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Chemistry 102(01) Spring 2013

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Chemistry 102(01) Spring 2013. Instructor: Dr. Upali Siriwardane e-mail : [email protected] Office : CTH 311 Phone 257-4941 Office Hours : M ,W 8:00-9:00 & 11:00-12:00 am; Tu,Th,F 9:30 - 11:30 am.  Test Dates :. September 27 , 2013 (Test 1): Chapter 12 & 13 - PowerPoint PPT Presentation
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13-1 CHEM 102, Spring 2013, LA TECH Instructor: Dr. Upali Siriwardane e-mail: [email protected] Office: CTH 311 Phone 257-4941 Office Hours: M,W 8:00-9:00 & 11:00-12:00 am; Tu,Th,F 9:30 - 11:30 am. Test Dates: Chemistry 102(01) Spring 2013 September 27, 2013 (Test 1): Chapter 12 & 13 April 24, 2013 (Test 2): Chapter 14 & 15 May13, 2013 (Test 3) Chapter 16 & 17 May 15, 2012 (Make-up test) comprehensive: Chapters 12-17 9:30-10:45:15 AM, CTH 328
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Page 1: Chemistry  102(01) Spring 2013

13-1CHEM 102, Spring 2013, LA TECH

Instructor: Dr. Upali Siriwardane

e-mail: [email protected]

Office: CTH 311

Phone 257-4941

Office Hours: M,W 8:00-9:00 & 11:00-12:00 am;

Tu,Th,F 9:30 - 11:30 am. 

Test Dates:

Chemistry 102(01) Spring 2013

September 27, 2013 (Test 1): Chapter 12 & 13

April 24, 2013 (Test 2): Chapter 14 & 15

May13, 2013 (Test 3) Chapter 16 & 17

May 15, 2012 (Make-up test) comprehensive: Chapters 12-17 9:30-10:45:15 AM, CTH 328

Page 2: Chemistry  102(01) Spring 2013

13-2CHEM 102, Spring 2013, LA TECH

Chapter 13. Chemical Kinetics

13.1 Catching Lizards 563

13.2 The Rate of a Chemical Reaction 564

13.3 The Rate Law: The Effect of Concentration

on Reaction Rate 569

13.4 The Integrated Rate Law: The Dependence of

Concentration on Time 573

13.5 The Effect of Temperature on Reaction Rate 581

13.6 Reaction Mechanisms 588

13.7 Catalysis 593

Page 3: Chemistry  102(01) Spring 2013

13-3CHEM 102, Spring 2013, LA TECH

A Nanoscale View:Elementary Reactions

Most reactions occur through a series of simple

steps or elementary reactions.

Elementary reactions could be

unimolecular - rearrangement of a molecule

bimolecular - reaction involving the collision of

two molecules or particles

termolecular - reaction involving the collision of

three molecules or particles

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13-4CHEM 102, Spring 2013, LA TECH

2NO2 (g) + F2 (g) 2NO2F (g)

If the reaction took place in a single step the rate law would be: rate = k

[NO2]2 [F2]

Observed: rate = k1 [NO2] [ F2]

If the observed rate law is not the same as if the reaction took place in a single

step that more than one step must be involved

Elementary Reactions and Mechanism

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13-5CHEM 102, Spring 2013, LA TECH

Elementary ReactionsA possible reaction mechanism might be:

Step one NO2 + F2 NO2F + F (slow)

Step two NO2 + F NO2F (fast)

Overall 2NO2 + F2 2NO2F

slowest step in a multi-step mechanismthe step which determines the overall rate of the reaction

rate = k1 [NO2] [ F2]

Rate Determining Step

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This type of plot

shows the energy

changes during

a reaction.

This type of plot

shows the energy

changes during

a reaction.

Reaction profile of rate determining step

DH

activation

energy

Pote

nti

al

En

erg

y

Reaction coordinate

Page 7: Chemistry  102(01) Spring 2013

13-7CHEM 102, Spring 2013, LA TECH

What Potential Energy Curves ShowExothermic Reactions

Endothermic Reactions

Activation Energy (Ea) of reactant or the minimum

energy required to start a reaction

Effect of catalysts

Effect of temperature

Page 8: Chemistry  102(01) Spring 2013

13-8CHEM 102, Spring 2013, LA TECH

Page 9: Chemistry  102(01) Spring 2013

13-9CHEM 102, Spring 2013, LA TECH

Exothermic reaction

Endothermic reaction

Examples of reaction profiles

Page 10: Chemistry  102(01) Spring 2013

13-10CHEM 102, Spring 2013, LA TECH

High activation energy (kinetic)

Low heat of reaction (thermodynamic)

Low activation energy (kinetic)

High heat of reaction (thermodynamic)

Examples of reaction profiles

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13-11CHEM 102, Spring 2013, LA TECH

Catalysts Lowers Ea

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13-12CHEM 102, Spring 2013, LA TECH

Page 13: Chemistry  102(01) Spring 2013

13-13CHEM 102, Spring 2013, LA TECH

1. Given the chemical reaction:

NO2(g) + CO(g) NO (g) + CO2 (g), and the mechanism:

 

NO2(g) + NO2 (g) NO3 (g) + NO (g); slow step

NO3(g) + CO (g) NO2 (g) + CO2 (g); fast step

 

a) How many elementary steps are in the mechanism?

 

b) Does the elementary steps adds up to overall chemical reaction? (Show your work)

 

 c) What’s is the molecularity of the slowest step?

 

 

Page 14: Chemistry  102(01) Spring 2013

13-14CHEM 102, Spring 2013, LA TECH

1. Given the chemical reaction:

NO2(g) + CO(g) NO (g) + CO2 (g), and the mechanism:

NO2(g) + NO2 (g) NO3 (g) + NO (g); slow step

NO3(g) + CO (g) NO2 (g) + CO2 (g); fast step

 

d) What is the rate determining step in the mechanism?

 

e) What is(are) the intermediates in the mechanism?

 

Page 15: Chemistry  102(01) Spring 2013

13-15CHEM 102, Spring 2013, LA TECH

1. Given the chemical reaction:

NO2(g) + CO(g) NO (g) + CO2 (g), and the mechanism:

NO2(g) + NO2 (g) NO3 (g) + NO (g); fast step

NO3(g) + CO (g) NO2 (g) + CO2 (g); slow step

 

f) What’s the rate law for the chemical reaction?

 

 

g) Rate law of what elementary step would agree with the experimentally determined the rate law?

Page 16: Chemistry  102(01) Spring 2013

13-16CHEM 102, Spring 2013, LA TECH

1. Given the chemical reaction:

NO2(g) + CO(g) NO (g) + CO2 (g), and the mechanism:

 

NO2(g) + NO2 (g) NO3 (g) + NO (g); slow step

NO3(g) + CO (g) NO2 (g) + CO2 (g); fast step

 

 

f) What’s the rate law for the chemical reaction?

 

 

g) Rate law of what elementary step would agree with the experimentally determined the rate law?

Page 17: Chemistry  102(01) Spring 2013

13-17CHEM 102, Spring 2013, LA TECH

2) Draw potential energy diagrams to show:a) An Exothermic Reaction:

b) Endothermic Reaction:

c) Label Activation Energy (Ea) on both diagrams a) and b) above.

 

 

 

 

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13-18CHEM 102, Spring 2013, LA TECH

2) Draw potential energy diagrams to show:

d) the effect of a catalyst in a chemical reaction.

 

 

 

Page 19: Chemistry  102(01) Spring 2013

13-19CHEM 102, Spring 2013, LA TECH

3) The chemical reaction:

2NO2 (g) + F2(g) 2NO2F(g)

follows Rate Law:     rate = k [NO2] [F2]

What would be the molecularity of the rate determining step in the mechanism?

 

 

 

Page 20: Chemistry  102(01) Spring 2013

13-20CHEM 102, Spring 2013, LA TECH

Reaction Mechanism

A set of elementary reactions which represent

the overall reaction

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13-27CHEM 102, Spring 2013, LA TECH

Mechanism Oxidation ofIodide Ion by Hydrogen Peroxide

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13-28CHEM 102, Spring 2013, LA TECH

Rate Law of Oxidation ofIodide Ion by Hydrogen Peroxide

Step 1.

HOOH + I- HOI + OH-

slow step - rate determining step, suggests that

the reaction is first order with regard to hydrogen

peroxide and iodide ion

rate = k[HOOH][I-]

Page 29: Chemistry  102(01) Spring 2013

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4) The mechanism of a reaction is shown below.

HOOH + I¯ HOI + OH¯ (slow)

HOI + I¯ I2 + OH¯ (fast)

2OH¯ + 2H3O+ 4 H2O (fast)

 

a) What is the overall reaction?

 

 

b) Which compounds are intermediates?

 

 

 

 

Page 30: Chemistry  102(01) Spring 2013

13-30CHEM 102, Spring 2013, LA TECH

4) The mechanism of a reaction is shown below.

HOOH + I¯ HOI + OH¯ (slow)

HOI + I¯ I2 + OH¯ (fast)

2OH¯ + 2H3O+ 4 H2O (fast)

 

c) Predict the rate law based on this mechanism.

 

 

d) What is the overall order of the reaction?

 

 

 

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13-31CHEM 102, Spring 2013, LA TECH

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13-32CHEM 102, Spring 2013, LA TECH

Arrhenius Equation: Dependence of Rate Constant (k) on T Rate constant (k)

k = A e-Ea/RT

A = frequency factor: A = p x z

Ea = Activation energyR = gas constantT = Kelvin temperaturep = collision factorz = Orientation factor

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13-33CHEM 102, Spring 2013, LA TECH

Page 34: Chemistry  102(01) Spring 2013

13-34CHEM 102, Spring 2013, LA TECH

An alternate form of the Arrhenius equation:

k = A e-Ea/RT

ln k = + ln A

If ln k is plotted against 1/T, a straight line of slope -Ea/RT is obtained.

Activation energy - Ea

The energy that molecules must have in order to react.

( ) ( )1

T

Ea

R-

Arrhenius Equation: ln form

Page 35: Chemistry  102(01) Spring 2013

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5) For the reaction A + B C, the rate constant at 215 oC is 5.0 x 10-3 and the rate constant at 452o C is 1.2 x 10-1.

a)How the rate constant is affected by increasing the temperature?

b)Write the form of Arrhenius equation and define the variables that fit the data for this problem:

Page 36: Chemistry  102(01) Spring 2013

13-36CHEM 102, Spring 2013, LA TECH

5) For the reaction A + B C, the rate constant at 215 oC is 5.0 x 10-3 and the rate constant at 452o C is 1.2 x 10-1.

c)What is the activation energy in kJ/mol?

d)What is the rate constant at 100oC.

Page 37: Chemistry  102(01) Spring 2013

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Arrhenius Equation: Dependence of Rate Constant (k) on T Rate constant (k)

k = A e-Ea/RT

Ea = Activation energyR = gas constantT = Kelvin temperatureA = frequency factor: A = p x zp = collision factorz = Orientation factor

Page 38: Chemistry  102(01) Spring 2013

13-38CHEM 102, Spring 2013, LA TECH

Orientation Factor: Some Unsuccessful Collisions

I- + CH3Br ICH3 + Br-

Page 39: Chemistry  102(01) Spring 2013

13-39CHEM 102, Spring 2013, LA TECH

Calculation of Eak = A e-

Ea/RT

ln k = ln A - Ea/RT

log k = log A - Ea/ 2.303 RT

using two set of values

log k1 = log A - Ea/ 2.303 RT1

log k2 = log A - Ea/ 2.303 RT2

log k1 - log k2 = - Ea/ 2.303 RT2 + Ea/ 2.303 RT1

log k1/ k2 = Ea/ 2.303 R[ 1/T1 - 1/T2 ]

Page 40: Chemistry  102(01) Spring 2013

13-40CHEM 102, Spring 2013, LA TECH

Reaction rates are temperature dependent.

0

1

2

3

4

5

6

7

20 25 30 35 40 45 50

Here are rate constants

for N2O5 decomposition

at various temperatures.

T, oC k x 10

4, s

-1

20 0.235

25 0.469

30 0.933

35 1.82

40 3.62

45 6.29

k x

10

4 (

s-1

)

Temperature (o

C)

Rate vs Temperature plot

Page 41: Chemistry  102(01) Spring 2013

13-41CHEM 102, Spring 2013, LA TECH

y = -12392x + 40.809

Slope = -12392R = 8.35 J/mol KEa = 103 kJ / mol

-2

-1

0

1

2

3

0.0031 0.0032 0.0033 0.0034 0.0035

ln k

T-1

Calculation of Ea from N2O5 data

Page 42: Chemistry  102(01) Spring 2013

13-42CHEM 102, Spring 2013, LA TECH

Collision ModelThree conditions must be met at the nano-scale

level if a reaction is to occur:

the molecules must collide;

they must be positioned so that the reacting

groups are together in a transition state between

reactants and products;

and the collision must have enough energy to

form the transition state and convert it into

products.

Page 43: Chemistry  102(01) Spring 2013

13-43CHEM 102, Spring 2013, LA TECH

Effect of Concentrationon Frequency ofBimolecular Collisions

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Transition State: Activated Complex or Reaction Intermediatesan unstable arrangement of atoms that has the

highest energy reached during the rearrangement

of the reactant atoms to give products of a reaction

Page 45: Chemistry  102(01) Spring 2013

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Catalyst

A substance which speeds up the rate of a

reaction while not being consumed

Homogeneous Catalysis - a catalyst which is in

the same phase as the reactants

Heterogeneous Catalysis- a catalyst which is

in the different phase as the reactants

catalytic converter• solid catalyst working on gaseous materials

Page 46: Chemistry  102(01) Spring 2013

13-46CHEM 102, Spring 2013, LA TECH

Conversion of NO to N2 + O2

Page 47: Chemistry  102(01) Spring 2013

13-47CHEM 102, Spring 2013, LA TECH

Catalytic Converter catalyst

H2O(g) + HCs CO(g) + H2(g) (unbalanced)

catalyst

2 H2(g) + 2 NO(g) N2(g) + 2 H2O(g)

catalyst

HCs + O2(g) CO2(g) + H2O(g) (unbalanced)

catalyst

CO(g) + O2(g) CO2(g) (unbalanced)

catalyst = Pt-NiOHCs = unburned hydrocarbons

Page 48: Chemistry  102(01) Spring 2013

13-48CHEM 102, Spring 2013, LA TECH

Enzymes: Biological catalystsBiological catalysts

Typically are very large proteins.

Permit reactions to ‘go’ at conditions that the body

can tolerate.

Can process millions of molecules every second.

Are very specific - react with one or only a few types

of molecules (substrates).

Page 49: Chemistry  102(01) Spring 2013

13-49CHEM 102, Spring 2013, LA TECH

The active site

Enzymes are typically HUGE proteins, yet only a

small part is actually involved in the reaction. The active site has two

basic components.

catalytic site

binding site

Model of

trios-phosphate-isomerase

Model of

trios-phosphate-isomerase

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Maximum Velocity for an Enzyme Catalyzed Reaction

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Enzyme Activity Destroyed by Heat

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Mechanisms with a Fast Initial Step

2 NO(g) + Br2(g) 2NOBr(g)

rateexperimental = k[NO]2[Br2]

Page 54: Chemistry  102(01) Spring 2013

13-54CHEM 102, Spring 2013, LA TECH

Mechanism of NO + Br2

Rate = k[NOBr2][NO]

Page 55: Chemistry  102(01) Spring 2013

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Rate Constants for NO + Br2

Step +1(forward), rate constant k1

Step -1(backward), rate constant k-1

Step 2, rate constant k2

rateStep+1 = rateStep-1 + rateStep2

k1[NO][Br2] = k-1[NOBr2] - k2[NOBr2]

Page 56: Chemistry  102(01) Spring 2013

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Relationships of Rate Constants

k1[NO][Br2] ~ k-1[NOBr2]

thus

[NOBr2] = (k1/k-1)[NO][Br2]

substituting into

rate = k2[NOBr2][NO]

rate = k2((k1/k-1)[NO][Br2])[NO]

rate = (k2k1/k-1)[NO]2[Br2]

Page 57: Chemistry  102(01) Spring 2013

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Chain Mechanismschain initiating step

• - the step of a mechanism which • starts the chain chain

propagating step(s) • the step or steps which keeps the chain going

chain terminating step(s) • the step or steps which break the chain

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Chain Mechanismscombustion of gasoline in an internal

combustion

engine

chain initiating step - additives which generate

free radicals, particles with unpaired electrons

chain propagating step(s) - steps which generate

new free radicals

chain terminating step(s)

- steps which do not generate new free radicals


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