Date post: | 14-Dec-2015 |
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Triangle: theta(=80 deg)Vertical:T sin =mg (T=0.4 N)
Horizontal:Tcos = mv2/R
V=0.49 m/s,Rev=2pi r,t= 1.9s
Vertical:N + F sin = W
Horizontal:a = 0: mu N = F Cos
So:
N = F/mu *cos
F/mu Cos + F sin = w F = w/(cos/mu +sin)
F = 400/ (cos30/0.25 + sin30) = 101 N
Vertical: P Sin = N + mg Horizontal: -fk + P Cos = m a
a = (P cos – mu * N) /m = (P Cos – mu * (Psin - mg) ) / m = 3.4 m/s^2
Break F to parallel (Fcos) and normal Fsin. Break mg as well: parallel (mgsin) and normal mg cosFind N then frictionFind acceleration by parallel to surface forces.