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Chemical Formulas and Chemical Compounds

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Chemical Formulas and Chemical Compounds. Chapter 7. Chemical Formulas. Combinations of symbols are used to represent compounds of two or more elements. Also indicate the ratio of the number of atoms of each type of element in the compound. - PowerPoint PPT Presentation
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Chemical Formulas and Chemical Compounds Chapter 7
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Page 1: Chemical Formulas and Chemical Compounds

Chemical Formulas and Chemical Compounds

Chapter 7

Page 2: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 2

Chemical Formulas

• Combinations of symbols are used to represent compounds of two or more elements.

• Also indicate the ratio of the number of atoms of each type of element in the compound.• H2O – means that there are 2 hydrogen atoms

for every oxygen atom.• No subscript on O – means there is 1

Page 3: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 3

Chemical Formulas

• Show either one molecule or one formula unit

Page 4: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 4

Organic Compounds

• Written differently than other formulas• The shorthand shows how the atoms are

joined, not just the number present.• Example –

• CH3COOH, not C2H4O2

Page 5: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 5

Ions

• Ion – charged atom or group of atoms• Monatomic Ions – single atom• Polyatomic Ions – more than one atom

Page 6: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 6

Monatomic Ions

• Can be anions or cations• Transition elements can form more than one

kind of ion• See table 7-1 on page 205• You must memorize this table.

Page 7: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 7

Naming monatomic ions

• Cations• Element’s name• Roman numerals are used when there are

multiple ions• Anions

• Drop the element name ending• Add -ide

Page 8: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 8

Binary compounds

• Contain two different elements• When we write chemical formula for a

compound, the charges must add up to zero.• Write the positive ion first.

Page 9: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 9

Example

• Write a formula for a compound of tin (II) and Iodine.

• Tin (II) is 2+• Iodine is 1-• We need two iodines to cancel out the

charge on the tin (II).• SnI2

Page 10: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 10

Nomenclature

• Naming system• Works for most compounds

Page 11: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 11

Naming binary compounds

• Write the name of the positive cation first.• Add the name of the negative anion

• AlN – Aluminum nitride• KCl – potassium chloride

Page 12: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 12

The stock system

• Elements with more than one possible charge

• Cu2S – copper (I) sulfide• CuS – copper (II) sulfide• Note – in an older naming system the above

could be written as cuprous sulfide and cupric sulfide

Page 13: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 13

Oxyanions

• Polyatomic ions that contain oxygen• When there are two or more oxyanions

formed from the same two elements, the most common has the ending –ate• The ion with one less oxygen than –ate ends in

–ite• The ion with one less oxygen than –ite adds the

prefix hypo-• The ion with one more oxygen than –ate adds

the prefix per-

Page 14: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 14

Compounds with polyatomic ions

• See table 7-2 on page 210• They are written like binary compounds.

• Except the ending isn’t changed to end in –ide• CuSO4 – copper (II) sulfate• Sn(SO4)2 – tin (IV) sulfate

Page 15: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 15

Discuss

• Practice problems 7-1, 7-2, and 7-3 on pages 207, 209, and 211

• Practice

Page 16: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 16

Polyatomic ions you must memorize

• Ammonium• Acetate• Chlorate• Chlorite• Hydroxide• Hypochlorite• Nitrate• Nitrite

• Perchlorate• Permanganate• Carbonate• Peroxide• Sulfate• Sulfite• Phosphate

Page 17: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 17

Naming binary molecular compounds

• Two systems – one will be covered in section 7-2

• Older system• Prefixes used – see table 7-3 on page 212• CO – carbon monoxide• CO2 – carbon dioxide• SO2 – sulfur dioxide• SO3 sulfur trioxide

Page 18: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 18

Rules

• List the less-electronegative element first.• Only has a prefix if there is more than one.

• The second element• Has a prefix• Root of the element name• -ide ending

• If the word begins with a vowel, drop the o or a at the end of the prefix (monoxide, not monooxide)

• Order: C, P, N, H, S, I, Br, Cl, O, F

Page 19: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 19

Examples

• PF5

• Phosphorus pentafluoride• N2O5

• Dinitrogen pentoxide• OF2

• Oxygen difluoride

Page 20: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 20

Acids

• Have a different naming rules.• Some common ones are listed in table 7-5

on page 214• You should know

• Hydrochloric acid (HCl)• Sulfuric acid (H2SO4)• Acetic acid (CH3COOH) (vinegar)

Page 21: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 21

Salts

• An ionic compound composed of a cation and the anion from an acid

• Sometimes the salt keeps one or more hydrogen atoms from the acid• The prefix bi- or the word hydrogen is added to

the anion name• HCO3

-

• Hydrogen carbonate ion or bicarbonate ion

Page 22: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 22

Discuss

• Sample problem 7-4 on page 213• Practice

Page 23: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 23

Discuss

• www.dhmo.org/facts.html

Page 24: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 24

Oxidation numbers

• Also called oxidation states• Assigned to atoms in molecules• Indicate the general distribution of electrons

among the bonded atoms• Sort of like ionic charge

Page 25: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 25

Pure elements

• Have oxidation numbers of zero• Single atoms – Na• Molecules of a pure substance

• O2

• P4

• S8

Page 26: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 26

Like charges on ions

• Shared electrons are assumed to belong to the more-electronegative atom

• The more electronegative element gets a number equal to the negative charge it would have as an anion.

• The less electronegative element gets a number equal to the positive charge it would have as a cation.

Page 27: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 27

Fluorine

• Oxidation number of -1• The most electronegative element

Page 28: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 28

Oxygen

• Usually -2• In peroxides, -1

• H2O2

• In compounds with halogens, +2• OF2

Page 29: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 29

Hydrogen

• +1 with more electronegative elements• -1 with metals

Page 30: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 30

Sum of oxidation numbers

• In a neutral compound must be zero• In a polyatomic ion must equal the charge

on the ion

Page 31: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 31

Ion

• Can be assigned an oxidation number equal to the charge on the ion

Page 32: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 32

Example

• Assign oxidation numbers to each atom in the following compound:

• KClO4• O is -2, which gives -8, since there are 4.• The charge on perchlorate is 1-, so Cl must be

+7• K must be +1 to cancel out the 1-

• +1, +7, -2

Page 33: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 33

Example

• Assign oxidation numbers to each atom in the following compound:

• SO32-

• O is -2, which gives -6, since there are 3.• The charge on sulfite is 2-, so S must be +4

• +4, -2

Page 34: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 34

You try

• Assign oxidation numbers to each atom in the following compound:

• CO2

• O is -2, which gives -4, since there are 2.• The charge is 0, so C must be +4

• +4, -2

Page 35: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 35

You try

• Assign oxidation numbers to each atom in the following compound:

• NO3-

• O is -2, which gives -6, since there are 3.• The charge is 1-, so N must be +5

• +5, -2

Page 36: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 36

More oxidation numbers

• See Appendix Table A-15• There is also a pattern on the periodic table• Group 1 is usually +1• Group 2 is usually +2• Group 13 is usually +3• Group 14 is usually +2 or +4• Group 15 is usually -3• Group 16 is usually -2• Group 17 is usually -1

Page 37: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 37

The stock system

• Can be used instead of prefixes for molecular compounds

• Use the oxidation number• SO2

• Sulfur dioxide• Sulfur (IV) oxide

• SO3• Sulfur trioxide• Sulfur (VI) oxide

Page 38: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 38

Discuss

• Name each of the following binary molecular compounds according to the stock system

• CI4

• SO3

• As2S3

• NCl3

Page 39: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 39

Formula mass

• The sum of the average atomic masses of all the atoms in a formula

• For ionic compounds or molecules• Can also be called molecular mass for

molecules

Page 40: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 40

Example

• Find the formula mass of Na2SO3

• 126.05 amu

Page 41: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 41

Example

• Find the formula mass of HClO3

• 84.46 amu

Page 42: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 42

You try

• Find the formula mass of MnO4-

• 118.94 amu

Page 43: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 43

You try

• Find the formula mass of C2H6O• 46.08 amu

Page 44: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 44

Molar Mass

• Chapter 3• The mass in grams of one mole (6.022 x

1023 particles) of a substance• Example: H2O

• The mass of two moles of hydrogen atoms and one mole of oxygen atoms

Page 45: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 45

Example

• Find the molar mass of K2SO4

• 174.27 g/mol

Page 46: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 46

You try

• Find the molar mass of (NH4)2CrO4

• 152.10 g/mol

Page 47: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 47

Formula mass and molar mass

• Numerically equal• Only the units are different

Page 48: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 48

Discuss

• How many moles of atoms of each element are there in one mole of ammonium carbonate, (NH4)2CO3

• 2 mol N, 8 mol H, 1 mol C, 3 mol O• Determine both the formula mass and the

molar mass of ammonium carbonate• 96.11 amu, 96.11 g/mol

Page 49: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 49

Converting with molar mass

• Relate mass in grams to number of moles• Relate mass in grams to number of particles

Page 50: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 50

Example

• What is the mass in grams of 3.04 mol of ammonia vapor, NH3?

• 51.8 g

Page 51: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 51

You try

• What is the mass in grams of 0.257 mol of calcium nitrate, Ca(NO3)2?

• 42.2 g

Page 52: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 52

Example

• How many moles of SO2 are in 3.82 g?• 0.0596 mol

Page 53: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 53

You try

• How many moles of Cl2 are there in 77.1 g?• 1.09 mol

Page 54: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 54

Example

• How many molecules are there in 77.1 g Cl2?

• 6.55 x 1023 molecules

Page 55: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 55

You try

• How many molecules are in 4.15 x 10-3 g of C6H12O6?

• 1.39 x 1019 molecules

Page 56: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 56

Percentage composition

• Percentage by mass of each element in a compound

• Example: gum

Page 57: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 57

Example

• Find the percentage composition of sodium nitrate NaNO3.

• 27.05% Na• 16.48% N• 56.47% O

Page 58: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 58

You try

• Find the percentage composition of silver sulfate, Ag2SO4.

• 69.19% Ag• 10.29% S• 20.53% O

Page 59: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 59

Discuss

• Zinc chloride, ZnCl2 is 52.02% chlorine by mass. What mass of chlorine is contained in 80.3 g of ZnCl2?

• How many moles of Cl is this?• 41.8 g• 1.18 mol

Page 60: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 60

Empirical formula

• The symbols for the elements combined in a compound

• Subscripts show the smallest whole-number mole ratio of the atoms

• Determined from the percent composition of a substance

Page 61: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 61

Empirical formula

• Usually the same as an ionic compound’s formula unit

• Not always the same as the molecular formula• Diborane’s molecular formula is B2H6

• The empirical formula is BH3

Page 62: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 62

Example

• A compound is analyzed and found to contain 36.70% potassium, 33.27% chlorine, and 30.03% oxygen. What is the empirical formula of the compound?

• KClO2

Page 63: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 63

You try

• Determine the empirical formula of the compound that contains 17.15% carbon, 1.44% hydrogen, and 81.41% fluorine.

• CHF3

Page 64: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 64

Example

• A 60.0 g sample of tetraethylead, a gasoline additive, is found to contain 38.43 g lead, 17.83 g carbon, and 3.74 g hydrogen. Find its empirical formula

• PbC8H20

Page 65: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 65

You try

• A 170.00 g sample of an unidentified compound contains 29.84 g sodium, 67.49 g chromium, and 72.67 g oxygen. What is its empirical formula?

• Na2Cr2O7

Page 66: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 66

Discuss

• Find the empirical formula of a compound that contains 53.70% iron and 46.30% sulfur.

• Fe2S3

Page 67: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 67

Molecular formula

• Show how many atoms are in each molecule

• Related to empirical formula

• x is the whole number the subscripts must be multiplied by• It might be 1

formulamolecular formula empirical x

Page 68: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 68

Mass relationship

mass formulamolecular mass formula empirical x

Page 69: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 69

Example

• The empirical formula for trichloroisocyanuric acid is OCNCl. The molar mass of this compound is 232.41 g/mol. What is its molecular formula?

• O3C3N3Cl3

Page 70: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 70

Example

• Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 amu.

• N2H4

Page 71: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 71

You try

• Determine the molecular formula of the compound with an empirical formula of CH and a formula mass of 78.110 amu.

• C6H6

Page 72: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 72

Example

• If 4.04 g of N combine with 11.46 g of O to produce a compound with a formula mass of 108.0 amu, what is the molecular formula of this compound?

• N2O5

Page 73: Chemical Formulas and Chemical Compounds

Chemistry chapter 7 73

You try

• The molar mass of a compound is 92 g/mol. Analysis of a sample of the compound indicates that it contains 0.606 g N and 1.390 g O. Find its molecular formula.

• N2O4


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