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Chemical Kinetics Practice Exam Chemical Kinetics Name (last)________________ (First)______________________ Read all questions before you start. Show all work and explain your answers to receive full credit . Report all numerical answers to the proper number of significant figures. By signing your signature above you agree that you have worked alone and neither give nor received help from any source. Keep your eyes on your own paper at all times System LENGTH: VOLUME MASS Temperature English: 1 ft = 12 in 1 mile = 5280 ft 1 yd = 3 ft 1 gal = 4 qt 1 qt = 57.75 in 3 1 lb = 16 oz 1 ton = 2000 lb T F = 1.8T C + 32 SI- English: 1 in = 2.54 cm 1 mi = 1.609 km 1 L = 1.057 qt 1 qt = 0.946 L 1 lb = 453.6 g 1 oz = 28.35 g T C = (T F 32) 1.8 Misc. info 1 mole = 6.02•10 23 R = 8.314 J/ mol•K or .08206 L•atm/mol•K Rates of Reaction rate = Δ[A] /Δ t = - Δ [react] /Δ t = Δ [prod] /Δ t Rate laws (Order of reaction) initial rate = k [A] x [B] y [C] z ... Overall order = x + y + z + ... Conc. vs. Time dependence Zeroth Order rate = k [A] = [A] o - kt Conc. vs. Time straight line. Half life; t 1/2 = [A] o / 2 k First Order rate = k [A] [A] = [A]o exp{- kt) ln[A] = ln[A] o - kt ln[Conc.] vs. Time straight line Half life; t 1/2 = 0.693 / k Second Order rate = k [A] 2 or k [A] [B] 1/[A] = 1/[A] o + kt 1/[Conc.] vs. Time straight line Half life; t 1/2 = 1 / k [A] o Temperature vs. Rate dependence k = A exp {-E a /RT} ln k = ln A - (Ea / R)•1/T ln(k) vs. 1/T straight line. ln(k1/k2) = (Ea / R) (1/T2-1/T1)
Transcript
Page 1: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

Chemical Kinetics

Practice Exam Chemical Kinetics Name (last)________________(First)______________________

Read all questions before you start. Show all work and explain your answers to receive full credit. Report all numerical answers to the proper number of significant figures. By signing your signature above you agree that you have worked alone and neither give nor received help from any source. Keep your eyes on your own paper at all times

System LENGTH: VOLUME MASS Temperature

English: 1 ft = 12 in

1 mile = 5280 ft

1 yd = 3 ft

1 gal = 4 qt

1 qt = 57.75 in3

1 lb = 16 oz

1 ton = 2000 lb

T F = 1.8T C + 32

SI-

English:

1 in = 2.54 cm

1 mi = 1.609 km

1 L = 1.057 qt

1 qt = 0.946 L

1 lb = 453.6 g

1 oz = 28.35 g T C =

(T F−32)1.8

Misc. info 1 mole = 6.02•1023 R = 8.314 J/ mol•K or .08206 L•atm/mol•K

Rates of Reaction rate = Δ[A] /Δ t = - Δ [react] /Δ t = Δ [prod] /Δ t

Rate laws (Order of reaction) initial rate = k [A]x [B]y [C]z ... Overall order = x + y + z + ...

Conc. vs. Time dependence

Zeroth Order

rate = k

[A] = [A]o - kt

Conc. vs. Time straight line.

Half life; t1/2 = [A]o / 2 k

First Order

rate = k [A]

[A] = [A]o exp{- kt)

ln[A] = ln[A]o - kt

ln[Conc.] vs. Time straight line

Half life; t1/2 = 0.693 / k

Second Order

rate = k [A]2 or k [A] [B]

1/[A] = 1/[A]o + kt

1/[Conc.] vs. Time straight line

Half life; t1/2 = 1 / k [A]o

Temperature vs. Rate dependence

k = A exp {-Ea /RT}

ln k = ln A - (Ea / R)•1/T

ln(k) vs. 1/T straight line.

ln(k1/k2) = (Ea / R) (1/T2-1/T1)

Page 2: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

Multiple -choice. Show work for partial credit.

1 Which of the following statement is true?

a) The activation energy of a reaction increases with increasing temperature.

b) The slowest step in a mechanism will always determine the rate of a reaction.

c) A catalyst not only changes the activation energy of a reaction, it also changes ΔHrxn.

d) All of these statements are true.

2 A plot of [A]-1 vs., time is most likely a

a) Arrhenius equation b) second order reaction

c) first order reaction d) zeroth order reaction

3 If the heat of reaction is endothermic, which of the following is always true?

a ) the reaction is fast b) the reaction is slow

c) the energy of the reactants is greater than the products

d) the energy of the reactants is lower than the products

4 The rate of a reaction is not influenced by:

a) concentration of reactant b) Catalyst

c) Energy of Reactant d) stirring of chemicals

5 The pre-exponential factor in the Arhenius equation takes in to account:

a) The steric factor b) The activation energy

c) The energy of the reaction d) The Maxwell-Boltzmann curve.

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6 The reaction: 2I-

(aq) + S2O82-

(aq) I2(aq) + 2SO42-

(aq) was studied at 25°C. The following results were obtained

[ I - ] o(M) [S2O82-] (M) Initial Rate (M/s)

1 0.040 0.080 12.50•10-6

2 0.040 0.040 3.125•10-6

3 0.020 0.080 12.50•10-6

i) Determine the rate law. ii) What is the rate constant using experiment # 2 iii) What is the molecularity of this reaction? iv) Calculate the half-life using the data from Experiment2

i)

Rate = k [I−]x[S2O82−

]y = k [I−]0[S2O82−

]2

ii)

Rate(expt2) = k [I−]0[S2O82−

]2

3.125 ⋅ 10-6 = k [.040]0[.040]2

k =3.125x10-6

1 ∗[.040]2=

iii) Bimolecular since Order = 2 = 0 + 2

iv)

t 12

=1

k Ao[ ]=

12.0 ⋅10−3 .040M[ ]

=12,800 s

7 Determine if the statements below are true or false then write a convincing statement to justify your answer. a) At a given temperature, all molecules posses the same kinetic energy

False. The MB distribution plot shows that any given temperature molecules will have a range of kinetic energy with the average centered at the Urms.

b) Reactant molecules must collide with greater energy than the activation energy in order to change to product molecules.

False. Not only must the molecules collide with sufficient energy to overcome the activation energy, they molecules must also have the right orientation (steric factor).

c) The activation energy of a reaction is not dependent on the temperature.

True. The Eact is a function of the mechanism of the reaction, which is a function of the chemicals that are involve in the reaction.

Remember in the Crystal Violet Experiment that Eact was the same whether the data was collected at high temperature or low

temperature. In fact the temperature data was used to determine Eact.

d) A catalyst increases the rate by increasing collision frequency.

False. A catalyst changes the mechanism, which alters (lowering) the Eact, thereby increasing the rate of the reaction. The reason the reaction rate increases is because Eact decreases. Collision Frequency may have been altered but it is not the primary reason for the rate change.

8 Explain using a Maxwell-Boltzmann Distribution curve why an exothermic reaction favors an increase of the reverse reaction at higher temperature even though according to the Kinetic Molecular Theory, the rate of a reaction increases with increasing temperature. For an exothermic reaction, if the temperature is increase, the percentage of the product molecules is greater than that of the reactant that surpasses the activation Energy. Therefore more products will return to reactants therefore shifting the reaction to the left.

Page 4: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

9 Most reaction occurs by a series of steps. The energy profile shown below is a three-step mechanism for the reaction of NO with

H2. i) 2NO N2O2 fast

ii) N2O2 + H2 → N2O + H2O slow

iii) N2O + H2 → N2 + H2O fast

ΔH1 = + 20 kJ

ΔH2 = + 30 kJ

ΔH3 = - 10 kJ DH1

Eact1 = 50 kJ

Eact2 =

Eact3 = 30 kJ

E1‡ = 50 kJ (Transition state)

E2‡ = 100 kJ

E3‡ = ?

Place answers to questions ii, iii, iv, & vi. E (NO) = __0_kJ

E(N2O2)= __20 kJ

Eact2 = __80 kJ

E3‡ = __80 kJ

ΔHrxn= __40 kJ

Eact(f)= __100 kJ

Eact(r)= __60 kJ

Label the graph above placing the chemical specie along the reaction profile diagram and then answer the following:

i) What is the overall stoichiometry and what are the intermediate and the catalyst (if any) ? 2NO + 2H2 N2 + 2H2O, Intermediate = N2O2, N2O, Catalyst = None

ii) What are the energies of NO and N2O2 according to the graph above? E NO = 0 kJ EN2O2

= 20 kJ

iii) What are the energies of Eact2 and E3‡ ?

Eact2 = 80 kJ E3‡ = 80 kJ

iv) What is the energy of the overall reaction, DHrxn ? ΔHrxn = + 40 kJ

v) Is the reaction endothermic or exothermic ? ΔHrxn = + 40 kJ > 0, Endothermic

vi) What are the activation energies for the overall forward Eact(f), and overall reverse Eact(r), reactions ? Eact(f) = 100 kJ Eact(r) = 60 kJ

vii) What are the rate law and the molecularity for this reaction ?

Rate = k [N2O2] [H2], but N2O2 is an intermediate thus Keq = [N2O2] / [NO]2

Thus, Rate = k Keq [NO]2 * [H2] = K [NO]2 * [H2], termolecular

viii) If the pre-exponential factor is 1.27•1010, what is the rate constant (include units) for this reaction at 600K ? k = A exp [-Ea/RT}, thus k = 1.27•1010 exp [-100,000 J / 8.314 J•mol K-1 * 600 K}

k = 25 M-2 / s

ix) What temperature is required to raise the rate constant to 250 ? (units are not shown here) k = A exp [-Ea/RT}, lnK = lnA - Ea/RT, T = Ea/R(lnK – lnA), T = 678 K

x) If the catalyzed reaction is ten times faster than the uncatalyzed reaction, what is the rate of disappearance of the reactant for the catalyzed reaction? You may assume that you are using the methods of initial rates in which the concentration of all chemicals are 1.0 M. T= 600 K

Rate = 250 M / s

Page 5: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

10 The reaction of hydrogen with iodine has the following accepted mechanism:

(1) I2 (g) → 2I (g) fast (2) H2(g) + I (g) → H2I (g) fast (3) H2I (g) + I (g) → 2HI (g) slow What is the rate law for this reaction?

11 Consider the following reaction energy diagram: i) How many elementary steps in the reaction mechanism?

ii) Which step is rate limiting? i.e. 1st, 2nd, 3rd, 4th,...

iii) Is the overall reaction exothermic or endothermic?

iv) What is the energy of the reaction (kJ)?

v) What is the activation energy (kJ) for the reverse rxn?

A → C

- 60 kJ

100 kJ

0 kJ

170 kJ

A

C

B45 kJ

vi) What is the Eact (kJ) for the rate determining step?

Page 6: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

12 A theoretical reaction: A + B → C, has the following initial rate data shown below.

Expt. # [A] M [B] M -Δ [A] / Δt M/s

1 (300K) 0.012 0.035 1.0 x 10-5 2 (300K) 0.024 0.070 8.0 x 10-5 3 (300K) 0.024 0.035 1.0 x 10-5 4 (300K) 0.012 0.070 8.0 x 10-5 5 (600K) 0.012 0.070 1.8

i) Determine the complete rate law for the reaction including the rate constant with proper units. ii) What is the activation energy (Ea in kJ) for this reaction and the frequency factor (A).

Page 7: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

13 A slightly bruised apple will rot extensively in about 4 days at room temperature (20°C). If it is kept in the

refrigerator at 0°C, the same extent of rotting takes about 16 days. What is the Eact (kJ) for the rotting reaction?

Page 8: Chemical Kinetics Practice Exam Chemical Kinetics Name ...faculty.sdmiramar.edu/fgarces/zCourse/All_Year/Ch201/aMy_FileLec/... · Multiple -choice. Show work for partial credit. 1

14 Determine if the statements are true or false. Give a reasonable explanation to support or refute these statements. i) At a given temperature, all molecules posses the same kinetic energy. ii) The higher the activation energy of a reaction, the slower the rate of the reaction.

iii) If reactant molecules collide with greater energy than the activation energy, products are formed automatically.

iv) Exothermic reaction have faster rates than endothermic reactions.

v) The activation energy of a reaction is lowered by a catalyst.

vi) The enthalpy change for a reaction is lowered by a catalyst.

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