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211
CHAPTER 8: EXPONENTS AND POLYNOMIALS Chapter Objectives By the end of this chapter, students should be able to: Simplify exponential expressions with positive and/or negative exponents Multiply or divide expressions in scientific notation Evaluate polynomials for specific values Apply arithmetic operations to polynomials Apply special-product formulas to multiply polynomials Divide a polynomial by a monomial or by applying long division
CHAPTER 8: EXPONENTS AND POLYNOMIALS ........................................................................................ 211
SECTION 8.1: EXPONENTS RULES AND PROPERTIES ........................................................................... 212
A. PRODUCT RULE OF EXPONENTS .............................................................................................. 212
B. QUOTIENT RULE OF EXPONENTS ............................................................................................. 212
C. POWER RULE OF EXPONENTS .................................................................................................. 213
D. ZERO AS AN EXPONENT............................................................................................................ 214
E. NEGATIVE EXPONENTS ............................................................................................................. 214
F. PROPERTIES OF EXPONENTS .................................................................................................... 215
EXERCISE ........................................................................................................................................... 216
SECTION 8.2 SCIENTIFIC NOTATION ..................................................................................................... 217
A. INTRODUCTION TO SCIENTIFIC NOTATION ............................................................................. 217
B. CONVERT NUMBERS TO SCIENTIFIC NOTATION ..................................................................... 218
C. CONVERT NUMBERS FROM SCIENTIFIC NOTATION TO STANDARD NOTATION .................... 218
D. MULTIPLY AND DIVIDE NUMBERS IN SCIENTIFIC NOTATION ................................................. 219
E. SCIENTIFIC NOTATION APPLICATIONS ..................................................................................... 220
EXERCISE ........................................................................................................................................... 222
SECTION 8.3: POLYNOMIALS ................................................................................................................ 223
A. INTRODUCTION TO POLYNOMIALS ......................................................................................... 223
B. EVALUATING POLYNOMIAL EXPRESSIONS .............................................................................. 225
C. ADD AND SUBTRACT POLYNOMIALS ....................................................................................... 226
D. MULTIPLY POLYNOMIAL EXPRESSIONS ................................................................................... 228
E. SPECIAL PRODUCTS .................................................................................................................. 230
F. POLYNOMIAL DIVISION ............................................................................................................ 231
EXERCISE ........................................................................................................................................... 237
CHAPTER REVIEW ................................................................................................................................. 239
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SECTION 8.1: EXPONENTS RULES AND PROPERTIES A. PRODUCT RULE OF EXPONENTS
MEDIA LESSON Product rule of exponents (Duration 2:57)
View the video lesson, take notes and complete the problems below
ππ3 β ππ2 = (ππ ππ ππ)(ππ ππ) = ππ5 Product rule: ππππ β ππππ = ππππ+ππ ____________________________!
Example 1: (2x3)(4x2)(β3x) = ___________________________
Example 2: (5a3b7)(2a9b2c4) = ___________________________
Warning! The rule can only apply when you have the same base.
YOU TRY
Simplify: a) 53510
b) π₯π₯1π₯π₯3π₯π₯2 c) (2π₯π₯3π¦π¦5π§π§)(5π₯π₯π¦π¦2π§π§3)
B. QUOTIENT RULE OF EXPONENTS
MEDIA LESSON Quotient rule of exponents (Duration 3:12)
View the video lesson, take notes and complete the problems below
ππ5
ππ3=ππ β ππ β ππ β ππ β ππ
ππ β ππ β ππ= ππ2
Quotient Rule: ππππ
ππππ= ππππβππ
_________________________________
Example 1: ππ7ππ2
ππ3ππ
= ___________________________
Example 2: 8ππ7ππ4
6ππ5ππ
= ___________________________
YOU TRY
Simplify
a) 713
75 b)
5ππ3ππ5ππ2
2ππππ3ππ c)
3π₯π₯5
π₯π₯3π¦π¦
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C. POWER RULE OF EXPONENTS
MEDIA LESSON Power rule of exponents (Duration 5:00)
View the video lesson, take notes and complete the problems below
(ab)3=_____________________________ = ________
Power of a product: (ππππ)ππ = ππππππππ
οΏ½πππποΏ½3
=____________________ =_____________
Power of a Quotient: οΏ½πππποΏ½ππ
= ππππ
ππππ , if b is not 0.
(ππ2)3 = _____________________ = ______ Power of a Power: (ππππ)ππ = ππππβππ
Example 1: (5ππ4ππ)3 Example 2: οΏ½5ππ
3
9ππ4οΏ½2
Warning! It is important to be careful to only use the power of a product rule with multiplication inside parenthesis. This property is not allowed for addition or subtraction, i.e.,
(ππ + ππ)ππ β ππππ + ππππ (ππ β ππ)ππ β ππππ β ππππ
YOU TRY
Simplify:
a) οΏ½π₯π₯3
π¦π¦2οΏ½5
b) οΏ½23
52οΏ½7
c) (π₯π₯3π¦π¦π§π§2)4
d) (4π₯π₯2π¦π¦5)3
e) οΏ½ ππ3ππ
ππ8ππ5οΏ½2
f) οΏ½4π₯π₯π¦π¦8π§π§οΏ½2
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D. ZERO AS AN EXPONENT
MEDIA LESSON Zero as Exponent (Duration 3:51)
View the video lesson, take notes and complete the problems below
ππ3
ππ3=_____________________________________________
Zero Power Rule: ππππ = ππ
Example 1: (5π₯π₯3π¦π¦π§π§5)0
Example 2: (3π₯π₯2π¦π¦0)(5π₯π₯0π¦π¦4)
YOU TRY
Simplify the expressions completely a) (3x2)0
b) 2ππ0ππ6
3ππ5
E. NEGATIVE EXPONENTS
MEDIA LESSON Negative Exponents (Duration 4:44)
View the video lesson, take notes and complete the problems below
ππ3
ππ5 = __________________________________________
=___________________________________________
Negative Exponent Rule: ππβππ = ππππππ
When a and b are not 0.
1ππβππ
= ππππ οΏ½πππποΏ½βππ
= οΏ½πππποΏ½ππ
=ππππ
ππππ
Example 1: 7π₯π₯β5
3β1π¦π¦π§π§β4
Example 2: 2
5ππβ4
Warning! It is important to note a negative exponent does not imply the expression is negative, only the reciprocal of the base. Hence, negative exponents imply reciprocals. YOU TRY
a) 3
5β1π₯π₯ b)
ππ3ππ2ππ2ππβ1ππβ4
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F. PROPERTIES OF EXPONENTS Putting all the rules together, we can simplify more complex expression containing exponents. Here we apply all the rules of exponents to simplify expressions.
Exponent Rules
Product
ππππ β ππππ = ππππ+ππ
Quotient
ππππ
ππππ= ππππβππ
Power of Power
(ππππ)ππ = ππππβππ
Power of a Product
(ππππ)ππ = ππππππππ
Power of a Quotient
οΏ½πππποΏ½ππ
=ππππ
ππππ
Zero Power
ππππ = ππ
Negative Power
ππβππ = ππππππ
Reciprocal of Negative Power
ππππβππ
= ππππ
Negative Power of a Quotient
οΏ½πππποΏ½βππ
= οΏ½πππποΏ½ππ
=ππππ
ππππ
MEDIA LESSON Properties of Exponents (Duration 5:00)
View the video lesson, take notes and complete the problems below
Example 1: (4x5y2z)2(2π₯π₯4π¦π¦β2π§π§3)4 Example 2:
οΏ½2x2y3οΏ½4οΏ½x4yβ6οΏ½β2
(xβ6y4)2
YOU TRY
Simplify and write your final answers in positive exponents.
a) 4π₯π₯β5π¦π¦β3β 3π₯π₯3π¦π¦β2
6π₯π₯β5π¦π¦3
b)
οΏ½3ππππ3οΏ½β2β ππππβ3
2ππβ4ππ0
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EXERCISE Simplify. Be sure to follow the simplifying rules and write answers with positive exponents.
1) 4 β 44 β 44 2) 4 β 22 3) 3ππ β 4ππππ
4) 2ππ4ππ2 β 4ππππ2 5) (33)4 6) (44)2
7) (2π’π’3π£π£2)2 8) (2ππ4)4 9) 45
43
10) π₯π₯2π¦π¦4 β π₯π₯π¦π¦2 11) (π₯π₯π¦π¦)3 12) 37
33
13) 32
3 14)
3ππππ2
3ππ 15)
4π₯π₯3π¦π¦4
3π₯π₯π¦π¦3
16) π₯π₯2π¦π¦4
4π₯π₯π¦π¦ 17) 3π₯π₯ β 4π₯π₯2 18) (π’π’2π£π£2 β 2π’π’4)3
19) (π₯π₯3π¦π¦4 β 2π₯π₯2π¦π¦3)2 20) 2π₯π₯(π₯π₯4π¦π¦4)4 21) 2π₯π₯7π¦π¦5
3π₯π₯3π¦π¦β 4π₯π₯2π¦π¦3
22) οΏ½(2π₯π₯)3
π₯π₯3οΏ½2
23) οΏ½ 2π¦π¦17
(2π₯π₯2π¦π¦4)4οΏ½3 24) οΏ½2ππππ4β 2ππ4ππ4
ππππ4οΏ½3
25) 2π₯π₯π¦π¦5β 2π₯π₯2π¦π¦3
2π₯π₯π¦π¦4β π¦π¦3 26)
2π₯π₯2π¦π¦2π§π§6β 2π§π§π₯π₯2π¦π¦2
(π₯π₯2π§π§3)2 27) 2π¦π¦
(π₯π₯0π¦π¦2)4
28) 2ππππ7β 2ππ4
ππππ2β 3ππ3ππ4 29)
2ππ2ππ2ππ7
(ππππ4)2 30) π¦π¦π₯π₯2β οΏ½π¦π¦4οΏ½2
2π¦π¦4
31) 2ππ2ππ2ππ7
(ππππ4)2 32) ππ3οΏ½ππ4οΏ½2
2ππππ 33)
οΏ½2π¦π¦3π₯π₯2οΏ½2
2π₯π₯2π¦π¦4π₯π₯2
34) 2ππ3ππ3ππ4β 2ππ3
(ππππππ3)2 35) 2π₯π₯4π¦π¦β2 β (2π₯π₯π¦π¦3)4 36) 2π₯π₯β3π¦π¦2
3π₯π₯β3π¦π¦3β 3π₯π₯0
37) π’π’π£π£β1
2π’π’0π£π£4β 2π’π’π£π£ 38) οΏ½2ππ
2ππ3
ππβ1οΏ½4
39) 2π₯π₯π¦π¦2β 4π₯π₯3π¦π¦β4
4π₯π₯β4π¦π¦β4β 4π₯π₯
40) 2ππ4ππβ2β οΏ½2ππ3ππ2οΏ½β4
ππβ2ππ4
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SECTION 8.2 SCIENTIFIC NOTATION A. INTRODUCTION TO SCIENTIFIC NOTATION One application of exponent properties is scientific notation. Scientific notation is used to represent really large or really small numbers, like the numbers that are too large or small to display on the calculator.
For example, the distance light travels per year in miles is a very large number (5,879,000,000,000) and the mass of a single hydrogen atom in grams is a very small number (0.00000000000000000000000167). Basic operations, such as multiplication and division, with these numbers, would be quite cumbersome. However, the exponent properties allow us for simpler calculations.
MEDIA LESSON Introduction of scientific notation (Watch from 0:00 β 9:00)
View the video lesson, take notes and complete the problems below
100 =___________
101 =____________
102 =_____________
103 = _____________
10100 = _________________________
Avogadro number: 602,200,000,000,000,000,000,000 = ______________________________
MEDIA LESSON Definition of scientific notation (Duration 4:59)
View the video lesson, take notes and complete the problems below
Standard Form (Standard Notation): _______________________________________________________
Scientific Notation: ____________________________________________________________________
b: _________________________________________
b positive: __________________________________
b negative: _________________________________
Example: Convert to Scientific Notation
a) 48,100,000,000 = _________________ b) 0.0000235 = ________________
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Definition Scientific notation is a notation for representing extremely large or small numbers in form of
ππ π₯π₯ 10ππ where 1 < a < 10 and b is number of decimal places from the right or left we moved to obtain a.
A few notes regarding scientific notation:
β’ b is the way we convert between scientific and standard notation. β’ b represents the number of times we multiply by 10. (Recall, multiplying by 10 moves the decimal
point of a number one place value.) β’ We decide which direction to move the decimal (left or right) by remembering that in standard
notation, positive exponents are numbers greater than ten and negative exponents are numbers less than one (but larger than zero).
Case 1. If we move the decimal to the left with a number in standard notation, then b will be positive. Case 2. If we move the decimal to the right with a number in standard notation, then b will be negative.
B. CONVERT NUMBERS TO SCIENTIFIC NOTATION
MEDIA LESSON Convert standard notation to scientific notation (Duration 1:40)
View the video lesson, take notes and complete the problems below
Example: Convert to scientific notation
8150000 =
0.00000245 =
YOU TRY
Convert the following number to scientific notation a) 14,200
b) 0.0042
c) How long is a Light-Year? The light-year is a measure of distance, not time. It is the total distance that a beam of light, moving in a straight line, travels in one year is almost 6 trillion (6,000,000,000,000) miles. Express a light year in scientific notation. (Source: NASA Glenn Educational Programs Office https://www.grc.nasa.gov/www/k-12/aerores.htm)
C. CONVERT NUMBERS FROM SCIENTIFIC NOTATION TO STANDARD NOTATION
To convert a number from scientific notation of the form ππ π₯π₯ 10ππ
to standard notation, we can follow these rules of thumb. β’ If b is positive, this means the original number was greater than 10, we move the decimal to
the right b times. β’ If b is negative, this means the original number was less than 1 (but greater than zero), we move
the decimal to the left b times.
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MEDIA LESSON Convert scientific notation to standard notation (Duration 2:22)
View the video lesson, take notes and complete the problems below
Example: Rewrite in standard notation (decimal notation)
a) 7.85 Γ 106
b) 1.6 Γ 10β4
YOU TRY
Covert the following scientific notation to standard notation
a) 3.21 Γ 105 b) 7.4 Γ 10β3
D. MULTIPLY AND DIVIDE NUMBERS IN SCIENTIFIC NOTATION Converting numbers between standard notation and scientific notation is important in understanding scientific notation and its purpose. Next, we multiply and divide numbers in scientific notation using the exponent properties. If the immediate result is not written in scientific notation, we will complete an additional step in writing the answer in scientific notation.
Steps for multiplying and dividing numbers in scientific notation
Step 1. Rewrite the factors as multiplying or dividing a-values and then multiplying or dividing 10b values.
Step 2. Multiply or divide the a values and apply the product or quotient rule of exponents to add or subtract the exponents, b, on the base 10s, respectively.
Step 3. Be sure the result is in scientific notation. If not, then rewrite in scientific notation.
MEDIA LESSON Multiply and divide scientific notation (Duration 2:47)
View the video lesson, take notes and complete the problems below
β’ Multiply/ Divide the ______________________________________ β’ Use ______________________________________________________on the 10s
Example:
a) (3.4 Γ 105)(2 β 7 Γ 10β2) b)
5.32Γ104
1.9Γ10β3
MEDIA LESSON Multiply scientific notations with simplifying final answer step (Duration 3:47)
View the video lesson, take notes and complete the problems below
Example: a) (1.2 Γ 104)(5.3 Γ 103) b) (9 Γ 101)(7 Γ 109)
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MEDIA LESSON Divide scientific notations with simplifying final answer step (Duration 3:44)
View the video lesson, take notes and complete the problems below
a) 7Γ1012
2Γ107
b) 2.4Γ107
4.8Γ102
YOU TRY
Multiply or divide
a) (2.1 π₯π₯ 10β7)(3.7 π₯π₯ 105)
b) 4.96 π₯π₯ 104
3.1 π₯π₯ 10β3
c) (4.7 π₯π₯ 10β3)(6.1 π₯π₯ 109)
d) (2 Γ 106)(8.8 Γ 105)
e) 8.4Γ105
7Γ102
f) 2.014 π₯π₯ 10β3
3.8 π₯π₯ 10β7
E. SCIENTIFIC NOTATION APPLICATIONS
MEDIA LESSON Scientific notation application example 1 (Duration 2:36)
View the video lesson, take notes and complete the problems below Example 1: There were approximately 50,000 finishers of the 2015 New York City Marathon. Each finisher ran a distance of 26.1 miles. If you add together the total number miles ran by all the runners, how many times around the earth would the marathon runners have ran? Assume the circumference of the earth to be approximately 2.5 x 104 miles. Total distance = _______________________________________________________________________ _____________________________________________________________________________________
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MEDIA LESSON Scientific notation application example 2 (Duration 3:24)
View the video lesson, take notes and complete the problems below
Example 2: If a computer can conduct 400 trillion operations per second, how long would it take the computer to perform 500 million operations? 400 trillion = __________________________________________________________________________
500 million = __________________________________________________________________________
Number of Operations: __________________________________________________________________
Rate of Operations: _____________________________________________________________________
_____________________________________________________________________________________
YOU TRY
a) It takes approximately 3.7 x 104 hours for the light on Proxima Centauri, the next closet star to our sun, to reach us from there. The speed of light is 6.71 x 108 miles per hours. What is the distance from there to earth? Given distance = rate x time. Express your answer in scientific notation
By ESO/Pale Red Dot - http://www.eso.org/public/images/ann16002a/, CC BY 4.0,
https://commons.wikimedia.org/w/index.php?curid=46463949
a) If the North Pole and the South Pole ice were to melt, the north polar ice would make essentially no contribution since it is float ice. However, the south polar ice would make a considerable contribution since it overlays the Antarctic land mass and is not float ice. If Antarctic ice melted, it would become approximately 1.5 x 109 gallons of water. If it takes roughly, 6 x 106 gallons of water to fill 1 foot of the earth, estimate how many feet the earthβs oceans would rise? Express your answer in the standard form. (Source: NASA Glenn Educational Programs Office https://www.grc.nasa.gov/www/k-12/aerores.htm)
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EXERCISE Write each number in scientific notation
1) 885 2) 0.081 3) 0.000039
4) 0.000744 5) 1.09 6) 15,000
Write each number in standard notation.
7) 8.7 Γ 105 8) 9 Γ 10β4 9) 2 Γ 100
10) 2.56 Γ 102 11) 5 Γ 104 12) 6 Γ 10β5
Simplify. Write each answer in scientific notation.
13) (7 Γ 101)(2 Γ 103) 14) (5.26 Γ 105)(3.16 Γ 102) 15) (2.6 Γ 10β2)(6 Γ 10β2)
16) (3.6 Γ 100)(6.1 Γ 10β3) 17) (6.66 Γ 10β4)(4.23 Γ 101) 18) (3.15 Γ 103)(8.8 Γ 10β5)
19) 4.81 Γ 106
9.62 Γ 102 20)
5.33Γ106
2Γ103 21)
4.08Γ10β6
5.1Γ10β4
22) 9Γ104
3Γ10β2 23)
3.22Γ10β3
7Γ10β6 24)
1.3Γ10β6
6.5Γ100
25) 5.8Γ103
5.8Γ10β3 26)
5Γ106
2.5Γ102 27)
8.4Γ105
7Γ10β2
Scientific Notation Applications (Source: NASA Glenn Educational Programs Office https://www.grc.nasa.gov/www/k-12/aerores.htm)
28) The mass of the sun is 1.98 x 1,033 grams. If a single proton has a mass of 1.6 x 10-24 grams, how many protons are in the sun?
29) Pluto is located at a distance of 5.9 x 1014 centimeters from Earth. At the speed of light (2.99 x 1010
cm/sec), approximately how many hours does it take a light signal (or radio message) to travel to Pluto and return? Write your answer standard form.
30) The planet Osiris was discovered by astronomers in 1999 and is at a distance of 150 light-years (1
light-year = 9.2 x 1012 kilometers). a) How many kilometers is Osiris from earth? Express your answer in scientific notation. b) If an interstellar probe were sent to investigate this world up close, traveling at a maximum speed
of 700 km/sec or 7 x 102 km/sec, how many seconds would it take to reach Osiris? c) There is about 3.15 x 106 seconds in a year. How many years would it take to reach Osiris?
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SECTION 8.3: POLYNOMIALS A. INTRODUCTION TO POLYNOMIALS
MEDIA LESSON Algebraic Expression Vocabulary (Duration 5:52)
View the video lesson, take notes and complete the problems below
Definitions
Terms: Parts of an algebraic expression separated by addition or subtraction (+ or β) symbols. Constant Term: A number with no variable factors. A term whose value never changes. Factors: Numbers or variable that are multiplied together Coefficient: The number that multiplies the variable.
Example 1: Consider the algebraic expression 4π₯π₯5 + 3π₯π₯4 β 22π₯π₯2 β π₯π₯ + 17
a. List the terms: __________________________________________________________________
b. Identify the constant term. ________________________________________________________
Example 2: Complete the table below
β4ππ βπ₯π₯ 12ππβ
2ππ5
List of Factors
Identify the Coefficient
Example 3: Consider the algebraic expression 5π¦π¦4 β 8π¦π¦3 + π¦π¦2 β π¦π¦4β 7
a. How many terms are there? ______________________
b. Identify the constant term. ______________________
c. What is the coefficient of the first term? ______________________
d. What is the coefficient of the second term ______________________
e. What is the coefficient of the third term? ______________________
f. List the factors of the fourth term. ______________________
YOU TRY
Example 3: Consider the algebraic expression 3π₯π₯5 + 4π₯π₯4 β 2π₯π₯ + 8
a. How many terms are there? ______________________
b. Identify the constant term. ______________________
c. What is the coefficient of the first term? ______________________
d. What is the coefficient of the second term ______________________
e. What is the coefficient of the third term? ______________________
f. List the factors of the third term. ______________________
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MEDIA LESSON Introduction to polynomials (Duration 7:12)
View the video lesson, take notes and complete the problems below
Definitions
Polynomial: An algebraic expression composed of the sum of terms containing a single variable raised to a non-negative integer exponent.
Monomial: A polynomial consisting of one term, example: _________________
Binomial: A polynomial consisting of two terms, example: _________________
Trinomial: A polynomial consisting of three terms, example: _________________
Leading Term: The term that contains the highest power of the variable in a polynomial,
example: _________________
Leading Coefficient: The coefficient of the leading term, example: _________________
Constant Term: A number with no variable factors. A term whose value never changes.
Example: _________________
Degree: The highest exponent in a polynomial , example: _________________
Example 1: Complete the table below
Polynomial Name
Leading Coefficient Constant Term Degree
24ππ6 + ππ2 + 5
2ππ3 + ππ2 β 2ππ β 8
5π₯π₯2 + π₯π₯3 β 7
β2π₯π₯ + 4
4π₯π₯3
YOU TRY
Complete the table below
Polynomial Name
Leading Coefficient Constant Term Degree
ππ2 β 2ππ + 8
7π¦π¦2
6π₯π₯ β 7
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MEDIA LESSON Introduction to polynomials 2 (Duration 2:58)
View the video lesson, take notes and complete the problems below Given: 9π¦π¦ + 7π¦π¦3 β 5 β 4π¦π¦2
1st term: _______________ Degree:_________________ Coefficient:______________ 2nd term: _______________ Degree:_________________ Coefficient:______________ 3rd term: _______________ Degree:_________________ Coefficient:______________ 4th term: _______________ Degree:_________________ Coefficient:______________
Leading coefficient: ________________ Degree of leading term: _____________ Degree of polynomial: _______________ Write the polynomial in descending order: ________________________________________________ (Or write the polynomial in the standard form)
Standard form of a polynomial The standard form of a polynomial is where the polynomial is written with descending exponents. For example: Rewrite the polynomial in standard form and identify the coefficients, variable terms, and degree of the polynomial
β12π₯π₯2 + π₯π₯3 β π₯π₯ + 2
The standard form of the above polynomial is π₯π₯3 β 12π₯π₯2 β π₯π₯ + 2.
The coefficients are 1; β12; β1, and 2; the variable terms are π₯π₯3,β12π₯π₯2,βπ₯π₯. The degree of the polynomial is 3 because that is the highest degree of all terms. YOU TRY
Write the following polynomials in the descending order or in standard form: a) 3π₯π₯ β 9π₯π₯3 + 2π₯π₯6 + 7π₯π₯2 β 3 + π₯π₯4
b) 5ππ2 β 5ππ4 + 3 β 4ππ3 β 2ππ7
B. EVALUATING POLYNOMIAL EXPRESSIONS
MEDIA LESSON Evaluating algebraic expressions (Duration 7:48)
View the video lesson, take notes and complete the problems below
To evaluate an algebraic or variable expression, ________________ the value of the variables into the expression. Then evaluate using the order of operations.
Example 1: If we are given 5π₯π₯ β 12 and π₯π₯ = 17 we can evaluate.
5π₯π₯ β 12
= 5 ( ___ ) β 12
= ___________________
Example 2: Let π₯π₯ = β3,π¦π¦ = 7, π§π§ = β2 Evaluate π₯π₯ β 3π¦π¦ + 7 Evaluate 2π₯π₯2 + 5π¦π¦ β π§π§3
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Example 3: Let = 3 . Evaluate 9π¦π¦
β8π¦π¦ + 2
Example 4: Let π₯π₯ = 3,π¦π¦ = β5. Evaluate 4π₯π₯ β 3π¦π¦2
Example 5: Let = β2 . Evaluate 3π₯π₯2 β π₯π₯2 + 2π₯π₯ + 9
Example 6: Let π₯π₯ = 2,π¦π¦ = β3. Evaluate π₯π₯2π¦π¦2
π₯π₯2β2π¦π¦3
YOU TRY
a) Evaluate 2π₯π₯2 β 4π₯π₯ + 6 when π₯π₯ = β4
b) Evaluate βπ₯π₯2 + 2π₯π₯ + 6 when π₯π₯ = 3
C. ADD AND SUBTRACT POLYNOMIALS
Combining like terms review
MEDIA LESSON Combine like terms 1 (Duration 4:36)
View the video lesson, take notes and complete the problems below
Definition Like terms: Two or more terms are like terms if they have the same variable or variables with the same exponents. Which of these terms are like terms? β2π₯π₯3, 2π₯π₯, 2π¦π¦, 7π₯π₯3, 49, 0π₯π₯2, π¦π¦2
Like terms: __________________________________________________________
Like terms: __________________________________________________________
To combine like terms, we __________________________________________. The variable factors __________________.
Example: Simplify each polynomials, if possible.
a) 4π₯π₯3 β 7π₯π₯3
b) 2π¦π¦2 + 4π¦π¦ β π¦π¦2 + 2 β 9π¦π¦ β 5 + 2π¦π¦
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MEDIA LESSON Combine like terms 2 (Duration 2:15)
View the video lesson, take notes and complete the problems below
Combine like terms
a) π₯π₯2π¦π¦ + 3π₯π₯π¦π¦2 + 4π₯π₯2π¦π¦
b) β7ππβ 4 + 2ππ + 9
YOU TRY
Combine like terms
a) 5π₯π₯2 + 2π₯π₯ β 5π₯π₯2 β 3π₯π₯ + 1
b) 3π₯π₯π¦π¦2 β 2π₯π₯2 + 6 + 3π¦π¦ β 5π₯π₯π¦π¦2 β 3
c) 3π₯π₯2π¦π¦π§π§ + 9π₯π₯2 β 5π₯π₯π¦π¦2π§π§ β 3π¦π¦2 + 5π₯π₯2
d) 3π₯π₯2 β 3π₯π₯ + 5π¦π¦2 β πππ₯π₯2 + 7 β π₯π₯ β 10π¦π¦2
Add and subtract polynomials
MEDIA LESSON Add and subtract polynomials (Duration 3:53)
View the video lesson, take notes and complete the problems below
To add polynomials: ____________________________________________________________________
To subtract polynomials: ________________________________________________________________
a) (5π₯π₯2 β 7π₯π₯ + ππ) + (2π₯π₯2 + 5π₯π₯ β 14) b) (3π₯π₯3 β 4π₯π₯ + 7) β (8π₯π₯3 + 9π₯π₯ β 2)
MEDIA LESSON Add and subtract polynomials (Duration 5:04)
View the video lesson, take notes and complete the problems below
c) (2π₯π₯5 β 6π₯π₯3 β 12π₯π₯2 β 4) β (11π₯π₯5 + 8π₯π₯ + 2π₯π₯2 + 6)
d) (β9π¦π¦3 β 6π¦π¦2 β 11π₯π₯ + 2) β (β9π¦π¦4 β 8π¦π¦3 + 4π₯π₯2 + 2π₯π₯)
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YOU TRY
Perform the operation below. a) (4π₯π₯3 β 2π₯π₯ + 8) + (3π₯π₯3 β 9π₯π₯2 β 11)
b) (5π₯π₯2 β 2π₯π₯ + 7) β (3π₯π₯2 + 6π₯π₯ β 4)
c) (2π₯π₯2 β 4π₯π₯ + 3) + (5π₯π₯2 β 6π₯π₯ + 1) β (π₯π₯2 β 9π₯π₯ + 8)
D. MULTIPLY POLYNOMIAL EXPRESSIONS 1. Distributive property review
MEDIA LESSON Distribute property review (Duration 6:08)
View the video lesson, take notes and complete the problems below
Distributive Property ππ(ππ + ππ) = ππππ + ππππ
ππ = 2 ππ = 3 ππ = 4
Example: Use the distributive property to expand each of the following expressions a) 5(2π₯π₯ + 4)
b) β3(π₯π₯2 β 2π₯π₯ + 7)
c) β(5π₯π₯4 β 8) d)
25οΏ½π₯π₯4β 1
3οΏ½
YOU TRY
Use the distributive property to expand each of the following expressions. a) 4(β5π₯π₯2 + 9π₯π₯ β 3) b) β7(β2ππ2 + ππβ 2)
2. Multiply a polynomial by a monomial
MEDIA LESSON Multiply a polynomial by a monomial (Duration 2:46)
View the video lesson, take notes and complete the problems below
To multiply a monomial by a polynomial: ___________________________________________________
Example 1: 5π₯π₯2(6π₯π₯2 β 2π₯π₯ + 5) Example 2: β3π₯π₯4(6π₯π₯3 + 2π₯π₯ β 7)
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YOU TRY
Multiply
a) 4π₯π₯3(5π₯π₯2 β 2π₯π₯ + 5)
b) 2ππ3ππ(3ππππ2 β 4ππ)
3. Multiplying with binomials
MEDIA LESSON Multiply binomials (Duration 4:27)
View the video lesson, take notes and complete the problems below
To multiply a binomial by a binomial: ___________________________________________________
_____________________________________________________________________________________
This process is often called ____________, which stands for ____________________________________
Example:
a) (4π₯π₯ β 2)(5π₯π₯ + 1) b) (3π₯π₯ β 7)(2π₯π₯ β 8)
YOU TRY
Multiply
a) (3π₯π₯ + 5)(π₯π₯ + 13)
b) (4π₯π₯ + 7π¦π¦)(3π₯π₯ β 2π¦π¦)
4. Multiply with trinomials
MEDIA LESSON Multiply with trinomials (Duration 5:00)
View the video lesson, take notes and complete the problems below
Multiplying trinomials is just like _______________, we just have to _____________________________.
Example: a) (2π₯π₯ β 4)(3π₯π₯2 β 5π₯π₯ + 1) b) (2π₯π₯2 β 6π₯π₯ + 1)(4π₯π₯2 β 2π₯π₯ β 6)
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YOU TRY
Multiply a) (2π₯π₯ β 5)(4π₯π₯2 β 7π₯π₯ + 3)
b) (5π₯π₯2 + π₯π₯ β 10)(3π₯π₯2 β 10π₯π₯ β 6)
E. SPECIAL PRODUCTS There are a few shortcuts that we can take when multiplying polynomials. If we can recognize when to use them, we should so that we can obtain the results even quicker. In future chapters, we will need to be efficient in these techniques since multiplying polynomials will only be one of the steps in the problem. These two formulas are important to commit to memory. The more familiar we are with them, the next two chapters will be so much easier.
1. Difference of two squares
MEDIA LESSON Difference of two squares (Duration 2:33)
View the video lesson, take notes and complete the problems below
Sum and difference
(ππ + ππ)(ππ β ππ) = _______________________________
= _______________________________
Sum and difference shortcut:
(ππ + ππ)(ππ β ππ) = ______________________
Example:
a) (π₯π₯ + 5)(π₯π₯ β 5)
b) (6π₯π₯ β 2)(6π₯π₯ + 2)
YOU TRY
Simplify: a) (3π₯π₯ + 7)(3π₯π₯ β 7)
b) (8 β π₯π₯2)(8 + π₯π₯2)
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2. Perfect square trinomials Another shortcut used to multiply binomials is called perfect square trinomials. These are easy to recognize because this product is the square of a binomial. Letβs take a look at an example.
MEDIA LESSON Perfect Square (Duration 3:40)
View the video lesson, take notes and complete the problems below
Perfect square
(ππ + ππ)2 = ____________________________________________________________________________
Perfect square shortcut:
(ππ + ππ)2 = _____________________________
Example: a) (π₯π₯ β 4)2
b) (2π₯π₯ + 7)2
YOU TRY
Simplify: a) (π₯π₯ β 5)2
b) (2π₯π₯ + 9)2
c) (3π₯π₯ β 7π¦π¦)2
d) (6 β 2ππ)2
F. POLYNOMIAL DIVISION Dividing polynomials is a process very similar to long division of whole numbers. Before we look at long division with polynomials, we will first master dividing a polynomial by a monomial.
1. Polynomial division with monomials
MEDIA LESSON Dividing polynomials by monomials - Separated fractions method (Duration 8:14)
View the video lesson, take notes and complete the problems below We divide a polynomial by a monomial by rewriting the expression as separated fractions rather than one
fraction. We use the fact: ππ+ππππ
= ππππ
+ ππππ
Example:
a) β6w8
30Ο3
b) 3π₯π₯β62
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c) 6π₯π₯3+2π₯π₯2β4
4π₯π₯
d) 20ππ2+35ππβ4
β5ππ2
YOU TRY
Simplify
a) 9π₯π₯5+6π₯π₯4β18π₯π₯3β24π₯π₯2
3π₯π₯2
b) 8π₯π₯3+4π₯π₯2β2π₯π₯+6
4π₯π₯2
MEDIA LESSON Long division review (Duration 3:55)
View the video lesson, take notes and complete the problems below
Long division review
5 2632 Long division steps: 1. ___________________________________________________
2. ___________________________________________________
3. ___________________________________________________
4. ___________________________________________________
5. ___________________________________________________
This method may seem elementary, but it isnβt the arithmetic we want to review, it is the method. We use the same method as we did in arithmetic, but now with polynomials.
MEDIA LESSON Dividing polynomials by monomials β Long division method (Duration 5:00)
View the video lesson, take notes and complete the problems below
Example:
a) 5π₯π₯5+18π₯π₯β9π₯π₯3
3π₯π₯2
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b) 15ππ6β25ππ5+5ππ4
5ππ4
YOU TRY
Divide using the long division method
a) 8π₯π₯6+ 20π₯π₯4+ 4π₯π₯3
4π₯π₯3
b) ππ4β ππ3+ ππ2
ππ
c) 12π₯π₯4β 24π₯π₯3 + 3π₯π₯2
6π₯π₯
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2. Polynomial division with polynomials
MEDIA LESSON Divide a polynomial by a polynomial (Duration 5:00)
View the video lesson, take notes and complete the problems below Polynomial division with polynomials On division step, only focus on the _______________________
Example 1: Divide π₯π₯3β2π₯π₯2β15π₯π₯+30
π₯π₯+4
Example 2: Divide 4π₯π₯3β6π₯π₯+12+8
2π₯π₯+1
YOU TRY
a) π₯π₯2+8π₯π₯+12
π₯π₯+1 =
b) 3π₯π₯3β5π₯π₯2β32π₯π₯+7
π₯π₯β4 =
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c) 6π₯π₯3β8π₯π₯2+10π₯π₯+103
2π₯π₯+4 =
MEDIA LESSON Divide a polynomial by a polynomial - rewriting the remainder as an expression (Duration 5:10)
View the video lesson, take notes and complete the problems below
Example: Divide π₯π₯3+8π₯π₯2β17π₯π₯β15
π₯π₯+3
YOU TRY
Divide the polynomials and write the remainder as an expression
a) π₯π₯2β5π₯π₯+7π₯π₯β2
=
b) π₯π₯3β4π₯π₯2β6π₯π₯+4
π₯π₯β1 =
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3. Polynomial division with missing terms Sometimes when dividing with polynomials, there may be a missing term in the dividend. We do not ignore the term, we just write in 0 as the coefficient.
MEDIA LESSON Polynomial division with missing terms (Duration 5:00)
View the video lesson, take notes and complete the problems below
Divide polynomials β Missing terms The exponents must ___________________________________.
If one is missing, we will add ___________________________________________.
Example 1: 3π₯π₯3β50π₯π₯+4
π₯π₯β4
Example 2: 2π₯π₯3+4π₯π₯2+9
π₯π₯+3
YOU TRY
a) 2π₯π₯3β4π₯π₯+42
π₯π₯+3=
b) 3π₯π₯3β3π₯π₯2+4
π₯π₯β3 =
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EXERCISE Evaluate the expression for the given value. Show your work.
1. βππ3 β ππ2 + 6ππ β 21 when ππ = β4 2. ππ2 β 3ππ β 11 when ππ = β6
3. ππ3 β 7ππ2 + 15ππ β 20 when ππ = 2 4. ππ3 β 9ππ2 + 23ππ β 21 when ππ = 5
5. β5ππ4 β 11ππ3 β 9ππ2 β ππ β 5 when ππ = 2 6. π₯π₯4 β 5π₯π₯3 β π₯π₯ + 13 when π₯π₯ = 1
7. π₯π₯2 + 9π₯π₯ + 23 when π₯π₯ = β3 8. βπ₯π₯3 + π₯π₯2 β π₯π₯ + 11 when π₯π₯ = 6
9. βπ₯π₯4 β 6π₯π₯3 + π₯π₯2 β 24 when π₯π₯ = β1 10. ππ4 + ππ3 + 2ππ2 + 13ππ + 5 when ππ = 3
Simplify. Write the answer in standard form. Show your work.
11. (5ππ β 5ππ4) β (8ππ β 8ππ4) 12. (3ππ2 β ππ3) β (2ππ3 β 7ππ2)
13. (8ππ + ππ4)β (3ππ β 4ππ4) 14. (1 + 5ππ3) β (1 β 8ππ3)
15. (5ππ4 + 6ππ3) + (8 β 3ππ3 β 5ππ4) 16. (3 + ππ4) + (7 + 2ππ + ππ4)
17. (8π₯π₯3 + 1) β (5π₯π₯4 β 6π₯π₯3 + 2) 18. (2ππ + 2ππ4) β (3ππ2 β 6ππ + 3)
19. (4ππ2 β 3 β 2ππ) β (3ππ2 β 6ππ + 3) 20. (4ππ3 + 7ππ2 β 3) + (8 + 5ππ2 + ππ3)
21. (3 + 2ππ2 + 4ππ4) + (ππ3 β 7ππ2 β 4ππ4) 22. (ππ β 5ππ4 + 7) + (ππ2 β 7ππ4 β ππ)
23. (8ππ4 β 5ππ3 + 5ππ2) + (2ππ2 + 2ππ3 β 7ππ4 + 1)
24. (6π₯π₯ β 5π₯π₯4 β 4π₯π₯2)β (2π₯π₯ β 7π₯π₯2 β 4π₯π₯4 β 8) β (8 β 6π₯π₯2 β 4π₯π₯4)
Multiply and simplify. Show your work
25. 6(ππ β 7) 26. 5ππ4(4ππ + 4)
27. (8ππ + 3)(7ππ β 5) 28. (3π£π£ β 4)(5π£π£ β 2)
29. (5π₯π₯ + π¦π¦)(6π₯π₯ β 4π¦π¦) 30. (7π₯π₯ + 5π¦π¦)(8π₯π₯ + 3π¦π¦)
31. (6ππ β 4)(2ππ2 β 2ππ + 5) 32. (8ππ2 + 4ππ + 6)(6ππ2 β 5ππ + 6)
33. 3(3π₯π₯ β 4)(2π₯π₯ + 1) 34. 7(π₯π₯ β 5)(π₯π₯ β 2)
35. (6π₯π₯ + 3)(6π₯π₯2 β 7π₯π₯ + 4) 36. (5ππ2 + 3ππ + 3)(3ππ2 + 3ππ + 6)
37. (2ππ2 + 6ππ + 3)(7ππ2 β 6ππ + 1) 38. 3ππ2(6ππ + 7)
39. (7π’π’2 + 2π’π’ β 3)(π’π’2 + 4) 40. 3π₯π₯2(2π₯π₯ + 3)(6π₯π₯ + 9)
Find each product by applying the special products formulas. Show your work
41. (π₯π₯ + 8)(π₯π₯ β 8) 42. (1 + 3ππ)(1 β 3ππ) 43. (1 β 7ππ)(1 + 7ππ)
44. (5ππ β 8)(5ππ + 8) 45. (4π₯π₯ + 8)(4π₯π₯ β 8) 46. (4π¦π¦ β π₯π₯)(4π¦π¦ + π₯π₯)
47. (4ππ β 2ππ)(4ππ + 2ππ) 48. (6π₯π₯ β 2π¦π¦)(6π₯π₯ + 2π¦π¦) 49. (ππ + 5)2
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50. (π₯π₯ β 8)2 51. (ππ + 7)2 52. (7 β 5ππ)2
53. (5ππ β 3)2 54. (5π₯π₯ + 7π¦π¦)2 55. (2π₯π₯ + 2π¦π¦)2
56. (5 + 2ππ)2 57. (2 + 5π₯π₯)2 58. (4π£π£ β 7)(4π£π£ + 7)
59. (ππ β 5)(ππ + 5) 60. (4ππ + 2)2 61. (ππ β 4)(ππ + 4)
62. (π₯π₯ β 3)(π₯π₯ + 3) 63. (8ππ + 5)(8ππ β 5) 64. (2ππ + 3)(2ππ β 3)
65. (ππ β 7)(ππ + 7) 66. (7ππ + 7ππ)(7ππ β 7ππ) 67. (3π¦π¦ β 3π₯π₯)(3π¦π¦ + 3π₯π₯)
68. (1 + 5ππ)2 69. (π£π£ + 4)2 70. (1 β 6ππ)2
71. (7ππ β 7)2 72. (4π₯π₯ β 5)2 73. (3ππ + 3ππ)2
74. (4ππ β ππ)2 75. (8π₯π₯ + 5π¦π¦)2 76. (ππ β 7)2
77. (8ππ + 7)(8ππ β 7) 78. (ππ + 4)(ππ β 4) 79. (7π₯π₯ + 7)2 Divide: Show your work
80. 20π₯π₯4+π₯π₯3+2π₯π₯2
4π₯π₯3 81.
5ππ4+ππ3+40ππ2
5ππ 82.
12π₯π₯4+24π₯π₯3+3π₯π₯2
6π₯π₯
83. 5π₯π₯5+18π₯π₯3+4π₯π₯ + 9
9π₯π₯ 84.
3ππ4+4ππ2+28ππ2
85. 10ππ4+5ππ3+2ππ2
ππ2
Divide and write your remainder as an expression. Show your work
86. π£π£2β2π£π£β89π£π£β10
87. π₯π₯2β2π₯π₯β71
π₯π₯+8
88.
ππ2+13ππ+32ππ+5
89. 10π₯π₯2β19π₯π₯+9
10π₯π₯β9
90.
ππ2β4ππβ38ππβ8
91. 45ππ2β56ππ+19
9ππβ4
92. 27ππ2+87ππ+35
3ππ+8
93.
4ππ2βππβ14ππ+3
94. ππ2β4ππβ2
95. π₯π₯3β26π₯π₯β41
π₯π₯+4
96.
4π₯π₯2β4π₯π₯+22π₯π₯β5
97. ππ3+5ππ2β4ππβ5
ππ+7
98. ππ3+5ππ2+3ππβ5
ππ+1
99. π₯π₯3β46π₯π₯+22
π₯π₯+7
100.
2π₯π₯3+12π₯π₯2β202π₯π₯+6
101. 4π£π£3+4π£π£+194π£π£+12
102. ππ3βππ2β16ππ+8
ππβ4
103.
12ππ3+12ππ2β15ππβ42ππ+3
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CHAPTER REVIEW KEY TERMS AND CONCEPTS
Look for the following terms and concepts as you work through the workbook. In the space below, explain the meaning of each of these concepts and terms in your own words. Provide examples that are not identical to those in the text or in the media lesson.
Product rule of exponents
Quotient rule of exponents
Power rule of a product
Power rule of a quotient
Power rule of a Power
Zero power rule
Negative exponent rule
Reciprocal of negative rule
Negative power of a quotient rule
Scientific notation
Standard notation (Decimal notation)
Polynomial
Monomial
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Binomial
Trinomial
Leading Term
Leading Coefficient
Degree of a Polynomial
Constant Term