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Ch 3. Kinematics in Two Dimensions

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Ch 3. Kinematics in Two Dimensions. Average velocity. instantaneous velocity. Equations of Kinematics. Average Acceleration. Example 1 A Moving Spacecraft - PowerPoint PPT Presentation
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Ch 3. Kinematics in Two Dimensions positi initial o r positi final r nt displacem o r r r t t t o o r r r v Average velocity t t r v 0 lim instantaneous velocity 1
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Page 1: Ch 3. Kinematics  in Two Dimensions

1

Ch 3. Kinematics in Two Dimensions

position initial or

position final r

ntdisplaceme orrr

ttt o

o

rrr

v

Average velocity

tt

rv

0lim

instantaneous velocity

Page 2: Ch 3. Kinematics  in Two Dimensions

2

ttt o

o

vvv

a

Average Acceleration

ov

v v

Equations of Kinematics

tvvx o 21

221 attvx o

atvv o

axvv o 222

Page 3: Ch 3. Kinematics  in Two Dimensions

3

tavv yoyy 2

21 tatvy yoy

tvvy yoy 21

yavv yoyy 222

tavv xoxx 2

21 tatvx xox

xavv xoxx 222

221 tatvx xox

Page 4: Ch 3. Kinematics  in Two Dimensions

4

Example 1 A Moving Spacecraft

In the x direction, the spacecraft has an initial velocity component of +22 m/s and an acceleration of +24 m/s2. In the y direction, the velocity is +14 m/s and acceleration is +12 m/s2.Find (a) x and vx, (b) y and vy, and (c) the final velocity of thespacecraft at time 7.0 s.

x ax vx vox t? +24.0

m/s2

? +22 m/s

7.0 s

y ay vy voy t? +12.0

m/s2

? +14 m/s

7.0 s

Page 5: Ch 3. Kinematics  in Two Dimensions

5

3.2 Equations of Kinematics in Two Dimensions

x ax vx vox t? +24.0 m/s2 ? +22 m/s 7.0 s

m 740s 0.7sm24s 0.7sm22 2221

221

tatvx xox

sm190s 0.7sm24sm22 2

tavv xoxx

Page 6: Ch 3. Kinematics  in Two Dimensions

6

3.2 Equations of Kinematics in Two Dimensions

y ay vy voy t? +12.0 m/s2 ? +14 m/s 7.0 s

m 390s 0.7sm12s 0.7sm14 2221

221

tatvy yoy

sm98s 0.7sm12sm14 2

tavv yoyy

Page 7: Ch 3. Kinematics  in Two Dimensions

7

sm210sm98sm190 22 v

2719098tan 1

Page 8: Ch 3. Kinematics  in Two Dimensions

8

3.3 Projectile Motion

Under gravity object will accelerate downwards at 9.80m/s2.

2sm80.9ya 0xa

constant oxx vv

Page 9: Ch 3. Kinematics  in Two Dimensions

9

Example 3 A Falling Care Package

An airplane is moving horizontally with a constant velocity of +115 m/s at an altitude of 1050m. Determine the time required for the care package to hit the ground.

y ay vy voy t-1050 m -9.80 m/s2 0 m/s ?

Page 10: Ch 3. Kinematics  in Two Dimensions

10

3.3 Projectile Motion

y ay vy voy t-1050 m -9.80 m/s2 0 m/s ?

221 tatvy yoy 2

21 tay y

s 6.14

sm9.80

m 1050222

ya

yt

Page 11: Ch 3. Kinematics  in Two Dimensions

11

Example 4 The Velocity of the Care Package

What are the magnitude and direction of the final velocity ofthe care package?

y ay vy voy t-1050 m -9.80 m/s2 ? 0 m/s 14.6 s

Page 12: Ch 3. Kinematics  in Two Dimensions

12

3.3 Projectile Motion

y ay vy voy t-1050 m -9.80 m/s2 ? 0 m/s 14.6 s

sm143

s 6.14sm80.90 2

tavv yoyy

Page 13: Ch 3. Kinematics  in Two Dimensions

13

Example 6 The Height of a Kickoff

A placekicker kicks a football at and angle of 40.0 degrees andthe initial speed of the ball is 22 m/s. Ignoring air resistance, determine the maximum height that the ball attains.

sm1440sinsm22sin ooy vv

sm1740cossm22cos oox vv

ov

oxv

oyv

Page 14: Ch 3. Kinematics  in Two Dimensions

14

3.3 Projectile Motion

y ay vy voy t? -9.80

m/s2

0 14 m/s

yavv yoyy 222

y

oyy

a

vvy

2

22

m 10

sm8.92

sm1402

2

y

Page 15: Ch 3. Kinematics  in Two Dimensions

15

Example 7 The Time of Flight of a Kickoff

What is the time of flight between kickoff and landing?

y ay vy voy t0 -9.80 m/s2 14 m/s ?

Page 16: Ch 3. Kinematics  in Two Dimensions

16

3.3 Projectile Motion

y ay vy voy t0 -9.80 m/s2 14 m/s ?

221 tatvy yoy

2221 sm80.9sm140 tt

t2sm80.9sm1420

s 9.2t

Page 17: Ch 3. Kinematics  in Two Dimensions

17

3.3 Projectile Motion

Example 8 The Range of a Kickoff

Calculate the range R of the projectile.

m 49s 9.2sm17

221

tvtatvx oxxox

Page 18: Ch 3. Kinematics  in Two Dimensions

18

3.4 Relative Velocity

TGPTPG vvv

Page 19: Ch 3. Kinematics  in Two Dimensions

19

Example 11 Crossing a River

The engine of a boat drives it across a river that is 1800m wide.The velocity of the boat relative to the water is 4.0m/s directed perpendicular to the current. The velocity of the water relativeto the shore is 2.0m/s.

(a) What is the velocity of the boat relative to the shore?

(b) How long does it take for the boat to cross the river?

Page 20: Ch 3. Kinematics  in Two Dimensions

20

sm5.4

sm0.2sm0.4 2222

WSBWBS vvv

WSBWBS vvv

630.2

0.4tan 1

s 450sm4.0

m 1800t


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