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Chapter 14

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Chapter 14. PHYSICS 2048C Fluids. What Is a Fluid?. A fluid, in contrast to a solid, is a substance that can flow. Fluids conform to the boundaries of any container in which we put them. Density and Pressure. Density To find the density ρ of a fluid at any point, - PowerPoint PPT Presentation
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Chapter 14 PHYSICS 2048C Fluids
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Page 1: Chapter 14

Chapter 14

PHYSICS 2048C

Fluids

Page 2: Chapter 14

What Is a Fluid?

A fluid, in contrast to a solid, is a substance that can flow.

Fluids conform to the boundaries of any container in which we put them.

Page 3: Chapter 14

Density and Pressure

Density To find the density ρ of a fluid at any

point, we isolate a small volume element ΔV

around that point and measure the mass Δm of the fluid contained within that element. The density is then

Page 4: Chapter 14

Some Densities

Page 5: Chapter 14

Pressure

We define the pressure on the piston from the fluid as

where F is the magnitude of the normal force on area A. The SI unit of pressure is the Newton per square meter, which is given a special name, the Pascal (Pa).

Page 6: Chapter 14

Some Pressures

Page 7: Chapter 14

Fluids at Rest

Here we want to find an expression for hydrostatic pressure as a function of depth or altitude.

m = ρV

Page 8: Chapter 14

Fluids at Rest

The pressure at a point in a fluid in static equilibrium depends on the depth of that point but not on any horizontal dimension of the fluid or its container.

To find the atmospheric pressure at a distance d above level 1

Page 9: Chapter 14

Example

The U-tube, example 3 page 364, contains two liquids in static equilibrium: Water of density ρw (= 998 kg/m3) is in the right arm, and oil of unknown density ρx is in the left. Measurement gives l = 135 mm and d = 12.3 mm. What is the density of the oil?

Page 10: Chapter 14

Example

Page 11: Chapter 14

Example

In the right arm, the interface is a distance l below the free surface of the water

In the left arm, the interface is a distance l + d below the free surface of the oil

Page 12: Chapter 14

Measuring Pressure The Mercury Barometer a device used to measure the pressure of

the atmosphere the long glass tube is filled with mercury and inverted with its open

end in a dish of mercury, as the figure shows. The space above the mercury column contains only mercury vapor, whose pressure is so small at ordinary temperatures that it can be neglected.

Page 13: Chapter 14

Measuring Pressure The Open-Tube Manometer It is a device used to measure the gauge pressure pg of a gas

It consists of a U -tube containing a liquid, with one end of the tube connected to the vessel whose gauge pressure we wish to measure and the other end open to the atmosphere. We can find the gauge pressure in terms of the height h

Page 14: Chapter 14

Pascal's Principle

A change in the pressure applied to an enclosed incompressible fluid is transmitted undiminished to every portion of the fluid and to the walls of its container.

Example for that in your daily live is When you squeeze one end of a tube to get toothpaste out the other end

Page 15: Chapter 14

Demonstrating Pascal's Principle

If you add a little more lead shot to the container to increase Pext by an amount ∆pext . The quantities ρ, g, h are unchanged.

Page 16: Chapter 14

Pascal's Principle and the Hydraulic Lever

The Equation shows that the output force Fo on the load must be greater than the input force Fi if Ao > Ai, as is the case in the figure

If we move the input piston downward a distance di, the output piston moves upward a distance do, such that the same volume V of the incompressible liquid is displaced at both pistons

Page 17: Chapter 14

Pascal's Principle and the Hydraulic Lever

we can write the output work as

With a hydraulic lever, a given force applied over a given distance can be transformed to a greater force applied over a smaller distance.

Page 18: Chapter 14

Archimedes' Principle

This net upward force is a buoyant force . It exists because the pressure in the surrounding water increases

with depth below the surface.

Plastic sack

Page 19: Chapter 14

Archimedes' Principle

When a body is fully or partially submerged in a fluid, a buoyant force from the surrounding fluid acts on the body. The force is directed upward and has a magnitude equal to the weight mf g of the fluid that has been displaced by the body.

Page 20: Chapter 14

Apparent Weight in a Fluid

A spherical, helium-filled balloon has a radius R of 12.0 m. The balloon, support cables, and basket have a mass m of 196 kg. What maximum load M can the balloon support while it floats at an altitude at which the helium density ρHe is 0.160 kg/m3 and the air density ρair is 1.25 kg/m3? Assume that only the balloon displaces air.

Page 21: Chapter 14

Solution

Fg = mfg

ρ = m/V

Page 22: Chapter 14

The Equation of Continuity

the speed v of the water depends on the cross-sectional area A through which the water flows

Page 23: Chapter 14

The Equation of Continuity

This relation between speed and cross-sectional area is called the equation of continuity for the flow of an ideal fluid. It tells us that the flow speed increases when we decrease the cross-sectional area through which the fluid flows

Page 24: Chapter 14

The Equation of Continuity

RV is the volume flow rate of the fluid

Rm is the mass flow rate

Page 25: Chapter 14

Bernoulli's Equation

If the speed of a fluid element increases as the element travels along a horizontal streamline, the pressure of the fluid must decrease, and conversely.

Page 26: Chapter 14

Proof of Bernoulli's Equation

The work done on the system is then p1ΔV, and the work done by the system is –p2 ΔV.

Page 27: Chapter 14

Proof of Bernoulli's Equation

Bernoulli's Equation

Wp+Wg=ΔK

Page 28: Chapter 14

Problem

block of wood floats in fresh water with two-third of its volume V submerged and in oil with 0.90 V submerged. Find the density of (a) the wood and (b) the oil.

Page 29: Chapter 14

Solution

a- Let V be the volume of the block. Then, the submerged volume is Vo= 2/3(V)

According to Archimedes' principle the weight of the displaced water is equal to the weight of the block, so

b- If ρo is the density of the oil, then Archimedes' principle yields


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