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Chem 120 Chap 6

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    !"#$%&'(%)#*%((&%

    !"+,-#.%/%0%1+2#2%

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    Prentice-Hall 2007General Chemistry: Chapter 6

    The Concept of Pressure

    !The pressure exertedby a solid.

    Both cylinders have thesame mass

    They have differentareas of contact

    P (Pa) =Area (m2)Force (N)

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Liquid Pressure

    !The pressure exerted bya liquid depends on:

    The height of thecolumn of liquid.

    The density of thecolumn of liquid.

    P = g !h !d

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Barometric Pressure

    Standard Atmospheric Pressure

    1.00 atm, 760 mm Hg, 760 torr, 101.325 kPa, 1.01325 bar

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Manometers

    hh

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-2 Simple Gas Laws

    !Boyle 1662 P" 1V

    PV = constant

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Charless Law

    Charles 1787

    Gay-Lussac 1802

    V " T V = b T

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Standard Temperature and Pressure

    !Gas properties depend on conditions.!Define standard conditions of temperature

    and pressure (STP).

    P = 1 atm = 760 mm Hg

    T = 0C = 273.15 K

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Avogadros Law

    !Gay-Lussac 1808 Small volumes of gases react in the ratio of

    small whole numbers.

    !Avogadro 1811 Equal volumes of gases have equal numbers of

    molecules and

    Gas molecules may break up when they react.

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    Avogadros Law

    V" n or V = c n

    At STP

    1 mol gas = 22.4 L gas

    At an a fixed temperature and pressure:

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-3 Combining the Gas Laws: The Ideal

    Gas Equation and the General GasEquation

    !Boyles law V" 1/P!Charless law V" T!Avogadros law V" n

    PV = nRT

    V "nTP

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    Prentice-Hall 2007General Chemistry: Chapter 6

    The Gas Constant

    R=

    PVnT

    = 0.082057 L atm mol-1 K-1

    = 8.3145 m3

    Pa mol-1

    K-1

    PV = nRT

    = 8.3145 J mol-1 K-1= 8.3145 m

    3

    Pa mol-1

    K-1

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Using the Gas Law

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    Prentice-Hall 2007General Chemistry: Chapter 6

    The General Gas Equation

    R= =P2V2n2T2

    P1V1n1T1

    =

    P2

    T2

    P1

    T1

    If we hold the amount and volume constant:

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-4 Applications of the Ideal Gas Equation

    PV = nRT and n =mM

    PV =mM

    RT

    M =m

    PV

    RT

    Molar Mass Determination

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Gas Densities

    PV = nRT and d =mV

    PV =m

    M RT

    MP

    RTV

    m= d =

    , n =mM

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-5 Gases in Chemical Reactions

    !Stoichiometric factors relate gas quantities toquantities of other reactants or products.

    !Ideal gas equation relates the amount of a gasto volume, temperature and pressure.

    !Law of combining volumes can be developedusing the gas law.

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-6 Mixtures of Gases

    !Partial pressure Each component of a gas mixture exerts a

    pressure that it would exert if it were in thecontainer alone.

    !Gas laws apply to mixtures of gases.!Simplest approach is to use ntotal, but....

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Daltons Law of Partial Pressure

    The total pressure of a mixture of gases is the sum of

    the partial pressures of the components of the mixture.

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    Partial Pressure

    Ptot = Pa + Pb +

    Va = naRT/Ptot and Vtot = Va + Vb+

    Va

    Vtot

    naRT/PtotntotRT/Ptot

    = =na

    ntot

    Pa

    Ptot

    naRT/VtotntotRT/Vtot

    = =na

    ntot

    na

    ntot= #aRecall

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-7 Kinetic Molecular Theory

    ! Particles are point masses in constant,random, straight line motion.

    ! Particles are separated by greatdistances.

    ! Collisions are rapid and elastic.!No force between particles.! Total energy remains constant.

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Pressure Assessing Collision Forces

    ! Translational kinetic energy,! Frequency of collisions,! Impulse or momentum transfer,! Pressure proportional to

    impulse times frequency

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Pressure and Molecular Speed

    ! Three dimensional systems lead to:

    um is the modal speed

    uavis the simple average

    urms

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Pressure

    Assume one mole:

    PV=RT so:

    NAm = M:

    Rearrange:

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    Distribution of Molecular Speeds

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    Determining Molecular Speed

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    Temperature

    Modify:

    PV=RT so:

    Solve for ek:

    Average kinetic energy is directly proportional to temperature!

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-8 Gas Properties Relating to the

    Kinetic-Molecular Theory

    !DiffusionNet rate is proportional to

    molecular speed.

    !Effusion A related phenomenon.

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Grahams Law

    ! Only for gases at low pressure (natural escape, not a jet).! Tiny orifice (no collisions)! Does not apply to diffusion.

    =

    (urms)A

    (urms)B=

    3RT/MA

    3RT/MB=

    MB

    MA

    ! Ratio used can be: Rate of effusion (as above) Molecular speeds Effusion times

    Distances traveled by molecules Amounts of gas effused.

    Rate of effusion of A

    Rate of effusion of B

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    Prentice-Hall 2007General Chemistry: Chapter 6

    6-9 Nonideal (Real) Gases

    !Compressibility factor PV/nRT = 1!Deviations occur for real gases.

    PV/nRT > 1 - molecular volume is significant. PV/nRT < 1 intermolecular forces of attraction.

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    Prentice-Hall 2007General Chemistry: Chapter 6

    Real Gases

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    Prentice-Hall 2007General Chemistry: Chapter 6

    van der Waals Equation

    P +n2a

    V2

    V nb = nRT


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