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Computational Fluid Dynamics
Natteri M. Sudharsan, PhD.
Natteri M Sudharsan, Ph.D., 2
CFD – A part of Knowledge Based Economy
Computational Fluid Dynamics (CFD) and Computational Structural Mechanics (CSM) is the study of fluid and structures subjected various external / internal flow and/or load conditions.
CFD is used in various fields such as: Aerospace AutomobileBio-medical
OceanOil and GasPower EngineeringTurbomachineryFluid – Structure InteractionEnvironmental Agencies
Natteri M Sudharsan, Ph.D., 3
Aerospace Applications
External Aerodynamics (all speed regimes)
High Lift Internal Flows Thermal Management Aero acoustics Stability and Control Tank Sloshing
Plume Analysis Multi-Species Propeller Simulation Heat Exchangers Fluid Structure
Interaction (FSI) Combustion
KEY APPLICATIONS INCLUDE
Natteri M Sudharsan, Ph.D., 4
CFD Simulations in Aerospace
Plume Analysis
Natteri M Sudharsan, Ph.D., 5
HIGH LIFTROTORCRAFT
Natteri M Sudharsan, Ph.D., 6
Environmental Control Systems
Natteri M Sudharsan, Ph.D., 7
Automotive Applications
Fuel Injection – Break-up
Natteri M Sudharsan, Ph.D., 8
Thermal Stress Analysis on Cylinder Head
Natteri M Sudharsan, Ph.D., 9
Valve Simulation
After Treatment Devices for Pollution Control
Natteri M Sudharsan, Ph.D., 10
Under the Hood
Natteri M Sudharsan, Ph.D., 11
Comfort
Natteri M Sudharsan, Ph.D., 12
Brake Cooling
Natteri M Sudharsan, Ph.D., 13
Biomedical Applications
Grid Generation from MRI Scan
Natteri M Sudharsan, Ph.D., 14
Streamline flow of Blood
Natteri M Sudharsan, Ph.D., 15
Building Applications
Fire & Smoke Modeling
Heating Ventilation and Air conditioning
Pollutions Dispersion Modeling
Natteri M Sudharsan, Ph.D., 16
Turbomachinery
Pelton Wheel Simulation
Natteri M Sudharsan, Ph.D., 17
Wind Turbine
Power – conventional vs. Shrouded Turbine
Natteri M Sudharsan, Ph.D., 18
Environmental Applications
ELECTROSTATIC PRECIPITATOR
Natteri M Sudharsan, Ph.D., 19
Forest Fire & Control
Natteri M Sudharsan, Ph.D., 20
Chemical Applications
Break-up and coalescence of bubbles
Natteri M Sudharsan, Ph.D., 21
Spray Dryer
Natteri M Sudharsan, Ph.D., 22
CFD Aided Design of HDDs
Objectives:•Identify the flow characteristics in HDDs at high rotating speed
•Seek solutions to reduce the flow-induced vibration of arms
Natteri M Sudharsan, Ph.D., 23
Governing Equations&
Numerical Methods
Natteri M Sudharsan, Ph.D., 24
Summary1. Derivation of Governing Equations for Energy.
2. Behavior of these Equations.
3. The three numerical schemes.
4. Discretization for transient problems.
5. Convection – Diffusion Equation and schemes.
Natteri M Sudharsan, Ph.D., 25
Derivation of Energy Equations Consider a control volume of Area A and length ∆x. The energy balance is given as:
Heat in = Heat out qx + g’’’ = q x+∆x + qconv + qrad (1)
Natteri M Sudharsan, Ph.D., 26
Figure: 1 Energy balance in a control volume
qx qx+∆x
∆x
g”’
qconv+ qrad
Natteri M Sudharsan, Ph.D., 27
Steady State Heat Conduction
Neglecting convective and radiation loss and for a steady state heat conduction with no internal heat generation g’’’, the energy balance simplifies as
qx = q x+∆x (2)
Using Taylor series expansion to estimate q x+∆x we have,
...x)(qdxd
!x)(q
dxdqq xxxΔxx +∆+∆+=+
22
2
21
Natteri M Sudharsan, Ph.D., 28
Neglecting higher order terms, we get,
(3)
Substituting the Taylor series expansion for qx+∆x In (2) yields
( ) xqdxdqq xxxx ∆+=∆+
( )
dxdTkAq
xqdxdqq
x
xxx
−=
∆+=
0=∆
− x
dxdTkA
dxd
(4)
Natteri M Sudharsan, Ph.D., 29
Assuming k and A to be constants (4) becomes
02
2
=∆− xdx
TdkA
since k, A or ∆x cannot be zero, in coordinate invariant form yields:
02 =∇ T
This is a 2nd order Linear PDE. Classified as Laplace equation.
Natteri M Sudharsan, Ph.D., 30
Steady State Heat Conduction with Internal Heat Generation
Assuming that there is internal heat generation within the control volume, equation (1) simplifies to qx + g’’’ = q x+∆x (5)
(6)
( )
02
2
=+
−=
∆+=∆+
kg
dxTd
dxdTkAq
xqdxdqxAgq
x
xxx
'''
'''
Natteri M Sudharsan, Ph.D., 31
Steady State Heat Conduction with Convection
Heat in = Heat out by conduction + Convection
L
∅ d
Natteri M Sudharsan, Ph.D., 32
02
2
=−−
−∆+∆
−+=
−∆+=
∞
∞
∞∆+
)(
)(
)(
TTkAhP
dxTd
TTxhPxdxdTkA
dxdqq
TTxhPqq
xx
xxx
Let,
222 dXLdxanddXLdxdTTdTLxX
TTTT
b
b
==−=
=−−=
∞
∞
∞
;)(
;
θ
θ
(7)
Natteri M Sudharsan, Ph.D., 33
Substituting in (7) we get,
( ) 02
2
2 =−+−−−∞∞∞
∞ TTTTkAhP
dxd
LTT
bb )()( θθ
022
2
=− θθ )(mLdxd (8)
Fin tip boundary condition is convective then
)(,
)(
θθθθ Bik
hLkhL
dXd
TThAdxdTkA
=−=
−=− ∞
Natteri M Sudharsan, Ph.D., 34
Steady state heat conduction with radiation
0442
2
=−− ∞ )( TTPdx
TdkA σ ε
Slug Flow
Tx Tx+∆x
Natteri M Sudharsan, Ph.D., 35
xxpxxxpx AUTCqAUTCq ∆+∆+ +=+ |||| ρρ
αθθ
θ
α
ρ
ULPedXdPe
dXd
TTTT
LxX
dxdTU
dxTd
AUdTCxdx
TdkA
iL
i
p
==
−−==
=
=∆
,
,
2
2
2
2
2
2
Natteri M Sudharsan, Ph.D., 36
Unsteady Heat Conduction
Heat in = Heat out + Heat stored Heat in – Heat out = Heat stored
Heat stored is τρ
∂∂∆=
• TxCAdTCm pp
.
τα
∂∂=
∂∂ T
xT2
2
Heat in – Heat out = 2
2
dxTdxkA∆
Natteri M Sudharsan, Ph.D., 37
DISCRETIZATION METHODS
Finite Difference Method
211
211
3
33
32
2
2
33
32
2
2
02
31
2
322
31
21
31
21
hh
yyy
hyyh
yy
hyhyhxyhxy
hdx
ydhdx
ydhdxdyxyhxy
hdx
ydhdx
ydhdxdyxyhxy
ii
ii
)('
!'
!')()(
...!!
)()(
...!!
)()(
'''
'''
+−=
+=−
+=−−+
+−+−=−
++++=+
−+
−+
i-2 I -1 ∆x i i+1 i+2
Natteri M Sudharsan, Ph.D., 38
The above is known as central difference. Theforward or backward difference for y’ can beobtained from yi and yi+1 or yi and yi-1 to yield
)(' xx
yyy ii ∆+∆
−= + 01 )(' xxyyy ii ∆+
∆−= − 01and
Similarly forward difference for y” is given as:-
212
212
32
32
22
2231
21
2312
2122
xyyyy
xyyyyhxyfromsubtractandbyhxyMultiply
hyhyhyyhxy
hyhyhyyhxy
iiii
iiii
iiii
iiii
∆+−=
∆+−=−++
+++=+
+++=+
++
++
''
''
''''''
''''''
)()()(
)(!
)(!
)()(
)(!
)(!
)()(
Natteri M Sudharsan, Ph.D., 39
Backward difference
211 2
xyyyy iii
i ∆+−= +−''Central difference using
y(x+h) and y(x-h) yields
2212
xyyyy iii
i ∆+−= −−''
Non uniform grid size discretization
i-1 i i+1
2
2
211
2
2
2
11
2
2
2
1
22
2
2
1
21
1211
2
2
xT
axaaTTaT
axaxTTaaTT
xxTx
xTTT
xaxTxa
xTTT
iii
iii
ii
ii
∂∂=
+∆++−
+∆∂∂++=+
∆∂∂+∆
∂∂+=
∆∂∂+∆
∂∂−=
+−
+−
+
−
)()(
)()(
)(
)(
Let the distance from node i-1 to i be a∆x and i to i+1 be ∆x.
Natteri M Sudharsan, Ph.D., 40
W P Ew e
∆xwP
∆xPE∆xWP
∆xPe
FVM Formulation
Natteri M Sudharsan, Ph.D., 41
Γ
Γ+=
−+=
++=
=∆+∆−
∆
−Γ−
∆
−Γ
=+−
Γ
++
ofbehaviourtheondependingmeanharmonicormeanarithmeticbemay
SSSaslinearizedisSourceTheWhereSaaa
Saaa
xSxnxx
yieldsabovethegIntegratin
Sndxd
dxd
wore
uPP
PewP
uEeWwPp
PewPPewPPWP
WPw
PE
PEe
)()(
)()(
)(
φ
φφφ
φφφφφ
φφ
0
0
Natteri M Sudharsan, Ph.D., 42
The 4 rules of Finite Volume
• Ensure that the flux across the face common to the two control volumes is represented by the same expression.
• Coefficients of ap and its neighbors should always be positive.
• SP should always be negative, at best should be less than 1.
• aP should be sum of all neighbors anb.
Natteri M Sudharsan, Ph.D., 43
Discretization for Transient Problems
)()(
;
PewP
n
WP
WPw
PE
PEe
n
WP
WPw
PE
PEe
nP
nP
p
xSxx
xx
yieldsabovethegIntegratinck
xx
+
++
∆+
∆
−Γ−∆
−Γ−
+
∆
−Γ−∆
−Γ=
∆
−
=Γ∂∂=
∂∂Γ
∂∂
φφφφβ
φφφφβτ
φφρ
τφρφ
1
11
Where β = 0 is Explicit and β = 1 is Implicit
Natteri M Sudharsan, Ph.D., 44
W P Ew e
∆xwP
∆xPE∆xWP
∆xPe
Convection – Diffusion Equation
Represents Upwind Formulation
Natteri M Sudharsan, Ph.D., 45
)(/;/;
)()()()(
)()(
weewp
eeewwwEeWwPp
WPwPEeWPw
PEe
WP
WPw
PE
PEewwee
FFaaaFDaFDaaaa
DDFFSchemeCD
xDanduFLetxx
uu
yieldsgIntegratindxd
dxd
dxdu
−++=
−=+=+=
−−−=+−+
∆Γ==
∆
−Γ−
∆
−Γ=−
Γ=
2222
φφφ
φφφφφφφφ
ρ
φφφφφρφρ
φφρ
CD Scheme Limitation F/D i.e. Pe less than 2
Natteri M Sudharsan, Ph.D., 46
Upwind Scheme
eeeww
eewww
PwEe
PeWw
FDaandDahaveWeFDaandFDahaveWeF
andhaveWeFandhaveWeF
−==<=+=>
==<==>
0000
φφφφφφφφ
Note: CD Scheme gives rise to artificial diffusion. Good for Pe < 2, hence ∆x needs to be small to ensure low Pe. Upwind gives reasonable results for higher Pe number. A hybrid scheme or power law can also be used.
Natteri M Sudharsan, Ph.D., 47
Fluid Mechanics
Natteri M Sudharsan, Ph.D., 48
TYPES OF FLUIDIdeal Fluid – Incompressible ‘zero viscosity’ fluid – Imaginary fluid.Real Fluid – Fluid with viscosityNewtonian – shear stress in proportional to ‘strain rate’ - grad V.Non – Newtonian – Ideal Plastic – shear stress in more than yield value and is proportional to strain rate.
Natteri M Sudharsan, Ph.D., 49
Linear translation refers to bodily movement of fluid element with out deformation
Linear deformation refers to deformation in linear direction with axis remaining parallel
Natteri M Sudharsan, Ph.D., 50
Angular deformation refers to average change contained by 2 adjacent sides
( )
∂∂+
∂∂=
∆+∆=
yu
xvratestrainshearOr
ndeformatioAngular
21
21
21 θθ
Natteri M Sudharsan, Ph.D., 51
Pure rotation occurs when fluid particle rotates such that both axis moves with the same magnitude and direction
∂∂−
∂∂=
∂∂−
∂∂=
∂∂−
∂∂=
xw
zu
zv
yw
yu
xv
yxz 21
21
21 ωωω ;;
The rotational components are given as
ω2orVisVorticity ×∇
Natteri M Sudharsan, Ph.D., 52
Reynold’s Transport TheoremConsider a fluid mass occupying an arbitrary volume. Let Φ be a transported quantity, and φ its intensive property, i.e. φ = Φ/m.
Let Sp be the space occupied by the fluid and cv the control volume overlapping fluid space Sp.
Natteri M Sudharsan, Ph.D., 53
∫ ∫==Φ)(
)()(tSp cv
dVdV ρ φρ φ
∫∫
∫ ∫•∇=•
•+∂∂=Φ
cvcs
cv cs
dVudSnu
dSnudVtdt
d
)()(
)()(
ρ φρ φ
ρ φρ φ
By Gauss divergence theorem
Natteri M Sudharsan, Ph.D., 54
u
Sp(∆ t) Sp(t+∆ t)
CV
Amount of fluid containedin time in time,t, is
∫)(
)(tsp
t dVρ φ
PROOF
Natteri M Sudharsan, Ph.D., 55
Thus from time t to t+∆t we have
∫ ρ φ)t(sp
t dV)( ∫∆+
∆+ρ φ)tt(sp
tt dV)(
The increment ∆Φ = Φ(t+∆t) - Φ(t) =
∫−)(
)(tsp
t dVρ φ ∫∆+
∆++)(
)(ttsp
tt dVρ φ
Natteri M Sudharsan, Ph.D., 56
this can be re-written as
∫∫
∫∫ρ φ−ρ φ
+ρ φ−ρ φ
∆+
∆+∆+
∆+
)t(spt
)t(sptt
)t(sptt
)tt(sptt
dV)(dV)(
dV)(dV)(
The first two terms deals with the deformation of the fluid and will occur at the rate of fluid velocity = u.n ds
Natteri M Sudharsan, Ph.D., 57
∫ ρ φcs
u)( dSn.
The next two terms yields ∫ ∆ρ φ∂∂
)t(sp
tdV)(t
Thus proved.
∫∫
∫ ∫ρ φ•∇=•ρ φ
•ρ φ+ρ φ∂∂=Φ=
∆∆ Φ
cvcs
cv cs
dV)u(dSnu)(
dSnu)(dV)(tdt
dt
Lim
Natteri M Sudharsan, Ph.D., 58
Derivation of Continuity Equation
Let Φ the transported quantity be mass, m, the intensive property φ = Φ/m =1. Law of conservation of Mass
0tt
m =∂Φ∂=
∂∂
0ndSudV)(t csCV
=•ρ+ρ∂∂
∫∫
Natteri M Sudharsan, Ph.D., 59
Hence , using Gauss divergence theorem we have,
0dV)u(tcv
=
ρ•∇+
∂ρ∂
∫For an incompressible fluid we have
0u. =∇
Natteri M Sudharsan, Ph.D., 60
Momentum Equation
By Newton’s II law, the rate of change of momentum is equal to the total force (both surface and body forces ) ∫
cv
dV.X
Natteri M Sudharsan, Ph.D., 61
Normal and shear components are given in figure below. I subscript refers to the plane at which force acts x – YZ plane.II subscript refers to the direction.
σxy
σxx
σyx
σyy
Natteri M Sudharsan, Ph.D., 62
ds dydx
Resolving the horizontal forces we have, dxdy yxxx ×σ−×σ
dxdy yyxy ×σ−×σAnd vertical forces =
Natteri M Sudharsan, Ph.D., 63
nx=dy/ds and ny= - dx/ds or [dy -dx] = n.dsThus the external forces can be written as n.σ ds
[ ]
σσσσ
×−yyyx
xyxxdxdy
Natteri M Sudharsan, Ph.D., 64
The surface + body forces =
Letting Φ to be momentum, mu, and φ=mu/m = u. Thus the rate of change of momentum
∫ ∫+σ•cs cv
dVXdsn
( ) dVXdtd
cv∫ +σ•∇=Φ
Natteri M Sudharsan, Ph.D., 65
dV)uu()u(tdt
d
cv∫
ρ•∇+ρ
∂∂=Φ
from Reynolds transport theorem we have
and equating this rate of change of momentum to the forces =
( ) dVXcv∫ +σ•∇
X)uu()u(t
+σ•∇=ρ•∇+ρ∂∂
Natteri M Sudharsan, Ph.D., 66
X
uuu.utu
tu
+σ•∇=
∇•ρ+ρ∇+∂∂ρ+
∂ρ∂
Taking the first and third term in LHS and second and fourth term of LHS we have,
Xuutuu
tu +σ•∇=
∇•+
∂∂ρ+
ρ•∇+
∂ρ∂
Natteri M Sudharsan, Ph.D., 67
By continuity equation the first term of LHS is equal to zero. Thus,
Xuutu +σ•∇=
∇•+
∂∂ρ
Now connect the equation by substituting σ with known quantities viz. pressure and velocity.
Natteri M Sudharsan, Ph.D., 68
( )
=
=
2
2
2
wwvwuvwvvuuwuvu
wvuwvu
uu
( ) Dz/wz/vz/uy/wy/vy/ux/wx/vx/u
wvuz/y/x/
u =
∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂
=
∂∂∂∂∂∂
=∇
zw
yv
xuu
∂∂+
∂∂+
∂∂=•∇
Natteri M Sudharsan, Ph.D., 69
A B
D C
A’
C’D’
B’ δ2
δ1
It moves to a position A’B’C’D’.
Consider a fluid volume ABCD in space
Natteri M Sudharsan, Ph.D., 70
Although the volume is conserved there is a strain in x and y direction as well as angular movement.
Strain, . xxx ∂ε∂=ε
Strain rate is given as,
xxx
xx
.u
txxtt=
∂ε∂
∂∂=
∂ε∂
∂∂=
∂ε∂
=ε•
yyy v=ε•
zzz w=ε•
Natteri M Sudharsan, Ph.D., 71
The angular movement , ( )21
.
xy 21 δ+δ=ε
xand
yWhere
21
21
.
21xy∂
η∂=δ∂
ε∂=δ
δ+δ=ε
•••••
( )xyxy
x2y1
vu21
vxt
uyt
+=ε
=
∂η∂
∂∂=δ=
∂
ε∂∂∂=δ
•
••
Natteri M Sudharsan, Ph.D., 72
If the fluid undergoes net rotation it is given by
( ) ( ) uuvt yx12 ×∇=−=δ−δ
∂∂
also known as vorticity ω.
Thus the full strain tensor is given as,
[ ]T
zzzyzx
yzyyyx
xzxyxx
DD +=
•••
•••
•••
21
εεε
εεε
εεε
Natteri M Sudharsan, Ph.D., 73
=
∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂
=
zzz
yyy
xxx
wvuwvuwvu
z/wz/vz/uy/wy/vy/ux/wx/vx/u
D
Constitutive relation as per Hooke’s Law is ε=σ ]E[
For a Newtonian Fluid its given as:
( ) ijijkkdij 2p µ ε+δλ ε+−=σ
εkk=εxx+εyy+εzz=∇•u
Natteri M Sudharsan, Ph.D., 74
Thus, ( ) ijijdij 2up µ ε+δ•∇λ+−=σ
The negative sign for p ensures positive flow along decreasing slope. pd stands for thermodynamic pressure, which includes the rotational and vibrational modes of energy as well as the mechanical pressure related to the translation energy (kinetic energy) of molecules.
Natteri M Sudharsan, Ph.D., 75
p = static pressure = - (σxx+σyy+σzz)/3 which is the mechanical energy related to translation of kinetic energy of molecules.
The constitutive equation can be written as
Natteri M Sudharsan, Ph.D., 76
)uw(212)uw(&
)vw(212)vw(&
)uv(212)uv(&
w2upv2upu2up
zxzxxzxz
zyzyyzzy
yxyxyxxy
zdzz
ydyy
xdxx
+µ×=+µ=σσ
+µ×=+µ=σσ
+µ×=+µ=σσ
µ+•∇λ+−=σ
µ+•∇λ+−=σµ+•∇λ+−=σ
Natteri M Sudharsan, Ph.D., 77
Since σxx+σyy+σzz= -3p
Adding the constitutive equations yields -3p= - 3pd+3λ∇•u+2µ(∇•u) pd – p = ∇•u(λ + 2/3µ)
For incompressible flow ∇•u = 0, therefore pd = p. (3λ + 2µ) is called the Bulk viscosity.
Natteri M Sudharsan, Ph.D., 78
By Stoke’s hypothesis setting bulk viscosity = 0 yields λ = - 2/3µThus,
δ•∇−εµ+δ−=σ ijijijij u
322p
Thus,
δ•∇−嵕∇+∇−=
+σ•∇=
∇•+
∂∂ρ
ijij u312pX
Xuutu
Natteri M Sudharsan, Ph.D., 79
For isothermal and incompressible flow ∇•u = 0, hence the III term in LHS equation simplifies as
( )
+•∇=•∇ jiijij εεµεµ212)(2
Natteri M Sudharsan, Ph.D., 80
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂
•∇=
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂
•∇
zw
yw
zv
xw
zu
yw
zv
yv
xv
yu
xw
zu
xv
yu
xu
zw
yw
zv
xw
zu
yw
zv
yv
xv
yu
xw
zu
xv
yu
xu
µµµ
µµµ
µµµ
µ
2
2
2
21
21
21
21
21
21
2
Natteri M Sudharsan, Ph.D., 81
∂∂
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂+
∂∂
∂∂
=
zw
zyw
zv
yxw
zu
x
yw
zv
zyv
yxv
yu
x
xw
zu
zxv
yu
yxu
x
µµµ
µµµ
µµµ
2
2
2
∂∂∂+
∂∂∂+
∂∂+
∂∂+
∂∂
∂∂∂+
∂∂∂+
∂∂+
∂∂+
∂∂
∂∂∂+
∂∂∂+
∂∂+
∂∂+
∂∂
=
zyv
zxu
yw
xw
zw
zyw
yxu
zv
xv
yv
zxw
yxv
zu
yu
xu
22
2
2
2
2
2
2
22
2
2
2
2
2
2
22
2
2
2
2
2
2
2
2
2
µµµµµ
µµµµµ
µµµµµ
Natteri M Sudharsan, Ph.D., 82
∂∂+
∂∂∂+
∂∂∂++
∂∂+
∂∂+
∂∂
∂∂∂+
∂∂+
∂∂∂+
∂∂+
∂∂+
∂∂
∂∂∂+
∂∂∂+
∂∂+
∂∂+
∂∂+
∂∂
=
2
222
2
2
2
2
2
2
2
2
22
2
2
2
2
2
2
22
2
2
2
2
2
2
2
2
zw
zyv
zxu
zw
yw
xw
zyw
yv
yxu
zv
yv
xv
zxw
yxv
xu
zu
yu
xu
µµµµµµ
µµµµµµ
µµµµµµ
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂+
∂∂
=
zw
yv
xu
zzw
yw
xw
zu
yu
xu
yzv
yv
xv
zw
yv
xu
xzu
yu
xu
µµµµ
µµµµ
µµµµ
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
Re-arranging, we get:
Natteri M Sudharsan, Ph.D., 83
But the sum in brackets at the end of each row is the divergence of the velocity, which is zero for Incompressible Flow.
zw
yv
xuv
∂∂+
∂∂+
∂∂=•∇
u
zw
yw
xw
zv
yv
xv
zu
yu
xu
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
∇=
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂
∂∂+
∂∂+
∂∂
= µµ
Natteri M Sudharsan, Ph.D., 84
upXuutu
0u
2∇µ+∇−=
∇•+
∂∂ρ
=•∇
( )u
jiijij
2
212)(2
∇=
+•∇=•∇
µ
εεµεµ
Thus,
We therefore have:
Natteri M Sudharsan, Ph.D., 85
For a creeping flow, neglecting inertial terms yields the Stokes equation:-
Xuptu 2 +∇µ+− ∇=
∂∂ρ
For high fluids with high inertial terms the viscous terms can be neglected to yield the Euler equation:-
pXuutu ∇−=
∇•+
∂∂ρ
Natteri M Sudharsan, Ph.D., 86
Integrating Euler equation over time yields the Bernoulli equation
Where, p* = p + X and
*puu − ∇=∇•ρ
( )
∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂∂
=∇•z/wz/vz/uy/wy/vy/ux/wx/vx/u
wvuuu
Natteri M Sudharsan, Ph.D., 87
∂∂+∂∂+∂∂∂∂+∂∂+∂∂∂∂+∂∂+∂∂
=∇•∴z/wwy/wvx/wu
z/vwy/vvx/vuz/uwy/uvx/uu
uu
We have seen the derivation of the Navier-Stokes Equation and the simplification of the equation to yield the Stokes, Euler and Bernoulli equation.
Natteri M Sudharsan, Ph.D., 88
Slug Flow using Reynold’s Transport Theorem
Γ==== UL
kULCULPe
Ck P
p
ρραρ
α ,PC
k=Γ
Continuity Equation
0=∂
∂+∂
∂ )( jj
uxt
ρρ
Generalized Transport Equation
( ) ( ) Sxx
uxt jj
jj
+
∂∂Γ
∂∂=
∂∂+
∂∂ φφρρ φ
Natteri M Sudharsan, Ph.D., 89
Let density remain constant and let φ =CpT and Assuming 1-D and constant velocity, U,
2
2
xT
xTU
tT
∂∂Γ=
∂∂+
∂∂ ρρ
dividing by density and for steady state
2
2
xT
xTU
∂∂=
∂∂
α
αθθ
θ
ULPedXdPe
dXd
TTTT
LxX
iL
i
==
−−==
,
,
2
2
Natteri M Sudharsan, Ph.D., 90
Boundary layer
Natteri M Sudharsan, Ph.D., 91
Boundary Layer Flows
Flow around bodies immersed in a fluid streamFlow will have viscous effects near body surface, inviscid in far fieldFlow is unconfined unlike pipe flowField of study – Aerodynamics, Hydrodynamics, Transportation, Wind engineering (Tall structures) etc.,
Natteri M Sudharsan, Ph.D., 92
Boundary layer analysis can be used to compute viscous effects near wall and patch the results to the outer inviscid motion. This patching is successful for large Re.
Consider figure with Re = 10. The fluid flow is retarded greatly with thick shear layer.
Natteri M Sudharsan, Ph.D., 93
Re 1 to 1000
Natteri M Sudharsan, Ph.D., 94
Flows with thick shear layers do not have simple theory for performing analysis.
Low range Re flows are studied experimentally or numerically (computational fluid dynamics).
Natteri M Sudharsan, Ph.D., 95
Turbulent Flow – Re=10
Very Thin boundary layer – Amenable to boundary layer patching (Prandtl,1904)
Natteri M Sudharsan, Ph.D., 96
The three regions in the boundary layer are:
1. The Wall Layer: Viscous shear dominates
2. Outer Layer: Turbulent shear dominates
3. Overlap Layer: Both shear types are important.
Natteri M Sudharsan, Ph.D., 97
Laws relating to Velocity Profile
VelocityFrictionalu w ,ρ
ττ =
Natteri M Sudharsan, Ph.D., 98
Linear Sub Layer y+<5 Law of the wall
wyuy τµτ ≈
∂∂=)(
Integrating with B.C’s u =0, y=0, gives a linear relationship and equated as,
++ ==
===
yuoryuuu
yuyyu ww
ν
νρ ντ
µτ
τ
τ
τ2
Natteri M Sudharsan, Ph.D., 99
Far away form the wall one can expect that velocity at a point be influenced by the retarding effect of the wall through the value of wall shear stress, but not by viscosity itself. Thus,
)/(max δτ
ygu
uu =−
is known as the velocity defect law.
Natteri M Sudharsan, Ph.D., 100
Log Layer – Turbulent region close to the smooth wall. The region outside viscous sub layer where both viscous and turbulent effects are important. 30 < y+ < 500. τ varies slowly with distance from the wall and within this inner region it is assumed to be constant and equal to wall shear stress.
]Ey[lnk1B,Byln
k1u +++ =+=
Natteri M Sudharsan, Ph.D., 101
k and B are universal constants, E is the wall roughness, the constants are obtained by measurements. B=5.5, k=0.4 and E = 9.8. The log layer is shown to be valid from 0.02 < y/δ <0.2 by experiments.
Natteri M Sudharsan, Ph.D., 102
Ayku
uu +
=−
δτ
lnmax 1
Outer Layer – Inertia dominated region. For larger values of y, the velocity defect law provides the correct form. For the overlap region between the log layer and the defect layer the values must be the same, i.e.
A is a constant and called the law of the wake
Natteri M Sudharsan, Ph.D., 103
TWO – DIMENSIONAL FLOW
∂∂+
∂∂µ+
∂∂−=
∂∂+
∂∂ρ
∂∂+
∂∂µ+
∂∂−=
∂∂+
∂∂ρ
=∂∂+
∂∂
2
2
2
2
2
2
2
2
yv
xv
yp
yvv
xvu
yu
xu
xp
yuv
xuu
0yv
xu
Since shear layer is thin for large Re (Prandtl), following assumptions apply
Natteri M Sudharsan, Ph.D., 104
only)x(ppor0yp
eqnmomentumytoapplyingyx
uv
==∂∂
−∂∂< <
∂∂
< <
For the outer inviscid flow applying the Bernoulli equation
2
2
2
2
yu
xu
dxdUU
dxdp
∂∂< <
∂∂
ρ−=
Natteri M Sudharsan, Ph.D., 105
The three full equations are reduced to Prandtl’s two – boundary layer equation
yu
yu
ydxdUU
yuv
xuu
yv
xu
t
l
∂∂=
∂∂=
∂∂+≈
∂∂+
∂∂
=∂∂+
∂∂
τµτ
µτ
τρ1
0
LAMINAR
TURBULENT
Natteri M Sudharsan, Ph.D., 106
Boundary Layers with Pressure Gradient
Flow separation is caused by excessive momentum loss near the wall in a boundary layer trying to move downstream against increasing pressure dp/dx>0 is called adverse pressure gradient. At the wall u = v = 0 thus
dxdp1
yu2
2
µ=
∂∂
Natteri M Sudharsan, Ph.D., 107
Boundary Layers with Pressure Gradient
Natteri M Sudharsan, Ph.D., 108
Natteri M Sudharsan, Ph.D., 109
Natteri M Sudharsan, Ph.D., 110
Turbulence
Natteri M Sudharsan, Ph.D., 111
The uniform distribution of velocity tends to become irregular either due to a solid interaction or when neighboring streams of the same fluid flow past one another causing what is known as turbulence. It is to be noted that the irregularity associated with turbulence can be described by the laws of probability by being able to determine the fluctuation by statistical averaging.
TURBULENCE
Natteri M Sudharsan, Ph.D., 112
N – S Equation for Turbulent Flow
The additional terms depend on the turbulent fluctuations of the stream. These terms can be interpreted as components of stress tensor. Therefore,
∂∂+
∂∂+
∂∂−∇+
∂∂−=
∂∂+
∂∂+
∂∂+
∂∂ ''''' wu
tvu
yu
xu
xP
zuw
yuv
xuu
tu 22 ρµρ
∂∂
∂∂+
∂∂+∇+
∂∂−=
∂∂+
∂∂+
∂∂+
∂∂
zxyxxx zyxu
xP
zuw
yuv
xuu
tu ''' ττσµρ 2
Natteri M Sudharsan, Ph.D., 113
in 3-D comparing the above
−=
=
2
2
2
'''''''''''''''
'''''''''
wvwuwwvvuvwuvuu
zzyzxz
zyyyxy
zxyxxx
T ρστττστττσ
σ
The total laminar and turbulent stresses in the fluid are
'':'';'' wuxw
zuvu
xv
yuu
xuP xzxyxx ρµτρµτρµσ −
∂∂+
∂∂=−
∂∂+
∂∂=−
∂∂+−=
22
Natteri M Sudharsan, Ph.D., 114
TURBULENCE MODLES
Mixing length – Prandtl’s mixing length hypothesis κ - ε Model Reynold’s Shear Stress (aka) 7 equation model
Natteri M Sudharsan, Ph.D., 115
Models for evaluating ρui’uj
’ J Boussinesq introduced a mixing co-efficient for the Reynold’s stress term as µτ
yu
yu
yu
yuvu
l
t
∂∂=
∂∂=
∂∂=
∂∂=−=
ρ νµτ
ρ νµρτ ττ''
Natteri M Sudharsan, Ph.D., 116
Thus the equation can be re-written as
( )
∂∂+
∂∂+
∂∂−=
∂∂+
∂∂
−
∂∂
∂∂+
∂∂−=
∂∂+
∂∂
yu
yxP
yuv
xuu
vuyu
yxP
yuv
xuu
tννρ
νρ
1
1 ''
term is known as eddie viscosity. The kinematic viscosity is a property and not influenced by flow, but the eddie viscosity is attributed to the random fluctuation and it is not a property of the fluid.
τν
Natteri M Sudharsan, Ph.D., 117
There are various models that relate the apparent (or) eddie viscosity to the mean velocity gradient.Prandtl mixing length hypothesis
yul
yul
∂∂=
∂∂=
2
2
τ
τ
ν
ρµ
l is the Prandtl mixing length, For wall – boundary layers
Natteri M Sudharsan, Ph.D., 118
.,.,,.,,.
)/()/(
wallfromdistyandrealisedisUwherelocationconstKarmanVonconstlengthmixing
yforlandyforyl
∞
==>=≤=
990410090
δχλ
δχλλ δδχλχ
Natteri M Sudharsan, Ph.D., 119
−=
−+ ν
ρτ
χ Ay w
eyl21
1
/)/(
, is the wall shear stress, and A+ is the Von Driest damping constant = 26 for smooth surface without suction or blowing on low pressure gradient surface.
wτ
−=
−+ ν
ρτ
χ Ay w
eyl21
1
/)/(
−=
−+ ν
ρτ
χ Ay w
eyl21
1
/)/(
wτ
−=
−+ ν
ρτ
χ Ay w
eyl21
1
/)/(
, is the wall shear stress, and A+ is the Von Driest damping constant = 26 for smooth surface without suction or blowing on low pressure gradient surface.
wτ
Very close to the wall, viscous effects play a vital role. The mixing length should gradually go to zero
−=
−+ ν
ρτ
χ Ay w
eyl21
1
/)/(
Natteri M Sudharsan, Ph.D., 120
For free shear flows, the mixing length scales with the shear layer thickness (δs). The eddie viscosity can be written as
sdCU δν τ =
where Ud, is the characteristic velocity defect across shear layer and C is the proportionality constant to be determined from experiments.
Natteri M Sudharsan, Ph.D., 121
κ - ε Model for Turbulence
The instantaneous velocity of the fluid is decomposed into mean and fluctuating components. The effect of the fluctuating components on the mean motion is modeled after obtaining empirical relations for specific cases from experiments.
Natteri M Sudharsan, Ph.D., 122
In κ - ε model, the local turbulent viscosity is determined from the solution of the transport equation for the turbulent kinetic energy, κ, and the rate of dissipation of kinetic energy, ε.
The x-momentum
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂−=
∂∂+
∂∂+
∂∂
xv
yu
yxu
xxPvu
yuu
xtu
effeff µµρρρ 2)()(
Natteri M Sudharsan, Ph.D., 123
The y-momentum
∂∂+
∂∂
∂∂+
∂∂
∂∂+
∂∂−=
∂∂+
∂∂+
∂∂
xv
yu
xyv
yyPvv
yvu
xtv
effeff µµρρρ 2)()(
0902 .;/; ==+= µµττ ερ κµµµµ CCeff
The transport of passive scalar is written as Advection = Diffusion + Generation – dissipation
Natteri M Sudharsan, Ph.D., 124
κερ
κεε
σµε
σµ
ερερ
ρ εκσµκ
σµ
κρκρ
εε
κκ
2
21 CGCyyxx
vy
ux
Gyyxx
vy
ux
effeff
effeff
−+
∂∂
∂∂+
∂∂
∂∂=
∂∂+
∂∂
−+
∂∂
∂∂+
∂∂
∂∂=
∂∂+
∂∂
)()(
)()(
G, is the generation of turbulent kinetic energy and is given as
∂∂+
∂∂+
∂∂+
∂∂=
222
2xv
yu
yv
xuG τµ
Empirical Values: C1 = 1.44, C2 = 1.92, σκ = 1.0, σε = 1.3 Cµ = 0.09
Natteri M Sudharsan, Ph.D., 125
For near wall region the equation for wall shear stress is given as
µρ κχκρ
τ µτ
µ pp
pw
yCyanduuuwhere
EyCu 41212141 ////
,/,)ln(
=== ++
+
+
uτ, is the frictional velocity and yp+ >11 non-
dimensional distance from the wall to the point outside viscous layer, E an empirical constant, wall roughness = 9.8.
Natteri M Sudharsan, Ph.D., 126
Since ,
ts is the characteristic time scale, vs=κ1/2 and ls=(κ3/2)/ε,
( )stt
andwvu κκεκ ~,'''21 222
∂∂=++=
ερ κµ µτ /2C=
B.C Inlet κ - ε distribution must be given, outlet or symmetry
00 =∂∂=∂∂ nandn // εκ
Free stream κ = ε = 0. Solid walls depends on Re.
Natteri M Sudharsan, Ph.D., 127
kyu
CuEy
uuu
321 τ
µ
τ
τ
εκχ
==== ++ ;);ln(
High Reynold’s number 30<y+<500.
Low Reynold’s number
0902 .;/; ==+= µµµττ ερ κµµµµ CfCeff
κερ
κεε
σµε
σµ
ερερ
ρ εκσµκ
σµ
κρκρ
εε
κκ
2
2211 fCGfCyyxx
vy
ux
Gyyxx
vy
ux
effeff
effeff
−+
∂∂
∂∂+
∂∂
∂∂=
∂∂+
∂∂
−+
∂∂
∂∂+
∂∂
∂∂=
∂∂+
∂∂
)()(
)()(
Natteri M Sudharsan, Ph.D., 128
ε νκµ
µ
/Re);Reexp(;.
Re.)]Re.exp([
222
3
1
2
10501
5201016501
=−−=
+=
+−−=
tt
ty
ff
f
f
Ret Turbulence Reynold’s number
Reynolds shear Stress Model 7 equation model, 6 PDE for the stresses
2
2
2
'''''''''
wwvvwuvuu
Natteri M Sudharsan, Ph.D., 129
Disadvantages
Completely incapable of describing flows with separation and recalculation.Only calculates mean flow properties and turbulent shear stress.
AdvantagesMixing length model: Easy to implement and cheap in terms of computing resources.Good Predictions for thin shear layers i.e. jets, mixing layers, wakes and boundary layers.Well established
Natteri M Sudharsan, Ph.D., 130
More expensive to implement than mixing length model (2 extra PDE’s)Poor performance in a variety of important cases such as Some unconfined flowsFlows with large extra strains (eg curved boundary layers, swirling flows)Rotating flowsFully developed flows in non-circular ducts.
k- ε Model:
Simplest turbulence models for which initial and/or boundary conditions need to be supplied.Excellent performance for many industrially relevant flows.Well established: The most widely validated turbulence model.
Natteri M Sudharsan, Ph.D., 131
Very large computing cost (7 extra PDE’s)Not as widely validated as mixing length and κ - ε models.Performs just as poorly as the κ - ε model in some flows owing to identical problem with the ε equation modeling (eg, axi-symmetric jets and unconfined re-circulating flows.
Reynold’s Stress model:
Potentially the most general of all classical turbulence models.Only initial and / or boundary conditions need to be suppliedVery accurate calculation of mean flow properties and all Reynold’s stresses for many simple and more complex flows including wall jets, asymmetric channels and non circular duct flows and curved flows.
Natteri M Sudharsan, Ph.D., 132
Unstructured Finite Volume Method
Natteri M Sudharsan, Ph.D., 133
Summary
1. Discretization of equations in unstructured finite volume method.
2. Simple Algorithm.
Natteri M Sudharsan, Ph.D., 134
0=−∫∂ S
s dSnvv ).(
∫ ∫ ∫∫∂ ∂
+=−+∂∂
S S Vbs
V
dVfdSnTdSnvvvvdVt
.).(ρρ
])([ TvvpIT ∇+∇+= µ
∫ ∫∫∫∫∂∂
+∇+∇−=−+∂∂
S Vb
VSs
V
dVfdSnvpdVdSnvvvvdVt
).().( µρρ
Continuity Equation
Momentum Equation
Governing Equations
Natteri M Sudharsan, Ph.D., 135
Linear system (momentum)
0 0 0 0 01
kC j jP p P P p
ja a bφ φ
== +∑
1 10
1 ( ) ( )k k
j j j j jCj jP j
p A Aa= =
′∇ ⋅ = ⋅
∑ ∑n v n
∫∫∂
=−∂∂
SV
dSnvdVt
0.Space Conservation Law
Pressure correction
Natteri M Sudharsan, Ph.D., 136
C
Njj
rc
rj
Arbitrary cell C with neighbor Nj across jth face
Natteri M Sudharsan, Ph.D., 137
Spatial Representation
∑∫∫ ∆≈⇒=
−+=
jjjC
SV
CjC
SV
graddSdVgrad
rrgradj
φφφφ
φφφ
1)(
)).(()(
The gradient is obtained using the Gauss Theorem (2nd
order approximation). Since the value of j would be different when applied from either side of face a symmetric expression is used and presented as follows:
( ) [ ]).()().()(jjj NjNCjCNC
SOj rrgradrrgrad −+−++= φφφφφ
21
21
Natteri M Sudharsan, Ph.D., 138
( )jNC φφ +
21 Term gives the value midway between cell
centers connected by a straight line.
[ ]).()().()(jj NjNCjC rrgradrrgrad −+− φφ
21
The above expression provides a correction which takes into account that the cell-face center may not lie on the line connecting the cell centers and/or that the distances to the two CV’s may not be equal. This would vanish otherwise.
( )FOj
SOj
FOjj
jN
jCFOj CtoNfromisflowWhen
NtoCfromisflowWhen
j
φφγφφ
φφ
φ
−+=
=
*
Natteri M Sudharsan, Ph.D., 139
Time Integration
ττφφφ ∆+= +++ ),( 1
11n
nnn F
A first order approximation can be used where temporal accuracy is not important
Implicit Schemes that can be used are the Crank-Nicolson Method or a second order approximation assuming a quadratic profile for φ
[ ][ ] profileQuadraticF
NicolsonCrankFF
nnnnn
nn
nnnn
ττφφφφ
τφτφτφφ
∆+−=
−+∆+=
++−+
+++
),(
),(),(
1111
111
32
31
34
2
Natteri M Sudharsan, Ph.D., 140
Moving Grid
tV
dSnvV
dSnvdVt
j
S
j
SV
∆==
=−∂∂
∫
∫∫
∂
•
∂
δ.
. 0
In second order the the swept volume by the cell face during the preceding time step is included to yield:
∫ ∆−
==•
jS
njj
sj tVV
dSvV2
3 δδ
Natteri M Sudharsan, Ph.D., 141
Convective Fluxes
)(
..)(
*
.)(
*
**
*
FOj
SOj
FOjj
jjjjS
s
jj
Ssj
VSvdSvvm
valuemeanfacecellindicates
mdSvvC
j
j
φφγφφ
ρρ
φρ φ
−+=
−≈−=
−
≈−=
••
•
∫
∫
Natteri M Sudharsan, Ph.D., 142
Diffusive Fluxes
( ) jS
jj SgraddSgradDj
j.. *∫ Γ≈Γ= φφ φφ
The approximation of the gradient based on the SO (second order) interpolation
jφΓ is diffusivity at face-center and obtained using:
( ) [ ]).()().()(jjjj NjNCjCNC
SO rrgradrrgrad −Γ+−Γ+Γ+Γ=Γ21
21
φ
∑∫∫ ∆≈⇒=
jjjC
SV
SV
graddSdVgrad φφφφ 1)(
Natteri M Sudharsan, Ph.D., 143
This II order space-centered expression cannot sense oscillations that are twice the characteristic length of the numerical mesh. Unphysical oscillatory profiles if induced, remain superimposed.
RECTIFICATION: A III order dissipation term is added as:
( ) ( )
j
j
NCj
j
j
j
j
j
CNjj
rrdIIIIIITERMS
SS
ddgrad
dgradgrad
−=
−
−+=
.* φφφφφ
Natteri M Sudharsan, Ph.D., 144
The over-bar in term III represents the arithmetic average of values calculated at node C and Nj.
The II & III term is the difference between the central difference approximation of the derivative in the direction of vector dj (II) and the value obtained by interpolating cell-center gradients (III). This term in brackets (II-III) vanishes if the spatial variation for phi is linear or quadratic. Its magnitude is proportional to the II order truncation error and reduces with grid refinement.
The I term is the contribution from the nearest neighbors and treated implicitly, the II & III term represent the cross-diffusion component and vanish with orthogonal grid. This is treated explicitly which is a deferred correction approach.
Natteri M Sudharsan, Ph.D., 145
The resulting algebraic equation is of the form
φφφ φφ Cj
NjCC raaj
=− ∑
SIMPLE Algorithm is used to solve the equation where, the momentum equations are solved assuming that the pressure field is known (predictor step).The mass fluxes are corrected to satisfy the continuity requirement in the corrector step by correcting velocity and density.
Natteri M Sudharsan, Ph.D., 146
SIMPLE Algorithm
Semi Implicit Pressure Linked Equation'' ; vvvpppLet oo +=+=
Substituting the values of p and v as estimated plus corrections in the momentum equations and neglecting other terms yields:
ρ
ρρ
tAypAvand
xpAu
yp
tvand
xp
tu
∆=∂∂−=
∂∂−=
∂∂−=
∂∂
∂∂−=
∂∂
;''''
''''
Note: Corrections are zero at the first iteration
Natteri M Sudharsan, Ph.D., 147
ypAvvand
xpAuu
∂∂−=
∂∂−= ''
00
Substituting this in the continuity equation gives
( )02
2
2
2
2
1
0
0
vA
p
yp
xpA
yv
xu
ypAv
yxpAu
x
oo
oo
.'
''
''
∇=∇
=
∂
∂∂
∂−
∂
∂+∂
∂
=
∂∂−
∂∂+
∂∂−
∂∂
This is poisson’s equation for pressure correction
Natteri M Sudharsan, Ph.D., 148
As seen the velocity obtained in the predictor step does not necessarily satisfy the continuity equation and there exist a mass imbalance in each CV.The velocity and pressure corrections are obtained from
'','' pp
pgradaVv vC ∂
∂=∆= ρρ
vCaV∆ This coefficient comes from the discretized
momentum equation.
p∂∂ ρ is calculated from the equation of
state.
Natteri M Sudharsan, Ph.D., 149
The velocities used to calculated the mass fluxes are obtained by interpolation as given below:
( ) [ ]).()().()(jjj NjNCjCNC
SOj rrvgradrrvgradvvv −+−++=
21
21
Cell-center pressure gradients are not sensitive to oscillations between immediate neighbors. Hence a dissipation term is added to the interpolated velocity which can sense such oscillations and smoothen it.
This method is for co-located grids. A staggered grid may also be used. However, requires more memory storage for storing geometric information along with tedious interpolation.
Natteri M Sudharsan, Ph.D., 150
j
j
j
CNvC
j
j
j
j
j
j
CNvC
jj
SS
d
ppaVv
SS
ddpgrad
d
ppaVvv
j
j
'''
.*
−
∆−=
−
−
∆−=
Thus the procedure is repeated till all corrections are within the limits prescribed.
Thank you