ) 200 ) 100

dP dP) 200 ) 100

A B t C tdt dt dt

D P E Pdt dt

26 | P a g e

8.4 Improper Integrals

1 31 )2

x

dx

1 3

2 )6

x

dx

What you'll Learn About How to integrate functions that approach infinity or functions that approach an

asymptote

27 | P a g e

0

32

)10x

dx

0

2 34

2 )14

xx

dx

28 | P a g e

0

2 )18 dxex x

43. Find the area of the region in the first quadrant that lies under the

given curve

2

ln

x

xy

29 | P a g e

dxxe x2

2 )22

1

0 21 )26

x

dx

30 | P a g e

4

1 )30

x

dx

2

0 1 )41

x

dx


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