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JPN Pahang Physics Module FChapter 2 : Force and Motion
2. FORCE AND MOTION
2.1 ANALYSING LINEAR MOTION
Distance and displacement
1. Types of physical quantity:
(i) Scalar quantity: .
(ii) Vector quantity:
2. The difference between distance and displacement:
(i) Distance:
(ii) Displacement:
3. Distance always longer than displacement.
4. Example: The following diagram shows the location of Johor Bahru and Desaru.
You can travel by car using existing road via Kota Tinggi, or travel by asmall plane along straight path.
Calculate how far it is from Johor Bahru to Desaru if you traveled by:a. The car
b. The plane
Solution:
Hands-on Activity 2.2 pg 10 of the practical book.
Idea of distance and displacement, speed and velocity.
Speed and velocity
1. Speed is ..
2. Velocity is: .....
3. Average of speed:
4. Average of velocity: ...
1
Kota Tinggi
60 km
41 km 53 km
DesaruJohor Bahru
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JPN Pahang Physics Module FChapter 2 : Force and Motion
5. Example:
An aeroplane flies from A to B, which is located 300 km east of A. Upon reaching B, theaeroplane then flies to C, which is located 400 km north. The total time of flight is 4
hours. Calculate
i. The speed of the aeroplane
ii. The velocity of the aeroplane
Solution:
Acceleration and deceleration
1. Study the phenomenon below;
Observation:
2. Acceleration is, .
Then, a =
3. Example of acceleration;
2
20 m s-10 m s-1 40 m s-1
Or, a v u
t
20 m s-10 m s-1 40 m s-1
A B C
t = 2 s t = 2 s
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Calculate the acceleration of car;
i) from A to B
ii) From B to C
4. Deceleration happens ...
5. Example of deceleration;
A lorry is moving at 30 m s -1, when suddenly the driver steps on the brakes and it stop 5seconds later. Calculate the deceleration of lorry.
Analysing of motion
1. Linear motion can be studied in the laboratory using a ticker timer and a ticker tape.
Refer text book photo picture 2.4 page 26.
(i) Determination of time:
(ii) Determination of displacement as the length of ticker tape over a period of time.
x
y
(iii) Determine the type of motion;
..
......
3
20 02
= 10 m s-2
. . . . . . . .
. . . . . . . .
. . . . . . . .
. . . . . . . .
. . . . . . . .
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JPN Pahang Physics Module FChapter 2 : Force and Motion
...
(iv) Determination of velocity
displacement = time = ..
Velocity, v =
(v) Determine the acceleration
The equation of motion
1. The important symbols : ..
2. The list of important formula;
3. Example 1 : A car traveling with a velocity of 10 m s-1 accelerates uniformly at a rate of 3
m s-2 for 20 s. Calculate the displacement of the car while it is accelerating.
4
Length/cm
8
7
6
5
4
3
2
1
0
u
v
ticks
. . . . . . . .
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 2 : A van that is traveling with velocity 16 m s-1 decelerates until it comes to rest.If the distance traveled is 8 m, calculate the deceleration of the van.
Execise 2.1
1. Figure 2.1 shows a tape chartconsisting of 5-tick strip. Describe
the motion represented by AB and BC.
In each case, determine the ;
(a) displacement
(b) average velocity
Figure 2.1
(c) acceleration
2. A car moving with constant velocity of 40 ms-1 . The driver saw and obtacle in front andhe immediately stepped on the brake pedal and managed to stop the car in 8 s. The
distance of the obstacle from the car when the driver spotted it was 180 m. How far is the
obstacles from the car has sttoped.
5
Length / cm
16
12
8
4
0A B C Time/s
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JPN Pahang Physics Module FChapter 2 : Force and Motion
2.2 ANALYSING MOTION GRAPHS
The data of the motion of the car can be presented.
The displacement-time Graph
6
0m 100m 200m 300m 400m 500m displacement
0s 10s 20s 30s 40s 50s time
a) displacement (m) Graph analysis:
time (s) ...
b) displacement (m) Graph analysis:
..
time (s) .
c) displacement (m) Graph analysis:
.
time (s) ..
d) Displacement (m) Graph analysis:
.
..
time (s)
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JPN Pahang Physics Module FChapter 2 : Force and Motion
The velocity-time Graph
c) v (m s-1) Graph analysis:
...
t1 t2 t (s)
7
e) displacement (m) Graph analysis:
..
..
..
time (s)..
f) displacement (m) Graph analysis:
A B ..
..
O C time (s)
a) v/ m s-1 Graph analysis:
..
..
t t / s
b) v/ m s-1 Graph analysis:
....
t t / s
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JPN Pahang Physics Module FChapter 2 : Force and Motion
d) v (m s-1) Graph analysis:
.......
..
t (s)
....
e) v (m s-1) Graph analysis:
......
.
..
t (s)
Examples
1. s/m
2.
8
O
PQ
R
S
0 2 4 6 8 t/s
O
P Q
R
v/m s-1
10
5
0 2 4 6 8 10 t/s
Calculate:-
(i) acceleration,a over OP, PQ and QR
(ii) Displacement
Solution :
Calculate:-
(i) Velocity over OP, QR and RS
(ii) Displacement
Solution :
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Excercise 2.2
1. (a) s/m (b) s/m (c) s/m
10
t/s 0 2 4 t/s t/s
-5 -10
Figure 2.21
Describe and interpret the motion of a body which is represented by the displacement
time graphs in Figure 2.21
2. Describe and interpret the motion of body which is represented by the velocity-timegraphs shown in figure 2.22. In each case, find the distance covered by the body and its
displacement
(a) v/m s-1 (b) v/m s-1
10
t/s 0 2 4 t/s
-5 -10
Figure 2.22
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JPN Pahang Physics Module FChapter 2 : Force and Motion
2.3 UNDERSTANDING INERTIA
Idea of inertia
1.
2.
3.
Hand-on activity 2.5 in page 18 of the practical book to gain an idea of inertia
4. Meaning of inertia :
...
Mass and inertia
1. Refer to figure 2.14 of the text book, the child and an adult are given a push to swing.
(i) which one of them will be more difficult to be moved ...
(ii) which one of them will be more difficult to stop? .
2. The relationship between mass and inertia : .
..
3. The larger mass .
Effects of inertia
1. Positive effect :
(i)
(ii)
(iii)
2. Negative effect : .
(i) ...
..
(ii)
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JPN Pahang Physics Module FChapter 2 : Force and Motion
(iii)
(iv)
Execise 2.3
1. What is inertia? Does 2 kg rock have twice the inertia of 1 kg rock?
2.
Figure 2,3
A wooden dowel is fitted in a hole through a wooden block as shown in figure 2.31.Explain what happen when we
(a) strike the top of the dowel with a hammer,
(b) hit the end of the dowel on the floor.
2.4 ANALYSING MOMENTUM
Idea of momentum
1. When an object ic moving, ...
2. The amount of momentum ...
3. Momentum is defined.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Conservation of momentum
The principle of conservation of momentum :
1. Elastic collision ...
12
(mb
+ mg)
mg
vg = 0
mb
vb&g
Starting position beforeshe catches the ball
vb
Receiving a massive ball
mb vb
mg
vg
Starting position
before she throws
the ballThrowing a massive ball
m1m2 m1
m2
u2 v2
u1
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Before collision after collision
2. Inelastic collision :...
Before collision after collision
3. explosion : ........
Before explosion after explosion
Example 1 :
Car A Car B
Car A of mass 100 kg traveling at 30 m s-1 collides with Car B of mass 90 kg traveling at20 m s-1 in front of it. Car A and B move separately after collision. If Car A is still moving at
25 m s-1 after collision, determine the velocity of Car B after collision.
Solution :
Example 2 :
Car A of mass 100 kg traveling at 30 m s-1 collides with Car B of mass 90 kg traveling at
20 m s-1 in front of it. Car A is pulled by Car B after collision. Determine the common velocity of
Car A and B after collision.
13
m1m2
m1 + m2
u2 = 0
u1
v
(m1 + m2), u = 0 v1
m2
v2
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Solution :
Ex
ample 3 :
A bullet of mass 2 g is shot from a gun of mass 1 kg with a velocity of 150 m s-1 . Calculate the
velocity of the recoil of the gun after firing.
Solution :
Exercise 2.4
1. An arrow of mass 150 g is shot into a wooden block of mass 450 g lying at rest on asmooth surface. At the moment of impact, the arrow is travelling horizontally at 15 ms -1.
Calculate the common velocity after the impact.
2. A riffle of mass 5.0 kg fires a bullet of mass 50 g with a velocity of 80 m s-1 .Calculate therecoil velocity. Explain why the recoil velocity of a riflle is much less than the velocity of
the bullet.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
2.5 UNDERSTANDING THE EFFECT OF A FORCE
Idea of force
1. What will happen when force act to an object?
Idea of balanced forces
1. An object is said to be in balance when it is:
2. Stationary object
explanation :
...
3. An object moving with uniform velocity
.. explanation :
... ..
..
..
...
15
Stationary object
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JPN Pahang Physics Module FChapter 2 : Force and Motion
..
..
Idea of unbalanced forces
1. A body is said to be in unbalanced..
2. .. Explanation;
..
Relationship between forces, mass and acceleration (F = ma)Experiment 2.2 page 29.
Aim : To investigate the relationship between acceleration and force applied on a constantmass.
Experiment 2.3 page 31
Aim: To investigate the relationship between mass and acceleration of an object under
constant force.
1. Refer to the result of experiment 2.2 and 2.3,
2. 1 newton (F = 1 N) is defined as the force required to produce an acceleration of 1 m s-2
(a=1 m s-2) when its acting on an object of mass 1 kg ( m = 1 kg)
So,
3. Example 1 : Calculate F, when a = 3 m s-2 dan m = 1000 kg
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 2 :
Calculate the acceleration, a of an object.
Exercise 2.5
1. A trolley of mass 30 kg is pulled along the ground by horizontal force of 50 N. Theopposing frictional force is 20 N. Calculate the acceleration of the trolley.
2. A 1000 kg car is travelling at 72 km h-1 when the brakes are applied. It comes to a stop in
a distance of 40 m. What is the average braking force of the car?
2.6 ANALYSING IMPULSE AND IMPULSIVE FORCE
Impulse and impulsive force
1. Impulse is .
2. Impulsive force is
3. Formula of impulse and impulsive force:
Refer, F = ma
17
m = 25 kgm = 25 kg
F = 200 NF = 200 N
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 1; v u
wall
If ; u = 10 m s-1 , v = - 10 m s-1 , m = 5 kg and t = 1 s
Impulse, Ft = and impulsive force, F =
Example 2; v u
Wall with a soft surface
If ; u = 10 m s-1 , v = - 10 m s-1 , m = 5 kg and t = 2 s
Impulse, Ft = and impulsive force, F =
4. The relationship between time of collision and impulsive force.
Exercise 2.6
1. A force of 20 N is applied for 0.8 s when a football player throws a ball from the sideline.What is the impulse given to the ball?
2. A stuntman in a movie jumps from a tall building an falls toward the ground. A largecanvas bag filled with air used to break his fall. How is the impulsive force reduced?
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JPN Pahang Physics Module FChapter 2 : Force and Motion
2.7 BEING AWARE OF THE NEED FOR SAFETY FEATURES IN VEHICLES
Importance of safety features in vehicles
Safety features Importance
Padded dashboardIncreases the time interval of collision so the impulsive force
produced during an impact is thereby reduced
Rubber bumper Absorb impact in minor accidents, thus prevents damage to the car.
Shatter-proof windscreen Prevents the windscreen from shattering
Air bagActs as a cushion for the head and body in an accident and thus
prevents injuries to the driver and passengers.
Safety seat belt
Prevents the passengers from being thrown out of the car. Slows
down the forward movement of the passengers when the car stops
abruptly.
19
Safety features in vehicles
Crash resistant doorpillars
Anti-lock brakesystem (ABS)
Traction control bumpers
Windscreen
Air bags
Head rest
Crumple zones
Reinforced passenger compartment
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Side bar in doors
Prevents the collapse of the front and back of the car into the
passenger compartment. Also gives good protection from a side-on
collision.
Exercise 2.7
1. By using physics concepts, explain the midifications to the bus that help to improve that
safety of passengers and will be more comfortable.
2.8 UNDERSTANDING GRAVITY
Carry out hands-on activity 2.8 on page 35 of the practical book.
Acceleration due to gravity.
1. An object will fall to the surface of the earth because...
2. The force of gravity also known ...
3. When an object falls under the force of gravity only, ...
4. The acceleration of objects falling freely
5. The magnitude of the acceleration due to gravity depends ...
Gravitational field
1. The region around the earth is .
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JPN Pahang Physics Module FChapter 2 : Force and Motion
2. The object in gravitational field
3. The gravitational field strength is defined ..
4. The gravitational field strength, g can be calculate as;
5. At the surface of the earth, .
..
6. This means
..
7. Example 1. Can you estimate the gravitational force act to your body?mass = 60 kg, g = 9.8 N kg-1, F = ?
Example 2,
A satellite of mass 600 kg in orbit experiences a gravitational force of 4800 N. Calculate
the gravitational field strength.
Example 3,A stone is released from rest and falls into a well. After 1.2 s, it hits the bottom of the
well.
(a) What is the velocity of the stone when it hits the bottom?
(b) Calculate the depth of the well.
Weight
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JPN Pahang Physics Module FChapter 2 : Force and Motion
1. The weight of an object is defined ..
2. For an object of mass m, the weight can be calculate as :
Example : The mass of a helicopter is 600 kg. What is the weight of the helicopter
when it land on the peak of a mountain where the gravitational field is
9.78 N kg-1?
Exercise 2.8
1. Sketch the following graphs for an object that falling freely.
(a) Displacement-time graph,
(b) Velocity-time graph(c) Acceleration-time graph
2. The following data was obtained from an experiment to measure the acceleration due to
gravity.Mass of steel bob = 200 g, distance covered = 3.0 m, time of fall = 0.79 s.
Calculate the acceleration due to gravity of steel bob.
Give the explanation why your answer different with the constant of gravitationalacceleration, g = 9.8 m s-2.
2.9 IDEA OF EQUILIBRIUM FORCES
An object is in equilibrium when :
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JPN Pahang Physics Module FChapter 2 : Force and Motion
1.
2.
stationary object
An object moving with uniform velocity
Addition of Force
1. Addition of force is defined as .....
Examples : the forces are acting in one direction
F1 = 10 N
F2 = 5 N
Resultant force, F
Example : the forces are acting in opposite directions
F1 = 10 N
F2 = 5 N
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Resultant force, F
Example : the forces are acting in different directions
F2 = 5 N
500
F1 = 10 N
Parallelogram method:
1. Draw to scale.
2. Draw the line parallel with F1 to the edge of F2, and the line parallel with F2 to the
edge of F1
3. Connect the diagonal of the parallelogram starting from the initial point.
4. Measure the length of the diagonal from the initial point as the value of the
resultant force.
F2
F1
Triangle method
1. Draw to scale.
2. Displace one of the forces to the edge of another force.
3. Complete the triangle and measure the resultant force from the initial
point.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 1: During Sport Day two teams in tug of war competition pull with forces of
6000 N and 5300 N respectively. What is the value of the resultant force?
Are the two team in equilibrium?
Example 2: A boat in a river is pulled horizontally by two workmen. Workmen A
pulls with a force of 200 N while workmen while workmen B pulls with a
force of 300 N. The ropes used make an angle 250 with each other. Draw a
parallelogram and label the resultant force using scale of 1 cm : 50 N.
Determine the magnitude of resultant force.
Resolution of a force
1. Resolution of a force is
Refer to trigonometric formula:
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example : The figure below shows Ali mopping the floor with a force 50 N
at an angle of 600 to the floor.
F = 50 N
Example of resolution and combination of forces
Problem solving
1. When a system is in equilibrium, .
2. If all forces acting at one point are resolved into horizontal and vertical
components,
3. Example 1; Show on a figure;
a) the direction of tension force, T of string
b) the resultant force act to lamp
c) calculate the magnitude of tension force, Ta)
mlamp = 1.5 kg
Wlamp = 14.7 N
26
F = ?
200 N
400
T b) T T70
0
700
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Exercise 2.9
1. Two force with magnitude 18 N and 6 N act along a straight line. With the aid ofdiagrams, determine the maximun possible value and the minimum possible value of the
resultant force.
2. A football is kicked simultaneously by two players with force 220 N and 200 N
respectively, as shown in Figure 2.9. Calculate the magnitude of the resultant force.
220 N
900
200 N
2.10 UNDERSTANDING WORK, ENERGY AND EFFICIENCY
Work
1. Work is done, ..
2. WORK is the product..
3. The formulae of work;
4. Example 1;
27
Force, F
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 2;
80 N
600
s = 5 m
Example 3;
Example 4;
28
s
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JPN Pahang Physics Module FChapter 2 : Force and Motion
F = 600 N
S = 0.8 m
Energy
1. Energy is .................................................................................................................
2. Energy cannot be ....................................................................................................
3. Exist in various forms such as ...
4. Example of the energy transformation;
5.
Example :
Work done and the change in kinetic energy
1. Kinetic energy is
2. Refer to the figure above,
29
s
Force, F
Through, v2= u2+2asu = 0
and, as = v2
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JPN Pahang Physics Module FChapter 2 : Force and Motion
3. Example 1; A small car of mass 100 kg is moving along a flat road. The
resultant force on the car is 200 N.
a) What is its kinetic energy of the car after moving through 10 m?b) What is its velocity after moving through 10 m?
Work done and gravitational potential energy
h = 1.5 m
1. Gravitational potential energy is...
2.
Refer to the figure above;
3. Example; If m = 10 kg
Principle of conservation of energy
Carry out hands-on activity 2.10 on page 38 of the practical book.
To show the principle of conservation of energy.
1. Energy cannot be
2. Example : a thrown ball upwards will achieve a maximum height before changing itsdirection and falls
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JPN Pahang Physics Module FChapter 2 : Force and Motion
3. Example in calculation : A coconut falls from a tree from a height of 20 m. What is the
velocity of coconut just before hitting the earth?
Power
1. Power is
2. A weightlifter lifts 180 kg of weights from the floor to a height of 2 m above his head in atime of 0.8 s. What is the power generated by the weightlifter during this time?
g = 9.8 ms-2)
Efficiency
1. Defined...
2. Formulae of efficiency :
3. Analogy of efficiency;
Energy transformation
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JPN Pahang Physics Module FChapter 2 : Force and Motion
4. Example; An electric motor in a toy crane can lift a 0.12 kg weight through a height of
0.4 m in 5 s. During this time, the batteries supply 0.8 J of energy to the motor. Calculate
(a) The useful of output of the motor.
(b) The efficiency of the motor
Carry out hands-on activity 2.11 on page 39 of the practical book to measure the power.
Exercise 2.10
1. What is the work done by a man when he pushes a box with a force of 90 N through a
distance of 10 m? State the amount of energy transferred from the man to the force.
2. A sales assistant at a shop transfers 50 tins of milk powder from the floor to the top shelf.Each tin has a mass of 3.0 kg and the height of thee top shelf is 1.5 m.
(a) Calculate the total work done by the sales assistant.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
(b) What is his power if he completes this work in 250 s?
2.11 APPRECIATING THE IMPORTANCE OF MAXIMISING THE EFFICIENCY
OF DEVICES
1. During the process of transformation the input energy to the useful output energy,
..
2. ...3.
Example of wasting the energy;
..
Input enegy outputfrom the petrol energy
. .
.... .. .. .
.... . . .
4. The world we are living in face acute shortage of energy.
5. It is very important that a device makes
Ways of increasing the efficiency of devices
1. Heat engines ..
2. Electrical devices. ......
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Operation of electrical devices
1. The electrical devices increase the efficiency.
2. Proper management .....
3. ..
2.12 UNDERSTANDING ELASTICITY
Carry out Hands-on activity 2.12 page 40 of the practical book.
1. Elasticity is ...
2. Forces between atoms ..
3. Forces between atoms in equilibrium condition
34
Force of repulsion
Force of attraction
Force of repulsion
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Explanation :
4. Forces between atoms in compression
Explanation ;
5. Forces between atoms in tension
force of attraction
stretching force stretching force
Explanation ;
Carry out Experiment 2.4 on page 41 of the practical book
To investigate the relationship between force and extension of a spring
Hookes Law
1. Hookes Law states
2. Elastic limit of a spring is defined.
3. The spring is said to have a permanent extension,...
35
compressive forcecompressive force
Force of repulsionForce of repulsion
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JPN Pahang Physics Module FChapter 2 : Force and Motion
4. The elastic limit is not exceeded,.
5. Graf F against xGraf F against x
F/ N
6. Spring Constant, k
F/N
0.8
0 8 x/cm
Example 1; A spring has an original length of 15 cm. With a load of mass 200 g
attached, the length of the spring is extend to 20 cm.
a. Calculate the spring constant.
b. What is the length of the spring when the load is in increasedby 150 g? [assume thatg= 10 N kg-1]
36
x (cm)0
EQ
P
R
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Example 2;
Elastic potential energy
1. Elastic potential energy ..
spring with the original length
F compression
x spring compressed x
F x = compression x
x F spring extended
x = extension F, extension
Other situation where the spring extended
and compressed
Relationship between work and elastic potential energy
Graph F against x
Example ;
37
The graph shows the relationship between the
stretching force, F and the spring extension, x.
(a) Calculate the spring constant of P and Q.(b) Using the graph, determine the
stretching force acts to spring P and
spring Q, when their extension are 0.5 cm
x / cm
F/N
F x
15 cm
5 kg
8 cm
F (N)
x (cm)
P
Q
8
7
6
5
4
3
2
1
0 0.1 0.2 0.3 0.4 0.5
Graph F against x ofspring P and spring Q
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JPN Pahang Physics Module FChapter 2 : Force and Motion
Factors that effect elasticity
Hands-on activity 2.13 on page 42 the practical book to investigate the factors that affect
elasticity.
Type of material different same same same
Diameter of spring wire same different same same
Diameter of spring same same different same
Length of spring same Same same different
Summarise the four factors that affect elasticity
Factor Change in factor Effect on elasticity
Length Shorter spring Less elasticLonger spring More elastic
Diameter of springSmaller diameter Less elastic
Larger diameter More elastic
Diameter of spring wireSmaller diameter More elastic
Larger diameter Less elastic
Type of material the elasticity changes with the type of materials
Exercise 2.12
1. A 6 N force on a spring produces an extension of 2 cm. What is the extension when the
force is increased to 18 N? State any assumption you made in calculating your answer.
2. If a 20 N force extends a spring from 5 cm to 9 cm,
(a) what is the force constant of the spring?
(b) Calculate the elastic potential energy stored in the spring.
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Reinforcement Chapter 2
Part A : Objective Questions
1. When a coconut is falling to the
ground, which of the followingquantities is constant?
A. Velocity
B. Momentum
C. Acceleration
D. Kinetic energy
2. In an inelastic collision, which of thefollowing quantities remains
constant before and after thecollision?
A. Total acceleration
B. Total velocityC. Total momentum
D. Total kinetic energy
3. Calculate the weight of a stone withmass 60 g on the surface of the
moon.
(The gravitational acceleration of themoon is 1/6 that of the Earth.)
A. 0.1 NB. 0.2 N
C. 0.4 N
D. 0.6 N
E. 0.8 N
4. The momentum of a particle is
dependent on
A. mass and acceleration
B. weight and force
C. mass and velocity
5. Which of the following diagrams
shows a body moving at constant
velocity?
A. 2 N 2N
B. 12 N 7 N
C. 12 N 14 N
D. 20 N 17 N
6. The graph below shows the motionof a trolley with mass 1.5 kg.
Velocity / ms-1
4
0 2 4 6 Time / s
Calculate the momentum of the
trolley from t = 2s to t = 4s.
A. 1.5 kg m s-1
B. 3.0 kg m s-1
C. 4.0 kg m s-1
D. 6.0 kg m s-1
E. 7.5 kg m s-1
7. This figure shows an aircraft flying
in the air.
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Lift
Thrust Air friction
Weight
The aircraft above accelerates if
A. Lift > Weight
B. Thrust > Lift
C. Lift > Air friction
D. Thrust>
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JPN Pahang Physics Module FChapter 2 : Force and Motion
8. m = 0.3 kg
5 m
What is the momentum of the stonejust before it hits the ground?
A. 0.15 kg m s-1
B. 0.3 kg m s-1C. 1.5 kg m s-1
D. 3.0 kg m s-1
E. 15.0 kg m s-1
Solution :
9. A big ship will keep moving for some
distance when its engine is turned off.
This situation happens because the shiphas
A. great inertiaB. great acceleration
C. great momentum
D. great kinetic energy
10. An iron ball is dropped at a height of
10 m from the surface of the moon.
Calculate the time needed for theiron ball to land.
(Gravitational acceleration of the
moon is 1/6 that of the Earth and
g = 9.8 N kg
-2
)
A 0.6 sB 1.4 s
C 1.7 s
D 3.5 s
E 12.0 s
Part B : Structure Questions
1.
(i) Car A (ii) Car B
Diagram 1.1
Diagram 1.1(i) and (ii) show two methods used by the mechanic to move a breakdown
car. A constant force, F = 500 N is used to push and pull the car in method A and B.
(a) (i) Which method is easier to move the car?
(ii) State a reason for your answer in (a)(i).
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JPN Pahang Physics Module FChapter 2 : Force and Motion
(b) The frictional force acting between the car and track surface in both methods is
200 N. Calculate, the
(i) horizontal resultant force in method A.
(ii) horizontal resultant force in method B.
(iii) acceleration of the car in method B.
( c ) Suggest a method to move Car B so that the acceleration produced is equal to thatof method A.
....
2. ceiling
Tin water M N hand
P Q R
(i) Diagram 2.1 (ii)
a) Diagram 2.1(i) shows tin P that is empty and tin Q that is filled with water. Astudent find difficult to pushed tin Q. Write the inference about the observation.
b) Diagram 2.1(ii) shows a tin being released from the different positions M and N.
The hand of a student at position R needs greater force to stop the motion of the
tin falling from position M. Explain this observation.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
c) Based on the observation (i) and (ii), state two factors that affect the magnitude of
the momentum of the object.
d) If water flows out from a hole at the bottom of the tin Q, how would the inertia of
Tin Q depends on time ?
3. 2 ms-1
P iron ball ( 2 kg )
S T3.0 m smooth surface
1.0 m 2.0 m
Q RDiagram 3 Rough surface
The figure shows a iron ball that is rolled through PQRST. The rough surface of QR hasfrictional force of 4 N.
a) Calculate
(i) the kinetic energy of the iron ball at P.
(ii) the potential energy of the iron ball at P.
(iii) the total of energy of the iron ball at P.
b)c) (i) Calculate the total of energy of the iron ball when it reaches at Q ?
(ii) Calculate the work done against friction along QR.
d) Calculate the total kinetic energy of the iron ball at S.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
e) Calculate the speed of the ball at position T.
Part C : Essay Questions
1.
(i) (ii)Diagram 1.1
Diagram 1.1(i) shows the condition of a car moving at high velocity when it suddenlycrashes into a wall.
Diagram 1.1(ii) shows a tennis ball hit with racquet by a player.
a) (i) What is the meaning of momentum?
(ii) Based on the observations of Diagram (i) and (ii), compare the
characteristics of car when it crashes into the wall and the tennis ball when
it is hit with a racquet. Hence, relate these characteristics to clarify aphysics concept, and name this concept.
b) Explain why a tennis player uses a taut racquet when playing.
c) In launching a rocket, a few technical problems have to be overcome before the
rocket can move upright to the sky. By using appropriate physics concepts,
describe the design of a rocket and the launch techniques that can launch therocket upright.
Answer
a) (i) momentum is product of mass and velocity
(ii) - The shape of car changed but the shape of wall remained.- The shape of ball remained but the shape of the racquet string was
changed. (The racquet string is elastic but the wall is harder)
- The time taken of collision between the ball and racquet string morethan
the time taken when the car hit the wall.
- The impulsive force will decrease when the time of collision increased.- The concept is the impulsive force.
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JPN Pahang Physics Module FChapter 2 : Force and Motion
b) - To decrease the time of collision between the ball and the racquet string.- Impulsive force will be increased.
- The force act to the ball will be increased.
- The velocity of ball will be increased.
c) - Make a gradually narrower at the front shape (tapering): To decrease air friction
- Made by the high strength and high rigidity of materials: To decrease the probability to become dented (kemik).
- Made by the low density of material.
: To reduce the mass/weight- The structure is fractional engine
: The mass will be decreased and the velocity will increase.
- Made by the high of heat capacity of materials
: It will be high heat resistance.
2.
Brand Reaction time / s Mass / kg
Engine thrust
force / N
Resistance
force / N
A 0.3 1.5 10.0 4.0
B 0.5 1.8 12.5 2.4
C 0.2 0.9 6.5 2.2
D 0.6 2.5 16.0 6.5
In a radio-controlled car racing competition, 4 mini-cars branded A, B, C and D took
part. The information of the 4 cars is given in the table above. Details of the aboveinformation are given as below;
Reaction time - Duration between the moment the radio-controlled is switched on and
the moment the car starts moving.Resistance - Average value of opposing forces includes the friction between
wheels and track, and air resistance.
(a) What is the meaning ofacceleration?
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JPN Pahang Physics Module FChapter 2 : Force and Motion
(b) Draw a graph of velocity against time that shows a car moving initially with
constant acceleration, then moving with constant velocity and followed by
constant deceleration until it stops.
(c) Explain the suitability of the properties in the above table in constructing a radio-
controlled car racing purpose. Hence, determine which brand of car will win the
50-metre race.(c) If Car B in the above table is moved up the plane at the angle of 30o to the
horizon,(i) Show that the car is able to move up the plane.
(ii) Determine the acceleration of the car.