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Chapter 5 - Detailing Durability

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Detailing durability for Eurocode 2
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Page 1: Chapter 5 - Detailing Durability
Page 2: Chapter 5 - Detailing Durability

Detailing and durability requirements are to ensure

that a structure has satisfactory durability and

serviceability performance under normal

circumstances throughout its lifetime.

These requirements will involve aspects of design,

such as concrete mix selection and determination of

cover to reinforcing bars, as well as selection of

suitable materials for the exposure conditions which

are expected .

Page 3: Chapter 5 - Detailing Durability

EC2 recommends simple rules concerning the

concrete mix and cover to reinforcement,

minimum member dimension, and limits to

reinforcement quantities and spacing which

must be taken into account at the member

sizing and reinforcement detailing stage.

Page 4: Chapter 5 - Detailing Durability

The nominal cover can be assessed as follows:

Cnom = Cmin + Cdev

where Cmin shall be provided in order to ensure:

•The safe transmission of bond forces

•The protection of steel against corrosion (durability)

•An adequate fire resistance

And Cdev is and allowance which should be made in the

design for deviation from the minimum cover. It should be

taken as 10 mm. It is permitted to reduce to 5 mm if the

fabrication subjected to a quality assurance system.

Page 5: Chapter 5 - Detailing Durability
Page 6: Chapter 5 - Detailing Durability
Page 7: Chapter 5 - Detailing Durability

Minimum cover for bond, Cmin, b (EN 1992-1-1)

Page 8: Chapter 5 - Detailing Durability

Arrangement of

bars

Minimum cover Cmin,b*

Separated Diameter of bar

Bundle Equivalent diameter

n = nb 55 mm

where nb is the number of bars in the bundle, which

is limited to

nb 4 for vertical bars in compression

nb 3 for all other cases

* If the nominal maximum aggregate size is 32 mm, cmin,b should be

increased by 5 mm

Minimum cover for bond, Cmin, b (EN 1992-1-1)

Page 9: Chapter 5 - Detailing Durability

Minimum cover for durability, Cmin, dur (EN 1992-1-1)

Recommended structural class

Page 10: Chapter 5 - Detailing Durability
Page 11: Chapter 5 - Detailing Durability
Page 12: Chapter 5 - Detailing Durability

Minimum cover for fire resistance, Cmin, fire

Rather than giving a minimum cover, the tubular method based on

nominal axis distance is used. This is the distance from the centre of the

main reinforcement bar to the top or bottom surface of the member.

a > Cnom + link + bar/2

asd = a + 10 mm

From Table 5.5 and 5.6 BS EN 1992-1-2: 2004

Page 13: Chapter 5 - Detailing Durability
Page 14: Chapter 5 - Detailing Durability

The minimum area of reinforcement that must be

provided within tensile zone is

As, min = kck fct, eff Act / fyk

The minimum area of reinforcement for beam also

specified in Cl. 9.2.1 as follows:

As, min = 0.26(fctm/fyk)btd but not less than 0.0013btd

Page 15: Chapter 5 - Detailing Durability
Page 16: Chapter 5 - Detailing Durability

As, max

To ensure the structural member is not congested

with reinforcements and for ease during concrete

compaction work

Page 17: Chapter 5 - Detailing Durability

hagg + 5 mm

hagg + 5 mm

The minimum distance between

bars is to permit concrete flows

around reinforcement during

construction and to ensure that

concrete can be compacted

satisfactorily for the development of adequate bond.

The clear distance between bars should not be less

than the maximum of (i) the maximum bar size, (ii) the

maximum aggregate size + 5 mm, or (iii) 20 mm.

(Specified in section 8.2 EC2).

Page 18: Chapter 5 - Detailing Durability

It is a common practice to cut off bars where they are no

longer required to resist moment.

Each curtailed bar should extend a full anchorage length

beyond the point at which it is no longer needed.

The basic required anchorage length given in EC2: Cl.

8.4.3 is as follows;

lb,rqd = ( / 4) (sd / fbd) = ( / 4) (fyk / 1.15) / fbd)

= (fyk / 4.6 fbd)

Page 19: Chapter 5 - Detailing Durability
Page 20: Chapter 5 - Detailing Durability
Page 21: Chapter 5 - Detailing Durability

The curtailment of the tension reinforcement is based upon the enveloped of

tensile forces, Fs derive from the bending moment envelop as shown in Fig. 9.2:

EC2 such that at any location along the span, Fs = MEd/z + ∆Ftd

Page 22: Chapter 5 - Detailing Durability

When considering the curtailment the following rules must be applied:

At least one-quarter of the bottom reinforcement should

extend to the support.

The bottom reinforcement at the end support should be

anchored into the support as shown in Fig. 9.3: EC 2.

At an end support where there is little or not fixity the

bottom steel should be designed to resist a tensile force of

0.5VEd to allow for the tension induced by the shear

with a minimum requirement of 25% of the reinforcement

provided in the span.

Page 23: Chapter 5 - Detailing Durability

At and end support where there is fixity but it has been

analysed as a simple support, top steel should be

design and anchored to resist at least 25% of the

maximum mid-span moment.

At internal supports the bottom steel should extend at

least 10 beyond the face of support. To achieve

continuity and resistance to such factors as accidental

damage or seismic forces, splice bars should be

provided across the support with a full anchorage lap on

each side as shown in Fig. 9.4: EC 2.

Page 24: Chapter 5 - Detailing Durability
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The design anchorage length lbd mentioned above is

given by,

lbd = 1 2 3 4 5 lbd, rqd lb, min

where

1, 2 ,3, 4 and5 = coefficient given in Table 5.5

lbd, rqd = Eq. (5.4)

lb, min = the minimum anchorage length

for tension bars: max {0.3 lbd, rqd; 10 ; 100 mm}

for compression bars: max {0.6 lbd, rqd; 10 ; 100 mm}

Page 28: Chapter 5 - Detailing Durability

Value of allows for the effect of Type of anchorageReinforcement in

Tension Compression1 The shape of the bars Straight 1.0 1.0

Other than straight 0.7 if cd > 3.0or 1.0 if not

1.0

2 Concrete cover to reinforcement Straight 1.0 – 0.15(cd - )/but 0.7 and ≤ 1.0

1.0

Other than straight 1.0 – 0.15(cd - 3)/but 0.7 and ≤ 1.0

1.0

3 Confinement of transverse reinforcement not welded to the main reinforcement

All types of reinforcement

1 – Kbut 0.7 and ≤ 1.0

1.0

4 Confinement of transverse reinforcement welded to the main reinforcement

All types, position and sizes of reinforcement

0.7 0.7

5 Confinement by transverse pressure

All types of reinforcement

1 – 0.04ρbut 0.7 and ≤ 1.0

-

Table 5.5: Values of 1, 2, 3, 4 and 5 coefficients

Page 29: Chapter 5 - Detailing Durability

Laps are required when bars placed short of their

required length need to be extended. Laps are

also required when the bar diameter has to be

changed along the length. The purpose of lapping

is to transfer effectively the axial force from the

terminating bar to the connecting bar with the

same line of action at the junction.

Page 30: Chapter 5 - Detailing Durability

Requirements for laps are discussed in EC2: Cl.

8.7. The code recommends that;

Laps between bars should be staggered

and should not occur in regions of high

stress.

The arrangement of lapped bars should

comply with Fig. 8.7: EC2 below.

Page 31: Chapter 5 - Detailing Durability
Page 32: Chapter 5 - Detailing Durability

Transverse reinforcement must be provided around

laps unless lapped bars are less than 20 mm

diameter or there is less than 25 % lapped bars. In

these cases minimum transverse reinforcement

provided for other purposes such as shear links will

be adequate. Otherwise transverse reinforcement

must be provided, as shown in Fig. 8.9: EC2, having

a total area of not less than the area of one lapped

bar.

Page 33: Chapter 5 - Detailing Durability

Figure 8.9: Transverse reinforcement for lapped splices

Page 34: Chapter 5 - Detailing Durability

The length of laps should be based on the minimum

anchorage length modified to take into account

factors such as cover, etc. The design lap length

required is given by;

lo = 1 2 3 5 6 lbd, rqd lo, min

Page 35: Chapter 5 - Detailing Durability

where

1, 2 ,3, 4 and5 = coefficient given in Table 5.5

For the calculation of 3 , Ast, min should be taken as 1.0As(sd/fyd), with As =

area of one lapped bar

6 = (ρ1/25)0.5 but not exceeding 1.5 nor less than 1.0 and ρ1 is the

percentage of reinforcement lapped within 0.65lo from the centre of the lap

length being considered.

lbd, rqd = Eq. (5.3)

lo, min = the absolute minimum lap length max {0.36 lbd, rqd ; 15; 200 mm}

Page 36: Chapter 5 - Detailing Durability

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