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Races a n d Games
Introduction 1. Race: A contest of speed is called a race. 2. Racecourse: The ground or path on which contests are
arranged is called a racecourse. 3. Starting Point: The point from where a race begins is
called the starting point. 4. Finishing Point: The point where the race finishes is
called finishing point or winning post. 5. Winner: The person who first reaches the finishing point
is called the Winner. 6. Dead-heat Race: If all the persons contesting a race reach
the goal exactly at the same time, then the race is called a dead-heat race.
Now, suppose A and B are two participants in a race. If, before the start of the race, A is at the starting point and B is ahead of A by 25 metres, then A is said to give B a start of 25 metres. To cover a race of 100 metres in this case, A will cover a distance of 100 metres and B will cover 100 - 25 = 75 metres only. Note: In the above case, we may say that "A has given a lead of 25 metres to B."
7. Games: If we say that it is a game of 100, then the person among the participants who scores 100 points first is the winner. If, when A scores 100 while B scores only 80 points, then we say that "A can give 20 points to B" or, "A can give B 20 points" in a game of 100.
Rule 1 Involving Two Participants In a contest with two participants, one is the winner and the other is the loser. a) The winner can give or allow the loser a start of t seconds or x metres, i.e.
start distance = x metres and start time = t seconds. b) The winner can beat the loser by t seconds or x metres, i.e.
beat distance = x metres and beat time = t seconds Now, consider the following cases,
I. A beats B < L = Length of race •
Winner's (A) distance = L p , Q
A beats B by 'x' metres
Loser's (B) distance =<L-x) m p ! L-JC
A and B start together at P When A finishes at Q, B reaches R
II. A gives B a start of x metres X"' •(
Loser's (B) distance = ( L - x) m P * * i (
R* L-x *
A starts at P, but B starts at R at the same time.
III. A beats B by t seconds
A and B starts together at P Winner's (A) time = Loser's (B) time - 1
A finishes at Q but t seconds before B finishes
IV. A gives B a start of t seconds
A starts t seconds after B starts at P From the above figures, we have the following formulae for a race of two participants. (i) Winner's distance = Length of race (ii) Loser's distance = Winner's distance - (beat distance + start distance) (iii) Winner's time =• Loser's time - (beat time + start time)
(iv) Winner's time Loser's time Loser's distance Winner's distance
beat time + start time
beat distance + start distance (v) I f a race ends in a dead lock, i.e. both reach the winning
post together then beat time = 0 and beat distance = 0
Illustrative Example Ex.: In one kilometre race, A beats B by 36 metres or 9
seconds. Find A's time over the course. Soln: Here A is the winner and B is the loser.
Races and Games 507
C B
182 169
182
1 6 < { ^ U82
350 325
.-. C beats B by 350 - 325 = 25 m. Quicker Method: Applying the above theorem, we have
the required answer = 31-18
1,200-18
13
x350
x350 = 25 metres. 182
Exercise L In a 100 metres race, A beats B by 10 metres and C by 13
metres. In a race of 180 metres, B will beat C by: a) 5.4 metres b) 4.5 metres c) 5 metres d) 6 metres
2 In a km race A beats B by 100 metres and C by 200 metres, by how much can B beat C in a race of 1350 metres? a) 150 metres b) 160 metres c) 140 metres d) 13 5 metres
3. In a 100 metres race A can beat B by 10 metres, and B can beat C by 10 metres. By how much can A beat C in the same race? / a) 10m b)12m c)19m d) Can't be determined
4. A can beat B by 25 metres in a — km race, and B can
beat C by 20 metres in a — km race. By how much can A beat C in a km race? a) 130 m b) 126 m c) 136 m d) Data inadequate
5. In a race of600 m, A can beat B by 60 m and in a race of 500 m, B can beat C by 50 m. By how many metres will A beat C in a race of400 m?
1 a) 70 m b) 76 m c) 77 - m d) None of these
6. In a race of600 m, A can beat B by 50 m and in a race of 500 m, B can beat C by 60 m. By how many metres will A beat C in a race of400 m?
a) 76 m
Answers
b) 7 6 j m c)77m d) 77y m
( 200-100 } b - * 2 a ; H i n H T o ^ ^ J x l 3 5 ° = , 5 0 m e t r e s -3. c; Hint: We can apply the given rule, in this problem also.
Now, applying the given rule we have
/ xV-10 ,xl00 =io
U o o - i o J w
or,x-10 = 9 .-. x=19m. 4. c; Hint: A can beat B by (25 x 4 =) 100 metres in a km race
B can beat C by (20 x 2 =) 40 metres in a km race. Now, applying the given rule, we have ( x-100 U000-100 or,*- 100 = 36
xlOOO =40
x= 100 + 36 = 136 metres.
60 5. b; Hint: A can beat B by -r^r* 400 = 40 m in 400 m race
600
B can beat C by ^ * 400 = 40 m in 400 m race.
Let A will beat C in a race of400 m by x m. Now, applying the given rule we have
x-40 x400 =40
6.d
400-40 J or,x-40 = 36 .•. x=40+36=76m. Note: Try to solve this type of question by Rule - 2 also.
Rule 8 Theorem: A can give B x metres and Cy metres (y >x)ina R metres race, while B can give C't' seconds over the course. Then the time taken to run R metres by (i) A is given by
(R-xXR-y) . ( y - x ) .
seconds and (Hi) C is given by t
Illustrative Example
^ seconds,(ii) B is given by 1
fR-x^
R - y y - x
U - x J seconds.
\.
I d ; Hint: Here y 2 >y\, hence formula will change as r \ yi-y\
A can give B 20 m and C 25 m in a 100 m race, while B can give C one second over the course. How long does each take to run 400 m?
Soln: Detail Method: A:B:C = I00:80:75
xx.
. required answer = ( 13-10 > 3
xl80 = —xl80 100-10 j 90
= 6 metres.
, / l Q O ^ B:C = 80:75 = 8 0 [ W J : 7 5 | — J =
100 375
.Cruns 100 375 25 m in 1 second.
508
C runs 100 m in — * 100 = 16 seconds.
Now, B runs 100 m in 16 -1 = 15 seconds. And A runs 100 m in the same time as B runs 80 m
ie., J O O x ^ ~ ^ seconds.
Quicker Method: Applying the above theorem, we have
(i) time taken by A = 1 100
(l00-20Xl00-25) (25-20)
(ii) time taken by B = 1
80x75 500
100-25 25-20
= 12 sec.
= — = \5 sec. 5
(iii) time taken by G = 1 (100-20 "l 80 -
= — = 16 ^ 25-20 J 5
sec.
Exercise 1. A can give B 40 metres and C 82 metres in a 880 metres
race while B can give C 9 seconds over the course. Find the time C takes to run 880 metres. a)lmin b) 180 min c)3min d) 60 sec
2 A can give B 10 metres and C 20 metres in a 100 metres race. B can give C 1 second over the course of 100 metres. How long does each take to run 100 metres? a) 7.2 sec, 8 sec, 9 sec b) 6.2 sec, 8 sec, 10 sec c) 7.2 sec, 9 sec, 10 sec d) Data inadequate
3. A can give B 40 metres and C 80 metres in a 400 metres race. B can give C 4 seconds over the course of 400 metres. How long does A take to run 400 metres? a) 28 sec b) 28.2 sec c) 28.8 sec d) 29 sec
Answers
1. c; Hint: Required answer = 9
2. a; Hint: Time taken by A
880-40 82-40
(100-10)(100-20) 20-10
Time taken by B :
Time taken by C =
1 100
72 10
= 180 sec=3 min.
«7.2 sec
' l 0 0 - 2 0 \ _ 8 0 ~ 10 ^ 20-10
100-10 90 10
= 8 sec
= 9 sec
3. c; Hint: Time taken by A
^ 20-10 (400-40)(100-80)
80-40 4
400 = 28.8 sec
PRACTICE BOOK ON QUICKER MATHS
Rule 9 Theorem: In a game of 'x'points, A can give B x, points
and C x2 points ( x 2 > x , ) then B can give
X T — X i
x - x 1 J points.
Illustrative Example Ex.: In a game of 100 points, A can give B 25 points and C
31 points, then how many points can B give C? Soln: Detail Method: A : B: C = 100:75 :69
7> 100 75x
B:C = ^ = 75-69 — 100 92
100
69x-75
.-. B can give C 8 points. Quicker Method: Applying the above theorem, we have
( 31 — 25 N
the required answer = ^ ^ J Q O - 2 5
Exercise 1. In a game
100x6 „ . = ——— = 8 points.
5.
— e of 100 points, A can given B 20 points and C 28 points. Then, B can give C: a) 8 points b) 10 points c) 14 points d) 40 points In a game of250 points A can give B 50 points and C 70 points. How many can B give G? a) 20 points b) 25 points c) 30 points d) None of these A can give B 20 points, A can give C 32 points and B can give C 15 points. How many points make the game? a) 1000 b)100 c)500 d)250 A can give B 20 points in 100 and B can give C 20 points in 100. How many in 100 can A give C? a) 26 b)36 c)46 d)30 A can give B 25 points, A can give C 40 points and B can m\ / A r . 7 n " ">» t< - Urt, ./ «-» '•". ' n n i n t c m',1L'r> thf* ( r a m p 9 give C 20 points a)200 b)150 c)100 d)120 A can give B 15 points, A can give C 22 points and B can give C 10 points. How many points make the game?
b)60 c)80 d)90
toints, A can give C 40 points and B c How many points make the game? 50 C ) 100 d) 120
a) 50
Answers l .b ••
3b; Hint: * 32-20
2.b
= 15 V x-20 j or, 12x = 15x - 300 or, -3x=-300 • x= 100 points
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