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Chapter 9: Virtual Memory

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Chapter 9: Virtual Memory. Chapter 9: Virtual Memory. Background Demand Paging Process Creation Page Replacement Allocation of Frames Thrashing Demand Segmentation Operating System Examples. Background. Virtual memory – separation of user logical memory from physical memory. - PowerPoint PPT Presentation
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Chapter 9: Virtual Memory Chapter 9: Virtual Memory
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Page 1: Chapter 9:  Virtual Memory

Chapter 9: Virtual MemoryChapter 9: Virtual Memory

Page 2: Chapter 9:  Virtual Memory

9.2 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Chapter 9: Virtual MemoryChapter 9: Virtual Memory

Background

Demand Paging

Process Creation

Page Replacement

Allocation of Frames

Thrashing

Demand Segmentation

Operating System Examples

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9.3 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

BackgroundBackground

Virtual memory – separation of user logical memory from physical memory.

Only part of the program needs to be in memory for execution.

Logical address space can therefore be much larger than physical address space.

Allows address spaces to be shared by several processes.

Allows for more efficient process creation.

Virtual memory can be implemented via:

Demand paging

Demand segmentation

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9.4 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

저장장치 구성의 발전저장장치 구성의 발전

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9.5 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

가상 저장장치 가상 저장장치 : : 기본개념기본개념

고정 / 가변 분할의 문제점 : fragmentation

원인 : “ 메모리에 프로그램이 적재될 때는 반드시 연속적으로 적재되어야 한다”

가상 주소 공간과 실 주소 공간의 분리 가상 주소 공간 : 현재 진행중인 프로세스가 생성하는 주소의

집합 실 주소 공간 : 주 기억 장치에서 사용가능한 주소

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9.6 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

인위적 연속성인위적 연속성

인위적 연속성 : 가상 저장 장치에서 연속된 항목들은 반드시 연속될 필요가 없는 실저장 장치의 항목들로 매핑된다 .

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Virtual Memory That is Larger Than Physical MemoryVirtual Memory That is Larger Than Physical Memory

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Virtual-address SpaceVirtual-address Space

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Shared Library Using Virtual MemoryShared Library Using Virtual Memory

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9.10 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Demand PagingDemand Paging

Bring a page into memory only when it is needed.

Less I/O needed

Less memory needed

Faster response

More users

Page is needed reference to it

invalid reference abort

not-in-memory bring to memory

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9.11 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Transfer of a Paged Memory to Contiguous Disk SpaceTransfer of a Paged Memory to Contiguous Disk Space

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9.12 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Valid-Invalid BitValid-Invalid Bit

With each page table entry a valid–invalid bit is associated(1 in-memory, 0 not-in-memory)

Initially valid–invalid but is set to 0 on all entries. Example of a page table snapshot.

During address translation, if valid–invalid bit in page table entry is 0 page fault.

11110

00

Frame # valid-invalid bit

page table

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Page Table When Some Pages Are Not in Main MemoryPage Table When Some Pages Are Not in Main Memory

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9.14 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Page FaultPage Fault

If there is ever a reference to a page, first reference will trap to OS page fault

OS looks at another table to decide: Invalid reference abort. Just not in memory.

Get empty frame. Swap page into frame. Reset tables, validation bit = 1. Restart instruction: Least Recently Used

block move

auto increment/decrement location

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Steps in Handling a Page FaultSteps in Handling a Page Fault

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9.16 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

What happens if there is no free frame?What happens if there is no free frame?

Page replacement – find some page in memory, but not really in use, swap it out.

algorithm

performance – want an algorithm which will result in minimum number of page faults.

Same page may be brought into memory several times.

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9.17 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Performance of Demand PagingPerformance of Demand Paging

Page Fault Rate 0 p 1.0

if p = 0 no page faults

if p = 1, every reference is a fault

Effective Access Time (EAT)

EAT = (1 – p) x memory access

+ p (page fault overhead

+ [swap page out ]

+ swap page in

+ restart overhead)

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Demand Paging ExampleDemand Paging Example

Memory access time = 1 microsecond

50% of the time the page that is being replaced has been modified and therefore needs to be swapped out.

Swap Page Time = 10 msec = 10,000 microsec

EAT = (1 – p) x 1 + p (15000)

≈1 + 15000P (in microsec)

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Process CreationProcess Creation

Virtual memory allows other benefits during process creation:

- Copy-on-Write

- Memory-Mapped Files

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Copy-on-WriteCopy-on-Write

Copy-on-Write (COW) allows both parent and child processes to initially share the same pages in memory.

If either process modifies a shared page, only then is the page copied.

COW allows more efficient process creation as only modified pages are copied.

Free pages are allocated from a pool of zeroed-out pages.

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Page ReplacementPage Replacement

Prevent over-allocation of memory by modifying page-fault service routine to include page replacement.

Use modify (dirty) bit to reduce overhead of page transfers – only modified pages are written to disk.

Page replacement completes separation between logical memory and physical memory – large virtual memory can be provided on a smaller physical memory.

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Need For Page ReplacementNeed For Page Replacement

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Basic Page ReplacementBasic Page Replacement

1. Find the location of the desired page on disk.

2. Find a free frame:- If there is a free frame, use it.- If there is no free frame, use a page replacement

algorithm to select a victim frame.

3. Read the desired page into the (newly) free frame. Update the page and frame tables.

4. Restart the process.

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Page ReplacementPage Replacement

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Page Replacement AlgorithmsPage Replacement Algorithms

Want lowest page-fault rate.

Evaluate algorithm by running it on a particular string of memory references (reference string) and computing the number of page faults on that string.

In all our examples, the reference string is

1, 2, 3, 4, 1, 2, 5, 1, 2, 3, 4, 5.

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9.26 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Graph of Page Faults Versus The Number of FramesGraph of Page Faults Versus The Number of Frames

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First-In-First-Out (FIFO) AlgorithmFirst-In-First-Out (FIFO) Algorithm Reference string: 1, 2, 3, 4, 1, 2, 5, 1, 2, 3, 4, 5 3 frames (3 pages can be in memory at a time per process)

4 frames

FIFO Replacement – Belady’s Anomaly more frames less page faults

1

2

3

1

2

3

4

1

2

5

3

4

9 page faults

1

2

3

1

2

3

5

1

2

4

5 10 page faults

44 3

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FIFO Page ReplacementFIFO Page Replacement

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FIFO Illustrating Belady’s AnamolyFIFO Illustrating Belady’s Anamoly

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Optimal AlgorithmOptimal Algorithm

Replace page that will not be used for longest period of time. 4 frames example

1, 2, 3, 4, 1, 2, 5, 1, 2, 3, 4, 5

How do you know this? Used for measuring how well your algorithm performs.

1

2

3

4

6 page faults

4 5

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Optimal Page ReplacementOptimal Page Replacement

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Least Recently Used (LRU) AlgorithmLeast Recently Used (LRU) Algorithm

Reference string: 1, 2, 3, 4, 1, 2, 5, 1, 2, 3, 4, 5

Counter implementation

Every page entry has a counter; every time page is referenced through this entry, copy the clock into the counter.

When a page needs to be changed, look at the counters to determine which are to change.

1

2

3

5

4

4 3

5

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LRU Page ReplacementLRU Page Replacement

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LRU Algorithm (Cont.)LRU Algorithm (Cont.)

Stack implementation – keep a stack of page numbers in a double link form:

Page referenced:

move it to the top

requires 6 pointers to be changed

No search for replacement

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Use of A Stack to Record The Most Recent Page ReferencesUse of A Stack to Record The Most Recent Page References

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LRU Approximation AlgorithmsLRU Approximation Algorithms

Reference bit With each page associate a bit, initially = 0 When page is referenced bit set to 1. Replace the one which is 0 (if one exists). We do not know

the order, however. Second chance

Need reference bit. Clock replacement. If page to be replaced (in clock order) has reference bit = 1.

then: set reference bit 0. leave page in memory. replace next page (in clock order), subject to same rules.

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9.37 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Second-Chance (clock) Page-Replacement AlgorithmSecond-Chance (clock) Page-Replacement Algorithm

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Counting AlgorithmsCounting Algorithms

Keep a counter of the number of references that have been made to each page.

LFU Algorithm: replaces page with smallest count.

MFU Algorithm: based on the argument that the page with the smallest count was probably just brought in and has yet to be used.

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9.39 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Allocation of FramesAllocation of Frames

Each process needs minimum number of pages.

Example: IBM 370 – 6 pages to handle SS MOVE instruction:

instruction is 6 bytes, might span 2 pages.

2 pages to handle from.

2 pages to handle to.

Two major allocation schemes.

fixed allocation

priority allocation

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9.40 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Fixed AllocationFixed Allocation

Equal allocation – e.g., if 100 frames and 5 processes, give each 20 pages.

Proportional allocation – Allocate according to the size of process.

mSs

pa

m

sS

ps

iii

i

ii

for allocation

frames of number total

process of size

5964137127

56413710

127

10

64

2

1

2

a

a

s

s

m

i

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9.41 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Priority AllocationPriority Allocation

Use a proportional allocation scheme using priorities rather than size.

If process Pi generates a page fault,

select for replacement one of its frames.

select for replacement a frame from a process with lower priority number.

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Global vs. Local AllocationGlobal vs. Local Allocation

Global replacement – process selects a replacement frame from the set of all frames; one process can take a frame from another.

Local replacement – each process selects from only its own set of allocated frames.

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ThrashingThrashing

If a process does not have “enough” pages, the page-fault rate is very high. This leads to:

low CPU utilization.

operating system thinks that it needs to increase the degree of multiprogramming.

another process added to the system.

Thrashing a process is busy swapping pages in and out.

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Thrashing Thrashing

Why does paging work?Locality model

Process migrates from one locality to another.

Localities may overlap.

Why does thrashing occur? size of locality > total memory size

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Locality In A Memory-Reference PatternLocality In A Memory-Reference Pattern

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LocalityLocality

프로그램의 메모리 참조는 고도의 지역성을 가짐

임의시간 t 내에 프로그램의 일부분만을 집중적으로 참조

시간 지역성 (Temporal Locality) : 현재 참조된 메모리가 가까운 미래에도 참조될 가능성이 높음ex) loop, subroutine, stack

공간지역성 (Spatial Locality) : 하나의 메모리가 참조되면 주변의 메모리가 계속 참조될 가능성이 높음ex) Array Traversal, 명령의 순차실행

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Working-Set ModelWorking-Set Model

working-set window a fixed number of page references Example: 10,000 instruction

WSSi (working set of Process Pi) =total number of pages referenced in the most recent (varies in time)

if too small will not encompass entire locality.

if too large will encompass several localities.

if = will encompass entire program.

D = WSSi total demand frames

if D > m Thrashing

Policy if D > m, then suspend one of the processes.

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Working-set modelWorking-set model

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Keeping Track of the Working SetKeeping Track of the Working Set

Approximate with interval timer + a reference bit

Example: = 10,000

Timer interrupts after every 5000 time units.

Keep in memory 2 bits for each page.

Whenever a timer interrupts copy and sets the values of all reference bits to 0.

If one of the bits in memory = 1 page in working set.

Why is this not completely accurate?

Improvement = 10 bits and interrupt every 1000 time units.

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9.50 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

Page-Fault Frequency SchemePage-Fault Frequency Scheme

Establish “acceptable” page-fault rate.

If actual rate too low, process loses frame.

If actual rate too high, process gains frame.

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페이지 폴트 빈도 페이지 교체페이지 폴트 빈도 페이지 교체

폴트 빈도에 따라 프로세스의 상주페이지 집합을 조절 두 폴트의 간격이 threshold 값을 초과하면 그 사이에 참조되지

않은 페이지를 모두 방출 Threshold 값보다 작으면 상주 페이지 집합 크기를 증가 Threshold 값 설정이 중요 Working set 기법은 참조 시마다 페이지 집합을 수정 PFF 기법은 폴트 시에만 페이지 집합을 수정

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Memory-Mapped FilesMemory-Mapped Files

Memory-mapped file I/O allows file I/O to be treated as routine memory access by mapping a disk block to a page in memory

A file is initially read using demand paging. A page-sized portion of the file is read from the file system into a physical page. Subsequent reads/writes to/from the file are treated as ordinary memory accesses.

Simplifies file access by treating file I/O through memory rather than read() write() system calls

Also allows several processes to map the same file allowing the pages in memory to be shared

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Memory Mapped FilesMemory Mapped Files

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Memory-Mapped Files in JavaMemory-Mapped Files in Java

import java.io.*;

import java.nio.*;

import java.nio.channels.*;

public class MemoryMapReadOnly

{

// Assume the page size is 4 KB

public static final int PAGE SIZE = 4096;

public static void main(String args[]) throws IOException {

RandomAccessFile inFile = new RandomAccessFile(args[0],"r");

FileChannel in = inFile.getChannel();

MappedByteBuffer mappedBuffer =

in.map(FileChannel.MapMode.READ ONLY, 0, in.size());

long numPages = in.size() / (long)PAGE SIZE;

if (in.size() % PAGE SIZE > 0)

++numPages;

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Memory-Mapped Files in Java (cont)Memory-Mapped Files in Java (cont)

// we will "touch" the first byte of every page

int position = 0;

for (long i = 0; i < numPages; i++) {

byte item = mappedBuffer.get(position);

position += PAGE SIZE;

}

in.close();

inFile.close();

}

}

The API for the map() method is as follows:

map(mode, position, size)

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Other IssuesOther Issues

Prepaging vs. demand paging

Page size selection

fragmentation

table size

I/O overhead

locality

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9.57 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

요구 페이징 요구 페이징 ((Demand Paging)Demand Paging)

프로세스가 요구할때 적재시키는 기법

통상적으로 사용 프로그램의 수행경로를 예상 불가 필요한 페이지만 적재됨 적재할 페이지 결정에 오버헤드 없음

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요구 페이징에서의 시간 공간의 곱요구 페이징에서의 시간 공간의 곱

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Other Issues -- PrepagingOther Issues -- Prepaging

Prepaging

To reduce the large number of page faults that occurs at process startup

Prepage all or some of the pages a process will need, before they are referenced

But if prepaged pages are unused, I/O and memory was wasted

Assume s pages are prepaged and α of the pages is used

Is cost of s * α save pages faults > or < than the cost of prepaging s * (1- α) unnecessary pages?

α near zero prepaging loses

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PrepagingPrepaging

사용자의 turnaround 시간을 줄이는데 기여 VAX / VMS 의 경우

공간 지역성을 활용 : 연속된 페이지를 클러스터로 페이징 장점

프로세스 수행시간의 단축 많은 경우 정확한 결정이 가능 하드웨어 가격의 저렴화

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페이지 방출 페이지 방출 ((release)release)

작업 집합 저장장치 관리기법 : 작업집합에서 제거된 페이지는 더 이상 사용 안됨

자발적으로 방출 가능

사용자가 수행 불가능

희망사항 : 컴파일러나 OS 가 작업집합 전략 사용시 보다 훨씬 빨리 자동검출

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Other Issues – Page SizeOther Issues – Page Size

전부 동일 크기 ?

여러 크기의 페이지 ?

고려사항 페이지가 작을수록 table fragmentation 이 커짐 페이지가 크면 페이지내의 불사용 정보가 많음 .

작은 페이지 선호 디스크 I/O 비용이 큼 . 큰 페이지 선호 지역성의 대상이 좁음 . 작은 페이지 선호 내부 단편화 가능 . 작은 페이지 선호

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페이지 시스템에서의 내부의 단편화페이지 시스템에서의 내부의 단편화

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페이징 시 프로그램의 거동페이징 시 프로그램의 거동

프로세스의 참조되는 페이지의 시간에 따른 백분율

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9.65 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

페이징 시 프로그램의 거동페이징 시 프로그램의 거동

주기억 장치가 일정할 경우페이지 부재의 페이지 크기에 대한 의존도

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9.66 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

페이징 시 프로그램의 거동페이징 시 프로그램의 거동

페이지 부재간 시간의한 프로세스에 할당된 페이지틀의 수에 대한 의존도

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9.67 Silberschatz, Galvin and Gagne ©2005Operating System Concepts

페이징 시 프로그램의 거동페이징 시 프로그램의 거동

한 프로세스의 페이지들에 대해페이지 부재율이 기억장치량에 대한 의존성

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Other Issues – TLB Reach Other Issues – TLB Reach

TLB Reach - The amount of memory accessible from the TLB

TLB Reach = (TLB Size) X (Page Size)

Ideally, the working set of each process is stored in the TLB. Otherwise there is a high degree of page faults.

Increase the Page Size. This may lead to an increase in fragmentation as not all applications require a large page size

Provide Multiple Page Sizes. This allows applications that require larger page sizes the opportunity to use them without an increase in fragmentation.

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Other Issues – Program StructureOther Issues – Program Structure

Program structure Int[128,128] data; Each row is stored in one page Program 1

for (j = 0; j <128; j++) for (i = 0; i < 128; i++) data[i,j] = 0;

128 x 128 = 16,384 page faults

Program 2

for (i = 0; i < 128; i++) for (j = 0; j < 128; j++) data[i,j] = 0;

128 page faults

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Other Issues – I/O interlockOther Issues – I/O interlock

I/O Interlock – Pages must sometimes be locked into memory

I/O 요청후 page out 될 경우

Consider I/O. Pages that are used for copying a file from a device must be locked from being selected for eviction by a page replacement algorithm.

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Reason Why Frames Used For I/O Must Be In MemoryReason Why Frames Used For I/O Must Be In Memory

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기타 고려 사항기타 고려 사항

Inverted page table

페이지 폴트 발생시 그 페이지를 어떻게 찾는가 ? External page table 사용

실시간 프로세스 Real memory 만 사용

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Operating System ExamplesOperating System Examples

Windows XP

Solaris

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Windows XPWindows XP

Uses demand paging with clustering. Clustering brings in pages surrounding the faulting page.

Processes are assigned working set minimum and working set maximum

Working set minimum is the minimum number of pages the process is guaranteed to have in memory

A process may be assigned as many pages up to its working set maximum

When the amount of free memory in the system falls below a threshold, automatic working set trimming is performed to restore the amount of free memory

Working set trimming removes pages from processes that have pages in excess of their working set minimum

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Solaris Solaris

Maintains a list of free pages to assign faulting processes

Lotsfree – threshold parameter (amount of free memory) to begin paging

Desfree – threshold parameter to increasing paging

Minfree – threshold parameter to being swapping

Paging is performed by pageout process

Pageout scans pages using modified clock algorithm

Scanrate is the rate at which pages are scanned. This ranges from slowscan to fastscan

Pageout is called more frequently depending upon the amount of free memory available

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Solaris 2 Page ScannerSolaris 2 Page Scanner

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End of Chapter 9End of Chapter 9


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