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1 20070412 Chap5 1 Chapter5 Constraint Satisfaction Problems 20070412 Chap5 2 Constraint Satisfaction Problems (CSPs) Standard Search Problem - State is a “black box”, can be represented by an arbitrary data structure that can be accessed only by the problem-specific routines --- the successor functions, heuristic function, and goal test. Constraint Satisfaction Problem - State and goal test conform to a standard, structured, and very simple representation.
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Page 1: Chapter5ai2007s/slides/... · Chapter5 Constraint Satisfaction Problems 20070412 Chap5 2 Constraint Satisfaction Problems (CSPs) zStandard Search Problem-State is a “black box”,

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20070412 Chap5 1

Chapter5

Constraint Satisfaction Problems

20070412 Chap5 2

Constraint Satisfaction Problems (CSPs)

Standard Search Problem- State is a “black box”, can be represented by an

arbitrary data structure that can be accessed only by the problem-specific routines --- the successor functions, heuristic function, and goal test.

Constraint Satisfaction Problem- State and goal test conform to a standard, structured,

and very simple representation.

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20070412 Chap5 3

CSP is defined by a set of variables, X1, X2, …, Xn,

with values from domain D1, D2, …, Dn, and a set of constraints, C1, C2, …, Cm,

specifying allowable combinations of values for subsets of variables

State is defined by an assignment of values to some or all of the variables,

{Xi = vi , Xj = vj , …}

Constraint Satisfaction Problems(cont.-1)

20070412 Chap5 4

Consistent (or legal) assignmentan assignment that does not violate any constraints.

Complete assignmentone in which every variable is mentioned.

Solutionis a complete assignment that satisfies all the constraints.

Some CSPs also require a solution that maximizes an objective function

Constraint Satisfaction Problems(cont.-2)

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20070412 Chap5 5

Example: Map-Coloring

Variables: WA, NT, Q, NSW, V, SA, TDomains: Di = {red, green, blue}Constraints: adjacent regions must have different colorse.g. WA ≠ NT or(WA, NT) ∈{(red, green), (red, blue), (green, red), (green, blue), …}

20070412 Chap5 6

Example: Map-Coloring (cont.)

Solutions: assignments satisfying all constraintse.g. {WA = red, NT = green, Q = red, NSW = green, V= red,

SA = blue, T = green}

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20070412 Chap5 7

Constraint Graph

• It is helpful to visualize a CSP as a constraint graph.- Nodes are variable, and arcs show constraints.

• CSP benefits- Standard representation pattern- Generic goal and successor functions- Generic heuristics (no domain

specific expertise).

20070412 Chap5 8

Varieties of CSPs

Discrete variables- finite domains, size d ⇒ O(dm) complete assignments

e. g. 8 Queens, Q1, …Q8, with the domain {1, 2, 3, 4, 5, 6, 7, 8}- infinite domains, (integers, strings, etc.)need a constraint language (cannot enumerate all allowed

combinations of values)e. g. job scheduling, Job1 which takes 5 days, must precede Job3

StartJob1 + 5 ≤ StartJob3

Continuous variablese g. Hubble Space Telescope observations

- Linear constraints are solvable in polynomial timeby Linear programming methods.

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20070412 Chap5 9

Varieties of ConstraintsUnary constraints, involves a single variable

e.g. SA ≠ green

Binary constraints, involves pairs of variablese.g. SA ≠ WA

Higher-order constraints, involves 3 or more variablese.g. cryptarithmetic column constraints

Every high-order, finite-domain constraint can be reduced to a set of binary constraints if enough auxiliary variables are introduced. (Exercise 5.11).

We deal only with binary constraints in this chapter.

20070412 Chap5 10

Varieties of Constraints (cont.)

Absolute vs. Preference constraintsPreference constraints can often be encoded as

costs on individual variable assignments

e.g. red is better than greenProf. X might prefer teaching in the morning,

whereas prof. Y prefers teaching in the afternoon.

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20070412 Chap5 11

Example: Cryptarithmetic

Variables: F T U W R O X1 X2 X3Domains: { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9}Constraints:

Alldiff(F, T, U, W, R, O)O + O = R + 10 * X1X1 + W + W = U + 10 * X2X2 + T + T = O + 10 * X3X3 = F

X3 X2 X1

Where X1, X2 and X3 are auxiliary variables

20070412 Chap5 12

Standard Search Formulation (Incremental)

Initial state: the empty assignment, { }

Successor function: assign a value to an unassigned variable that does not conflict with current assignment

Goal test: the current assignment is complete.

Path cost: a constant cost for every step.

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20070412 Chap5 13

Backtracking Search for CSPs

In all CSPs, variable assignments are commutative.[WA = red then NT = green] same as [NT = green then WA = red ]

Only need to consider assignments to a single value at each node.

there are dn leaves (where d: domain size, n: number of variables)

Backtracking searcha form of depth-first search for CSP with single–variableassignments

20070412 Chap5 14

Backtracking Search for CSPs (cont.)

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20070412 Chap5 15

Backtracking Example

20070412 Chap5 16

Backtracking Example (cont.-1)

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20070412 Chap5 17

Backtracking Example (cont.-2)

20070412 Chap5 18

Backtracking Example (cont.-3)

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20070412 Chap5 19

Improving backtracking efficiency

Previous improvements introduce heuristicsGeneral-purpose methods can give huge gains in speed:- Which variable should be assigned next?- In what order should its values be tried?- Can we detect inevitable failure early?- Can we take advantage of problem structure?

20070412 Chap5 20

Some Key Questions of Backtracking Search

Variable and Value OrderingWhich variable should be assigned next,

and in what order should its values be tried?

Propagating information through constraintsWhat are the implications of the current variable assignments

for the other unassigned variables?

Intelligent backtrackingWhen a path fails --- that is, a state is reached in which a

variable has no legal values --- can the search avoid repeating this failure in subsequent paths?

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20070412 Chap5 21

Minimum Remaining Values

Minimum remaining value (MRV) heuristicor Most constrained variable heuristicor Fail-first heuristic

- choose the variable with the fewer legal valuesvar ← SELECT-UNASSIGNED-VARIABLE(VARIABLES[csp],assignment,csp)

After WA = red and NT = green, SA is assigned next rather than assigning Q

20070412 Chap5 22

Degree heuristic

Degree heuristic (Most Constraining Variable)- tie-breaker among most constrained variables- choose the variable with the most constraints

on remaining variables

SA (degree is 5) is assigned first

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20070412 Chap5 23

Least Constraining Value

After WA = red and NT = green, Q is assigned to redBlue is bad choice since it eliminated

the last legal value left for Q’s neighbor, SA

• Least constraining value heuristic- try to leave the maximum flexibility for subsequent variable

assignment- prefer the value that rules out the fewest choices

for the neighboring variables in the constraint graph

20070412 Chap5 24

Constraint Propagation

Propagating the implications of a constraint on one variable onto other variables

- Forward checking - Arc consistency (more stronger)

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20070412 Chap5 25

Forward Checking

Idea: Keep track of remaining legal values for unassigned variables

Terminate search when any variable has no legal values

Whenever a variable X is assigned, the forward checking process looks at each unassigned variable Ythat is connected to X by a constraint and deletes from Y’s domain any value that is inconsistent with the value chosen for X.

20070412 Chap5 26

Forward Checking (cont.-1)

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20070412 Chap5 27

Forward Checking (cont.-2)

After WA = red NT can no longer be redSA can no longer be red

20070412 Chap5 28

Forward Checking (cont.-3)

After WA = red and Q = green

With MRV, NT = blue and SA = blue

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20070412 Chap5 29

Forward Checking (cont.-4)

After WA = red, Q = green and V = blue, leaving SA with no legal values

FC has detected that partial assignment is inconsistent with the constraints and backtracking can occur.

20070412 Chap5 30

Forward Checking (cont.-5)

Forward checking propagates information from assigned to unassigned variable, but does not provide early detection for all failures.

After WA = red and Q = green

With MRV, NT = blue and SA = blue, but they cannot both be blue

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20070412 Chap5 31

Example: 4-Queens Problem

1

3

2

4

32 41

X1{1,2,3,4}

X3{1,2,3,4}

X4{1,2,3,4}

X2{1,2,3,4}

[4-Queens slides copied from B.J. Dorr CMSC 421 course on AI]

20070412 Chap5 32

Example: 4-Queens Problem (cont.-1)

1

3

2

4

32 41

X1{1,2,3,4}

X3{1,2,3,4}

X4{1,2,3,4}

X2{1,2,3,4}

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20070412 Chap5 33

Example: 4-Queens Problem (cont.-2)

1

3

2

4

32 41

X1{1,2,3,4}

X3{ ,2, ,4}

X4{ ,2,3, }

X2{ , ,3,4}

20070412 Chap5 34

Example: 4-Queens Problem (cont.-3)

1

3

2

4

32 41

X1{1,2,3,4}

X3{ ,2, ,4}

X4{ ,2,3, }

X2{ , ,3,4}

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20070412 Chap5 35

Example: 4-Queens Problem (cont.-4)

1

3

2

4

32 41

X1{1,2,3,4}

X3{ , , , }

X4{ ,2, , }

X2{ , ,3,4}

20070412 Chap5 36

Example: 4-Queens Problem (cont.-5)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1,2,3,4}

X4{1,2,3,4}

X2{1,2,3,4}

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20070412 Chap5 37

Example: 4-Queens Problem (cont.-6)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, ,3, }

X4{1, ,3,4}

X2{ , , ,4}

20070412 Chap5 38

Example: 4-Queens Problem (cont.-7)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, ,3, }

X4{1, ,3,4}

X2{ , , ,4}

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20070412 Chap5 39

Example: 4-Queens Problem (cont.-8)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, , , }

X4{1, ,3, }

X2{ , , ,4}

20070412 Chap5 40

Example: 4-Queens Problem (cont.-9)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, , , }

X4{1, ,3, }

X2{ , , ,4}

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20070412 Chap5 41

Example: 4-Queens Problem (cont.-10)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, , , }

X4{ , ,3, }

X2{ , , ,4}

20070412 Chap5 42

Example: 4-Queens Problem (cont.-11)

1

3

2

4

32 41

X1{ ,2,3,4}

X3{1, , , }

X4{ , ,3, }

X2{ , , ,4}

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20070412 Chap5 43

Arc Consistency

Simplest form of propagation makes each arc consistent.

X → Y is consistent ifffor every value x of X, there is some allowed y

Applying arc consistency has result in early detection of an inconsistency that is not detected by pure forward checking.

20070412 Chap5 44

Arc Consistency (cont.-1)

SA → NSW is consistent iffSA=blue and NSW=red

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20070412 Chap5 45

Arc Consistency (cont.-2)

NSW → SA is consistent iffNSW=red and SA=blueNSW=blue and SA=???

Arc can be made consistent by removing bluefrom NSW

20070412 Chap5 46

Arc Consistency (cont.-3)

V → NSW

Arc can be made consistent by removing blue from NSW

If X loses a value, neighbors of X need to be rechecked.

Remove red from V

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20070412 Chap5 47

Arc Consistency (cont.-4)

SA → NT, but SA becomes empty.Arc consistency detects failure earlier than forward checking

Can be run as a preprocessor or after each assignment

Repeated until no inconsistency remains

20070412 Chap5 48

Arc Consistency Algorithm

O(n2d3) can be reduces to O(n2d2) But cannot detect all failures in polynomial time.

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20070412 Chap5 49

k-consistency

A CSP is k-consistent, if for any k-1 variables and for any consistent assignment to those variables, a consistent value can always be assigned to any kthvariable.

k=1 i.e. node consistentk=2 i.e. arc consistentk=3 i.e. path consistent

20070412 Chap5 50

Strongly k-consistency

A graph is strongly k-consistent if- It is k-consistent and- It is also (k-1) consistent, (k-2) consistent, … all the

way down to 1-consistent.

This is ideal since a solution can be found in time O(nd) instead of O(n2d3)YET no free lunch: any algorithm for establishing n-consistency must take time exponential in n, in the worst case.

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20070412 Chap5 51

Further improvementsChecking special constraints- Checking Alldiff(…) constraint

If m variables involved, n possible distinct values and m > n then the constraint cannot be satisfied.e.g. {WA=red, NSW=red}

3 variables (SA, NT and Q)can be only 2 values {green, blue}

- Checking Atmost(…) constraintBounds propagation for larger value domains

e.g. atmost(10, PA1, PA2, PA3, PA4)

20070412 Chap5 52

Further improvements (cont.-1)

Intelligent backtracking- Standard form is chronological backtracking

i.e. try different value for preceding variable.

- More intelligent, backtrack to conflict set.Set of variables that caused the failure or set of

previously assigned variables that are connected to X by constraints.

Backjumping moves back to most recent element of the conflict set.

Forward checking can be used to determine conflict set.

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20070412 Chap5 53

Local Search for CSPs(Iterative algorithms)

Hill-climbing, simulated annealing typically use complete state representation. (i.e., all variables assigned.)

To apply to CSPs- allow states with unsatisfied constraints- operators: reassign variable values- variable selection: randomly select any conflicted variable- value selection: min-conflict heuristic

Select new value that results in a minimum number of conflicts with other variables.

20070412 Chap5 54

Min-Conflict Algorithm

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20070412 Chap5 55

An An 44--queens Problemqueens ProblemStates: 4 queens in 4 columns (44 = 256 states)Operators: move queen in columnGoal test: no attacksEvaluation: h(n) = number of attacks

20070412 Chap5 56

An An 44--queens queens ProblemProblem(cont(cont.).)

Assume one queen in each column.Which row does each one go in?

Variables Q1, Q2, Q3, Q4Domains Di = {1, 2, 3, 4}Constraints

Qi ≠ Qj (cannot be in same row)|Qi − Qj| ≠ |i − j| (or same diagonal)

Translate each constraint into set of allowable values for its variables

E.g., values for (Q1,Q2) are (1, 3) (1, 4) (2, 4) (3, 1) (4, 1) (4, 2)

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20070412 Chap5 57

An 8An 8--queens Problemqueens ProblemAlgorithm chosen:

the min-conflicts heuristic repair method

Algorithm Characteristics:repairs inconsistencies in the current configurationselects a new value for a variable that results in the minimum number of conflicts with other variables

20070412 Chap5 58

Detailed StepsDetailed Steps1. One by one, find out the number of conflicts between

the inconsistent variable and other variables.

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20070412 Chap5 59

2. Choose the one with the smallest number of conflicts to make a move

Detailed StepsDetailed Steps (cont.(cont.--1)1)

20070412 Chap5 60

3. Repeat previous steps until all the inconsistent variables have been assigned with a proper value.

Detailed Steps Detailed Steps (cont.(cont.--2)2)

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20070412 Chap5 61

Performance of min-conflictsGiven random initial state, can solve n-queens in almost constant time for arbitrary n with high probability (e.g., n = 10,000,000)The same appears to be true for any randomly-generated CSP except in a narrow range of the ratio

20070412 Chap5 62

Problem Structure

How can the problem structure help to find a solution quickly?Subproblem identification is important

- Coloring Tasmania and mainland are independent subproblems- Identifiable as connected components of constrained graph.

Improves performance

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20070412 Chap5 63

Problem Structure (cont.)

Completely independent subproblems are delicious, then, but rare.

Suppose each subproblem has c variables out of n totalWith decomposition

solution cost : n/c * dc, --- linear in nWithout decomposition

solution cost : dn, --- exponential in n

e.g. n=80, d=2, c=20280 = 4 billion years at 10 million nodes/sec4 * 220 = 0.4 sec at 10 million nodes/sec

20070412 Chap5 64

Tree-Structured CSPs

In most cases subproblems of a CSP are connected as a tree.Any tree-structured CSP can be solved in time linear in the number of variables.Theorem: if the constraint graph has no loops, the CSP can be solved in O(n d2) time.(Compare to general CSPs, where worse-case time is O(dn)

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20070412 Chap5 65

Algorithm for Tree-Structured CSPs

1. Choose a variable as root, order variables from root to leaves, such that every node’s parent precedes it in the ordering.

2. For j from n down to 2, apply RemoveInconsistent(Parent(Xj), Xj)

3. For j from 1 to n, assign Xj consistently with Parent(Xj)

20070412 Chap5 66

Nearly Tree-Structured CSPsTo reduce constraint graph to tree- by removing nodes- by collapsing nodes

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20070412 Chap5 67

Nearly Tree-Structured CSPs (cont.-1)

Idea: assign values to some variables so that the remaining variables form a tree.Assume that we assign {SA=x} cycle cutsetAnd remove any values from the other variables that are inconsistent.The selected value for SA could be the wrong one so we have to try

all of them

20070412 Chap5 68

Nearly Tree-Structured CSPs (cont.-2)

This approach is worthwhile if cycle cutset is small.Finding the smallest cycle cutset is NP-hard- Approximation algorithms exist

This approach is called cutset conditioning.

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20070412 Chap5 69

Nearly Tree-Structured CSPs (cont.-3)

• Necessary requirements:Every variable appears in at least one of the subproblems.If two variables are connected in the original problem, they must

appear together in at least one subproblem.If a variable appears in two subproblems, it must appear in

every subproblem along the path connecting those subproblems

• Tree decomposition of theconstraint graph in a set ofconnected subproblems.

• Each subproblem is solved independently.

• Resulting solutions are combined


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