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Chapter 12: Kinetics; Outline 1. Introduction

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Chapter 12: Kinetics; Outline 1. Introduction  2. macroscopic determination of rate (experimental) define rate  define rate law, rate constant, reaction order  rate determination via expt: initial rate  integrated rate laws  first order; half-lives  second order; half-lives  - PowerPoint PPT Presentation
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Chapter 12 1 er 12: Kinetics; Outline troduction croscopic determination of rate (experimenta ne rate ne rate law, rate constant, reaction order determination via expt: initial rate grated rate laws irst order; half-lives econd order; half-lives & temperature: the Arrhenius equation
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Page 1: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 1

Chapter 12: Kinetics; Outline1. Introduction2. macroscopic determination of rate (experimental)•define rate •define rate law, rate constant, reaction order •rate determination via expt: initial rate •integrated rate laws

first order; half-lives second order; half-lives

•rate & temperature: the Arrhenius equation

Page 2: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 2

Arrhenius equation:•from observation, reaction rates and rate constants increase with temperature

examples: food decays faster at higher temperature; cooking; fireflies;

•from observation, a graph of log(k) vs. 1/T gives a straight line•the slope of the log(k) vs. 1/T graph is related to the activation energy

Page 3: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 3

)ln(1

303.2)log( A

TR

Ek A

A graph of ln(k) vs. 1/T gives a straight line with a slope of -EA/Rand an intercept of ln(A)

where k is rate constant, EA is the activation energy, R is the gas constant in J K-1mol-1, T is temperature in Kelvin, and A is the “steric factor”

Page 4: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 4

Example: The rate constant for a certain reaction is measured at four temperatures (see the data below). What is the activation energy for the reaction? What is the value of the rate constant at 400°C?

T(C) k

330 0.77

354 1.8

378 4.1

383 4.7

Page 5: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 5

k T(K) 1/T log(k)0.77 603 0.001658 -0.11351.8 627 0.001595 0.25534.1 651 0.001536 0.61284.7 656 0.001524 0.6721

Page 6: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 6

Arrhenius Plot

y = -5904.6x + 9.6756

R2 = 0.9998

-0.5

0

0.5

1

1.520E-031.590E-03

1.660E-031/T (1/K)

log(

k)

activation energy = slope ·2.303·(-R) = +1.13x105 J mol-1

Page 7: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 7

3. molecular view of kinetics•mechanisms•relationship to rate laws•Arrhenius equation4. Catalysis, Factors affecting rates3. Molecular View of Kinetics

Page 8: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 8

•MechanismsA mechanism is a series of elementary reactions, or steps, that describe what happens as a reaction proceeds.

Elementary reactions are not overall reactions: overall reactions summarize the products and reactants and give the stoichiometry.

Elementary reactions may have intermediates: short-lived (<1 second) species that are formed and then react away as the reaction proceeds.

An elementary reaction often involves a collision between two species (a bimolecular step or reaction).

Page 9: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 9

example: NO2+CONO+CO2

rate=k[NO2]2 [2nd order]

NO2+NO2 NO3+NO

NO3+CO NO2+CO2

possible mechanism:

Page 10: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 10

A few comments on the mechanism and its relation to the rate law:

•NO and NO3 are intermediates. They don’t appear as

reactants or products and they are very reactive (unstable).•Each of these steps is bimolecular: involves 2 molecules.•The individual reactions add up to give the overall

reaction with the correct stoichiometry.•The order and the rate equation of an elementary reaction is determined by its stoichiometry

step 1: rate(1)=k1[NO2]2 bimolecularstep 2: rate(2)=k2[NO][NO3] bimolecular

Page 11: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 11

•If one step is much slower than the others, the rate of that slow step is the rate of the overall reaction

step 1: slow (forms two unstable intermediates)step 2: FAST (two unstable, reactive intermediates react)

overall rate predicted by the mechanism: k1[NO2]2

rate determined by experiment: k[NO2]2

Therefore, we say that the proposed mechanism is REASONABLE.

Page 12: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 12

example: devise a plausible mechanism consistent with the overall reaction and the overall reaction rates for each of the following

Co(CN)5H2O-2(aq)+I-1(aq) Co(CN)5I-3(aq)+H2O(l)rate=k[Co(CN)5H2O-2]1(aq)

Co(CN)5H2O-2 Co(CN)5-2+H2O k[Co(CN)5H2O-2]

Co(CN)5-2+I1- Co(CN)5I-3 k[Co(CN)5

-2][I1-]

slow

fast

Page 13: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 13

2NO2(g)+F2(g)2NO2F(g) rate=k[NO2][F]

[HINT: consider a slow step and a fast step.]

Page 14: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 14

•Collision Theory From observation, we know

1. reaction rates and rate constants increase with temperature

2. a graph of ln(k) versus 1/T gives a straight line with a negative slope

3. rate constants are relatively slow considering the HUGE number of collisions that occur at room temperature (around 1025 in a cm3 at 1 atm and 298 K)

Develop a theory that accounts for these observations

Page 15: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 15

•reactions occurs as the result of a collision

•only collisions above some minimum energy (the ACTIVATION ENERGY)will result in product formation

•only collisions of the correct geometry (orientation) will result in product formation

Page 16: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 16

So, we can write an equation based on theory that gives the reaction rate;

this equation is based on molecular parameters.

rate=(collision rate)x (fraction molecules with EA)x (fraction molecules with correct geometry)

collision rate=Z[A][B] where Z depends on temperature and [A], [B] are concentrations

fraction molecules with EA=f

fraction molecules with correct geometry=P

Page 17: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 17

combineZPfk

definitionBAkrate

theoryPfBAZrate

]][[

]][[

Page 18: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 18

fraction of molecules with enough energy to react: Activation Energy

Page 19: Chapter 12: Kinetics; Outline 1. Introduction

0.00

0.01

0.02

0.03

0.04

0 20 40 60 80 100 120 140 160

energies

fraction

activation energy

lower temperature

highertemperature

more particles have energy>EA at higher T

113145.8

molJKRef RTEA

fraction of particles withenergy >EA

Page 20: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 20

ZPfk from before

we have 113145.8

molJKRef RTEA

RTEA

eAk

line form of Arrhenius equationbmxy

ART

Ek A

)ln()ln(

combining

rearranging

Page 21: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 21

•Catalysis

1. definition: a catalyst is a chemical substance that increases the rate of a chemical reaction but is not consumed in the reaction (does not appear as a reactant or product).

catalysts work by

2. providing an alternate, lower energy reaction pathway to product formation

or

3. stabilizing the activated complex (transition state) and thus lowering the activation energy

Page 22: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 22

Page 23: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 23

3 examples

1. HOMOGENEOUS CATALYSIS: ozone depletion

depletiongOgOgO

formationgOgOgO

)(2)()(

)()()(

23

32

Cl· catalyzes the depletion reaction through a series of reactions:

)()()()(

)()()()(

)()()(

2

23

222

gOgClgOgClO

npropagatiogOgClOgClgO

formationgClgClCFgClCF

Cl· acts as a catalyst in the second two steps

Page 24: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 24

2. HETEROGENEOUS CATALYSIS catalytic converterCO(g)+1/2O2(g)CO2(g)

reactant molecules adsorb (by intermolecular forces or by chemical bonding) to the metal surface in the converter bonds in reactants weaken activated complex energy is reduced reaction goes faster

Page 25: Chapter 12: Kinetics; Outline 1. Introduction

Chapter 12 25

3. enzymes: large molecules that act as catalysts in biological reactions

•enzymes are specific: they work with only 1 substrate

•reaction rates are increased by factors of 108 to 1020

•the “turnover number” of number of reaction events per second is large:

103 to 107 s-1

link to www: http://wizard.pharm.wayne.edu/biochem/enz.html


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