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Chapter 15 Chemical Equilibrium

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Chapter 15 Chemical Equilibrium. The Concept of Equilibrium. The double arrow implies the process is dynamic. Consider Forward reaction: A  B Rate = k f [A] Reverse reaction: B  A Rate = k r [B] At equilibrium k f [A] = k r [B]. The Concept of Equilibrium. - PowerPoint PPT Presentation
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Chapter 15 Chapter 15 Chemical Equilibrium Chemical Equilibrium
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Page 1: Chapter 15 Chemical Equilibrium

Chapter 15Chapter 15Chemical EquilibriumChemical Equilibrium

Page 2: Chapter 15 Chemical Equilibrium

• The double arrow implies the process is dynamic.• Consider

Forward reaction: A B Rate = kf[A]

Reverse reaction: B A Rate = kr[B]

• At equilibrium kf[A] = kr[B].

The Concept of EquilibriumThe Concept of Equilibrium

A B

Page 3: Chapter 15 Chemical Equilibrium

The Concept of EquilibriumThe Concept of Equilibrium

Page 4: Chapter 15 Chemical Equilibrium

The Equilibrium ConstantThe Equilibrium Constant

• For a general reaction in the gas phase

the equilibrium constant expression is given in terms of pressures

where Keq is the equilibrium constant.

aA + bB cC + dD

ba

dceq

PP

PPK

BA

DC

Page 5: Chapter 15 Chemical Equilibrium

The Equilibrium ConstantThe Equilibrium Constant

• For a general reaction

the equilibrium constant expression for everything in solution is given in terms of molar concentrations

where Keq is the equilibrium constant.

aA + bB cC + dD

ba

dceqK

BADC

Page 6: Chapter 15 Chemical Equilibrium

• The same equilibrium is established independent of the initial conditions of the reaction

Page 7: Chapter 15 Chemical Equilibrium

The Magnitude of Equilibrium Constants

• The larger K the more products are present at equilibrium:

K >> 1: products dominate at equilibrium and equilibrium lies to the right.

• The smaller K the more reactants are present at equilibrium:

K << 1: reactants dominate at equilibrium and the equilibrium lies to the left.

Page 8: Chapter 15 Chemical Equilibrium

• An equilibrium can be approached from any direction.Example:

N2O4(g) 2NO2(g) 46.6

42

2

ON

2NO

P

PKeq

• In the reverse direction:

2NO2(g) N2O4(g)46.61155.02

NO

ON

2

42 P

PKeq

Page 9: Chapter 15 Chemical Equilibrium

Keq depends on the stoichiometry of the reaction:

For the reaction

but if the reaction is written as:

2N2O4(g) 4NO2(g)

2ON

4NO

42

2

P

PKeq

N2O4(g) 2NO2(g)

42

2

ON

2NO

eq PP

=Kwhich is the square root of the expression above

Page 10: Chapter 15 Chemical Equilibrium

In summary:

• Equilibrium constant for the reverse direction is the inverse of that for the forward direction.

• When a reaction is multiplied by a number, the equilibrium constant is raised to that power.

• The equilibrium constant for a reaction which is the sum of other reactions is the product of the equilibrium constants for the individual reactions.

Page 11: Chapter 15 Chemical Equilibrium

• If one or more reactants or products are in a different phase, the equilibrium is heterogeneous.

• Consider:

– experimentally, the amount of CO2 does not seem to depend on the amounts of the solids CaO and CaCO3.

Heterogeneous EquilibriaHeterogeneous Equilibria

CaCO3(s) CaO(s) + CO2(g)

Page 12: Chapter 15 Chemical Equilibrium

• The concentration of a solid or pure liquid is its density divided by molar mass.

• Neither density nor molar mass is a variable, the concentrations of solids and pure liquids are constant.

• For

22 COCO3

eq P×constant=P×]CaCO[

CaO][=K

CaCO3(s) CaO(s) + CO2(g)

•We ignore the concentrations of pure liquids and solids in equilibrium constant expressions.

Page 13: Chapter 15 Chemical Equilibrium

Predicting the Direction of Reaction• We define Q, the reaction quotient, for a general reaction

as

• Q = K only at equilibrium, that is when the system has reached equilibrium

aA + bB cC + dD

ba

dc

PP

PPQ

BA

DC

Page 14: Chapter 15 Chemical Equilibrium

Predicting the Direction of Reaction• If Q > K then the reverse reaction must occur to reach

equilibrium (i.e., products are consumed, reactants are formed, the numerator in the equilibrium constant expression decreases and Q decreases until it equals K).

• If Q < K then the forward reaction must occur to reach equilibrium.

Page 15: Chapter 15 Chemical Equilibrium
Page 16: Chapter 15 Chemical Equilibrium

• Consider the production of ammonia

• As the pressure increases, the amount of ammonia present at equilibrium increases.

• As the temperature decreases, the amount of ammonia at equilibrium increases.

• If we increase the amount of hydrogen the amount of ammonia increases

Le ChLe Châtelier’s Principleâtelier’s Principle

N2(g) + 3H2(g) 2NH3(g)

Page 17: Chapter 15 Chemical Equilibrium

• Le Châtelier’s Principle: if a system at equilibrium is disturbed, the systemwill move in such a way as to counteract thedisturbance.

Le ChLe Châtelier’s Principleâtelier’s Principle

Page 18: Chapter 15 Chemical Equilibrium

Change in Reactant or Product Concentrations

• If H2 is added while the system is at equilibrium, the system must respond to counteract the added H2 (by Le Châtelier).

• The system must consume the H2 and produce products until a new equilibrium is established.

• So, PH2 and PN2 will decrease and PNH3 increases.

N2(g) + 3H2(g) 2NH3(g)

Page 19: Chapter 15 Chemical Equilibrium

22

3

N3H

2NH

eq PPP

=K

If PH2 increases thenPN2 should decrease andPNH3 should increaseTo keep Keq constant

Page 20: Chapter 15 Chemical Equilibrium

Change in Reactant or Product Concentrations

• Adding a reactant or product shifts the equilibrium away from the increase.

• Removing a reactant or product shifts the equilibrium towards the decrease.

Page 21: Chapter 15 Chemical Equilibrium

Effects of Volume and Pressure Changes• Boyle’s Law: As volume is decreased pressure increases.

• if pressure is increased the system will shift to counteract the increase.

• That is, the system shifts to remove gases and decrease pressure.

• An increase in pressure favors the direction that has fewer moles of gas.

• In a reaction with the same number of product and reactant moles of gas, pressure has no effect.

Page 22: Chapter 15 Chemical Equilibrium

• An increase in pressure (by decreasing the volume) favors the formation of colorless N2O4.

• The instant the pressure increases, the system is not at equilibrium and the concentration of both gases has increased.

• The system moves to reduce the number moles of gas (i.e. the forward reaction is favored).

N2O4(g) 2NO2(g)

Page 23: Chapter 15 Chemical Equilibrium

Effect of Temperature Changes• The equilibrium constant is temperature dependent.

•Adding heat (i.e. heating the vessel) favors away from the increase:

–if H > 0, adding heat favors the forward reaction,

–if H < 0, adding heat favors the reverse reaction.

•Removing heat (i.e. cooling the vessel), favors towards the decrease:

–if H > 0, cooling favors the reverse reaction,

–if H < 0, cooling favors the forward reaction.

Page 24: Chapter 15 Chemical Equilibrium

• Consider

for which H > 0 (endothermic)– Since H > 0 (endothermic), adding heat favors the forward

reaction, i.e. the formation of blue CoCl42-.

– Since H > 0, removing heat favors the reverse reaction which is the formation of pink Co(H2O)6

2+.

Cr(H2O)62+(aq) + 4Cl-(aq) CoCl42-(aq) + 6H2O(l)

Page 25: Chapter 15 Chemical Equilibrium
Page 26: Chapter 15 Chemical Equilibrium

The Effect of Catalysis• A catalyst lowers the activation energy barrier for the

reaction.• Therefore, a catalyst will decrease the time taken to reach

equilibrium.• A catalyst does not effect the composition of the

equilibrium mixture.

Page 27: Chapter 15 Chemical Equilibrium

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