Cetking Shortcuts Visual Geometry Workshop

8/11/2019 Cetking Shortcuts Visual Geometry Workshop

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To join Classroom or online program call 09820500380 or see details cetking.com

VisualGeometry


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1 of 12 workshop seriesQuant cutoff clearing:1. Visual Geometry2. Vedic Numbers3. Equations Polynomials4. Dirty (Modern) Quant5. Arithmetic6. DI Without Pen

Verbal cutoff clearing:1. RC in half time2. Grammar/Sentence Cor3. Vocab & FIBs4. Paragraph Comp & Jum5. Critical Reasoning6. Logical Reasoning

VisualGeometry


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Homework before workshop

Try these questionswithout using pen!


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Scope Angles Circles Triangles Theorems Triangles Similar/Cong Mensuration Areas Mensuration Volume Trigonometry Geometry Coordinate Geometry


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Importance


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Geometry Angles Circles Triangles Theorems Triangles Similar/Cong Mensuration Areas Mensuration Volume Trigonometry Geometry Coordinate Geometry

VisualGeometry

Angles Side Area


7/70To join Classroom or online program call 09820500380 or see details cetking.comTo join Classroom or online program call 09820500380 or see details cetking.com

1.Uniform Figures

2.Triple Delight

3.Draw Lines

4.Scale drawing

5.Angular6.Drawing to scale

7.Trigonometry

8.Areas9.Volumes

10.Circles in C

VisualGeometry



AB BC, BD AC and CE bisectsC, A = 30. Then what is CED?

a. 30 b. 60 c. 45 d. 65



Find the area bigger circle A?1. 4

2. 63. 84. 3

A



Total circumference of smaller circlesIf the diameter of the biggest circle

is 20m1. 402. 203. 18

4. 30



Ratio of shaded to unshaded areaIf the diameter of the biggest circle

is 20m1. 2:12. 1:13. 1:3

4. 2:3


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VIRTUALPOSITIONING



a)25b)35c)45

d)55


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To join Classroom or online program call 09820500380 or see details cetking.comTo join Classroom or online program call 09820500380 or see details cetking.com

PQRS is a square. SR is a tangent (at point S)to the circle with centre O and TR = OS. Thenthe ratio of area of the circle to the area of

the square is


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In ABC, B is a right angle, AC = 6cm, and D is the mid-point of AC. The

length of BD is


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From a circular sheet of paper with a

radius 20 cm, four circles of radius 5cm each are cut out. What is the ratioof the uncut to the cut portion?

a. 1 : 3 b. 4 : 1c. 3 : 1 d. 4 : 3


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Given:AC = BD

AD = 15AE = 9

Find the area of trapezium?

1. 1082. 6123. 1124. 152


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Circle in squareFinding RadiusFinding Area

CAT2004


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Consider two different cloth-cutting processes. Inthe first one, n circular cloth pieces are cut from asquare cloth piece of side a in the following steps:

the original square of side a is divided into nsmaller squares, not necessarily of the same size;then a circle of maximum possible area is cut fromeach of the smaller squares. In the second

process, only one circle of maximum possible areais cut from the square of side a and the processends there. The cloth pieces remaining aftercutting the circles are scrapped in both theprocesses. The ratio of the total area of scrap clothgenerated in the former to that in the latter is:

1 : 1 2. \/2 : 1

3. n(4 - n)/(4n - n) 4. (4n -n)/n(4 - n)

CAT2004


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Circle of radius 2 is placed against a

right angle. Another smaller circle isalso placed as shown. What is theradius of the smaller circle?

a. 3-22b. 4-22c. 7-42

d. 6-42


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The figure shows the rectangle ABCD with asemicircle and a circle inscribed inside in it as

shown. What is the ratio of the area of thecircle to that of the semicircle?


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a) 20

b) 30c) 50d) 60

Find ADE angle


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The figure shows a circle of diameterAB and radius 6.5 cm. If chord CA is

5 cm long, find the area of ABC.

a. 60 sq. cm b. 30 sq. cmc. 40 sq. cm d. 52 sq. cm


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In ACD, AD = AC and C = 2 E. The

distance between parallel lines AB and CD is h.Then:I. Area of parallelogram ABCDII. Area of ADE.

Mark (a) if I > II.Mark (b) if I < II.

Mark (c) if I = II.Mark (d) None


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a. 12 cm b. 15 cm c. 8 cm d. 11c m


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What is the length of rectangle ABCD?I. Area of the rectangle is 48 square units.

II. Length of the diagonal is 10 units.

a. if I alone.b. if II, alone.c. if both statementd. None

The length of a ladder is exactly equal to the


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The length of a ladder is exactly equal to theheight of the wall it is learning against. If lowerend of the ladder is kept on a stool of height 3 m

and the stool is kept 9 m away from the wall,the upper end of the ladder coincides with thetop of the wall. Then the height of the wall is

a. 12 m b. 15 m c. 18 m d. 11 m


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In ABC, B is a right angle, AC = 6cm, and D is the mid-point of AC. The

length of BD is

In a right angled triangle median is equal to half of the hypotenuse


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In the given figure, EADF is a rectangle andABC is a triangle whose vertices lie on the sidesof EADF and AE = 22, BE = 6, CF = 16 and BF

= 2. Find the length of the line joining the mid-points of the sides AB and BC.a. 42 b. 5 c. 3.5 d. None of these


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QR is parallel to ST.What is the length of PR?a) 4.8 b) 3.2c) 5.7 d) 4.2


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k1, k2, k3 are parallel lines. AD = 2 cm,BE = 8 cm and CF = 32 cm.I. (AB)(EF)II. (BC)(DE)

Mark (a) if I > II.Mark (b) if I < II.Mark (c) if I = II.Mark (d) None


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In the adjoining figure, points A, B, C andD lie on the circle. AD = 24 and BC = 12.

What is the ratio of the area of CBE tothat of ADE?a. 1 : 4 b. 1 : 2

c. 1 : 3d. Data insufficient


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In ABC, points P, Q and R are themid-points of sides AB, BC and CA

respectively. If area of ABC is 20 sq.units, find the area of PQR.

a. 10 sq. unitsb. 53 sq. unitsc. 5 sq. units

d. None of these


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Find the area of the shadedtriangle to that of the complete triangle

a) 1/8 b) 1/32c) 1/16 d) Cannot be det


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What is the length of rectangle ABCD?I. Area of the rectangle is 48 square units.

II. Length of the diagonal is 10 units.

a. if I alone.b. if II, alone.c. if both statement

d. None


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Find the height of the string d?a) 3003 b) 600

c) 300 d) 4003e) 2003

d


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Find the distancebetween the posts d?a) 3003 b) 600c) 300 d) None of th.


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In the figure below, What is the ratio

of the area of the sector to that of thecircle

a) 1/12 b) 1/6

c) 1/24 d) 1/2


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of the area of the shaded region tothat of the rectangle with Length 20and breath 10.

a) 1/2 b) 1/6c) 1/4 d) 1/12

Cut and adjust


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a) 1/2 b) 1/6

c) 1/4 d) 1/8


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a) 1/2 b) 1/6c) 1/4 d) 1/12


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a) 1/2 b) 5/6

c) 3/4 d) 3/8


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In the figure below, ABCDEF is aregular hexagon. What is the ratio of

the area of the triangle ACE to that ofthe hexagon ABCDEF? a)1/12 b) 1/6

c) 1/24 d) 1/2


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In the figure below, ABCDEF is a

regular hexagon and angle AOF =90. FO is parallel to ED. What is theratio of the area of the triangle AOF to

that of the hexagon ABCDEF? CAT 2003a) 1/12 b) 1/6

c) 1/24 d) 1/18


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In the figure below, ABCDEF is aregular hexagon. Find the area of

shaded region if the area of hexagonis 600?

a) 200 b) 600

c) 300 d) 180


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In the figure below, Find the area

of shaded region I and II if the side of

the square is 20m?a) 200 b) 60

c) 300 d) 50


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In the adjoining figure, points A, B, C andD lie on the circle. AD = 24 and BC = 12.

What is the ratio of the area of CBE tothat of ADE?a. 1 : 4 b. 1 : 2

c. 1 : 3d. Data insufficient


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Coordinate


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Equation of line joining two points

Find the equation of the line passing

through (-1,-2) & (-5,2)(a) 2x + y = 3

(b) 3x - 2y + 7 = 0

(c) x + y + 3 = 0

(d) None of these

Two Point Form:

(y + 2)/(-2-2) = (x +

1)/(-1+5)4(y + 2) = -4 (x + 1)y + 2 = -x -1x + y = -3Option (c)


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Equation of line joining two points

Find the equation of the line passingthrough (2,-4) & (-3,2)

(a) 2x + y = 3

(b) 6x - 5y + 7 = 0

(c) 5x + 6y + 3 = 0

(d) None of these

Two Point Form:

(y - 2)/(2+4) = (x +3)/(-3 - 2)

-5(y - 2) = 6(x + 3)-5y + 10 = 6x +186x + 5y = -8Option (d)


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Equation using slope and point

Find the equation of line passing through

point (2,-3) having slope 5/4.(a) 4x - 5y = 20

(b) 3x 2y = 5(c) 5x - 4y = 22

(d) None of these

(y - y1) = m (x-

x1)(y + 3) = 5/4 (x -2)4y + 12 = 5x -105x - 4y = 22Option (c)Note: Sometimes angle will be given. Slope can be

found as tan


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Point of intersection of two lines

Point of intersection of 2x + y = 4 and x - y+ 1= 0

a) (3, 1)

b) (1, 2)

c) (3, 2)d) (1, 4)

Solution of two equations is thepoint of intersection3x = 3x=12 + y = 4y = 2

Solution: (1 ,2)


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Distance between points

Find the distance between (7, 5) & (4, 1)a) 5

b) 5 2c) 7 3d) 10


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Distance between points

Find the distance between

(4, 2) & (6, 6)a) 5

b)4.47c) 4.14

d)4.65


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Equation of parallel

Find the equation of the line passing throughpoint (2,7) and parallel to 2x + 3y + 8= 0

a) 5x - 2y = 17

b) 2x + 3y = 25

c) 2x + 3y = -4

d) 4x + 6y = -16

Slope of options (b), (c)

and (d) match thecondition of parallelismOnly option (b) satisfies(2,7)


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Equation of perpendicular

Find the equation of the line passing throughpoint (2,7) and perpendicular to 2x + 3y +8= 0

a) 5x 2y = 17b) 3x + 2y = 20

c) 3x 2y = -4d) 6x 4y = -16 Slope of options (c)

and (d) match thecondition ofperpendicularityOnly option (d)

satisfies (2,7)


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Equation of perpendicular

Find the equation of the line passing throughpoint (-4,-9) and perpendicular to 3x - 5y +8= 0

a) 5x 2y = 17b) 10x + 6y = 20

c) 3x y = -4d) -5x 3y = 47 Slope of options (c)

and (d) match thecondition ofperpendicularityOnly option (d)

satisfies (2,7)

G t


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Geometry Angles

Circles Triangles Theorems Triangles Similar/Cong Mensuration Areas Mensuration Volume Trigonometry Geometry Coordinate Geometry

VisualGeometry

Angles Side Area


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1.Uniform Figures

2.Triple Delight

3.Draw Lines

4.Scale drawing

5.Angular6.Drawing to scale

7.Trigonometry

8.Areas9.Volumes

10.Cir in Cir

VisualGeometry


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To joinClassroom or online

program

call 09820500380 orsee details cetking.com

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Cetking Shortcuts Visual Geometry Workshop

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