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Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be...

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Chem. 230 – 9/23 Lecture
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Page 1: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chem. 230 – 9/23 Lecture

Page 2: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Announcements

• Exam 1 today – first 40 min.• Second Homework Set will be online soon• Today’s Topics – Chromatographic Theory

– Basic definitions (flow – time relationship, distribution constant, retention factor, velocities, plate number, plate height, asymmetry factor, resolution, separation factor)

– How to read chromatograms– Meaning of parameters (more when we cover

optimization)

Page 3: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryQuestions on Definitions

1. When is chromatographic separation needed vs. only simple separations?

2. An analyte interacts with a stationary phase via adsorption. The stationary phase is most likely:

a) Liquid b) Liquid-like c) Solid3. What are the required two phases in

chromatography called?4. What are advantages and disadvantages

with the three common stationary phases (liquid, liquid-like, and solid)?

Page 4: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definition Section – Flow – Volume Relation

• Relationship between volume (used with gravity columns) and time (most common with more modern instruments):V = t·F V = volume passing through column part in

time t at flow rate FAlso, VR = tR·F where R refers to retention

time/volume (time it takes component to go through column or volume of solvent needed to elute compound)

Page 5: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definition Section – More on Volume

• Hold-up volume = VM = volume occupied by mobile phase in column

• Stationary phase volume = VS

• Calculation of VM:

VM = Vcolumn – Vpacking material – VS

VM = tM·F, where tM = time needed for unretained compounds to elute from column

Page 6: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definition Section – Partition and Retention

• Distribution Constant (= Partition Coefficient from LLE) = KC = [X]S/[X]M

• KC is constant if T and/or solvent remain constant

• Retention Factor (= Capacity Factor = Partition Ratio) = k = (moles X)S/(moles X)M = KC/(VM/VS)

• k = KC/β where β = VM/VS

• Retention Factor is more commonly used because of ease in measuring, and since β = constant, k = constant·KC (for a given column)

• Note: kColumn1 ≠ kColumn2 (because β changes)

Page 7: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definition Section – Partition and Retention

• Since the fraction of time a solute molecule spends in a given phase is proportional to the fraction of moles in that phase,k = (time in stationary phase)/(time in mobile phase)

• Experimentally, k = (tR – tM)/tM

• The same equations can be made with volumes instead: k = (VR – VM)/VM

• Note: t’R = tR – tM = adjusted retention time

Page 8: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Reading Chromatograms

• Determination of parameters from reading chromatogram (HPLC example)

• tM = 2.37 min. (normally determined by finding 1st peak for unretained compounds – contaminant below)

• VM = F·tM = (1.0 mL/min)(2.37 min) = 2.37 mL (Note: 4.6 x 250 mm column, so total vol. = (π/4)(0.46 cm)2(25 cm)(1 mL/cm3) = 4.15 mL

• Vol. of packing material + stationary phase = 4.15 mL – 2.37 mL = 1.78 mL (note only VS is useful)

• 1st peak, tR = 5.93 min.; k = (5.93 -2.37)/2.37 = 1.50

Page 9: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryWhat do all these Parameters Mean?

• KC is just like KP in liquid – liquid extractions for HPLC or KH (Henry’s law constant) for GC

• Large KC value means analyte prefers stationary phase• In GC:

– KC value will depend on volatility and polarity (analyte vs stationary phase)

– KC value adjusted by changing T (most common)– The mobile phase or carrier gas (e.g. He vs. N2) has no effect

on KC

• In HPLC– KC value will depend on analyte vs. mobile phase and

stationary phase polarity– KC value adjusted by changing mobile phase polarity

Page 10: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryWhat do all these Parameters Mean? II

• Retention Factor is a more useful measure of partitioning because value is related to elution time

• Compounds with larger KC, will have larger k, and will elute later

• Practical k values– ~0.5 to ~10– Small k values → usually poor selectivity– Large k values → must wait long time – Higher k values are more practical for

complicated samples while low k values are desired for simpler samples to save time

Page 11: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definition Section – Velocity

• Mobile phase velocity (u) and analyte average speed (v) can be useful quantities

• u = L/tM (L = column length)

• v = L/tR

• R = retardation factor = v/u (similar to RL used in TLC based on distance migrated)

Page 12: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Reading Chromatogram – cont.

• u = L/tM = 250 mm/2.37 min = 105 mm/min• v(1st peak) = L/tR = 250 mm/5.93 min = 42.2

mm/min• R = 42.2/105 = 0.40

Page 13: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryShape of Chromatographic Peak

• Gaussian Distribution

• Normal Distribution Area = 1

• Widths– σ (std deviation)– wb (baseline width) = 4σ– wh (peak width at half height)

= 2.35σ– w’ = Area/ymax = 2.51σ (often

given by integrators)

Gaussian Shape (Supposedly)

2

21

exp2

1xx

y

Inflection lines

wb

Height

Half Height

wh

Page 14: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryMeasures of Chromatographic Efficiency

• Plate Number = N (originally number of theoretical plates – similar to number of liquid-liquid extractions or distillations)

• N = (tR/σ)2 (= 16(tR/wb)2 )• N is an absolute measure of column

efficiency but depends on length• Plate Height = H = length of column

needed to get N of 1• H = L/N, but H is constant under specific

conditions, while N is proportional to L

Page 15: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryMeasures of Chromatographic Efficiency

• Measuring N and H is valid under isocratic conditions• Later eluting peaks normally used to avoid effects from

extra-column broadening• Example: N = 16(14.6/0.9)2 = 4200 (vs. ~3000 for pk 3)• H = L/N = 250 mm/4200 = 0.06 mm

Wb ~ 0.9 min

Page 16: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryNon-ideal Peak Shapes

40

45

50

55

60

65

70

75

80

85

13.00 13.20 13.40 13.60 13.80 14.00

time

Res

po

nse

Tailing Peak (actually slow detector)

Tailing Factor = TF = b/a > 1 (tailing peak)

a b

Fronting Peak (TF < 1)

Page 17: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryDefinitions - More on Peak Shapes

• A Gaussian peak shape is assumed for many of the calculations given previously (e.g. peak width and N)

• For non-Gaussian peaks, the equations relating specific widths to σ are no longer valid.

• New equations are required for equations that have width in them

Page 18: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Resolution

• Resolution is a measure of the ability to separate two peaks from each other

• Resolution = RS

where d = (tR)B – (tR)A

and ave w = [(wb)A + (wb)B]/2

bS w

dR

Page 19: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Resolution

• Resolution indicates the amount of overlap between peaks

• RS < 1, means significant overlap

• RS = 1.5, means about minimum for “baseline resolution” (at least for two peaks of equal height)

• RS > 2 often needed if it is important to integrate a small peak near a large peak

Page 20: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Resolution

• RS calculation examples:– 1st two peaks:

• tR(1st pk) = 4.956 min., w (integrator) = w’ = 0.238 min, so wb = 0.238·(4/2.5) = 0.38 min.

• tR(2nd pk) = 5.757 min., wb = 0.44 minRS = 0.801/0.410 = 1.95 (neglecting non-Gaussian peak shape)

– Last two peaks, RS = 3.0

Page 21: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Resolution

• Higher resolution values are needed to quantify small peaks next to large peaks

• RS = 1.61 (assuming wb 1st peak equals 2nd peak)

• RS is not sufficient for accurate integration of 1st peak (but o.k. for integration of 2nd peak)

Expansion of above box

Large integration error on 1st pk

Page 22: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Peak Capacity

• Peak Capacity is the theoretical maximum number of peaks that can be separated with RS = 1.0 within a given time period.

• We won’t cover calculation, but for example, about 2X more peaks could be possible between 5 and 13 min.

• Peak capacity 2.3 to 20 min. would be ~27 peaks.• Greater peak capacity is typical with temperature/gradient

programs (like in example).

Page 23: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Separation Factor

• Separation Factor = = ratio of distribution constants = KB/KA = kB/kA = (t’R)B/(t’R)A

Where (tR)B > (tR)A so that > 1• Smaller (closer to 1) means more difficult separation• In example chromatogram, (1st 2 peaks)

= (5.77 – 2.37)/(4.96 – 2.37) = 1.31

Page 24: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic Theory Definitions - Overview

• The “good” part of chromatography is separation, which results from differences in KC values giving rise to > 1

• The “bad” part of chromatography is band broadening or dispersion, leading to decreased efficiency (and also reducing sensitivity)

• The “ugly” part of chromatography is non-Gaussian peak shapes (leads to additional band broadening plus need for new equations)

Page 25: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryQuestions on Definitions

1. List two ways in which a stationary phase is “attached” to a column?

2. What column component is present in packed columns but not open-tubular columns?

3. In HPLC, typical packing material consist of μm diameter spherical particles. Even though tightly packing the spheres should lead to > 50% of the column being sphere volume, the ratio of VM/Column Volume > 0.5. Explain this.

Page 26: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryQuestions on Definitions

4. List 3 main components of chromatographs.5. A chemist perform trial runs on a 4.6 mm

diameter column with a flow rate of 1.4 mL/min. She then wants to scale up to a 15 mm diameter column (to isolate large quantities of compounds) of same length. What should be the flow rate to keep u (mobile phase velocity) constant?

6. A chemist purchases a new open tubular GC column that is identical to the old GC column except for having a greater film thickness of stationary phase. Which parameters will be affected: KC, k, tM, tR(component X), β, .

Page 27: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryQuestions on Definitions

7. What “easy” change can be made to increase KC in GC? In HPLC?

8. A GC is operated close to the maximum column temperature and for a desired analyte, k = 10. Is this good?

9. If a new column for problem 8 could be purchased, what would be changed?

10. In reversed-phase HPLC, the mobile phase is 90% H2O, 10% ACN and k = 10, is this good?

11.Column A is 100 mm long with H = 0.024 mm. Column B is 250 mm long with H = 0.090 mm. Which column will give more efficient separations (under conditions for determining H)?

Page 28: Chem. 230 – 9/23 Lecture. Announcements Exam 1 today – first 40 min. Second Homework Set will be online soon Today’s Topics – Chromatographic Theory –Basic.

Chromatographic TheoryQuestions on Definitions

• Given the two chromatograms to the right:– Which column shows a

larger N value?– Which shows better

resolution (1st 2 peaks top chromatogram)?

– Which shows better selectivity (larger ; 1st 2 peaks on top)?

– Should be able to calculate k, N, RS, and α

min0 2.5 5 7.5 10 12.5 15 17.5

mV

0

200

400

600

800

1000

ADC1 A, ADC1 CHANNEL A (LILLIAN\102507000009.D)

0.9

26

7.1

73

8.4

44

12.

821

14.

242

15.

436

VWD1 A, Wavelength=210 nm (LILLIAN\102507000009.D)

0.8

41 1

.201

1.4

70 1

.613

2.6

96

8.3

09

14.

103

ADC1 A, ADC1 CHANNEL A (LILLIAN\102507000006.D)

0.9

24 1

.042

12.

754

VWD1 A, Wavelength=210 nm (LILLIAN\102507000006.D)

0.8

45 1

.204

1.4

73 1

.616

2.6

95

Unretained pk

min0 1 2 3 4 5 6 7 8

mV

50

100

150

200

250

ADC1 A, ADC1 CHANNEL A (MONIQUE\062608000004.D)

2.2

08

2.5

99

5.7

56

6.6

59

7.8

72

ADC1 B, ADC1 CHANNEL B (MONIQUE\062608000004.D) VWD1 A, Wavelength=205 nm (MONIQUE\062608000004.D)

2.8

42


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