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SEE 2053 Teknologi Elektrik
Chapter 2
Electromagnetism
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Electromagnetism
1. Understand magnetic fields and theirinteractions with moving charges.
2.
Use the right-hand rule to determine thedirection of the magnetic field around acurrent-carrying wire or coil.
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Electromagnetism
3. Calculate forces on moving charges andcurrent carrying wires due to magneticfields.
4. Calculate the voltage induced in a coil by achanging magnetic flux or in a conductor
cutting through a magnetic field.5. Use Lenzs law to determine the polarities
of induced voltages.
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Electromagnetism
6.
Apply magnetic-circuit concepts todetermine the magnetic fields in practicaldevices.
7. Determine the inductance and mutualinductance of coils given their physicalparameters.
8. Understand hysteresis, saturation, coreloss, and eddy currents in cores composedof magnetic materials such as iron.
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Electromagnetism
Magnetism is a force field that acts onsome materials (magnetic materials)but not on other materials (nonmagnetic materials).
Magnetic field around a bar magnet Two poles dictated by direction of the
field
Opposite poles attract (aligned
magnetic field) Same poles repel (opposing magnetic
field)
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By convention, flux lines leave the north-seeking end (N) of a magnet and enter itssouth-seeking end (S).
Electromagnetism
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Magnetic flux lines form closed paths that areclose together where the field is strong andfarther apart where the field is weak.
Electromagnetism
N N
SS
Strong field weak field
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Magnetic materials (ferromagmagnetic): iron,
steel, cobalt, nickel and some of their alloys.
Non magnetic materials: water, wood, air,quartz, silver, copper etc.
Electromagnetism
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The basic source of the magnetic field is electrical chargein motion. In magnetic materials, fields are created bythe spin of electrons in atoms. These fields aid oneanother, producing the net external field that we observe.
In most other materials (non magnetic materials), themagnetic fields of electrons tend to cancel one another.
In a current-carrying wire, the moving electrons in the wire
create magnetic fields around the wire.
Electromagnetism
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Electromagnetism
Iron bar
Magnetic molecules
In an unmagnetised state, the molecular magnets lie inrandom manner, hence there is no resultant externalmagnetism exhibited by the iron bar.
wood
Non-magnetic molecules
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Electromagnetism
Iron bar
Magnetic molecules
When the iron bar is placed in a magnetic field or underthe influence of a magnetising force, then these molecularmagnets start turning their axes and orientate themselvesmore or less along a straight lines.
S N
SN
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Electromagnetism
Iron barMagnetic molecules
When the iron bar is placed in a very strong magneticfield, all these molecular magnets orientate themselvesalong a straight lines (saturated).
S N
NS
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Electromagnetism
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Field Detector
Can use a compass to mapout magnetic field
Field forms closed fluxlines around the magnet(lines of magnetic fluxnever intersect)
Magnetic flux measured inWebers (Wb)
Symbol *
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Magnetic Flux
Magnetic flux lines are assumed to have the followingproperties:
Leave the north pole (N) and enter the south pole (S) ofa magnet.
Like magnetic poles repel each other. Unlike magnetic poles create a force of attraction.
Magnetic lines of force (flux) are assumed to becontinuous loops.
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Magnetic Field Conductor
Magnetic fields alsoexist in the spacearound wires thatcarry current.
Field can bedescribed using righthand screw rule
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Right Hand Rule
Thumb indicatesdirection ofcurrent flow
Finger curlindicates thedirection of field
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Right-HandRule
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Wire Coil
Notice that acarrying-currentcoil of wire willproduce aperpendicularfield
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Magnetic Field: Coil
A series of coils produces a fieldsimilar to a bar magnet but weaker!
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Magnetic Field: Coil
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Magnetic Field
*Flux can be increased byincreasing the currentI,
I
I
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Magnetic Field
*Flux can be increased byincreasing the number of turns N,
I
N
N
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Magnetic Field
*Flux can be increased byincreasing the cross-sectionarea of coil A,
I
A
N
A
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Magnetic Field
* Flux can be increased byincreasing the cross-sectionarea of coil A,
I
A
N
A
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Magnetic Field
* Flux is decreased byincreasing the length of coil l,
I
N
A
1
ll
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Magnetic Field
* Therefore we can write anequation for flux as,
I
N
A
NIA
ll
or
=
0NIA
l
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Where 0 is vacuum or non-magnetic materialpermeability
0= 4 x 10-7 H/m
Magnetic Field
=
0NIA
l
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Magnetic Field: Coil
Placing a ferrous materialinside the coil increases themagnetic field
Acts to concentrate the fieldalso notice field lines areparallel inside ferrous element
flux density has increased
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Magnetic Field
* By placing a magnetic materialinside the coil,
I
N
A
l =
NIA
l
Where is thepermeability of themagnetic material(core).
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Magnetic Field
* By placing a magnetic materialinside the coil,
I
N
A
l =
NIA
l
Where is thepermeability of themagnetic material(core).
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Flux Density
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Permeability
Permeability is a measure of the ease bywhich a magnetic flux can pass through amaterial (Wb/Am)
Permeability of free space o = 4 x 10-7(Wb/Am)
Relative permeability:
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Reluctance
Reluctance: resistance toflow of magnetic flux
Associated with magneticcircuit flux equivalent to
current Whats equivalent of voltage?
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Magnetomotive Force, F
Coil generates magneticfield in ferrous torroid
Driving force Fneededto overcome torroidreluctance
Magnetic equivalent ofohms law
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Circuit Analogy
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Magnetomotive Force
The MMF is generated by the coil Strength related to number of turns
and current, measured in Ampereturns (At)
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Field Intensity
The longer the magnetic path the greaterthe MMF required to drive the flux
Magnetomotive force per unit length is
known as the magnetizing force H
Magnetizing force and flux density relatedby:
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Electric circuit:
Emf = V = I x R
Magnetic circuit:
mmf = F = x
= (B x A) x
l
A= (B x A) x
l
= B x = H x l
= H x l
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Hysteresis
The relationship between Band Hiscomplicated by non-linearity andhysteresis
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= x
l
A=
0.16
1.818 x 10-3 x 2 x 10-3=
= 44004.4
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= x
= x
= 4 x 10-4 x 44004.4
= 17.6
I=F
N
=17.6
400= 44 mA
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Circuit Analogy
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Leakage Flux and Fringing
Leakage
flux
fringing
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Leakage Flux
It is found that it is impossible to confine all theflux to the iron path only. Some of the fluxleaks through air surrounding the iron ring.
Leakage coefficient =Total flux produced
Useful flux available
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Fringing
Spreading of lines of flux at the edges of theair-gap. Reduces the flux density in the air-gap.
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Forceson Charges Moving
in MagneticFields
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Forceson Charges Moving
in MagneticFields
Buf v! q
UsinquBf!
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Forceson Current-Carrying
Wires
Blfv!
idd
sinilBf!
Force on a current carrying
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Force on a current-carryingconductor
It is found that whenever a current-carryingconductor is placed in a magnetic field, itexperiences a force which acts in a directionperpendicular both to the direction of the current
and the field.
N
S
Force on a current carrying
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Force on a current-carryingconductor
It is found that whenever a current-carryingconductor is placed in a magnetic field, itexperiences a force which acts in a directionperpendicular both to the direction of the currentand the field.
N
S
Force on a current carrying
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Force on a current-carryingconductor
It is found that whenever a current-carryingconductor is placed in a magnetic field, itexperiences a force which acts in a directionperpendicular both to the direction of the currentand the field.
N
S
On the left hand side,the two fields in the
same direction
On the right handside, the two fields inthe opposition
Force on a current carrying
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Force on a current-carryingconductor
Hence, the combined effect is to strengthen themagnetic field on the left hand side and weaken iton the right hand side,
N
S
On the left hand side,the two fields in the
same direction
On the right handside, the two fields inthe opposition
Force on a current carrying
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Force on a current-carryingconductor
Hence, the combined effect is to strengthen themagnetic field on the left hand side and weaken iton the right hand side, thus giving the distributionshown below.
N
S
On the left hand side,the two fields in the
same direction
On the right handside, the two fields inthe opposition
Force on a current carrying
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Force on a current-carryingconductor
This distorted flux acts like stretched elastic cordsbend out of the straight , the line of the flux try toreturn to the shortest paths, thereby exerting aforce Furging the conductor out of the way.
N
S
On the left hand side,the two fields in the
same direction
On the right handside, the two fields inthe oppositionF
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Faradays Law
First Law.
Whenever the magnetic flux linked with acoil changes, an emf (voltage) is always
induced in it.Or
Whenever a conductor cuts magnetic flux,an emf (voltage) is induced in that
conductor.
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Faradays Law
Second Law.
The magnitude of the induced emf(voltage) is equal to the rate of change of
flux-linkages.
dt
de
P!
JP N!where
dt
Nd
dt
Nde
JJ!!
)(
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Direction of Induced emf
The direction (polarity) of induced emf(voltage) can be determined by applyingLenzs Law.
Lenzs law is equivalent toNewtons law.
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Lenzslawstates that the polarity ofthe induced voltage is such that thevoltage
would produce a current that opposesthe change in flux linkagesresponsible for inducing that emf.
LenzsLaw
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N S
I
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SELF INDUCTANCE,L
i
e
From Faradays Law:
dt
d
Ne
J
!
By substituting
=
NIA
l
v
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SELF INDUCTANCE,L
i
e
Rearrange theequation, yield
dt
l
NId
Ne
!
Q
dt
di
l
ANe
2Q
!
v
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SELF INDUCTANCE,L
i
e
dt
di
l
ANe
2Q!
dt
diLe !
or
where
l
ANL
2Q
!
v
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MUTUAL INDUCTANCE, M
i
e1
From Faradays Law:
v1 v2
e2
dtdNe J22 !
=
N1i1A
l
substituting
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MUTUAL INDUCTANCE, M
i
e1
v1 v2
e2
rearrange
dt
l
AiNd
Ne
!
11
22
Q
dt
di
l
ANNe
1
122
! Q
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MUTUAL INDUCTANCE, M
i
e1
v1 v2
e2
or
dt
di
l
ANNe
1
122
! Q
dt
diMe
1
2!
where
!
l
ANNM
12Q
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MUTUAL INDUCTANCE, M
!
l
ANNM
12Q
ForM2,2
2
1
2
2
22
!
l
ANNM Q
!l
ANM
2
1
2Q
vl
AN
2
2Q = L1 x L2
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MUTUAL INDUCTANCE, M
M2 = L1 x L2
M = (L1 x L2)
or
M = k(L1 x L2)
k = coupling coeeficient (0 --- 1)
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Dot Convention
Aiding fluxes are produced by currentsentering like marked terminals.
H t i L
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Hysteresis Loss
Hysteresis loopUniform distribution
From Faraday's law
WhereA is the cross section area
H t i L
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Hysteresis Loss
Field energyInput power :
Input energy from t1
to t2
where Vcore
is the volume of thecore
H t i L
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Hysteresis Loss
One cycle energy loss
where is the closed area ofB
-Hhysteresis loop Hysteresis power loss
where fis the operatingfrequency and Tis the period
H t i L
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Hysteresis Loss
Empirical equation
Summary : Hysteresis loss is proportional to fandABH
Edd C t L
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Eddy Current Loss
Eddy currentAlong the closed path, apply Faraday's law
whereA is the closed area
Changes in B = BA changes
induce emf along the closed pathproduce circulating circuit (eddy current) in the core
Eddy current losswhere R is the equivalent resistance along theclosed path
*
Edd C t L
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Eddy Current Loss
How to reduce Eddy current loss Use high resistivity core material
e.g. silicon steel, ferrite core (semiconductor)
Use laminated core
To decrease the area closedby closed path
Lamination thickness0.5~5mm for machines, transformers at line frequency
0.01~0.5mm for high frequency devices
Edd C t L
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Eddy Current Loss
Calculation of eddy current loss Finite element analysis
Use software: Ansys, Maxwell, Femlab, etc
Empirical equation
C L
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Core Loss
Core Loss
losscurrenteddyP
losshysteresisPwhere
PPP
e
h
ehc
!
!
!