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Evaluating Algebraic Expressions 5-2 Rates and Unit Rates Warm Up Warm Up California Standards California Standards Lesson Presentation Preview Preview
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Page 1: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Warm UpWarm Up

California StandardsCalifornia Standards

Lesson Presentation

PreviewPreview

Page 2: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Warm UpDivide. Round answers to the nearest tenth.

1. 2.

3. 4.

23.3 3.5

23.8 23.9

420 18

73 21

380 16

430 18

Page 3: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

California Standards

MG1.3 Use measures expressed as rates (e.g., speed, density) and measures expressed as products (e.g., person-days) to solve problems; check the units of the solutions; and use dimensional analysis to check the reasonableness of the answer.

Page 4: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Ratio: 903

Rate: 90 miles3 hours

Read as “90 miles per 3 hours.”

A rate is a comparison of two quantities measured in different units.

Page 5: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Unit rates are rates in which the second quantity is 1.

unit rate: 30 miles,1 hour

or 30 mi/h

The ratio 903

can be simplified by dividing:

903

= 301

Page 6: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesAdditional Example 1: Finding Unit Rates

Geoff can type 30 words in half a minute. How many words can he type in 1 minute?

Write a rate.

=

Geoff can type 60 words in one minute.

Multiply to find words per minute.

60 words 1 minute

30 words minute

12

30 words • 2 minute • 212

Page 7: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesCheck It Out! Example 1

Penelope can type 90 words in 2 minutes. How many words can she type in 1 minute?

90 words 2 minutes

Write a rate.

=

Penelope can type 45 words in one minute.

90 words ÷ 2 2 minutes ÷ 2

Divide to find words per minute.

45 words 1 minute

Page 8: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesAdditional Example 2A: Chemistry Application

Five cubic meters of copper has a mass of 44,800 kilograms. What is the density of copper?

Copper has a density of 8,960 kg/m3.

44,800 kg5 m3

Write the rate.

Divide to find kilograms per 1 m3.

44,800 kg ÷ 55 m3 ÷ 5

8,960 kg1 m3

Page 9: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesAdditional Example 2B: Chemistry Application

A piece of gold with a volume of 0.5 cubic meters weighs 9650 kilograms. What is the density of gold?

Gold has a density of 19,300 kg/m3.

9650 kg0.5 m3

Write the rate.

Multiply to find kilograms per 1 m3.

9650 kg • 20.5 m3 • 2

19,300 kg1 m3

Page 10: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesCheck It Out! Example 2A

Four cubic meters of precious metal has a mass of 18,128 kilograms. What is the density of the precious metal?

The precious metal has a density of 4,532 kg/m3.

18,128 kg4 m3

Write the rate. Divide to find kilograms per 1 m3.

18,128 kg ÷ 44 m3 ÷ 4

4,532 kg1 m3

Page 11: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesCheck It Out! Example 2B

A piece of gemstone with a volume of 0.25 cubic meters weighs 3540 kilograms. What is the density of the gemstone?

The gemstone has a density of 14,160 kg/m3.

3540 kg0.25 m3

Write the rate.

Multiply to find kilograms per 1 m3.

3540 kg • 40.25 m3 • 4

14,160 kg1 m3

Page 12: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Estimate each unit rate.

Additional Example 3A: Estimating Unit Rates

Choose a number close to 468 that is divisible by 91.

468 students to 91 computers

468 students to 91 computers is approximately 5 students per computer.

468 students91 computers

455 students91 computers

5 students1 computer

Divide to find students per computer.

Page 13: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Estimate each unit rate.

Additional Example 3B: Estimating Unit Rates

Choose a number close to 313 that is divisible by 8.

313 feet in 8 seconds

313 feet to 8 seconds is approximately 40 feet per second.

313 feet8 seconds

320 feet8 seconds

40 feet1 second

Divide to find feet per second.

Page 14: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Estimate each unit rate.

Check It Out! Example 3A

Choose a number close to 583 that is divisible by 85.

583 soccer players to 85 soccer balls.

583 soccer players to 85 soccer balls is approximately 7 players per soccer ball.

583 players85 soccer balls

595 players85 soccer balls

7 players1 soccer ball

Divide to find players per soccer ball.

Page 15: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Estimate each unit rate.

Check It Out! Example 3B

Choose a number close to 271 that is divisible by 3.

271 yards in 3 hours

271 yards to 3 hours is approximately 90 yards per hour.

271 yards3 hours

270 yards3 hours

90 yards1 hour

Divide to find yards per hour.

Page 16: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Unit price is a unit rate used to compare price per item.

Page 17: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Pens can be purchased in a 5-pack for $1.95 or a 15-pack for $6.20. Which pack has the lower unit price?

Additional Example 4A: Finding Unit Prices to Compare Costs

Divide the price by the number of pens.

price for packagenumber of pens

=$1.955

= $0.39

price for packagenumber of pens

= $6.2015

$0.41

The 5-pack for $1.95 has the lower unit price.

Page 18: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Jamie can buy a 15 oz jar of peanut butter for $2.19 or a 20 oz jar for $2.78. Which jar has the lower unit price?

Additional Example 4B: Finding Unit Prices to Compare Costs

$2.1915

= $0.15

= $2.7820

$0.14

The 20 oz jar for $2.78 has the lower unit price.

price for jarnumber of ounces

price for jarnumber of ounces

Divide the price by the number of ounces.

Page 19: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit Rates

Golf balls can be purchased in a 3-pack for $4.95 or a 12-pack for $18.95. Which pack has the lower unit price?

Check It Out! Example 4A

Divide the price by the number of balls.

price for packagenumber of balls

$4.953

= $1.65

price for packagenumber of balls

= $18.9512

$1.58

The 12-pack for $18.95 has the lower unit price.

Page 20: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesCheck It Out! Example 4B

John can buy a 24 oz bottle of ketchup for $2.19 or a 36 oz bottle for $3.79. Which bottle has the lower unit price?

$2.1924

= $0.09

= $3.7936

$0.11

The 24 oz jar for $2.19 has the lower unit price.

price for bottlenumber of ounces

price for bottlenumber of ounces

Divide the price by the number of ounces.

Page 21: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesLesson Quiz: Part I

1. Meka can make 6 bracelets per half hour. How many bracelets can she make per hour?

2. A penny has a mass of 2.5 g and a volume of approximately 0.360 cm3. What is the approximate density of a penny?

Estimate each unit rate.

3. $2.22 for 6 stamps

4. 8 heartbeats in 6 seconds

$0.37 per stamp

≈ 6.94 g/cm3

1.3 beats/s

12

Page 22: Chapter5.2

Evaluating Algebraic Expressions

5-2 Rates and Unit RatesLesson Quiz: Part II

Find each unit price. Then tell which has the

lower unit price.

5. A half dozen carnations for $4.75 or a dozen

for $9.24

6. 4 pens for $5.16 or a ten-pack for $12.90.

a dozen

They cost the same.