Challenger Center Cooling Tower

Enev/Ench 435September 23, 2008

Performed By:Dianah DuganAlex Saputa

Contents

Block Diagram Schematic Equipment Data Collection Results Conclusion

Block Diagram of Cooling Tower

Air Inlet

Air Outlet

CT unit

mh

T

i

i

ˆ

mh

T

o

o

ˆP= 1 atm

W= 0

Chilled WS

Chilled WR

H <0CW

H >0Air

Cooling Tower Schematic from Side View

Outside Intake

Outside Intake

Inside Intake

Exhaust A Exhaust B

Outside Inlet B Outside Inlet A

Inner Inlet B Inner Inlet A

Schematic of Exhaust Fan

                                                                                                                                       

                                                                                          

0.22 ft

0.72 ft

1.22 ft

*Distances measured from center of fan

Equipment

Anemometer Yard Stick Ladder Sling Psychrometer Psychrometric Chart

Radial Dependence of Temperature for Week 1

99

101

103

105

107

109

111

0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4Radial Position (ft)

Tem

pera

ture

(F)

Fan #1Fan #2Fan #3Fan #4

Fan #4

Fan #3

Fan #2

Fan #1

Radial Dependence of Temperature for Week 2

99

101

103

105

107

109

111

0 0.2 0.4 0.6 0.8 1 1.2 1.4

Radial position (ft.)

Tem

pera

ture

(F)

Fan#1

Fan#2

Fan#3

Fan#4Fan #1

Fan #3

Fan #4

Fan #2

Average Air Velocity for Week 1

0

500

1000

1500

2000

2500

0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4

Radial Position (ft)

Velo

city

(ft/m

in)

Fan #1Fan #2Fan #3Fan #4

Fan #4

Fan #3

Fan #2Fan #1

Average Air Velocityfor Week 2

0

500

1000

1500

2000

2500

0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4

Radial distance (ft)

Velo

city

of a

ir (ft

/min

)

Fan#1Fan#2Fan#3Fan#4

Fan #2

Fan #2

Fan #2

Fan #2

Calculating the Cross-Sectional Area

r1 r2 r3 r4R1

R2

R3R4

r1= 0.22 ft

r2= 0.72 ft

r3= 1.22 ft

r4= 1.30 ft

A1= π*(R2² - R1²)

A2= π*(R3² - R2²)

A3= π*(R4² - R3²)

Formulas To Solve:

Volumetric Flow Rate = cross-sectional area* measured velocity

Mass Flow Rate = volumetric flow rate * density

Heat = mass flow rate * change in enthalpy

Density is found by taking the inverse of Humid Volume, found on Psychrometric chart

*Vm

vAV *

)(* inletexhaust hhmQ

Comparative Volumetric Flow for Each Exhaust Fan

0

800

1600

2400

3200

4000

4800

5600

6400

7200

0.22 0.72 1.22Radial Position (ft)

Volu

met

ric F

low

Rat

e (ft

^3/m

in)

Fan 1Fan 2Fan 3Fan 4

Mass Flow Rate Per Fan

729

772

727

747

690

700

710

720

730

740

750

760

770

780

1 2 3 4Fan #

Mas

s Fl

ow R

ate

(lb/m

in)

Calculating Enthalpy from Psychrometric Chart

Enthalpy for Inlet and Exhaust Fans

31 31 31 30

79 78 76 75

0

10

20

30

40

50

60

70

80

90

1 2 3 4Fan #

Enth

alpy

(Btu

/lb)

Inlet

Exhaust

Heat Generated

116657

271078

183596

266618

0

50000

100000

150000

200000

250000

300000

1 2 3 4

Fan #

Heat

(Btu

/hr)

Change to bar graph***

Date   A B8/20/200

8 Starts 1915 1915

  Running hours 3039 28878/21/200

8 Starts 1917 1917

  Running hours 3060 28908/22/200

8 Starts 1919 1919

  Running hours 3081 28918/25/200

8 Starts 1923 1923

  Running hours 3125 2920

Conclusions

Velocity is the least in the center of the exhaust

Comments