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Home > CCNA – Drag and Drop 3
CCNA – Drag and Drop 3September 17th, 2010 Go to comments
Here you will find answers to CCNA Drag and Drop Questions – Part 3
Question 1
Drag the security features on the left to the specific security risks they help protect against on the right. (Not all options areused)
Answer:
1) VTY password: remote access to device console2) console password: access to the console 0 line3) access-group: access to connected networks or resources4) service password-encryption: viewing of passwords5) enable secret: access to privileged mode
The unselected left-box – CHAP – is used to verify the identity of the peer by means of a three-way handshake.
Question 2
Refer to the exhibit. PC-A is sending packets to the FTP server. Consider the packets as they leave RA interface Fa0/0forwards RB. Drag the correct frame and packet address to their places in the table.
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Answer:
Source MAC: 0000.0C93.9999Destination MAC: 0000.0C89.3333Source IP: 172.16.21.7Destination IP: 172.16.34.250
Explanation
Remember these rules:
The IP addresses (of source and destination) of a packet never change during the transportation through the network. Forexample if PC-A wants to send a packet to PC-Z then the source and destination IP addresses of the packet will be the IPaddresses of PC-A and PC-Z no matter how many devices they go through.
The MAC addresses, conversely, will change while passing the devices. The source MAC address is the address of the lastsender and the destination MAC address is the address of the next device.
Question 3
As a network administrator, you are required to configure the network security policy. And the policy requires that only onehost be permitted to attach dynamically to each switch interface. If that policy is violated, the interface should shut down.Which two commands must the network administrator configure on the 2950 Catalyst switch to meet this policy? Pleasechoose appropriate commands and drag the items to the proper locations.
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Answer:
Appropriate commands:
SW(config-if)# switchport port-security maximum 1SW(config-if)# switchport port-security violation shutdown
Question 4
The left describes boot sequence, while the right describes the orders. Drag the items on the left to the proper locations.
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Answer:
1) Step 1: The power on self test executes. 2) Step 2: The bootstrap loader in ROM executes.3) Step 3: The IOS is located and loaded based on boot system commands in NVRAM.4) Step 4: The configuration file is loaded from NVRAM.5) Step 5: If no configuration file is located, the setup dialog initiates.
Explanation
When a router boots up, it performs a series of steps, called the boot sequence, to test the hardware and load thenecessary software. The boot sequence consists of the following steps:
1) Power on self test (POST): tests the hardware to verify that all components of the device are operational and present.2) The bootstrap loader in ROM executes: The bootstrap loader is a program in ROM that is used to find where a validCisco IOS image is located. 3) If a valid Cisco IOS image is located, it is loaded.4) IOS loads configuration file. Once the IOS image is loaded, it will search for a valid startup configuration in NVRAM.5) If a valid startup configuration file cannot be found, the router will load the System Configuration Dialog (sometimescalled setup mode). This mode allows you to perform the initial configuration of the router.
Question 5
Drag and Drop question. Drag the items to the proper locations.
Routing has been configured on the local router with these commands:Local(config)# ip route 0.0.0.0 0.0.0.0 192.168.1.1Local(config)# ip route 10.1.0.0 255.255.255.0 192.168.2.2Local(config)# ip route 10.1.0.0 255.255.0.0 192.168.3.3
Drag each destination IP address on the top to its correct next hop address at the bottom.
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Answer:
Next hop 192.168.1.1: + 10.2.1.3+ 10.6.8.4
Next hop 192.168.2.2:+ 10.1.0.14+ 10.1.0.123
Next hop 192.168.3.3: + 10.1.1.10+ 10.1.4.6
Explanation
If we have many entries matching for next hop ip address then the router will choose the one with most specific path to sendthe packet. This is called the “longest match” rule, the route with the most bits in the mask set to “1″ will be chosen to routepacket.
Question 6
If a Cisco router has learned about network 10.1.1.0 from multiple sources, the router will select and install only one entry
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into the routing table. Indicate the order of preference that the router will use by dragging the routes on the left to the orderof preference category on the right.
Answer:
1) First preference: S 10.1.1.0 is directly connected, Serial1 2) Second preference: S 10.1 1.0/24 [1/0] via 10.1.2.23) Third preference: D 10.1.1.0/24 [90/2172416] via 10.1.5.5, Serial04) Fourth preference: O 10.1.1.0/24 [ 110/789] via 10.1.3.1, Serial05) Fifth preference: R 10.1.1.0/24 [120/3] via 10.1.3.1, Senal0
Explanation
Administrative distance is the first criterion that a router uses to determine which routing protocol to use if two protocolsprovide route information for the same destination. It is a measure of the trustworthiness of the source of the routinginformation. The smaller the administrative distance value, the more reliable the protocol.
In this question, notice that the destination of all routes is 10.1.1.0/24 so we need to use Administrative distance of eachrouting protocol to specify the priority of each route. Below lists the Administrative Distance default values of popularrouting protocols:
+ Directly connected: 0+ Static route: 1+ EIGRP (symbolize by “D”): 90+ OSPF (symbolize by “O”): 110+ RIP (symbolize by “R”): 120
Comments
1. MooneyDecember 2nd, 2010
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I am having a hard time understanding question #5.Can anyone please explain?It would be greatly appreciated as I am testing in 6 days.
Thanks!
2. jeetDecember 2nd, 2010
hey Mooney,
trick in this question is to look at the ip and subnet mask and then choose the answer.Here is how I have understood it,
First look at the Next hop 192.168.2.2:
Since the address under this is 10.1.0.0 255.255.255.0 (From: 10.1.0.0 255.255.255.0 192.168.2.2) and becuasethe subnet mask is 255.255.255.0 so the consecutive series of ip addresses should be,
10.1.0.010.1.0.010.1.0.110.1.0.210.1.0.310.1.0.410.1.0.5…………10.1.0.255
Hence the answer10.1.0.14 only option available in the list10.1.0.123 only option available in the list
On the similar note,With next hop 192.168.3.3:
The addresses under it is: 10.1.0.0 255.255.0.0Since the mask is 255.255.0.0Hence consecutive addresses should be,10.1.0.010.1.0.110.1.0.210.1.0.310.1.0.4…………10.1.0.25510.1.1.010.1.1.110.1.1.210.1.1.310.1.1.410.1.1.5
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………..10.1.1.10 only option available in the list
………….…………10.1.4.110.1.4.210.1.4.310.1.4.410.1.4.510.1.4.6 only option available in the list
Hope it helps.
cheers…
3. KarlDecember 2nd, 2010
Hey guys, what are your thoughts on #6? I am confused about the first two preferences…
1) First preference: S 10.1.1.0 is directly connected, Serial12) Second preference: S 10.1 1.0/24 [1/0] via 10.1.2.2
It states that (S 10.1.1.0 is directly connected, Serial1) is the first preference because it is directly connected….however it is not… it is clearly a Static route because of the S.
This means both of these are static routes with Administrative Distance of 1. Static routes display as directlyconnected when an exit interface is used instead of the next hop address, but they are still an AD of 1.
Any thoughts?!?!?
4. Vijay0n26December 2nd, 2010
Hi karl ,
While configuring static routes if you give the next hop address as exit interface the AD will be ”ZERO”.
If you give next hop as IP address AD would be ”ONE”.
Simple concept for directly connected Networks AD is ”0”.
For static routes AD is ”1”.
Rectify me if i’m misunderstood.
Regards,
5. RobertDecember 2nd, 2010
Hi karl ,
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While configuring static routes if you give the next hop address as exit interface the AD will be ”ZERO”.
If you give next hop as IP address AD would be ”ONE”.
Simple concept for directly connected Networks AD is ”0”.
For static routes AD is ”1”.
Rectify me if i’m misunderstood.
Regards,
I understand your answer, but your explanation dose not explain then the directly connected is not #2 and the staticroute that points to the next hop is not #3???
6. Gowtham SaranDecember 2nd, 2010
dear 9tut,
I am still cant understand question no 5. kindly guide me in this issue
7. Gowtham SaranDecember 2nd, 2010
dear 9tut,Now i got clear idea by seeing explanation in comments for question no 5.So no further explanation is necessary
8. ntDecember 2nd, 2010
ip route 0.0.0.0 0.0.0.0 192.168.1.1 is the default route.If any ip address that is not in the routing table it will bedirected to next hop 192.168.1.1(default network 192.168.1.0).
That means any ip address outside of 10.1.0.0 -10.1.255.255 will beforwarded to default route. In the case for question 5 the10.2.x.x and 10.6.x.x are sent to hop 192.168.1.1.
The rest self explanatory.
9. RajDecember 2nd, 2010
Yha exactly.All Static routes carry same Administrative disatance (1) only.In case many static routes, exceptedNETWORK from static will be moved in Default Route (0.0.0.0) .
Any one can Differentiate CSU/DSU and MODEM?
10. MMSDecember 2nd, 2010
CSU/DSU connect Digital interface devices such as router (DTE) to leasng line (T1/T3) , while a modem isconnectinf the same devices to the phone line . Hope this may help
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11. UthmanHassanDecember 8th, 2010
Hi karl, Vijay and Robert
Just a small correction… The AD of static route out an interface is NOT ZERO.
Make a small two routers topology in Packet Tracer or GNS3. R1 and R2 connected via serial link or whatever youlike.
Create on R2 two loopback interfaces 1.1.1.1/24 and 2.2.2.2/24.
Configure on R1 static routes to both the networks, 1.1.1.0/24 and 2.2.2.0/24.Use the serial interface as next hop for 1.1.1.0/24 and the serial interface’s IP address for other.
You can use “show ip route static” command to view both static routes.Use “show ip route 1.1.1.0″ and “show ip route 2.2.2.0″ commands to verify that AD for both of them is 1.
R1#show ip route 192.168.1.1Routing entry for 192.168.1.0/30Known via “connected”, distance 0, metric 0 (connected, via interface)Routing Descriptor Blocks:* directly connected, via Serial0/0/0Route metric is 0, traffic share count is 1
R1#show ip route 192.168.1.2Routing entry for 192.168.1.0/30Known via “connected”, distance 0, metric 0 (connected, via interface)Routing Descriptor Blocks:* directly connected, via Serial0/0/0Route metric is 0, traffic share count is 1
R1#show ip route 1.1.1.1Routing entry for 1.1.1.0/24Known via “static”, distance 1, metric 0 (connected)Routing Descriptor Blocks:* directly connected, via Serial0/0/0Route metric is 0, traffic share count is 1
R1#show ip route 2.2.2.2Routing entry for 2.2.2.0/24Known via “static”, distance 1, metric 0Routing Descriptor Blocks:* 192.168.1.2Route metric is 0, traffic share count is 1
You can make the topology for yourself or can download mine from here:http://www.mediafire.com/?srma9c81aykhsrr
Cheers
12. UthmanHassan
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December 13th, 2010
Hi everyone
Just an update from Wikipedia regarding my above post on AD:
“Since IOS 12.2, the administrative distance of a static route with an exit interface is 1. Prior to the release of 12.2 itwas in fact 0.”
I haven’t verified it from the Cisco docs yet but wanted here FYI.
13. AnonymousJanuary 13th, 2011
lpc
14. khalujJanuary 14th, 2011
regarding question 6,** S 10.1.1.0 is directly connected, Serial1 -this entry should indicate C as routing sourceinstead of S, since its a directly connected to its local interface
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