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Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample...

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Carpentry & Joinery Phase 4 Trigonometry Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions Sample Questions & Solutions
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Page 1: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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TrigonometryTrigonometry

Tangent

Өadjacent

cosine

sine

Right

Ang

le

Sample Questions & SolutionsSample Questions & Solutions

Page 2: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Pythagoras TheoremPythagoras Theorem• Given a = 3.25m & b = 3.45m calculate

the length of c

• a² + b² = c²

• 3.25² + 3.45² = c²

• 10.5635 + 11.9025 = c²

• 22.466 = c²

• c = √22.466

• c = 4.74m Answer 4.74m Answer

ca

b

Page 3: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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QuestionQuestionCopy each of the triangles below and label each of the sides and the angle.

A

(a)

(c)

A

(b)

A

(d)

A

(e)A

(f)

A

Page 4: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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AnswerAnswerCopy each of the triangles below and label each of the sides and the angle.

A

(a)

(c)

A

(b)

A

(d)

A

(e)A

(f)

A

hyphyp

adjadj

oppopp

hyphyp

hyphyp

hyphyp

hyphyp

hyphyp

oppoppoppopp

oppopp

oppopp

adjadj

adjadj

adjadj

adjadj

adjadj

oppopp

Page 5: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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QuestionQuestion• Use your calculator to answer to 4 decimal

places (a) cos 25° (b) sin 50° (c) tan 34°

Page 6: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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AnswerAnswer• Use your calculator to answer to 4 decimal

places (a) cos 25° (b) sin 50° (c) tan 34°

• (a) cos 25 = 0.906307787

= 0.90630.9063

• (b) sin 50 = 0.766044443

= 0.76600.7660

• (c) tan 34 = 0.674508516

= 0.67450.6745

Page 7: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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QuestionQuestion• Use your calculator to find the angles to the

nearest degree

(a) sin A = 0.83 (b) cos B = ¾ (c) tan A = 5/7

Page 8: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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AnswerAnswer• Use your calculator to find the angles to the

nearest degree

(a) sin A = 0.83 (b) cos B = ¾ (c) tan A = 5/7

• (a) 2ndF, sin, .83 = 56.098738 = 56°56°

• (b) 2ndF, cos, a/b, 3 ↓ 4 = 41.40962211 = 41°41°

• (c) 2ndF, tan, a/b, 5 ↓ 7 = 35.53767779 = 36°36°

Page 9: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• In the triangle below, find the length of b

• The side we must find is the adjacent (b)

• We have the hypotenuse c = 10m

• The ratio that uses adj. & hyp. is cos

• So cos 60° = =

• 0.5 =

• b = 10(0.5)

• b = 5m Answer

c = 10m

a

b60°

adjacenthypotenuse

b10

b10

Page 10: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• Find the angle A to the nearest degree

• We have the opposite & the adjacent so we use tan ratio

• Tan A = =

• Tan A =

• Use calculator 2ndF, tan, a/b, 4 ↓ 3 =

• A = 53.1301

• A = 53° Answer 3m adjacent

4m opposite

Oppositeadjacent

43

43

Page 11: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• Find the side c (hyp.) to 2 decimal places

• We are given angle & opposite to find hyp.

• sin 40° =

• 0.6428 =

• 0.6428 x c = 15

• c =

• c = 23.34 Answer 23.34 Answer 15m

b

40°

c

15c

15c

150.6428

Page 12: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• Given a section through a roof with 2

unequal pitches, calculate

(a) the rise of the roof

(b) the length of rafter c

(c) the span b

30°

b

40°

c

5.42m

Page 13: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• This question may seem complicated but

we can simplify it by using our knowledge of right-angle triangles

• Firstly, divide triangle into 2 right-angled triangles (using the rise line)

30°

b

40°

c

5.42m

rise

Page 14: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• On the larger triangle we have the angle

30° & the hypotenuse 5.42m so we can use ratio sin 30° to find the opposite (rise)

Sin = (soh)

30°

b

40°

c

5.42m

oppositeoppositehypotenusehypotenuse

Page 15: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles

• Sin 30°=

• 0.5 =

• 0.5 x 5.42 = rise

• rise = 2.71m Answer (a)2.71m Answer (a)

30°

b

40°

c

5.42m

oppositeoppositehypotenusehypotenuse

rise5.42

Page 16: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• So on the smaller triangle we now have the

opposite (2.71m) and the angle 40°• So to find adjacent (part of span) we use Tan

Tan 40° =

0.839 =

0.839 x adj. = 2.71

adj. = 2.71 ÷ 0.839

= 3.23m3.23m

30°b

40°

c

5.42m

2.71adjacent

adj.

OppositeOppositeadjacentadjacent

Page 17: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• Using Pythagoras we can find c • a² + b² = c²• 2.71² + 3.23² = c² • 7.3441 + 10.4329 = c²• c² = 17.777• c = √17.777• c = 4.216m Answer (b) 4.216m Answer (b)

30°b

40°

c5.42m

2.71m

3.23m

Page 18: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle Triangles• Using Pythagoras we can find the rest of the span

i.e. the base of the larger triangle• a² + b² = c²

• 2.71² + b² = 5.42²

• 7.344 + b² = 29.376

• b² = 29.376 – 7.344

• b² = 22.032

• b = √22.032

• b = 4.694m4.694m 30° b 40°

c5.42m

2.71m

3.23m

Page 19: Carpentry & Joinery Phase 4 Trigonometry Tangent Ө adjacen t cosine sine Right Angle Sample Questions & Solutions.

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Solving Right-angle TrianglesSolving Right-angle TrianglesSo 4.694 + 3.23 = span

Span = 7.924m Answer (c)7.924m Answer (c)

30° b 40°

c5.42m

2.71m

3.23m


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